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Transcript of Stability of rock blocks - UNICAEN · Influence of water on slope stability EPFL -LMR Sliding...
1
ÉCOLE POLYTECHNIQUEFÉDÉRALE DE LAUSANNE
L M RRock mechanics
LABORATOIRE DEMÉCANIQUE DES ROCHES
V. Labiouse, J. Abbruzzese
Stability of rock blocks
EPFL - LMR
Stability of rock blocks
1. Stability of one block
2. Stability of a column
3. Stability of two blocks
4. Stability of several blocks (fauchage)
5. Influence of water on slope stability
EPFL - LMR
Sliding stability of a block
ββ W cos β
W sin β
W σ = N/A = W cos β /A
b h
τres = σ tan ϕ + c*
τsol = T/A = W sin β /A
EPFL - LMR
ββ W cos β
W sin β
W
b h
W sin β /A < (W cos β /A) tan ϕ + c*
τsol < τres = σ tan ϕ + c*Stable if
Sliding stability of a block
2
EPFL - LMR
Safety Factor with respect to sliding :
solsol
ress
ctanFτ
+ϕ⋅σ=
ττ
=∗
β W
b h
β⋅
+βϕ
=∗
sinWAc
tantanFs
β
+ϕ⋅β=
∗
sinAW
ctancosAW
Fs
Sliding stability of a block
EPFL - LMR
ϕϕ β
β
β > ϕ
β < ϕ
β = ϕ
Sliding
Stable
Stability limit
ϕ β
Sliding of a block on a smooth plane (c* = 0)
EPFL - LMR
SlidingStable
tan β
b/h
β > ϕβ < ϕ
tan ϕ
Sliding of a block on a smooth plane (c* = 0)
EPFL - LMR
β
β
W cos β
W sin β
W
Mdestabilizing,0 = W sin β . h/2 b
h
Toppling stability of a block
Toppling instability occurs if the direction line of the weight vector Wintersects the slope surface beyond the base of the column.
Μdestab,0 < Μstab,0
Stable if
0
Mstabilizing,0 = W cos β . b/2
tan β < b/h
3
EPFL - LMR
β
β
W cos β
W sin β
W
b
h
Safety Factor with respect to toppling :
β==
tanhb
MM
F0,déstab
0,stabs
Toppling stability of a blockEPFL - LMR
b/h < tan β
b/h > tan βb/h = tan β
Toppling
Stable
Stability limit
ββ
b
h
β
Toppling stability of a block
EPFL - LMR
Toppling
Stable
tan β
b/h
b/h < tan β
b/h > tan β
b / h= ta
n β
Toppling stability of a blockEPFL - LMR
Sliding and toppling stability of a block on a smooth plane (c* = 0)
Sliding
Stable
tan ϕ
tan β
b/h
b / h= ta
n β
Slidingand
Toppling
Toppling
4
EPFL - LMR
Safety Factor with respect to sliding :
β
A
β⋅
+βϕ
=∗
sinWAc
tantanFs
τres = σ tan ϕ + c*
WCG
Sliding stability of a columnEPFL - LMR
β
β==
tanhb
MMF
CG
CG
déstab
stabsCG
bCG
hCG
Toppling instability occurs if the direction line of the weight vector Wintersects the slope surface beyond the base of the column.
