Bellringer – March 13, 2014

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Green color (G) is dominant to white color (g) in turtles. In a population of 200 turtles, 13% are white. A) What are the allele frequencies? B) What percentage of each genotype are in this population? C) How many turtles are heterozygous? Bellringer – March 13, 2014

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Bellringer – March 13, 2014. Green color (G) is dominant to white color ( g ) in turtles. In a population of 200 turtles , 13% are white. A) What are the allele frequencies? B) What percentage of each genotype are in this population? C) How many turtles are heterozygous?. - PowerPoint PPT Presentation

Transcript of Bellringer – March 13, 2014

Page 1: Bellringer  – March 13, 2014

Green color (G) is dominant to white color (g) in turtles.

In a population of 200 turtles, 13% are white.

A) What are the allele frequencies?B) What percentage of each genotype are in

this population? C) How many turtles are heterozygous?

Bellringer – March 13, 2014

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G= Green g= white White = 13% = 0.13 = gg= q2

√0.13=√q2

A) q = 0.36 then p = 0.64B) GG = p2= (0.64)2=0.4096= 40.96% Gg = 2pq= 2(0.64)(0.36)=0.4608= 46.08% gg = q2= (0.36)2= 0.1296= 12.96%C) (.4608)(200) = 92 turtles are heterozygous

ANSWER KEY

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A scientist has studied the amount of PTC tasters in a population. PTC tasting is dominant. From one population, 500 individuals were sampled. The scientist found the following individuals: AA = 110, Aa = 350; aa = 40.

Calculate the genotypic and allelic frequencies for the PTC gene at this population.

Determine the genotypic and allelic frequencies expected at Hardy-Weinberg equilibrium using the homozygous recessive. Is this population in Hardy-Weinberg equilibrium? Is the population evolving?

Practice Problem #2

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AA = 110, Aa = 350; aa = 40. AA = 110/500 = 0.22; Aa=350/500 = 0.70 ; aa=

40/500= 0.08 A=110 + 110 + 350 = 570/1000 = 0.57; a = 40 + 40 + 350 = 160/1000 = 0.43

A) Actual population

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p=A= PTC taster q= a = PTC non-taster 40/500= 0.08 = PTC non-taster = aa= q2

√0.08=√q2

q = 0.28 then p = 0.72 RR = p2 = (0.72)2 = 0.52 = 52.00% Rr = 2pq = 2(0.72)(0.28) = 0.40= 40.00% rr = q2 = (0.28)2 = 0.08 = 8.00%

b) Hardy-weinberg

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Evolution and Zygotic Barriers (Macroevolution

part 2)

Ms. KimH. Biology

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1. Geographic isolation2. Reproductive barriers (isolation)3. Change in chromosome numbers

through mutation4. Adaptive radiation (example of

divergent evolution)

Speciation = formation of NEW species

Why don’t similar species interbreed??

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A. harrisi A. leucurus

Hello over

there

Geographic Isolation

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Two general modes of speciation determined by the way gene flow among populations is initially

interrupted:Geographic and Reproductive Isolation

Speciation can occur in two ways:◦Geographic: Allopatric speciation (means

“other”) a genetic isolation WITH a geographical

barrier; new group isolated from its parent population

◦Reproductive: Sympatric speciation (means “together”) genetic isolation WITHOUT a geographical

barrier; a reproductive barrier isolates population in SAME habitat

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http://www.pbs.org/wgbh/nova/evolution/evolution-action-salamanders.html

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Reproductive Isolationbiological factors (barriers) that stop 2 species from producing viable, fertile hybrids

Two types of barriers◦Postzygotic “after the zygote” Zygote can NOT develop

◦Prezygotic “before the zygote” Sperm and egg can not fuse

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Pre-Zygotic Barriers

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2 species encounter each other rarely, or not at all, because they live in different habitats, even though not isolated by physical barriers

Sympatric: Habitat Isolation

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Species that breed at different times of the day, different seasons, or different years cannot mix their gametes

Sympatric: Temporal Isolation

Late WinterLate Summer

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Morphological differences can prevent successful mating

Related species may attempt to mate but CAN’T anatomically incompatible

Sperm = transfer

Sympatric: Mechanical Isolation

Mating organs don’t fit

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Sperm of one species may not be able to fertilize eggs of another species

Ex: specific molecules on egg coat adhere to specific molecules on sperm

Sympatric: Gametic Isolation

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Post-Zygotic Barriers

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Genes of the different parent species may interact and impair the hybrid’s development

Hybrids are very weak and/or underdeveloped

Reduced Hybrid Viability

Salamander hybrid shows

incomplete development

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Even if hybrids may live and be strong, they may be sterile

Reduced Hybrid Fertility

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Polyploidy is presence of EXTRA sets of chromosomes due to accidents during cell division ◦ex: “nondisjunction”

It has caused the evolution of some plant species

More common in plants than in animals

Polyploidy