Add Maths Normal Distribution
Click here to load reader
-
Upload
tang-pei-pei -
Category
Documents
-
view
2.102 -
download
1
description
Transcript of Add Maths Normal Distribution
PROBABILITY DISTRIBUTIONS
Example 1 :
Find the value of each of the following probabilities by using the calculator.
(a) P(Z > 0.934)
SD
Mode casio 570
shift + 3dist P( Q( R(
1 2 3
Choose P(z) if P(z<)
Choose Q(z) if P( <z<0) or P( 0<z< )
Choose R(z) if P(z>)
= R(0.934)
= 0.1752
Example 2 :
Find the value of each of the following probabilities by using the calculator.
(b) P(Z <1.25)
Solution P(z< 1.25) = 1 – P(Z > 1.25) = 1 – 0.1057
= 0.8944
1.25 1.25
Or P(1.25)
= 0.8944
(c) P(Z < - 1.512)
-1.512 1.512
P(Z < - 1.512) = P(Z > 1.512) = 0.06527
or
P(-1.512) = R(1.512)
= 0.06527
(d) P(Z > - 0.23)
-0.23 0.23
P(z > - 0.23) = 1 – P(Z < - 0.23) = 1 – P(Z > 0.23) = 1 – 0.40905
= 0.59095
orR(-0.23)
=0.59095
(e) P(0.4 < Z < 1.2)
P(0.4 < Z < 1.2) = P(Z > 0.4) – P(Z > 1.2) = 0.3446 – 0.1151
= 0.2295
0.4 1.20.4 1.2
Or R(0.4) – R (1.2) = 0.3446 – 0.1151
= 0.2295
(f) P(- 0.828 < Z < - 0. 555)
-0.828 -0.555 0.555 0.828 0.555 0.828
P(-0.828 < z < - 0. 555) = P(0.555 < z < 0. 828)
= P(Z > 0.555) – P(Z > 0.828) = 0.28945 – 0.20384 = 0.08561
R(0.555) – R(0.828)P(-0.555) – P(-0.828) =
= 0.08561
(g) P(- 0.255 < Z < 0.13)
-0.255 0.13 0.13-0.255
P(-0.255< Z < 0.13) = 1 – P(Z < - 0.255) – P(Z > 0.13) = 1 – P(Z > 0.255) – P(Z > 0.13) = 1 – 0.39936 – 0.44828 = 0.1524
or
Q(-0.255) + Q(0.13)
= 0.10064 + 0.05172
= 0.1524
Usaha tangga
kejayaan