Oakland Math TestSelect Questions and Answers
NOT Multiple Choice
What number added to the sum of equal the number 1?
π₯+ 13 +14=1
12π₯+4+3=12
12π₯=5
π₯= 512
(43 )2
16=?
(43 )2
16=4
6
42=44=254
solve for w.
10π€=35π€=3.5
Jan is making clay coasters for an art fair. Each coaster costs $2.25 to make. If she sells the coasters for $4.00 each, how many will she have to sell to make a profit of exactly $70.00?
πΏππ‘ π₯ππ hπ‘ πππ’ππππ ππ ππππ π‘πππ hπ πππππ .ππππππ‘ ππ hπππ Γ hπ‘ πππ’ππππ ππ ππππ π‘πππ =ππππππ‘
(4.00β2.25 ) π₯=70.00
1.75 π₯=70π₯=40
Four pieces of ribbon are cut from a length of ribbon that is 80 ft long. One of the pieces is 15 feet long. Two of the pieces are 7Β½ feet long. One of the pieces is 3ΒΎ feet long. How many feet of ribbon are left from the original length?
πΏππ‘ π₯ ππ‘ ππ hπ‘ π hπππππ‘ ππ hπ‘ π ππππ‘ππ£ππ πππππ .15+2(7 12 )+3 34 +π₯=80
15+15+ 154 +π₯=80154 +π₯=50
15+4 π₯=2004 π₯=185π₯=46 14 ππ‘
A taxi cab charges $0.80 for the first of a mile and $0.10 for each additional of a mile. What is the cost of 3 mile trip?
πΏππ‘ $ π₯ππ hπ‘ ππππ π‘
π₯=0.80+0.10 [ (3β 15 )110
]π₯=πππ π‘ ππ 1 π π‘ 15ππππ+πππ π‘ ππ hπ‘ ππππ π‘ππ hπ‘ ππ‘πππ
π₯=0.80+0.10 [ 145110
]π₯=0.80+0.10 (28)π₯=0.80+2.80π₯=3.60
Another Method: since taxi cab charges by tenths of a mile. For a 3 mile trip, there are 30 tenths of a mile. The first or 2 tenths of a mile costs 80Β’, the rest, 28 tenths of a mile costs 10Β’.
πππ π‘=80Β’+10Β’(28)
Continue
ΒΏ80+280=360=$3.60
John works a variety of different jobs. On Monday he earned $50. Tuesday he earned $40. On Wednesday and Thursday he earned $30 each day, and ion Friday he earned $100. What was johnβs average daily pay for the 5 days?
π΄π£πππππ=50+40+30+30+100
5
ΒΏ2505 =$50
Evaluate:
3 (β2 )2β2 (β2 ) (3 )+32
ΒΏ3 (4 )+12+9
ΒΏ12+12+9
ΒΏ33
Simplify:
(π₯+ π¦ )2β (9π₯π¦β6 π₯2 )ΒΏ π₯2+2π₯π¦+ π¦2β9 π₯π¦+6 π₯2
ΒΏ7 π₯2β7π₯π¦+ π¦2
Multiply:
(2 π₯β5 ) (6 π₯+4 )
ΒΏ12 π₯2+8π₯β30 π₯β20
ΒΏ12 π₯2β22 π₯β20
Divide:
12π₯5β6 π₯3+4 π₯2
4 π₯2
ΒΏ12π₯5
4 π₯2β 6 π₯
3
4 π₯2+4 π₯2
4 π₯2
ΒΏ3 π₯3β 32 π₯+1
Factor:
6 π₯3+27 π₯2β105 π₯ΒΏ3 π₯ (2π₯2+9 π₯β35)
ΒΏ3 π₯ (2 π₯β5 ) (π₯+7 )
Simplify:
π₯2β5 π₯+4π₯β1
ΒΏ(π₯β4 ) (π₯β1 )
π₯β1
ΒΏ π₯β4
Simplify:
ΒΏ3+4=7
Evaluate: , find A
π΄=π (1+π )
π΄=450 (1+0.12 )
π΄=450(1.12)
π΄=504
Simplify:
β18 π₯β4βπ₯3ΒΏ3 β2 π₯β4 π₯ βπ₯
Rationalize:
2+β32ββ3
β(2+β3 )(2+β3 )
ΒΏ 4+4β3+34β3
ΒΏ7+4 β3
Solve:
3 π₯+7=2(π₯β1)
3 π₯+7=2π₯β2
π₯+7=β2π₯=β9
Find the sum of the roots:
π₯2β6 π₯=7π₯2β6 π₯β7=0
(π₯+1 ) (π₯β7 )=0
π₯+1=0 ππ π₯β7=0
π₯=β1ππ π₯=7
π π’πππ ππππ‘π =β1+7=6
Solve for x:
1π₯ +
2π₯=10
1+2=10 π₯
10 π₯=3
π₯= 310
Solve the Inequality:
β2 π₯+3<5β2 π₯<2π₯>β1
System of Equations:
(1 )2π₯+3 π¦=β11(2 )6 π₯+π¦=7
πΉπππ (2): π¦=7β6 π₯ππ’π π‘π (1 ) :2 π₯+3 (7β6 π₯ )=β11
2 π₯+21β18 π₯=β11β16 π₯=β32π₯=2
π¦=7β6 (2 )=7β14=β7
Solution:
Simplify the Expression:
2πβ 2
(2π)β 3
ΒΏ2 (2π)3
π2
ΒΏ2 (8π3 )π2
ΒΏ16π3
π2
ΒΏ16 π
Scientific Notation:
(2.1Γ105 )2
ΒΏ (2.1Γ105 ) (2.1Γ105 )
ΒΏ 4.41Γ1010
Radicals:
3βπ β 4βπΒΏπ1 /3 βπ1 /4
ΒΏπ13 +14
ΒΏπ412+ 312
ΒΏπ712
ΒΏ 12βπ7
Altogether Mark, John, and Alan earned $104. John earned twice as much as Mark and Alan earned $4 more than John. How much did Alan earn?