Toppling stability of a column
Safety Factor with respect to toppling :
EPFL - LMR
Sliding and toppling stability ofrock columns
EPFL - LMR
Stability of two blocks
Toppling of the two blocks
Toppling and sliding
Stability of the two blocks
5
EPFL - LMR
The « fauchage » phenomenon
Toppling in layered or
fractured rocks
characterized by a
system steeply dipping
into the slope EPFL - LMR
β
b
huu = γw h cos β
Pressure distributions for allowed seepage
0
Hypotheses:1. Hydrostatic along the
rear fracture2. Flow with constant
gradient in the basaldiscontinuity
u0 = 0
V
UV = ½ γw h2 cos β
U = ½ γw h b cos β
EPFL - LMR
βW cos β
W
b
h
τres = σ´ tan ϕ + c*V
U
W sin βσ´ = N/Aτsol = T/A
Sliding stability for allowed seepage
0N = W cos β - UT = W sin β + V
Stable if τsol < τres
Stability highly endangered
EPFL - LMR
βW cos β
W
b
h
V
U
W sin β
Toppling stability for allowed seepage
0
Mdestabilizing,0 = W sin β . h/2 + V. h/3 + U. 2b/3
Μdestab,0 < Μstab,0
Stable if
Mstabilizing,0 = W cos β . b/2
Stability highly endangered
6
EPFL - LMR
Pressure distributions if no outflow possible
β
b
h
V
U
u0
u = γw h cos β
Hypotheses:1. Hydrostatic along the
rear fracture2. No outflow at the toe of
the basal discontinuity
u0 = γw (h cos β + b sin β)
V = ½ γw h2 cos β
U = ½ γw b (2h cos β + b sin β)
ÉCOLE POLYTECHNIQUEFÉDÉRALE DE LAUSANNE
L M RRock mechanics
LABORATOIRE DEMÉCANIQUE DES ROCHES
V. Labiouse, J. Abbruzzese
Plane slide
EPFL - LMR
Stability of a plane slide
1. Kinematical conditions
2. Sliding along a plane
3. Sliding along a plane, with a rear tension crack
4. Stabilising measures
Control of water
Pre-tense anchors (active)
Grouted bar bolts (passive)
EPFL - LMR
Plane slide on the D526 roadconnecting Mens and Clelles (Isère – France)
http://www.irma-grenoble.com/
7
EPFL - LMR
Plane slide in layered rocksin Sylans (France)
EPFL - LMR
When is a sliding mechanism possible ?
Yes No
NoNoautomatic detection of potential sliding planes, based on the use
of DTM25.
examplefor plane sliding
EPFL - LMR
Slide on a single plane joint: dry slope
Factor of safety:max. shear strengthapplied shear stressFS =
- applied shear stress:τsol = (T/A) = W/A sin β
A = L x 1 (m)σ´= (N/A) = W/A cos βτ = (T/A) = W/A sin βc*= 0β
ϕ=
βϕ⋅β
=tantan
sinWtancosWFS
- max. shear strength:τres = σ´ tan ϕ + c*
= (N/A) tanϕ ββ
W cos β
W
W sin β
L
EPFL - LMR
U
Hw
Slide on a single plane joint: role of water
U = resultant of the pore water pressure distribution, as a function of the hydraulic conditions
( )β
ϕ⋅−β=
sinWtanUcosWFS
τres = (σ - u) tan ϕτres =[ (Wcosβ-U)/Α ] tanϕ
The maximum shear strength on the failure surface is reduced
β W cos β
W
W sin β
L
8
EPFL - LMR
Slide on a single joint (with tension crack)
Seepage allowedActions due to water presence:
1. Hydrostatic pressure in the tension crack;
2. Seepage through the joint at the base.
at the toe of the tension crack:u = γw hw
β
L
V
UW cos β
W
W sin βu
hw
2ww h
21V γ= Lh
21U wwγ=
EPFL - LMR
Slide on a single joint (with tension crack)
Seepage allowedstability against sliding
↑ : Ν = W cosβ – U – V sinβ
← : Τ = W sinβ + V cosβ
( )β+β
⋅+ϕβ−−β=
cosVsinWA*ctansinVUcosWFS
Shear strength reduced and applied forces increasedstability highly endangered.
βL
V
UW cos β
W
W sin βu
hw
EPFL - LMR
Slide on a single joint (with tension crack)
No outflow possible (at 0)Actions due to water presence:
1. Hydrostatic pressure inthe tension crack;
2. No water flow; Hydrostatic pressure in the failure plane.
at the toe 0 of the basal plane:u = γw (hw+ L sinβ)
βL
V
UW cos β
W
W sin βu
hw
0
2ww h
21V γ=
( )2
sinLh2LU ww β+γ=
EPFL - LMR
1. Surface drainage(cut-off ditch)
2. Pumping from wells3. Gravity drainage of
the rear tension crack4. Gravity drainage of
the basal plane5. Drainage gallery and
radial drains
Methods to control water in jointed rock slopes
1.2.
