Conditional Probability example: Toss a balanced die once and record the number on the top face. ...
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Transcript of Conditional Probability example: Toss a balanced die once and record the number on the top face. ...
Conditional Probabilityexample: Toss a balanced die once and record the
number on the top face. Let E be the event that a 1 shows on the top
face. Let F be the event that the number on the
top face is odd.– What is P(E)?– What is the Probability of the event E if we are
told that the number on the top face is odd, that is, we know that the event F has occurred?
Conditional Probability Key idea: The original sample space no
longer applies. The new or reduced sample space is
S={1, 3, 5} Notice that the new sample space
consists only of the outcomes in F. P(E occurs given that F occurs) = 1/3 Notation: P(E|F) = 1/3
Conditional Probability
Def. The conditional probability of E given F is the probability that an event, E, will occur given that another event, F, has occurred
)()(
)|(FP
FEPFEP
0)( FPif
If the outcomes of an experiment are equally likely, then
FFE
FEPin outcomes ofnumber
in outcomes ofnumber )|(
Example:
Earned degrees in the United States in recent year
B M P D Total Female 616 194 30 16 856 Male 529 171 44 26 770 Total 1145 365 74 42 1626
4620.01145529
)|( BMaleP
4735.01626
770)( MaleP
32.04.0*8.0)( FEP
Example:E: dollar falls in value against the yenF: supplier demands renegotiation of contract
8.0)|(
40.0)(
EFP
EP
)( FEP Find
Independent Events-sec2If the probability of the occurrence of event A is the same regardless of whether or not an outcome B occurs, then the outcomes A and B are said to be independent of one another. Symbolically, if
then A and B are independent events.
)()|( APBAP
Independent Events
then we can also state the following relationship for independent events:
if and only if
A and B are independent events.
)()|()( BPBAPBAP
)()()( BPAPBAP
Example A coin is tossed and a single 6-sided die is
rolled. Find the probability of getting a head on the coin and a 3 on the die.
Probabilities:
P(head) = 1/2
P(3) = 1/6
P(head and 3) = 1/2 * 1/6 = 1/12
The Notion of Independence applied to Conditional Probability
If E, F, and G are independent given that an event H has occurred, then
)|(*)|(*)|()|( HGPHFPHEPHGFEP
Important Independent Events vs. Mutually Exclusive
Events (Disjoint Events) If two events are Independent,
If two events are Mutually Exclusive Events then they do not share common outcomes
)()()( BPAPBAP )()|( APBAP
Focus on the Project
How can conditional probability help us with the decision on whether or not to attempt a loan work out?
How might our information about John Sanders change this probability?
Focus on the Project
Recall: EventsS- An attempted workout is a SuccessF- An attempted workout is a FailureP(S)=.464P(F)=.536How might our information about John Sanders change this probability?
Calculations- Expected Values
More Events
Y- 7 years of experience
T- Bachelor’s Degree
C- Normal times Conditional Probabilities
P(S|Y)=? P(F|Y)=?
P(S|T)=? P(F|T)=?
P(S|C)=? P(F|C)=?
Each team will have their client data
Each team will have to calculate
complementary formula
P(F|Y)=1- P(S|Y)
.)(
)()|()|(
BR
BRBRBRBR YP
YSPYSPYSP
recordsofnumber
andinnumber)(
BR
YSYSP BRBR
BRBR recordsofnumber
innumber)(
BR
YYP BR
BR
.innumber
andinnumber)|(
BR
BRBRBRBR Y
YSYSP
AssumptionSimilar clients
Indicates that the event occurred at the given bank
Recall-BR BankRange1
Range2
Range3
Range4
Ranges
Former BankYears In
BusinessEducation
LevelState Of
EconomyLoan Paid
Back?
BR yes
Former BankYears In
BusinessEducation
LevelState Of
EconomyLoan Paid
Back?
BR 7 yes
Former BankYears In
BusinessEducation
LevelState Of
EconomyLoan Paid
Back?
