2_Theory Related to Subsea Lifting Op_Sandvik

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Theory related to subsea lifting op_Sandvik

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    Subsea lifting operationsStavanger - Dec. 1-2 2010

    Peter Chr. SandvikMARINTEK

    Theory related to subsea lifting operations

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    Content Introduction, main criteria for safe lifting Lifting dynamics, simple equation of motion

    Static and dynamic forces, wave forces on small objects Mass, stiffness and damping Response (motion) calculation, resonance

    Large structures, 6 degrees of freedom Wave forces on long structures (e.g. pipes)

    Snatch and impact loads Statistics used for estimation of extremes Stability

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    The installation often gives the highest life-time forces on subsea equipment

    General

    Templates, protection structures

    Suction anchor

    Snatch at lift-off or after slack Impact after uncontrolled

    pendulous motion Local loads from wave impact

    Wave forces in the splash zone

    Wave forces in the splash zone Soil penetration forces (and soil

    failure)

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    Lift in general

    Is the structure designed for the loads occurring during lifting and deployment?

    Hydrodynamic forces

    Limited lifting height may give large compressive forces from the slings

    Measures:

    Lifting frame

    Spreader beam

    Reinforcement (compression bar)

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    Operation criterion:Ensure safe operation Avoid:

    Excessive pendulum motion in air

    Slack wire (when not intended)

    Overload (in any lifting equipment)

    Too hard landing (and second lift-off)

    Do: Ensure acceptable stability

    Have ability to handle unexpected changes

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    Static forces may be unknown Example: Drainage when H-frame is taken on board

    W = mgB = gVWs = mg - gV

    W = Weight in airB = BuoyancyWs = Submerged weight

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    Wreck recovery

    Unknown weight,weight distributionand stability

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    Lift in air

    Steel structure with GRP coversDimensions: 18 x 18 x 7 mMass: 180 tonnes

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    Wave forces in the splash zone

    1

    218 x 18 x 7 m, 180 tonnes

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    Wave forces in the splash zoneExample: Template (3- 8)

    Large dynamic forces ( 140 T)

    3 4 5

    6 7 8

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    Details should be checkedExample: Template structure

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    Damaged cover

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    -15.00

    -10.00

    -5.00

    0.00

    5.00

    10.00

    15.00

    0 500 1000 1500 2000 2500

    Tension (kN)

    Ver

    tical

    pos

    ition

    (m)

    !

    !

    Wire tension when lowering a body through the splash zoneExample

    }Splash zone dynamicsReducing

    Weight in air

    Weightin water

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    Forces on the lifted object (Newtons, or kN)

    Dynamic forces:

    Damping

    Inertia, moving object

    Inertia, wave force

    Slamming force

    rrrr

    rd vvcvcv

    vcF 210 ++=

    ( ) ( )xcVmxmmF aai +=+=( ) ( ) aaiw cVmVF +=+= 1

    2221

    ra

    rss vdhdcVvAcF ==

    x = body motion = wave particle motioncs = slamming coefficientca = added mass coefficient

    (depth dependent)

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    Wave kinematics (1)

    Profile of regular waves propagating in x direction

    Wave number (deep water)

    Wave length

    Propagation speed

    Max. wave slope

    kx)t( = sin0

    2

    2 42Tg

    k ==

    256.12 Tk

    ==

    TT

    vw 56.1==

    020max

    4 T

    kdxd

    =

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    Heave force and pitch moment on a long member(It is conservative to assume small body, concentrated loads)

    Wave force on an element dx:

    Maximum total wave force:

    dxcAf a 2)1( +=

    lengthwaveLLF

    F ==

    sin

    0

    02

    0 )1( acLAF +=

    Harmonic wave:amplitude frequency

    0

    0.2

    0.4

    0.6

    0.8

    1

    0 0.5 1 1.5 2 2.5 3L / Wavelength

    F / F

    0,

    M /

    F0 L

    ForceMoment

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    Wave kinematics (2)Reduction with depth

    Reduction of wave kinematics with depth

    -100-90-80-70-60-50-40-30-20-10

    0

    0 0.2 0.4 0.6 0.8 1Depth reduction

    Z (m

    )

    T = 4sT = 6sT = 10sT = 14sT = 20s

    =2

    4T

    zkz eeR

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    Shielding-effect from the crane vesselExample of analysis results

    1500

    1750

    2000

    2250

    2500

    2750

    3000

    6 7 8 9 10 11 12Tp (s)

    Max

    liftw

    ire fo

    rce

    (kN

    )

    Wavedir. 180 deg.Wavedir. 165 deg.Wavedir. 150 deg.

    x

    y21

    3

    45

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    Hydrodynamic data:Added mass, ma and drag , Fd 6 values - (for motion in 3 directions and rotation about 3 axis)

    Plate

    Box Suction anchor

    Added mass coefficient:Ca = ma / V

    = water densityV = reference volume

    Drag coefficient: cdFd = cdAv2

    v = velocityA = area

    Fd

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    Added mass - simple structures

    ca Vm =

    b4aV

    2c

    =

    a

    b

    Cylinder volume:

    Geometry Formula b/a Rectan-gular

    a = shortest edge

    1.0 0.5791.2 0.6301.25 0.6421.33 0.6601.5 0.6912.0 0.7572.5 0.8013.0 0.8304.0 0.8715.0 0.8978.0 0.93410.0 0.947

    (Cf. DnV-RP-H103)

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    Added mass of ventilated structuresExample

    Added mass

    0.0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    0 0.5 1 1.5 2

    z(1-p)/(2Dp^2)

    a/a0 Hatch 20, p=0.15

    Hatch 18, p=0.25Roof #1, p=0.267Roof #2, p=0.47Roof #3, p=0.375

    a = added massa0 = added mass for solid structurep = perforation ratio = open area / total areaD = dimension

    Recommended values arefound in DnV-RP-H103

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    Damping

    Coulomb damping Friction, hysteresis loss, ....

    Linear damping Wave potential damping,

    material damping, oscillation damping in wind, ....

    Quadratic damping

    Hydrodynamic dragMorison's formulaNotice:cd for oscillating objects is larger

    than cd for steady flow !

    vvcF = 00

    vcF = 11

    vvcF = 22

    rrdd vvAcF 21=

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    Stiffness General

    Axial wire stiffness E = modulus of elasticity A = section area L = length

    Transverse stiffness

    Hydrostatic stiffness

    Rotation stiffness(spring k, distance b from

    rotation center) Parallel springs

    Springs in series

    dxFkx

    =

    == ii

    tot kF

    k

    =

    ==

    itotitot kkkF

    kF 11

    LEAk =

    LFFk

    LFF

    y

    yy

    yy =

    ==

    WPAgk =

    2bkK =

    [Compression: k = 0]

    [AWP = waterplane area]

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    Simple equation of motion

    )()()()( tFxkxcxM =++

    )()()()( 0 txkxkxcxM =++

    Force excitation

    Motion excitationF(t)

    x0(t)

    Force excitation Motion excitation

    x

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    Response curve (RAO) of simple oscillating system

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    Resonance periods - examples

    Vertical oscillation in air:

    =

    == 22220 gmgm

    EAmLT

    = elongation of wire due to weight mg

    Vertical oscillation in water (long wire, wire mass mwincluded):

    ( )L

    EAmmm

    T wa 31

    0 2++

    =

    LLgmg

    mLF

    mLT 22220 ===

    Pendulum oscillation in air:

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    Example: Lifting in airAmplitude dependent transverse stiffness

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    Wire length: 25 mNatural period : 10.0 sVessel: L=100 mRegular waves H=2m

    T = 5 s

    T = 7 s T = 10 s

    T = 9 s

    T = 8 s T = 11 s

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    Example: Lifting in air

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    Wire length: 25 mNatural period : 10.0 sVessel: L=100 mIrregular waves Hs=2 m

    Tp = 6 s

    Tp = 8 s

    Tp = 10 s

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    Example: Installation of suction anchorsSplash zone crossing

    Two suction anchors:

    Anchor B4 B30

    D x H (m) 4 x 4 4 x 30

    Mass, steel (t) 26 156

    Added mass (t) 86 400

    Total mass (t) 111 556

    Submerged weight (kN) 213 1330

    D

    H

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    Splash zone - Anchor B30(Hs = 2.5 m, Tp = 8 s)

    DAF 1.35

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    Hydrodynamic mass for suction anchorsfound from model tests

    D

    A = amplitudep = perforation ratioa0 = added mass,

    without ventilation

    Example: p = 1%A/D = 0.5

    X =

    X = 4950

    0

    0.2

    0.4

    0.6

    0.8

    1

    1 10 100 1000 10000

    (A/D)*(1-p)/p^2

    a / a

    0 p = 0.01p = 0.03p = 0.11

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    -35

    -30

    -25

    -20

    -15

    -10

    -5

    0

    0 0.2 0.4 0.6 0.8 1

    Depth reduction

    Z (m

    )

    T = 3sT = 4sT = 5sT = 6sT = 7sT = 8 sT = 9 sT = 10 sT = 11 sT = 12 sT = 14 s

    Reduction of wave kinematics with depth Reduced dynamic pressure at lower end of anchor

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    Numerical modelling of a suction anchorElements with distributed forces

    Horizontal added mass and damping

    Vertical addedmass and damping,

    topEnclosed water ++

    All are positiondependent

    (zero when element is above water

    Anchor(steel)

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    Vertical wave forces on fixed buckets (Hs = 2.0 m)

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    Bucket B4 Bucket B30

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    Liftwire tension (Hs = 2.0 m)

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    Bucket B4 Bucket B30

    DAF = 2.5 / 1.5 DAF = 1.4 / 1.3

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    Example: a 30x30 m stiffened foundation plate

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    M = 400 t

    M = 30 t

    M = 50 t

    W = 3420 kNma = 15000 t

    ma = 3000 t

    Just fully submerged Inclination 79 deg.

