Oakland Math Test

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Oakland Math Test Select Questions and Answers NOT Multiple Choice

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Oakland Math Test. Select Questions and Answers NOT Multiple Choice. What number added to the sum of equal the number 1?. solve for w. - PowerPoint PPT Presentation

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Page 1: Oakland Math Test

Oakland Math TestSelect Questions and Answers

NOT Multiple Choice

Page 2: Oakland Math Test

What number added to the sum of equal the number 1?

π‘₯+ 13 +14=1

12π‘₯+4+3=12

12π‘₯=5

π‘₯= 512

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(43 )2

16=?

(43 )2

16=4

6

42=44=254

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solve for w.

10𝑀=35𝑀=3.5

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Jan is making clay coasters for an art fair. Each coaster costs $2.25 to make. If she sells the coasters for $4.00 each, how many will she have to sell to make a profit of exactly $70.00?

𝐿𝑒𝑑 π‘₯𝑏𝑒 h𝑑 π‘’π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘Žπ‘ π‘‘π‘’π‘Ÿπ‘  h𝑠 π‘’π‘šπ‘Žπ‘˜π‘’ .π‘π‘Ÿπ‘œπ‘“π‘–π‘‘ π‘œπ‘“ hπ‘’π‘Žπ‘ Γ— h𝑑 π‘’π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘Žπ‘ π‘‘π‘’π‘Ÿπ‘ =π‘π‘Ÿπ‘œπ‘“π‘–π‘‘

(4.00βˆ’2.25 ) π‘₯=70.00

1.75 π‘₯=70π‘₯=40

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Four pieces of ribbon are cut from a length of ribbon that is 80 ft long. One of the pieces is 15 feet long. Two of the pieces are 7Β½ feet long. One of the pieces is 3ΒΎ feet long. How many feet of ribbon are left from the original length?

𝐿𝑒𝑑 π‘₯ 𝑓𝑑 𝑏𝑒 h𝑑 𝑒 h𝑙𝑒𝑛𝑔𝑑 π‘œπ‘“ h𝑑 𝑒 π‘™π‘’π‘“π‘‘π‘œπ‘£π‘’π‘Ÿ 𝑝𝑖𝑒𝑐𝑒 .15+2(7 12 )+3 34 +π‘₯=80

15+15+ 154 +π‘₯=80154 +π‘₯=50

15+4 π‘₯=2004 π‘₯=185π‘₯=46 14 𝑓𝑑

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A taxi cab charges $0.80 for the first of a mile and $0.10 for each additional of a mile. What is the cost of 3 mile trip?

𝐿𝑒𝑑 $ π‘₯𝑏𝑒 h𝑑 π‘’π‘π‘œπ‘ π‘‘

π‘₯=0.80+0.10 [ (3βˆ’ 15 )110

]π‘₯=π‘π‘œπ‘ π‘‘ π‘œπ‘“ 1 𝑠𝑑 15π‘šπ‘–π‘™π‘’+π‘π‘œπ‘ π‘‘ π‘œπ‘“ h𝑑 π‘’π‘Ÿπ‘’π‘ π‘‘π‘œπ‘“ h𝑑 π‘’π‘‘π‘Ÿπ‘–π‘

π‘₯=0.80+0.10 [ 145110

]π‘₯=0.80+0.10 (28)π‘₯=0.80+2.80π‘₯=3.60

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Another Method: since taxi cab charges by tenths of a mile. For a 3 mile trip, there are 30 tenths of a mile. The first or 2 tenths of a mile costs 80Β’, the rest, 28 tenths of a mile costs 10Β’.

π‘π‘œπ‘ π‘‘=80Β’+10Β’(28)

Continue

ΒΏ80+280=360=$3.60

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John works a variety of different jobs. On Monday he earned $50. Tuesday he earned $40. On Wednesday and Thursday he earned $30 each day, and ion Friday he earned $100. What was john’s average daily pay for the 5 days?