BR no
Former BankYears In
BusinessEducation
LevelState Of
EconomyLoan Paid
Back?
BR 7 no
Using DCOUNT
Counting
NumberSuccessful
Number Successful
With YNumber
Failed
Number Failed With Y
NumberWith Y
1,470 105 1,779 134 239
105+134Range1 Range2 Range3 Range4
Number with S BR and Y BR
Number with Y BR
Estimated P (S BR |Y BR)
Estimated P (F BR |Y BR)
105 239 0.439 0.561
BR Bank
Estimated P (S |Y )
Estimated P (F |Y )
0.439 0.561
Acadia Bank
P(S|Y) & P(F|Y) –BR Bank
ZY -The Money bank receives from loan work out attempt to a borrower with 7 years experience
expected value of ZY.
)|(000,250$)|(000,000,4$
)000,250$(000,250$)000,000,4$(000,000,4$)(
YFPYSP
ZPZPZE Y
=$1,897,490 =4,000,000* .439 +250,000*.561
Analysis of E(Zy)?
Foreclosure value - $ 2,100,000 E(Zy)=$ 1,897,490
This piece of information E(Zy) indicates FORECLOSURE
Decision?Recall
Bank Forecloses a loan if
Benefits of Foreclosure > Benefits of Workout
Bank enters a Loan Workout if
Expected Value Workout > Expected Value Foreclose
SimilarlyYou can calculate
E(Zt), E(Zc) for the Team Project1 Do a Similar analysis using E(Zt), E(Zc) RANDOM VARIABLES
Zt -The Money bank receives from loan work out attempt to a borrower with Bachelor’s Degree
Zc -The Money bank receives from loan work out attempt to a borrower during normal economy
CalculationsConditional Probability
Recall Events
Y- 7 years of experience
T- Bachelor’s Degree
C- Normal times Conditional Probabilities
P(Y|S)=? P(Y|F)=?
P(T|S)=? P(T|F)=?
P(C|S)=? P(C|F)=?
Each team will have their client data
Each team will have to calculate
Important – Here we cannot use the complementary formula
P(Y|S) & P(Y|F) –BR Bank
Number with Y BR and S BR
Number with S BR
Estimated P (Y BR |S BR)
Number with Y BR and F BR
Number with F BR
Estimated P (Y BR |F BR)
105 1,470 0.071 134 1,779 0.075
BR Bank
Estimated P(Y|S)
Estimated P(Y|F)
0.071 0.075
P(Y|S) –BR Bank
P(YBR|SBR) 105/1,470 0.071.
P(Y|S) P(YBR|SBR) 0.071.
.innumber
andinnumber)|(
BR
BRBRBRBR S
SYSYP
recordsofnumberandinnumber
)(BR
SYSYP BRBR
BRBR recordsofnumber
innumber)(
BR
SSP BR
BR
*Slide 20
Next stepP(Y|S) 0.071 (BR)
Similarly
P(T|S) 0.530 (Cajun)
P(C|S) 0.582 (Dupont)
We know Y, T, and C are independent events, even when they are conditioned upon S or F. Hence,
P(Y T C|S) = P(Y|S)P(T|S)P(C|S)
(0.071)(0.530)(0.582) 0.022
Similarly, can calculate
P(Y T C|F) = P(Y|F)P(T|F)P(C|F)
Recall-The Notion of Independence applied to Conditional Probability
Next step P(Y T C|S) will be used to calculate
P(S|Y T C) P(Y T C|F) will be used to calculate
P(F|Y T C) HOW????? We will learn in the next lesson?
SummaryConditional Probabability Formula
If two events are Independent,
Independence Formula –3 events
The Notion of Independence applied to Conditional Probability
)(*)(*)()( GPFPEPGFEP
)()(
)|(FP
FEPFEP
0)( FPif
)(*)()( BPAPBAP )()|( APBAP
)|(*)|(*)|()|( HGPHFPHEPHGFEP