EE 5340 Semiconductor Device Theory Lecture 23 - Fall 2010
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Transcript of EE 5340 Semiconductor Device Theory Lecture 23 - Fall 2010
EE 5340Semiconductor Device TheoryLecture 23 - Fall 2010
Professor Ronald L. [email protected]
http://www.uta.edu/ronc
L23 10Nov2010 2
Gummel-Poon Staticnpn Circuit Model
C
E
B
B’
ILC
ILEIBF
IBRICC - IEC = {IS/QB}*
{exp(vBE/NFVt)-exp(vBC/NRVt)}
RC
RE
RBB
IntrinsicTransistor
L23 10Nov2010 3
Gummel Poon npnModel Equations
IBF = ISexpf(vBE/NFVt)/BF
ILE = ISEexpf(vBE/NEVt)
IBR = ISexpf(vBC/NRVt)/BR
ILC = ISCexpf(vBC/NCVt)
QB = (1 + vBC/VAF + vBE/VAR )
{½ + ¼ + (BFIBF/IKF + BRIBR/IKR)}
L23 10Nov2010 4
Charge componentsin the BJT **From Getreau, Modeling the
Bipolar Transistor, Tektronix, Inc.
L23 10Nov2010 5
Gummel PoonBase ResistanceIf IRB = 0, RBB = RBM+(RB-RBM)/QB
If IRB > 0RB = RBM + 3(RB-RBM)(tan(z)-z)/(ztan2(z))
[+iB/(IRB)]1/2-
(/)(iB/IRB)1/2z =
From An Accurate Mathematical Model for the Intrinsic Base Resistance of Bipolar Transistors, by Ciubotaru and Carter, Sol.-St.Electr. 41, pp. 655-658, 1997.
RBB = Rbmin + Rbmax/(1 + iB/IRB)RB
L23 10Nov2010 6
BJT CharacterizationForward GummelvBCx= 0 = vBC + iBRB - iCRC
vBEx = vBE +iBRB +(iB+iC)RE
iB = IBF + ILE =
ISexpf(vBE/NFVt)/BF
+ ISEexpf(vBE/NEVt)
iC = FIBF/QB =
ISexpf(vBE/NFVt)/QB
+
-
iC RC
iB
RE
RB
vBEx
vBC
vBE
++
-
-
L23 10Nov2010 7
Ideal F-G DataiC and iB (A)
vs. vBE (V)
N = 1 1/slope = 59.5 mV/dec
N = 2 1/slope = 119 mV/dec
BJ T I (A) vs. Vbe (V) for the G-P model Forward Gummel configuration (Vbcx=0)
1.E-16
1.E-15
1.E-14
1.E-13
1.E-12
1.E-11
1.E-10
1.E-09
1.E-08
1.E-07
1.E-06
1.E-05
1.E-04
1.E-03
1.E-02
0.0 0.2 0.4 0.6 0.8
I c
I b
L23 10Nov2010 8
BJT CharacterizationReverse Gummel
+
-
iE
RC
iB
RE
RB
vBCxvBC
vBE
++
-
-
vBEx= 0 = vBE + iBRB - iERE
vBCx = vBC +iBRB +(iB+iE)RC
iB = IBR + ILC =
ISexpf(vBC/NRVt)/BR
+ ISCexpf(vBC/NCVt)
iE = RIBR/QB =
ISexpf(vBC/NRVt)/QB
L23 10Nov2010 9
Ideal R-G DataiE and iB (A)
vs. vBE (V)
N = 1 1/slope = 59.5 mV/dec
N = 2 1/slope = 119 mV/dec
BJ T I (A) vs. Vbe (V) for the G-P model Forward Gummel configuration (Vbcx=0)
1.E-16
1.E-15
1.E-14
1.E-13
1.E-12
1.E-11
1.E-10
1.E-09
1.E-08
1.E-07
1.E-06
1.E-05
1.E-04
1.E-03
1.E-02
0.0 0.2 0.4 0.6 0.8
I c
I b
Ie
L23 10Nov2010 10
Ideal 2-terminalMOS capacitor/diode
x
-xox
0SiO2
silicon substrate
Vgate
Vsu
b
conducting gate,area =
LW
tsub
0y
L
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Band models (approx. scale)
Eo
Ec
Ev
qox
~ 0.95 eV
metal silicon dioxide
p-type s/c