π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’=50+40+30+30+100

5

ΒΏ2505 =$50

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Evaluate:

3 (βˆ’2 )2βˆ’2 (βˆ’2 ) (3 )+32

ΒΏ3 (4 )+12+9

ΒΏ12+12+9

ΒΏ33

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Simplify:

(π‘₯+ 𝑦 )2βˆ’ (9π‘₯π‘¦βˆ’6 π‘₯2 )ΒΏ π‘₯2+2π‘₯𝑦+ 𝑦2βˆ’9 π‘₯𝑦+6 π‘₯2

ΒΏ7 π‘₯2βˆ’7π‘₯𝑦+ 𝑦2

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Multiply:

(2 π‘₯βˆ’5 ) (6 π‘₯+4 )

ΒΏ12 π‘₯2+8π‘₯βˆ’30 π‘₯βˆ’20

ΒΏ12 π‘₯2βˆ’22 π‘₯βˆ’20

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Divide:

12π‘₯5βˆ’6 π‘₯3+4 π‘₯2

4 π‘₯2

ΒΏ12π‘₯5

4 π‘₯2βˆ’ 6 π‘₯

3

4 π‘₯2+4 π‘₯2

4 π‘₯2

ΒΏ3 π‘₯3βˆ’ 32 π‘₯+1

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Factor:

6 π‘₯3+27 π‘₯2βˆ’105 π‘₯ΒΏ3 π‘₯ (2π‘₯2+9 π‘₯βˆ’35)

ΒΏ3 π‘₯ (2 π‘₯βˆ’5 ) (π‘₯+7 )

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Simplify:

π‘₯2βˆ’5 π‘₯+4π‘₯βˆ’1

ΒΏ(π‘₯βˆ’4 ) (π‘₯βˆ’1 )

π‘₯βˆ’1

ΒΏ π‘₯βˆ’4

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Simplify:

ΒΏ3+4=7

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Evaluate: , find A

𝐴=𝑃 (1+π‘Ÿ )

𝐴=450 (1+0.12 )

𝐴=450(1.12)

𝐴=504

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Simplify:

√18 π‘₯βˆ’4√π‘₯3ΒΏ3 √2 π‘₯βˆ’4 π‘₯ √π‘₯

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Rationalize:

2+√32βˆ’βˆš3

βˆ™(2+√3 )(2+√3 )

ΒΏ 4+4√3+34βˆ’3

¿7+4 √3

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Solve:

3 π‘₯+7=2(π‘₯βˆ’1)

3 π‘₯+7=2π‘₯βˆ’2

π‘₯+7=βˆ’2π‘₯=βˆ’9

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Find the sum of the roots:

π‘₯2βˆ’6 π‘₯=7π‘₯2βˆ’6 π‘₯βˆ’7=0

(π‘₯+1 ) (π‘₯βˆ’7 )=0

π‘₯+1=0 π‘œπ‘Ÿ π‘₯βˆ’7=0

π‘₯=βˆ’1π‘œπ‘Ÿ π‘₯=7

π‘ π‘’π‘šπ‘œπ‘“ π‘Ÿπ‘œπ‘œπ‘‘π‘ =βˆ’1+7=6

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Solve for x:

1π‘₯ +

2π‘₯=10

1+2=10 π‘₯

10 π‘₯=3

π‘₯= 310

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Solve the Inequality:

βˆ’2 π‘₯+3<5βˆ’2 π‘₯<2π‘₯>βˆ’1

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System of Equations:

(1 )2π‘₯+3 𝑦=βˆ’11(2 )6 π‘₯+𝑦=7

πΉπ‘Ÿπ‘œπ‘š (2): 𝑦=7βˆ’6 π‘₯𝑆𝑒𝑏 π‘‘π‘œ (1 ) :2 π‘₯+3 (7βˆ’6 π‘₯ )=βˆ’11

2 π‘₯+21βˆ’18 π‘₯=βˆ’11βˆ’16 π‘₯=βˆ’32π‘₯=2

𝑦=7βˆ’6 (2 )=7βˆ’14=βˆ’7

Solution:

