Operating Characteristics of Nozzles P M V Subbarao Professor Mechanical Engineering Department I I...
-
Upload
braedon-wilborn -
Category
Documents
-
view
214 -
download
0
Transcript of Operating Characteristics of Nozzles P M V Subbarao Professor Mechanical Engineering Department I I...
Operating Characteristics of Nozzles
P M V SubbaraoProfessor
Mechanical Engineering DepartmentI I T Delhi
From Takeoff to cruising ……Realizing New Events of Physics…….
Converging Nozzle
p0
pb
pb = Back Pressure
Design Variables: 00 ,, Tpm
Outlet Condition:
exitexitb MorAorp
Designed Exit Conditions
121
00
2
11
exit
exitexit
MT
T
p
p
12
1
20
0
21
1
exit
exitexit
M
MA
T
p
Rm
Under design conditions the pressure at the exit plane of the nozzle is applied back pressure.
121
00
2
11
exit
exitb
MT
T
p
p
Profile of the Nozzle 12
1
2
2
21
1
)(2
11
)(
)(
exit
exit
exit M
xM
xM
M
A
xA
1
2
2
)(12
12)(
xM
M
p
xp exit
b
1
2
2
)(12
12)(
xM
M
p
xp exit
exit
At design Conditions:
Full Capacity Convergent Nozzle
1
2, )(12
1)(
xMp
xp
criticalb
12
1
21
)(2
11
)(
1)(2
,
xM
xMA
xA
criticalexit
Remarks on Isentropic Nozzle Design
• Length of the nozzle is immaterial for an isentropic nozzle.
• Strength requirements of nozzle material may decide the nozzle length.
• Either Mach number variation or Area variation or Pressure variation is specified as a function or arbitrary length unit.
• Nozzle design attains maximum capacity when the exit Mach number is unity.
Operational Characteristics of Nozzles
• A variable area passage designed to accelerate the a gas flow is considered for study.
• The concern here is with the effect of changes in the upstream and downstream pressures
• on the nature of the inside flow and • on the mass flow rate through a nozzle.• Four different cases considered for analysis are:• Converging nozzle with constant upstream conditions.• Converging-diverging nozzle with constant upstream conditions.• Converging nozzle with constant downstream conditions.• Converging-diverging nozzle with constant downstream
conditions.
Pressure Distribution in Under Expanded Nozzle
p0
Pb,critical
pb=p0
pb,critical<pb1<p0
pb,critical<pb2<p0
pb,critical<pb3<p0
At all the above conditions, the pressure at the exit plane of nozzle, pexit = pb.
Convergent-Divergent Nozzle with High Back Pressure
• When pb is very nearly the same as p0 the flow remains subsonic throughout.
• The flow in the nozzle is then similar to that in a venturi.
• The local pressure drops from p0 to a minimum value at the throat, pthroat , which is greater than p*.
• The local pressure increases from throat to exit plane of the nozzle.
• The pressure at the exit plate of the nozzle is equal to the back pressure.
• This trend will continue for a particular value of back pressure.
Convergent-Divergent Nozzle with High Back Pressure
At all these back pressures the exit plane pressure is equal to the back pressure.
pthroat> p*
0
2
2
)()( TC
xuxTC pp
12
)(
1
)( 20
22
cxuxc
12
1
0
12
0
2
1
00
)()()()(
x
p
xp
T
xT
c
xc
)(1
2
1
)(
12)( 22
0
2202 xcc
xccxu
20
2202 )(
11
2)(
c
xccxu
1
0
202 )(
11
2)(
p
xpcxu
1
0
02 )(1
1
2)(
p
xpRTxu
1
00
02 )(1
1
2)(
p
xppxu
2/1
1
00
0 )(1
1
2)(
p
xppxu
2/1
1
00
0
00
)(1
1
2)(
)(
p
xppxA
xm
)()()( xuxAxm
)()()(
00 xuxA
xm
2/1
1
00
0
1
00
)(1
1
2)(
)(
p
xppxA
p
xpm
At exit with high back pressure pb
2/1
1
00
0
1
00 1
1
2
p
ppA
p
pm exit
exitb
At throat with high back pressure pb
2/1
1
00
0*
1
00 1
1
2
p
ppA
p
pm tt
2/1
1
0
*
1
0
2/1
1
0
1
0
11
p
pA
p
p
p
pA
p
p ttbexit
b
•For a given value of high back pressure corresponding throat pressure can be calculated. •As exit area is higher than throat area throat pressure is always less than exit plane pressure.•An decreasing exit pressure produces lowering throat pressure
Numerical Solution for Mach Number Caluculation
• Use “Newton’s Method” to extract numerical solution
• At correct Mach number (for given A/A*) …
F(M ) 0
F(M ) 1
M
2
1
1 1
2M 2
1
2 1
A
A*
• Define:
• Expand F(M) is Taylor’s series about some arbitrary Mach number M(j)
F(M ) F(M ( j ) ) F
M
( j )
M M ( j ) 2F
M 2
( j )
M M ( j ) 2
2 ...O M M ( j ) 3
• Solve for M
M M ( j )
F(M ) F(M ( j ) )
2F
M 2
( j )
M M ( j ) 2
2 ...O M M ( j ) 3
F
M
( j )
• From Earlier Definition , thusF(M ) 0
M M ( j )
F(M ( j ) )
2F
M 2
( j )
M M ( j ) 2
2 ...O M M ( j ) 3
F
M
( j )
• if M(j) is chosen to be “close” to M M M ( j ) 2 M M ( j )
And we can truncate after the first order terms with “little”Loss of accuracy
Still exact expression
• First Order approximation of solution for M
• However; one would anticipate that
“Hat” indicates that solution is no longer exact
M^
M ( j ) F(M ( j ) )
F
M
( j )
M M^
M M ( j )
“estimate is closer than original guess”
• And we would anticipate that
“refined estimate” …. Iteration 1
M^^
M^
F(M
^
)F
M
|M^
M M^^
M M^
• If we substitute back into the approximate expressionM^