3.
4.
9
EPFL - LMR
Support methods: active measures
Pre-tension active anchors
Free length
Spiral winding cables or rodsGrouted zone
Fixed anchor length
β
EPFL - LMR
↑ : Ν = Wcosβ - U - Vsinβ + Pa sin(β + γ)← : Τ = Wsinβ + Vcosβ - Pa cos(β + γ)
β
V
UW cos β
W
W sin β
Pa
Pa cos(β + γ)
Pa sin(β + γ)
βγ
Support methods: active measures
EPFL - LMR
β
V
UW cos β
W
W sin β
Pa
Pa cos(β + γ)
Pa sin(β + γ)
βγ
Support methods: active measures
( )( )( )γ+β−β+β
ϕγ+β+β−−β=
cosPcosVsinWtansinPsinVUcosWFS
a
a
The pre-tension of anchors both increases N and
decreases T, thus improving the stability of the slope.
EPFL - LMR
Support methods: passive measures
Grouted boltsGrouting all along the bar’s length
Thread bar Grouted zone
Passive anchors increasethe rock mass cohesion(Bjurström, 1974):
f
ca
aa S
SCσσ
τ=
Sa = area of bar’s transversal sectionS = area of the surface reinforced by boltsτa = shear strength of the bar (τa ≈ 0.6 σf)σc = rock’s compressive strengthσf = yielding stress of the bar’s material (steel)
β
! Take care that there is also tension in the bolts in addition to bending and shear stresses…
10
EPFL - LMR
Support methods: passive measures
↑ : Ν = Wcosβ - U - Vsinβ
← : Τ = Wsinβ + Vcosβ
β
V
UW cos β
W
W sin βT
ScS*ctanNFS a ⋅+⋅+ϕ=
! either c*·S or ca·S(do not add contributions)
EPFL - LMR
Support methods: passive measures
TS*ctanNFS ⋅+ϕ
=
( )β+β
⋅+ϕβ−−β=
cosVsinWSCtansinVUcosWFS a
β
V
UW cos β
W
W sin β
ÉCOLE POLYTECHNIQUEFÉDÉRALE DE LAUSANNE
L M RRock mechanics
LABORATOIRE DEMÉCANIQUE DES ROCHES
V. Labiouse, J. Abbruzzese
Wedge slide
EPFL - LMR
Wedge slide above the road of Cogne (Italy)
http://www.crealp.ch/
Wedge sliding on
two intersecting
discontinuities
11
EPFL - LMR
Wedge sliding stability
Vertical plane Transverse section to i direction
Sliding failure of a rock wedge on the S1 and S2planes, which define an intersection line in i direction.
βW
i
nW cos β
W sin βS1
S2
W cos β
N1 N2θ1
n
hθ2
i
S1
h
S2
n
EPFL - LMR
Wedge sliding stability
β⋅+⋅+ϕ+ϕ
=sinW
ScSctanNtanNFS 2*21
*12211
Solving the equilibrium equations in the h, i and n directions:
( )21
21 sin
sincosWNθ+θ
θ⋅β=
( )21
12 sin
sincosWNθ+θ
θ⋅β=
βW
i
nW cos β
W sin βS1
S2
W cos β
N1 N2θ1
n
hθ2
EPFL - LMR
Wedge stability higher than plane failure
For example: if c1*=c2*=0 (smooth joints)and ϕ1= ϕ2= ϕ
βϕ
=tantanKFS
( )21
21sin
sinsinKθ+θ
θ+θ=
with K : wedge factor
Wed
ge fa
ctor
K
Aperture angle of the wedge ω