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Simplify the Expression:

2π‘Žβˆ’ 2

(2π‘Ž)βˆ’ 3

ΒΏ2 (2π‘Ž)3

π‘Ž2

ΒΏ2 (8π‘Ž3 )π‘Ž2

ΒΏ16π‘Ž3

π‘Ž2

ΒΏ16 π‘Ž

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Scientific Notation:

(2.1Γ—105 )2

ΒΏ (2.1Γ—105 ) (2.1Γ—105 )

ΒΏ 4.41Γ—1010

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Radicals:

3βˆšπ‘Ž βˆ™ 4βˆšπ‘ŽΒΏπ‘Ž1 /3 βˆ™π‘Ž1 /4

ΒΏπ‘Ž13 +14

ΒΏπ‘Ž412+ 312

ΒΏπ‘Ž712

ΒΏ 12βˆšπ‘Ž7

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Altogether Mark, John, and Alan earned $104. John earned twice as much as Mark and Alan earned $4 more than John. How much did Alan earn?

𝐿𝑒𝑑 $ π‘₯𝑏𝑒 h𝑑 π‘’π‘Žπ‘šπ‘œπ‘’π‘›π‘‘ π‘€π‘Žπ‘Ÿπ‘˜π‘’π‘Žπ‘Ÿπ‘›π‘’π‘‘hπ½π‘œ 𝑛=2 π‘₯

π΄π‘™π‘Žπ‘›= hπ½π‘œ 𝑛+4=2π‘₯+4

π‘€π‘Žπ‘Ÿπ‘˜+ hπ½π‘œ 𝑛+ π΄π‘™π‘Žπ‘›=104π‘₯+2π‘₯+2π‘₯+4=104

5 π‘₯+4=1045 π‘₯=100π‘₯=20

π‘€π‘Žπ‘Ÿπ‘˜=$20

hπ½π‘œ 𝑛=2 (20 )=$ 40

π΄π‘™π‘Žπ‘›=2 (20 )+4=$ 44

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A train travels 4 hrs at 60 miles per hour and 2 hours at 75 miles per hour. What is the train’s average rate for 6 hours?

π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’=π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’π‘œπ‘“ 1 π‘ π‘‘π‘π‘Žπ‘Ÿπ‘‘+π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’π‘œπ‘“ 2π‘›π‘‘π‘π‘Žπ‘Ÿπ‘‘

π‘‡π‘œπ‘‘π‘Žπ‘™π‘‘π‘–π‘šπ‘’

π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’=4 (60 )+2 (75 )

6

ΒΏ3906 =65 hπ‘šπ‘

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Graph:

2 π‘₯+𝑦=5𝑦=βˆ’2π‘₯+5

π‘š=βˆ’21 π‘œπ‘Ÿ

2βˆ’1 π‘Žπ‘›π‘‘π‘=5

Start with point A, where b = 5 or (0, 5).For point B, start from point A, go down 2 and go to the right 1, For point C, start from point A,go up 2 and go to the left 1.

𝐴

𝐡

𝐢

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Slope: Are these two lines parallel?

𝐿13 𝑦=βˆ’2π‘₯+6

𝑦=βˆ’ 23 π‘₯+2 ;π‘š1=βˆ’23

𝐿2π‘š2=7βˆ’105βˆ’3 =

βˆ’32

𝐿1π‘Žπ‘›π‘‘πΏ2π‘Žπ‘Ÿπ‘’π‘π‘‚π‘‡ π‘π‘Žπ‘Ÿπ‘Žπ‘™π‘™π‘’π‘™ ,π‘ π‘™π‘œπ‘π‘’π‘ π‘Žπ‘Ÿπ‘’ 𝑁𝑂𝑇 π‘’π‘žπ‘’π‘Žπ‘™ .

