Disk Struct
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Transcript of Disk Struct
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8/6/2019 Disk Struct
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Disk Storage
CIT 595Spring 2007
17 - 2CIT 595
Magnetic Disk Physical Structure
Each platter(disc-shaped) iscoated with magnetic material onboth surfaces
Each platter surface has armextended from fixed position
Tip of the arm containsread/write headfor reading orwriting data
The arm moves the heads fromthe spindle edge to the edge ofthe disc
17 - 3CIT 595
Magnetic Disk: Physical Structure
Copyright: Howstuffworks.com 17 - 4CIT 595
Low-Level Disk Formatting
Track Width is 1-2 microns(micrometer)
A sector contains fixed numberof bytes
E.g. 215 bytes or 4096 bytes
Divided in header (stores
sector number), data andECC
Width of 1 bit in a sector is 0.1to 0.2 microns
Cylinder: is a set of tracks onall the surfaces at a fixed armposition
Platter Surface View
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17 - 9CIT 595
Access Time
Seektime is the time that it takes for a disk arm tomove into position over the desired cylinder
Quoted by disk manufactures to be between 4-5ms
Also depends disk schedule i.e. in what order do you accessthe blocks (done by OS or disk controller)
Rotationaldelay is the time that it takes for the desiredsector to move into position beneath the read/write head
On Avg: Half the rotational Speed
Current rotational speed is 7200 RPM (revolutions/min) givingus ~4.2 ms
Access Time= Seek time + Rotational delay
17 -10CIT 595
Transfer Time
Transfer Time= Time for read/write + Access TimeCalculation for read or write time can be derived from specified
transfer rate e.g. 60 MB/Sec
Example: What is transfer time for reading 512 bytes ofdata? Assume seek time on average is 4.5 ms
Transfer T = Time for Read + Seek Time + Rotational
= 512 B/ (60 MB/sec) + 4.5 + 4.2
= 0.00853 + 4.5 + 4.2
= 8.70853 ms