qm= 4.1 eV for Al
Eo
EF
m
EFp
Eo
Ec
Ev
EFi
qs,p
qSi= 4.05e
VEg,ox
~ 8 eV
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Flat band condition (approx. scale)
Ec,Ox
Ev
Al SiO2p-Si
q(m-ox)= 3.15 eV
EF
m EFp
Ec
Ev
EFi
q(ox-Si)=3.1eV
Eg,ox
~8eV
cond band-flat for
VVV8.0
V
eV8.0EE
Then
eV85.0EE
If
sg
MS
fpfmFB
fpfm
fpc
qfp= 3.95e
V
L23 10Nov2010 13
Equivalent circuitfor Flat-Band• Surface effect analogous to the
extr Debye length = LD,extr = [Vt/(qNa)]1/2
• Debye cap, C’D,extr = Si/LD,extr
• Oxide cap, C’Ox = Ox/xOx
• Net C is the series comb
Oxextr,Dtot 'C1
'C1
'C1
C’Ox
C’D,extr
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Accumulation for Vgate< VFB
SiO2
p-type Si
Vgate<
VFB
Vsub = 0
EOx,x<0
x
-xox
0
tsu
b
x,OxSi
Ox
Si
SiSix,OxOx
Ox
Oxx,Ox
E31
E
39.37.11
EE
0xV
E
holes
L23 10Nov2010 16
Equivalent circuitfor accumulation• Accum depth analogous to the
accum Debye length = LD,acc = [Vt/(qps)]1/2
• Accum cap, C’acc = Si/LD,acc
• Oxide cap, C’Ox = Ox/xOx
• Net C is the series comb
Oxacctot 'C1
'C1
'C1
C’Ox
C’acc
L23 10Nov2010 17
Depletion for p-Si, Vgate> VFB
SiO2
p-type Si
Vgate>
VFB
Vsub = 0
EOx,x> 0
x
-xox
0
tsu
b
x,OxSi
Ox
Si
SiSix,OxOx
Ox
Oxx,Ox
E31
E
39.37.11
EE
0xV
E
Acceptors
Depl Reg
L23 10Nov2010 19
Equivalent circuitfor depletion• Depl depth given by the usual
formula = xdepl = [2Si(Vbb)/(qNa)]1/2
• Depl cap, C’depl = Si/xdepl
• Oxide cap, C’Ox = Ox/xOx
• Net C is the series comb
Oxdepltot 'C1
'C1
'C1
C’Ox
C’depl
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Inversion for p-SiVgate>VTh>VFB
Vgate>
VFB
Vsub = 0
EOx,x> 0
inversion for
threshold above
E Induced
depletes 0
E Induced
0xV
E
Si
Si
Ox
Oxx,Ox
Acceptors
Depl Reg
e- e- e- e- e-
L23 10Nov2010 22
Approximation concept“Onset of Strong Inv”• OSI = Onset of Strong Inversion occurs
when ns = Na = ppo and VG = VTh
• Assume ns = 0 for VG < VTh
• Assume xdepl = xd,max for VG = VTh and it doesn’t increase for VG > VTh
• Cd,min = Si/xd,max for VG > VTh
• Assume ns > 0 for VG > VTh
L23 10Nov2010 24
Equivalent circuitabove OSI• Depl depth given by the maximum
depl = xd,max = [2Si|2p|/(qNa)]1/2
• Depl cap, C’d,min = Si/xd,max
• Oxide cap, C’Ox = Ox/xOx
• Net C is the series comb
Ox,mindtot 'C1
'C1
'C1
C’Ox
C’d,min
L23 10Nov2010 25
MOS surface states**p- substr = n-channel
VGS s Surf chg Carr Den
VGS < VFB < 0 s < 0 Accum. ps > Na
VGS = VFB < 0 s = Neutral ps = Na
VFB < VGS s > 0 Depletion ps < Na
VFB < VGS < VTh s = |p| I ntrinsic ns = ps = ni
VGS < VTh s > |p| Weak inv ni< ns < Na
VGS = VTh s = 2|p| O.S.I . ns = Na