    Hs = 2.0 mTp = 6, 8, 10 s

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    Calculated forces

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    Max.: 5700 kN

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    -15.00

    -10.00

    -5.00

    0.00

    5.00

    10.00

    15.00

    0 500 1000 1500 2000 2500

    Tension (kN)

    Ver

    tical

    pos

    ition

    (m)

    Analysis of transient processes(Splash zone crossing, other non-linear cases)

    Analysis approach

    A few examples

    Estimation of extreme forces

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    Lowering through the splash zoneNumerical analysis - 2 methods

    Slow lowering in small, regularwaves 1 2 typical wave periods Find most onerous object position

    Stationary analysis in most onerous position, in irregularwaves (0.5 - 3 hours) Calculated max./min. force

    Evaluate results Study time series Find peaks in time series Statistical analysis (WEIBULL) Estimate extreme force

    Repeated lowering in irregularwaves From air to well below surface Different wave realizations

    (MonteCarlo random selection)

    Find the calculated max./min. forcefrom each lowering case

    Evaluate results Statistical analysis (GUMBEL) Study time series (explanation of

    physical phenomena) Estimate extreme force

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    Statistical estimation from a time history

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    Extreme estimation from local peaks, stationary processWEIBULL plot

    ln [-

    ln (1

    -P)]

    Reduced slope due tonon-linear effects, e.g.: Quadratic damping Snatch loads

    P = cumulative probabilityx = local peaks = average value of peaks

    off points may be due to statistical spread,or they may have aphysical explanation.

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    Extreme estimation from repeated tests, random processExtremes from 20 lowerings through splash zone, GUMBEL plot

    Cumulative probability

    -1.5-1

    -0.50

    0.51

    1.52

    2.53

    3.54

    900 1000 1100 1200 1300 1400 1500Tension (kN)

    -ln(-l

    n(P)

    )

    off points may be due to statistical spread,OR:may represent a differentphysical mechanism(example: impact, snatch).

    .95.90

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    Snatch loads -Example: Lift-off from transport vessel

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    Blind lift-off at max.relative velocity:

    Fmax = approx. 5600 kN

    Start in constant-tension modeLift when winch stops to pay in

    Mass: 365 tonnesHs : 2.5 m

    P = 0.95

    P = 0.80

    +=

    +=

    Mk

    gVMg

    MkVMgF

    rel

    rel

    1

    max

    General expression:

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    Example: Personnel transfer to offshore wind turbines

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    Intention:The boat should hang onfender friction during personnel transfer.

    All slippages were considered as events. Statistics by use of GUMBEL plots

    .90.95

    .80

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    Assume:Centre of buoyancy, CB, off centre of gravity, CG.

    The force centre,

    will be vertically below the hookheel angle

    If center of vertical added mass is not inline with F:vertical excitation tilting oscillations

    Lifting at points below CG should be analysed with care

    Stability -Tilt angle and angular oscillations

    B

    CF CG CB

    F = mg-B

    mg

    BmgCGmgCBBCF

    =

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    Underwater lifting operation(Not intended)

    (Stability of the lifting body)

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    Safe Job Analysis

    Can anything go wrong ?

    Shhh, Zog! ....Here come one now!

    Subsea lifting operations Stavanger - Dec. 1-2 2010ContentThe installation often gives the highest life-time forces on subsea equipmentLift in generalOperation criterion:Ensure safe operationStatic forces may be unknown Example: Drainage when H-frame is taken on boardWreck recoveryLift in airWave forces in the splash zone Wave forces in the splash zone Example: Template (3- 8) Details should be checked Example: Template structureDamaged coverWire tension when lowering a body through the splash zoneExampleForces on the lifted object(Newtons, or kN)Wave kinematics(1)Heave force and pitch moment on a long member(It is conservative to assume small body, concentrated loads)Wave kinematics(2)Reduction with depthShielding-effect from the crane vesselExample of analysis resultsHydrodynamic data:Added mass, ma and drag , Fd 6 values - (for motion in 3 directions and rotation about 3 axis)Added mass - simple structuresAdded mass of ventilated structures ExampleDampingStiffnessSimple equation of motionResponse curve (RAO) of simple oscillating systemResonance periods - examplesExample: Lifting in airAmplitude dependent transverse stiffnessExample: Lifting in airExample: Installation of suction anchorsSplash zone crossingSplash zone - Anchor B30 (Hs = 2.5 m, Tp = 8 s)Hydrodynamic mass for suction anchorsfound from model testsReduction of wave kinematics with depth Reduced dynamic pressure at lower end of anchorNumerical modelling of a suction anchorElements with distributed forcesVertical wave forces on fixed buckets (Hs = 2.0 m)Liftwire tension (Hs = 2.0 m)Example: a 30x30 m stiffened foundation plateCalculated forcesAnalysis of transient processes (Splash zone crossing, other non-linear cases)Lowering through the splash zone Numerical analysis - 2 methodsStatistical estimation from a time historyExtreme estimation from local peaks, stationary processWEIBULL plot Extreme estimation from repeated tests, random processExtremes from 20 lowerings through splash zone, GUMBEL plotSnatch loads - Example: Lift-off from transport vesselExample: Personnel transfer to offshore wind turbinesStability - Tilt angle and angular oscillationsUnderwater lifting operation (Not intended)Safe Job AnalysisCan anything go wrong ?