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SBI PO (Pre) (PH-I) 2016 MOCK TEST PAPER - 136 (SOLUTION)

ENGLISH16. (2) Replace 'troubles' by 'trouble'.17. (2) Replace 'five-years' by 'five-

year'.18. (2) Replace 'student' by 'students'.19. (2) Delete 'more'.20. (1) Add 'the' before 'harder'.

MATHS(31-35):31. (2) 4656 ÷ 145.5

? = 4656145.6 = 32

32. (4) ? = 6561 100

1018 215 3

= 81

33. (5) 7365 + 29.16 + ? = 7437.16? = 473.16 – 7394.16? = 43 = 1849

34. (1)3

10 × 40% of ? = 78

310 × 40

100 × ? = 78;

? = 78 25

3

= 65035. (3) 125% of 3060 – 85% of ? = 408

125100 × 3060 – 85

100 × ? = 408

3825 – 408 = 85

100 × ?

? = 3417 100

85

= 4020

(36-40):36. (1) The solution of the series is as

follows:

The number in place of ? shouldbe:12 + 7 = 19

37. (4) The given question has two series– one is decreasing (101, 99, 97,95) and the other is increasing(103, 103 + 2 = 105, ...). Therequired number = 105 + 2 = 107.

38. (5) 1280 = 5120 ÷ 4320 = 1280 ÷ 480 = 320 ÷ 4So, the required number= 80 ÷ 4 = 20

40 × 12 = 20

20 × 32 = 30

30 × 52 = 75

75 × 72 = 262.5

262.5 × 92 = 1181.25

39. (1) 20 = 40 × 12

30 = 20 × 32

75 = 3052 262.5 = 75 ×

72

40. (2) The given series follows thepattern as:2 × 1 = 2 (required number)2 × 2 = 44 × 3 = 1212 × 4 = 4848 × 5 = 240

(41-45):41. (5) I. . 6 6x x x

II. 3 3/2 3/2 1/3 1/26 (6 ) 6 6y y

42. (1) 3x – 2y = 10 × 35x – 6y = 6

y = 4; x > y43. (5) I. x2 + x – 12 = 0

x2 + 4x – 3x – 12 = 0x(x + 4) – 3(x + 4) = 0(x + 4)(x – 3) = x = –4, 3

II. y2 – 5y + 6 = 0y2 – 3y – 2y + 6 = 0y(y – 3) –2(y – 3) = 0(y – 3)(y – 2) = 0y = 3, 2x < y

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44. (3) I. x2 + 6x + 3x + 18 = 0x(x + 6) +3(x + 6) = 0(x + 6)(x + 3) = 0x = –6, –3

II. y2 – 8y – 5y + 40 = 0y(y – 8) –5(y – 8) = 0(y – 8)(y – 5) = 0y = 8, 5

45. (2) I. 6 11 6x

= 6 5x ; x + 6 = 25; x =19II. y2 + 112 = 473

y2 = 473 – 112 = 361;y = +19

46. (2) Speed of the carDistance covered 720

Time Taken 9 = 80 km/hr

Speed of the bus = 3 804

= 60 km/hr

Speed of the train = 27 6015

= 108 km/hr

Distance covered by train in 7 hrs= (7 × 108) = 756 km

47. (4) Area of circle = r2 = 5544

r2 = 5544 7

22

= 1764r = 42Circumference of circle= 2 × perimeter of rectangle

or, 2 × 227

× 42 = 2 × perimeter of rectangle

or, Perimeter of rectangle = 132 cmor, 2(l + b) = 132 l + b = 66b = 66 – 40 = 26Area of rectangle= 40 × 26

= 1040 cm2

= 1040 sq cm48. (4) Part of tank empited in 1 hr by

the leak 1 32 7 14

The leak will empty the tank in14 hrs.

49. (3) Difference of amount received byR and Q is (7 – 5 =) 2, Totalamount received by P and Q = (3+ 5=) 8:, Then 2 = ` 4000

8 : 4000

2 × 8 = ` 16000

50. (5) Principal (P) = 1000 100

5 4

= ` 5000

CI = 5000 × 225

1 1100

= 10000 × 441 1400

= 10000 × 41

100 = ` 1025Note: Combined rate of interestfor 2 yrs in case of calculatingcompound interest

5 55 5100

% = (10 + 0.25)% = 10.25%

Required CI = 10000 × 10.25100 = ` 1025

(51-55):51. (3) Average marks obtained by F

=

175 80 12574 68 42100 100 100

3

= (129.5 54.4 52.5)

3

= 236.4

3 = 78.852. (4) Average marks obtained by all

students in Science

= (91 87 81 70 49 42)

6

× 125100

=

54204

6

=

5256 = 87.5

53. (1) Reqd ratio = 49 125 175: 83

100 100

= 35 : 8354. (5) 80% of 125 = 100 and 1% of 125 =

1.25 Students getting less than81% marks are not eligible to optscience stream in the next year.The number of such students is 3.