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Write the equation of the line through (2, -1) and has slope m = 3. Write the equation in general form (standard form).

(2 ,βˆ’1 )π‘₯1 , 𝑦1

π‘¦βˆ’ 𝑦1=π‘š (π‘₯βˆ’π‘₯1 )

π‘¦βˆ’ (βˆ’1 )=3(π‘₯βˆ’2)

π‘š=3

𝑦+1=3 π‘₯βˆ’6βˆ’3 π‘₯+𝑦=βˆ’7

Standard form

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What is the distance between A(2, -5) and B(6, 3)? (Round to the nearest tenth).

𝐴 (2 ,βˆ’5 )𝐡 (6 ,3)π‘₯1 𝑦1π‘₯2 𝑦2

𝐷=βˆšπ‘Ÿπ‘–π‘ π‘’2+π‘Ÿπ‘’π‘›2

𝐷=√ ( 𝑦2βˆ’ 𝑦1 )2+ (π‘₯2βˆ’π‘₯1)2

𝐷=√ (3+5 )2+(6βˆ’2 )2

𝐷=√ (8 )2+ (4 )2

𝐷=√64+16𝐷=√80𝐷=4√5

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Graph:

𝑦=βˆ’π‘₯2+4𝑦=βˆ’(π‘₯2βˆ’4)𝑦=βˆ’ (π‘₯+2 ) (π‘₯βˆ’2 )π‘Ÿπ‘œπ‘œπ‘‘π‘  : 𝐴 (βˆ’2 ,0 ) ,𝐡 (2 ,0 )

π‘Žπ‘₯π‘–π‘ π‘œπ‘“ π‘ π‘¦π‘šπ‘šπ‘’π‘‘π‘Ÿπ‘¦ :π‘₯=βˆ’ 𝑏2π‘Ž

π‘₯=βˆ’ 02 (βˆ’1 )

=0

π‘Ž=βˆ’1 ;𝑏=0 ;𝑐=4

𝑦=βˆ’02+4=4π‘€π‘Žπ‘₯=𝐢(0 ,4 )

𝐴𝐡

𝐢

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.

ΒΏπ‘Ž2+2π‘Ž+1+2π‘Ž+2+3

ΒΏπ‘Ž2+4π‘Ž+6

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What is the domain of ?

2 π‘₯+6=02 π‘₯=βˆ’6π‘₯=βˆ’3

The domain of f(x) is ALL real numbers except -3

π·π‘œπ‘šπ‘Žπ‘–π‘›=(βˆ’βˆž ,βˆ’3 )βˆͺ (βˆ’3 ,∞ )

hπ‘Š 𝑒𝑛𝑖𝑠 𝑓 (π‘₯ )𝑒𝑛𝑑𝑒𝑓𝑖𝑛𝑒𝑑?

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What is the domain of

π‘₯βˆ’7 β‰₯0π‘₯β‰₯7h𝑇 π‘’π‘‘π‘œπ‘šπ‘Žπ‘–π‘›π‘œπ‘“ 𝑓 (π‘₯ ) π΄π‘™π‘™π‘Ÿπ‘’π‘Žπ‘™ π‘π‘’π‘šπ‘π‘’π‘Ÿπ‘ β‰₯7

π‘‘π‘œπ‘šπ‘Žπ‘–π‘›=ΒΏ

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Composition of functions: Find

( 𝑓 βˆ™π‘”) (3 )= 𝑓 (3) βˆ™π‘”(3)ΒΏ [3 (3 )βˆ’2 ] βˆ™[32+1]

ΒΏ7 βˆ™10( 𝑓 βˆ™π‘” ) (3 )=70

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Composition of functions: Find .

𝑓 (𝑔 (3 ) )= 𝑓 (32+1)ΒΏ 𝑓 (10)ΒΏ3 (10 )βˆ’2

𝑓 (𝑔 (3 ))=28

𝑓 (𝑔 (3 ) )=( 𝑓 βˆ˜π‘”)(3)