Planejamento e Otimização de Experimentos
Transcript of Planejamento e Otimização de Experimentos
Planejamento e Otimização de
Experimentos
Mixture Experiments
Prof. Dr. Anselmo E de Oliveira
anselmo.quimica.ufg.br
• In mixture experiments, the factors are the
components of ingredients of a mixture, and
consequently their levels are not independent
0 ≤ 𝑥𝑖 ≤ 1 𝑖 = 1,2, … , 𝑝 components
and
𝑥1 + 𝑥2 +⋯+ 𝑥𝑝 = 1
𝒙𝟏 + 𝒙𝟐 = 𝟏
x2
x1 0 1
1
𝒙𝟏 + 𝒙𝟐 + 𝒙𝟑 = 𝟏
Trilinear coordinate system
Simplex Designs
• Simplex Designs are used to study the effects of
the mixture components on the response variable
• 𝒑,𝒎 Simplex lattice design
𝑝 components
𝑚+ 1 equally spaced values from 0 to 1
𝑥𝑖 = 0,1
𝑚,2
𝑚,… , 1
All possible combinations (mixtures) of the proportions
are used
Ex: 𝒑 = 𝟑 and 𝒎 = 𝟐 3,2 simplex lattice design
𝑥𝑖 = 0,1
2, 1 𝑖 = 1,2,3
Six runs:
X1, X2, X3 = 1,0,0 , 0,1,0 , 0,0,1 ,1
2,1
2, 0 ,
1
2, 0,1
2, 0,1
2,1
2
The number of points in
a {𝑝,𝑚} simplex lattice
design is
𝑁 =𝑝 +𝑚 − 1 !
𝑚! 𝑝 − 1 !
• An alternative to simplex lattice design
is the simplex centroid design
2𝑝 − 1 points corresponding to 1
𝑝,1
𝑝, … ,1
𝑝
3,2 simplex lattice design: 6 runs
1,0,0 , 0,1,0 , 0,0,1 ,1
2,1
2, 0 ,
1
2, 0,1
2, 0,1
2,1
2
3,2 simplex centroid design: 23 − 1 = 7 runs
1,0,0 , 0,1,0 , 0,0,1 ,1
2,1
2, 0 ,1
2, 0,1
2, 0,1
2,1
2 𝟏
𝟑,𝟏
𝟑,𝟏
𝟑
{3,2}
{4,3}
• It is usually desirable to augment the simplex
lattice or simplex centroid
Mixture Models
• Linear
𝑦 = 𝑏𝑖𝑥𝑖
𝑝
𝑖=1
• Quadractic
𝑦 = 𝑏𝑖𝑥𝑖
𝑝
𝑖=1
+ 𝑏𝑖𝑗𝑥𝑖𝑥𝑗
𝑝
𝑖<𝑗
• Full Cubic
𝑦 = 𝑏𝑖𝑥𝑖
𝑝
𝑖=1
+ 𝑏𝑖𝑗𝑥𝑖𝑥𝑗
𝑝
𝑖<𝑗
+ 𝛿𝑖𝑗𝑥𝑖𝑥𝑗
𝑝
𝑖<𝑗
𝑥𝑖 − 𝑥𝑗 + 𝑏𝑖𝑗𝑘𝑥𝑖𝑥𝑗𝑥𝑘𝑖<𝑗<𝑘
• Special Cubic
𝑦 = 𝑏𝑖𝑥𝑖
𝑝
𝑖=1
+ 𝑏𝑖𝑗𝑥𝑖𝑥𝑗
𝑝
𝑖<𝑗
+ 𝑏𝑖𝑗𝑘𝑥𝑖𝑥𝑗𝑥𝑘𝑖<𝑗<𝑘
– Linear blending portion
𝑏𝑖𝑥𝑖
𝑝
𝑖=1
– When curvature arises from nonlinear blending
between component pairs, the parameters 𝑏𝑖𝑗
represent either synergistic or antagonistic blending
– Higher order terms are frequently necessary in
mixture models
Plots
Mixture Designs with
• Example
Three components – polyethylene(𝑥1), polystyrene(𝑥2), and polypropylene(𝑥3) – were
blended to form fiber that will be spun into yarn for
draperies. The response variable of interest is yarn
elongation in kilograms of force applied. A {3,2}
simplex lattice design is used to study the product.
Design Point
Component Proportions Observed Elongation values
Average Elongation value (𝒚 ) 𝑥1 𝑥2 𝑥3
1 1 0 0 11.0,12.4 11.7
2 ½ ½ 0 15.0,14.8,16.1 15.3
3 0 1 0 8.8,10.0 9.4
4 ½ 0 ½ 17.7,16.4,16.6 16.9
5 0 ½ ½ 10.0,9.7,11.8 10.5
6 0 0 1 16.8,16.0 16.4
install.packages("mixexp") library(mixexp) dat <- SLD(3,2) #{3,2} simplex lattice design DesignPoints(dat) #plot mixvars <-c("x1","x2","x3") y <- c(11.7,15.3,9.4,16.9,10.5,16.4) MixModel(dat,"y",mixvars,2) #second-order mixture polinomial coefficients Std.err t.value Prob x1 11.7 NaN NaN NaN x2 9.4 NaN NaN NaN x3 16.4 NaN NaN NaN x2:x1 19.0 NaN NaN NaN x3:x1 11.4 NaN NaN NaN x2:x3 -9.6 NaN NaN NaN Residual standard error: NaN on 0 degrees of freedom Corrected Multiple R-squared: 1 Call: lm(formula = mixmodnI, data = frame) Coefficients: x1 x2 x3 x1:x2 x1:x3 x2:x3 11.7 9.4 16.4 19.0 11.4 -9.6 𝑦 = 11.7𝑥1 + 9.4𝑥2 + 16.4𝑥3 + 19.0𝑥1𝑥2 + 11.4𝑥1𝑥3 − 9.6𝑥2𝑥3
because 𝑏3 > 𝑏1 > 𝑏2 we would conclude that component3 (polypropylene) produces yarn with the highest elongation
because 𝑏12 and 𝑏13 are positive, blending components 1 and 2 or 1 and 3 produces higher elongation values than would be expected just by averaging the elongations of the pure blends (synergistic blending effects)
components 2 and 3 have antagonistic blending effects
MixturePlot(dat$x3,dat$x2,dat$x1,y, x3lab="Fraction x3", x2lab="Fraction x2", x1lab="Fraction x1", corner.labs=c("x3","x2","x1"), constrts=FALSE,contrs=TRUE,cols=TRUE, mod=2,n.breaks=9)
If the maximum elongation is desired, a blend of components 1 and 3 should be chosen consisting of about 80% component 3 and 20% component 1
• In some mixture problems, constraints on the individual components arise – Lower bound constraint
𝑙𝑖 ≤ 𝑥𝑖 ≤ 1 When only lower bound constraints are present, the feasible design region is still a simplex
– Pseudocomponents
𝑥𝑖′ =𝑥𝑖 − 𝑙𝑖
1 − 𝑙𝑖𝑝𝑗=1
with 𝑙𝑖𝑝𝑗=1 < 1 and 𝑥1
′ + 𝑥2′ +⋯+ 𝑥𝑝
′ = 1
𝑥𝑖 = 𝑙𝑖 + 1 − 𝑙𝑖
𝑝
𝑗=1
𝑥𝑖′
– If the components have both upper and lower bound constraints, the feasible region is no longer a simplex: irregular polytope • Computer-generated optimal designs
feasible design region
Simplex centroid design