55. (2) Marks obtained

= 48 × 175100 + 55 ×

120100 + 94

= 84 + 66 + 94= 244

(56-60):56. (4) Average number of players who

play Football and Rugby together

= 12 × 30% of 4200 = 630

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57. (1) Number of female players who playLawn Tennis = 22% of 2000 = 440Number of male players who play Rugby= 13% of 4200 – 10% of 2000= 546 – 200= 346Required number = 440 – 346 = 94

58. (3) Number of female players who playCricket = 40% of 2000 = 800Number of male players who playHockey = 10% of 4200 – 15% of 2000

= 420 – 300 = 120Required ratio = 800 : 120 = 20 : 3

59. (2) Required number of male playerswho play Football, Cricket and LawnTennis together = 77% of 4200 –75% of 2000= 3234 – 1500= 1734

60. (1) Male players who play Rugby= 13% of 4200 – 10% of 2000= 546 – 200= 346Required percentage

346 100 33%25% of 4200

(61-65):61. (2) Required average

(25 50 70 45 65) 255 51%5 5

62. (1) Income = Expenditure × 100+% profit

100

Income

Expenditure =100 50

100

=150100 = 3 : 2

We may not use the given valueof expenditure to solve thisproblem.

63. (3)64. (5) By the rule given in solution to

Q.No. 62, we can f indexpenditure of company in 2005

as ` 680000 × 100125 and in 2007

as ` 680000 × 100170

Required difference

= 680000 × 1001 1

125 170

= `144,000

65. (1) % profit = ProfitExp × 100

45 = 90,000

Exp × 100; Exp = 90,000

45 ×100= 2000 × 100 = 2,00,000Inc= Exp + Profit = 2,00,000 + 90,000

= ` 2,90,000REASONING

(66-70):

66. (3) L sits to the immediate right ofO. Only one person sits betweenP and O. O faces one of theimmediate neighbours of C or A.

67. (5) N is facing A.68. (1) E is facing M.69. (4) Except PO, in all other pairs, the

two persons are immediateneighbours of each other. Thereis one person between O and P.

70. (2) C sits third to the left of B.(71-72):

C < R < E < A = MY > EY > E < A = MC < R < E < Y

71. (4) Conclusions:I. M > R (True)II. Y > A (Not true)

72. (5) Conclusions:I. C = Y (Not true)II. C < Y (True)

(73-74):B < L < A = M > E > SL > W > JW < L < A = M > E > SJ < W < L < A = M

73. (3) Conclusions:I. L < S (Not true)II. E > W (Not true)

74. (2) Conclusions:I. J < M (Not true)II. J = M (Not true)J is either smaller than M orequal to M. Therefore, eitherconclusion I or II is true.

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75. (5) C > H > O > K = E < DConclusions:I. O > D (Not true)II. E < C (True)

(76-80):always follow your passion ke ag mo jp ... (i)great passion for music mo bu sc nd ...(ii)music always on mind fi sc ag lw ... (iii)follow music on twitter jy jp fi sc ... (iv)From (i) and (ii), passion mo ... (v)From (i) and (ii), always ag ... (vi)From (i) and (iv), follow jp ... (vii)From (i), (iii) and (iv), music sc ... (viii)From (iii), (iv) and (viii), on fi ... (ix)76. (2) follow jp77. (3) mind lw78. (1) nd great/for79. (4) music sc

always aghelp hrTherefore, help hryour ketwitter ty

80. (5) passion moThe code for 'divine' may be 'xy'.

(81-85):

81. (4) 82. (4) 83. (2) 84. (2) 85. (2)(86-90): The machine rearrange a word

and a number in each step. InStep I the large number comeson the left and the last word inalphabetical order comes on theright. In Step II the second largestnumber comes on the left and thesecond-last word in alphabeticalorder comes on the right. Thisgoes on till all the numbers arearranged in ascending order andall the words in reversealphabetical order.