πΏππ‘ $ π₯ππ hπ‘ πππππ’ππ‘ ππππππππππhπ½π π=2 π₯
π΄πππ= hπ½π π+4=2π₯+4
ππππ+ hπ½π π+ π΄πππ=104π₯+2π₯+2π₯+4=104
5 π₯+4=1045 π₯=100π₯=20
ππππ=$20
hπ½π π=2 (20 )=$ 40
π΄πππ=2 (20 )+4=$ 44
A train travels 4 hrs at 60 miles per hour and 2 hours at 75 miles per hour. What is the trainβs average rate for 6 hours?
π΄π£πππππ=π·ππ π‘ππππππ 1 π π‘ππππ‘+π·ππ π‘ππππππ 2ππππππ‘
πππ‘πππ‘πππ
π΄π£πππππ=4 (60 )+2 (75 )
6
ΒΏ3906 =65 hππ
Graph:
2 π₯+π¦=5π¦=β2π₯+5
π=β21 ππ
2β1 ππππ=5
Start with point A, where b = 5 or (0, 5).For point B, start from point A, go down 2 and go to the right 1, For point C, start from point A,go up 2 and go to the left 1.
π΄
π΅
πΆ
Slope: Are these two lines parallel?
πΏ13 π¦=β2π₯+6
π¦=β 23 π₯+2 ;π1=β23
πΏ2π2=7β105β3 =
β32
πΏ1ππππΏ2ππππππ ππππππππ ,π πππππ πππ πππ πππ’ππ .
Write the equation of the line through (2, -1) and has slope m = 3. Write the equation in general form (standard form).
(2 ,β1 )π₯1 , π¦1
π¦β π¦1=π (π₯βπ₯1 )
π¦β (β1 )=3(π₯β2)
π=3
π¦+1=3 π₯β6β3 π₯+π¦=β7
Standard form
What is the distance between A(2, -5) and B(6, 3)? (Round to the nearest tenth).
π΄ (2 ,β5 )π΅ (6 ,3)π₯1 π¦1π₯2 π¦2
π·=βπππ π2+ππ’π2
π·=β ( π¦2β π¦1 )2+ (π₯2βπ₯1)2
π·=β (3+5 )2+(6β2 )2
π·=β (8 )2+ (4 )2
π·=β64+16π·=β80π·=4β5
Graph:
π¦=βπ₯2+4π¦=β(π₯2β4)π¦=β (π₯+2 ) (π₯β2 )ππππ‘π : π΄ (β2 ,0 ) ,π΅ (2 ,0 )
ππ₯ππ ππ π π¦ππππ‘ππ¦ :π₯=β π2π
π₯=β 02 (β1 )
=0
π=β1 ;π=0 ;π=4
π¦=β02+4=4πππ₯=πΆ(0 ,4 )
π΄π΅
πΆ
.
ΒΏπ2+2π+1+2π+2+3
ΒΏπ2+4π+6
What is the domain of ?
2 π₯+6=02 π₯=β6π₯=β3
The domain of f(x) is ALL real numbers except -3
π·πππππ=(ββ ,β3 )βͺ (β3 ,β )
hπ ππππ π (π₯ )π’ππππππππ?
What is the domain of
π₯β7 β₯0π₯β₯7hπ πππππππππ π (π₯ ) π΄ππππππ ππ’πππππ β₯7
ππππππ=ΒΏ
Composition of functions: Find
( π βπ) (3 )= π (3) βπ(3)ΒΏ [3 (3 )β2 ] β[32+1]
ΒΏ7 β10( π βπ ) (3 )=70
Composition of functions: Find .
π (π (3 ) )= π (32+1)ΒΏ π (10)ΒΏ3 (10 )β2
π (π (3 ))=28
π (π (3 ) )=( π βπ)(3)