Latihan Thermo 5a

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LATIHAN TERMO

Transcript of Latihan Thermo 5a

5

SMK LUNDUKIMIA

EXERCISEJULAI 20141 HOURNama Pelajar:Kelas:Markah :

1Diagram below shows the apparatus set-up to determine the heat of displacement of silver by copper from silver nitrate solution

Rajah di bawah menunjukkan susunan radas untuk menentukan haba penyesaran argentum oleh kuprum dari larutan argentum nitrat.

200 cm 0.2 mol dmsilver nitrate solution200 cm 0.2 mol dmlarutan argentumnitrat3-33-3Excess copperpowderSerbuk kuprumberlebihanThermometerTermometerpolystyrene cupcawan polistrin5

Table below shows the results of the experiment.

Jadual menunjukkan keputusan eksperimen ini.

DescriptionPenerangan Temperature ( C)Suhu ( C)

Initial temperature of the solutionSuhu awal larutan. 29.0

Final temperature of the solution.Suhu akhir larutan.36.5

(a)What is the function of the polystyrene cup in this experiment?

Apakah fungsi cawan polistrin dalam eksperimen ini?

[ 1 mark/ markah]

(b)State one observation in this experiment.

Nyatakan satu pemerhatian dalam eksperimen ini.

[ 1 mark/ markah]

(c)Write a balanced equation for the above reaction.

Tuliskan satu persamaan yang seimbang bagi tindak balas di atas.

[ 1 mark/ markah]

(d)From the results of the experiment, calculate

Dari keputusan eksperimen, kira

(i)the heat change

perubahan haba

[ 1 mark/ markah]

(ii)the heat of displacement

haba penyesaran

[Specific heat capacity of solution : 4.2Jg -1 C-1]

[ 1 mark/ markah]

(e)Draw an energy level diagram for this reaction.

Lukis rajah aras tenaga bagi tindak balas tersebut.

[ 1 mark/ markah]

2The combustion of an alcohol in air is represented by the equation below :

Pembakaran suatu sebatian alkohol di udara diwakili oleh persamaan berikut :

C2H5OH + 3O2 2CO2 + 3H2OH = -1260 kJ mol-1

(a)(i)Name the alcohol in the above equation.

Namakan sebatian alkohol di dalam persamaan di atas.

[ 1 mark/ markah]

(ii)What is meant by H = -1260 kJ mol-1 in the above equation?

Apakah yang dimaksudkan dengan H = -1260 kJ mol-1 dalam persamaan di atas?

[ 1 mark/ markah]

(b)200 g of water is heated by the combustion of 0.23 g of the alcohol.

200 g air dipanaskan oleh pembakaran 0.23 g alkohol tersebut.

(i)Calculate the heat released by the alcohol in the reaction.

Kirakan haba yang dibebaskan oleh alkohol itu dalam tindak balas.

[ Relative Atomic Mass : H=1 ; C=12 ; O=16][ Jisim atom relatif : H=1 ; C=12 ; O=16 ]

[ 3 mark/ markah]

(ii)Calculate the temperature change of water expected in the experiment.

Kirakan perubahan suhu air yang dijangkakan dalam eksperimen itu.

[ Specific heat capacity of water : 4.2 J g-1 C-1 ]

[ Haba tentu air : 4.2 J g-1 C-1 ]

[ 2 mark/ markah]

(c)Why is the value of heat of combustion obtained always less than the actual value?

Mengapa nilai haba pembakaran yang didapati biasanya lebih rendah daripada nilai yang sebenar?

[ 1 mark/ markah]

(d)Draw the energy level diagram for the combustion of the alcohol.

Lukiskan gambarajah aras tenaga untuk pembakaran alkohol tersebut.

[ 2 mark/ markah]

(e)Table below shows the heat of combustion of various alcohols.

Jadual below menunjukkan haba pembakaran bagi pelbagai alkohol.

Number of carbon atomsBilangan atom karbonMolecular formulaFormula molekulName of substancesNama sebatianHeat of combustionHaba pembakaran ( kJ / mol-1 )

1CH3OHMethanol-728

2C2H5OH

-1376

3C3H7OHPropanol-2016

4C4H9OHButanol

Predict the heat of combustion of butanol.

Ramalkan haba pembakaran bagi butanol.

[ 1 mark/ markah]

3Diagram below shows the energy profile diagram for the reaction between hydrogen and chlorine.

Rajah di bawah menunjukkan gambar rajah profil tenaga untuk tindak balas antara hidrogen dan klorin.

(a)Is the reaction exothermic or endothermic?Support you answer.

Adakah tindak balas tersebut eksotermik atau endotermik?Terangkan jawapan anda.

[ 2 marks/ markah]

(b)Heat energy is required for bond breaking. What are the bonds that have been broken?

Tenaga haba diperlukan untuk pemecahan ikatan. Apakah ikatan-ikatan yang telah dipecahkan?

[ 2 marks/ markah]

(c)Heat energy is released from bond making. What is the bond that has been formed?

Tenaga haba dibebaskan daripada pembentukan ikatan. Apakah ikatan yang terbentuk?

[ 2 marks/ markah]

(d)7.1 g of chlorine reacts completely with hydrogen.

Calculate.

Sebanyak 7.1 g klorin bertindak balas dengan hydrogen dengan lengkap.

Hitung.

(i)The number of moles of chlorine gas that reacted.

[Relative atomic mass: Cl, 35.5]

Bilangan mol gas klorin yang bertindak balas

[Jisim atom relatif: Cl, 35.5]

[ 1 mark/ markah]

(ii)Heat change, in joules, in the experiment

Perubahan haba, dalam joule, di dalam eksperimen

[ 1 mark/ markah]

(e)Given that the heat released from the experiment is used to heat 500 g of water. [Specific capacity of water = 4.2 J g-1 C-1; density of water = 1.0 g cm-3]

Diberikan bahawa haba yang dibebaskan daripada eksperimen digunakan untuk memanaskan 500 g air. [Muatan haba tentu air = 4.2 J g-1 C-1; ketumpatan air = 1.0 g cm-3]

Predict the expected rise in temperature of the water.

Ramalkan kenaikan suhu air yang dijangkakan.

[ 2 marks/ markah]

END OF QUESTION PAPER KERTAS SOALAN TAMAT