Input: 11 east 54 vent kind 35 over 2771 bowl

Step I: 71 11 east 54 kind 35 over 27bowl vent

Step II: 54 71 11 east kind 35 27 bowlvent over

Step III: 35 54 71 11 east 27 bowl ventover kind

Step IV: 27 35 54 71 11 bowl vent overkind east

Step V: 11 27 35 54 71 vent over kindeast bowl

86. (2) 87. (3) 88. (5)89. (4) Third element to the left of the

sixth element from the left = (6 –3 =) 3rd element from the left is'east'.

90. (5)(91-95):91. (4) No apartment is a motel (E)

conversion No motel is anapartment (E) + All apartmentsare houses (A) = E + A = O* = Somehouses are not motels. Thus, thepossibility in I exists. Henceconclusion I fol lows. Butconclusion II does not follow.

92. (1) Some trees are weeds (I) + Allweeds are shrubs (A) = I + A = I =Some trees are shrubs (I). Now,All plants are trees (A) + Sometrees are shrubs (I) = A + I = Noconclusion. Hence conclusion Idoes not follow. But thepossibility in II exists from thesecond statement. Henceconclusion II follows.

93. (1) Some drinks are juices (I) + Alljuices are beverages (A) = I + A = I= Some drinks are beverages (I) +No beverage is solid (E) = I + E =O = Some drinks are not solid (O).Hence conclusion II does notfollow. Again, All juices arebeverages (A) + No beverage is asolid (E) = A + E = No juice is asolid (E). Hence conclusion Ifollows.

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94. (4) Some drinks are juices (I) + Alljuices are beverages (A) = I + A =Some drinks are beverages (I).Hence conclusion I follows. Butconclusion II does not follow.

95. (3) Some trees are weeds (I) + Allweeds are shrubs (A) = I + A = I =Some trees are shrubs (I). Henceconclusion I follows. Again, Allplants are trees (A) + Some treesare shrubs (I) = A + I = Noconclusion. But the possibility inII exists. Hence conclusion IIfollows.

(96-98):

96. (3) Thus, R has the second least no.of offices.

97. (4) Even numbers between 23 and12 are 14, 16, 18, 20.Now, only 18 is divisible by 2 aswell as 3. Hence no. of offices Phas = 18

99. (5) R lies between S and T. Hencethe no. of offices in R = 11. (12> 11 > 5)

(99-100):

99. (4) 100. (3)

CORRECTION OF SBI PO (PRE) MTP - 135Directions (69-73): Study the following informationcarefully and answer the questions given below:

I. Six friends were seated around arectangular table facing towards thecentre. Their chairs (#1, #2, ... #6) werearranged around the table like this:

II. Among these six persons three werewomen (A, B and C) and three men(D, E and F).

III. A, who occupied chair #3, sat oppositeB or D.

IV. E sat on the immediate left of C.V. F sat on the immediate left of one

woman and on the immediate right ofanother woman.

VI. The person who owned the table wasthe only person who sat both oppositea man and to the left of a woman.

Note: 'Left' . (69-73):

:I.

:

II. (A, B C)

III. A, #3 , B D

IV. E, C V. F

VI.

Sol:

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1. (5)2. (1)3. (2)4. (1)5. (3)6. (2)7. (4)8. (2)9. (2)10. (4)11. (2)12. (1)13. (5)14. (3)15. (4)16. (2)17. (2)18. (2)19. (2)20. (1)

21. (2)22. (1)23. (3)24. (1)25. (2)26. (5)27. (4)28. (1)29. (2)30. (4)31. (2)32. (4)33. (5)34. (1)35. (3)36. (1)37. (4)38. (5)39. (1)40. (2)

SBI PO (Pre) (PH-I) 2016 MOCK TEST PAPER - 136 (ANSWERKEY)

41. (5)42. (1)43. (5)44. (3)45. (2)46. (2)47. (4)48. (4)49. (3)50. (5)51. (3)52. (4)53. (1)54. (5)55. (2)56. (4)57. (1)58. (3)59. (2)60. (1)

61. (2)62. (1)63. (3)64. (5)65. (1)66. (3)67. (5)68. (1)69. (4)70. (2)71. (4)72. (5)73. (3)74. (2)75. (5)76. (2)77. (3)78. (1)79. (4)80. (5)

81. (4)82. (4)83. (2)84. (2)85. (2)86. (2)87. (3)88. (5)89. (4)90. (5)91. (4)92. (1)93. (1)94. (4)95. (3)96. (3)97. (4)98. (5)99. (4)100. (3)