JEE Main - 2018Paper - I
CHEMISTRYCODE- C
CHEMISTRY Analysis
Sl.No. UNIT NAME Q. Nos. Correct Wrong
1. ATOMIC STRUCTURE
2. PERIODIC TABLE
3. CHEMICAL BONDING 10,12,15
4. STATES OF MATTER
5. STOICHIOMETRY 23
6. THERMODYNAMICS 7
7. CHEMICALAND IONIC EQUILIBRIUM 1,5,6,28,26
8. HYDROGENAND ITS COMPOUNDS 17
9. ALKALI AND ALKALINE EARTH METALS
10. P-BLOCK ELEMENTS ( BORON, CARBON FAMILY) 11,3
11. PRACTICAL CHEMISTRY
12. ENVIRNMENTAL CHEMISTRY 20
13. ORGANIC CHEMISTRY 4
14. HYDRO CARBONS 22
15. SOLID STATE 14
16. SOLUTIONS
17. ELECTROCHEMISTRY & CHEMCIAL KINETICS 9,29
18. SURFACE CHEMISTRY
19. METALLURGY
20. OXYGEN FAMILY
21. NITROGEN FAMILY 8
22. HALOGEN FAMILY
23. D & F-BLOCK ELEMENTS, COORDINATION COMPOUNDS 30,21,16
24. POLYMERS
25. BIOMLECULES 18,19
26. CHEMISTRY IN EVERY DAY LIFE
27. ORGANIC COMPOUNDS CONTAINING C, H AND O
28. ORGANIC COMPOUNDS CONTAINING NITROGEN 4,27,24
29. INERT GASES 13
30. HALO ALKANES - ALKYL & ARYL HALIDES31. PURIFICATION AND ANALYSIS ORG COMPOUNDS 25
32. CHEMICAL KINETICS 2
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[CODE -C ]
1. Which of the following slats is the most basic in aqueous solution?
a) 3CH COOK b) 3FeCl c) ( )3 2Pb CH COO d) ( )3
Al CN
Sol : A
Salts of weak acid and strong base have basic aqueous solution
2. Which of the following compoundswill be suitable for Kjeldahl’s method for nitrogen estimation?
a) b)
c) d)
Sol: A
Nitrogen in organic compound should be linked to C & H. The method is not used in the case ofnitro, azo and azoxy compounds and to the compounds containing nitrogen in the ring (e.g. pyridinequinoline, isoquinoline, etc.). The method is extensively used for estimating nitrogen in food, fertilizersand agricultural products.
3. Which of the following are Lewis acids?
a) 3 3AlCl and SiCl b) 3 4PH and SiCl
c) 3 3BCl and AlCl d) 3 3PH and BCl
Sol: C
Group 13 element form electron deficient compounds and hence act as Lewis acids Both B and Al
have only 6 electronsin their valence shell in 3 3&BCl AlCl
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4. Phenol on treatment with 2CO in the presence of NaOH followed by acidification produces
compounds X as major product. X on treatment with ( )3 2CH CO O in the presence of catalytic
amount of 2 4H SO produces:
a) b)
c) d)
Sol: D
O
( ) 21 /CO NaOH
( ) 32 H O+
( )3 2CH Co O
2 4H SO
OH OHCOOH COOH
O C 3CH
Kolbes reaction
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5. An alkali is treated against an acid with methyl orange as indicator, which of the following is acorrect combination
Base Acid End Point
a) Strong Strong Pinkish red to yellow
b) Weak Strong Yellow to pinkish red
c) Strong Strong Pink to colourless
d) Weak Strong Colourless to pink
sol: B
Less than Hp 3.1it is red, greater than 4.4 yellow
6. An aqueous solution contains 0.01 2M H S and 0.02 M HCl . If the equilibrium constants forthe
formation of HS − from 2H S is 71.0 10−× and that of 2S − from HS − ions is 131.2 10−× then
the concentration of 2S − ions in aqueous solution is
a) 203 10−× b) 216 10−× c) 195 10−× d) 85 10−×Sol: A
72
2 13
2 202
10
1.2 10
2 1.2 10
H S H SH K
SH H S K
H S H S K
+ −
+ − −
+ − −
+ =
+ = ×
− − − − − − − − − − − − − − − − − − − − −
+ = ×
[ ]
2 2
2
H SK
H S
+ − =
[ ]2 2
200.2
1.2 100.1
S −−
× = [ ]H HCl+ = as HCl is a strong acid and dissociation of 2H S is
suppressed ( H + ion concentration will be mainly due to HCl a strong acid)
2 203 10S M− − = ×
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7. The combustion of benzene (I) gives 2CO (g) and ( )2H O I Given that heat of combustion of
benzene at constant volume is -3263.9 1kJ mol− at 025 C heat of combination of benzene at con
stant pressure will be ( )1 18.314R JK mol− −=
a) -452.46 b) 3260 c) -3267.6 d) 4152.6
Sol: C
( )6 6 2 2215/ 2 6 3 ; 3263.9gC H O CO H O U kJ+ → + ∆ = −
15 36
2 2n
−∆ = − =
3
3
33263.9 8.314 298 10
2
3263.9 3716.358 10
3263.9 3.716
3267.6
H U nRT
kJ
−
−
∆ = ∆ + ∆
= − + − × × × = − − ×= − −= −
8. The compound that does not produce nitrogen gas by the thermal decomposition is
a) ( )4 2 72NH Cr O b) 4 2NH NO c) ( )4 42
NH SO d) ( )3 2Ba N
Sol: C
( )4 4 4 4 32NH SO NH HSO NH∆→ +
9. How long (approximate) should water be electrolysed by passing through 100amperes current sothat the oxygen released can completely burn 27.66g of diborane? (Atomic weight of B=10.8u)
a) 0.8hours b) 3.2 hours c) 1.6 hours d) 6.4 hours
Sol: B
2 6 2 2 3 23 3B H O B O H O+ → +
27.6gm of 2 6B H requries 23 32gm O×
Ectw
F=
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8 1003 32
96500
t× ×× =
3 32 96500
8 100t
× ×=×
=11580sec
Time in hours =11580
3.213600
hours=
10. Total numbers of lone pair of electrons in 3I − ion is
a) 6 b) 9 c) 12 d) 3
Sol: B
: : : : : : :I I I I I I−
− + → − →
9 lone pairs
11. When metal ‘M’ is treated with NaOH a white gelatinous precipitate ‘X’ is obtained which is solublein excess of Na OH Compound ‘X’ when heated strongly gives an oxide which is used in chromatgraphyas an adsorbent. Then meatl ‘M’
a) Ca b) Al c) Fe d) Zn
Sol : B
( )2 242 2 2 2Al NaOH H O Na Al OH H + + → +
12. According to molecular orbital theory, which of the folloiwng will not be a viable molecule?
a) 2He+ b) 2H − c) 22H − d) 2
2He +
Sol: C
22H − will have configaration
*2 21 1S S
Bond order =2 2
02
− =
Hence 22H − is not formed
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13. The increasing order of basicity of the following compounds is
a. b.
c. d.
a) b < a < c < d b) b < a < d < c c) d < b < a < c d) a < b < c < d
Sol : A
14. Which type of ‘defect’ has the presence of cation in the interstitial sites?
a) Vacancy defect b) Frenkel defecct
c) Metal deficiency defect d) Schottky defect
Sol : B
15. Which of the following compounds contain(s) no covalent bond(s)?
3 2 2 6 2 4, ,KCI PH O B H H SO
a) 2 4,KCI H SO b) KCI c) 2 6,KCI B H d) 2 6 3, ,KCI B H PH
Sol: B
Since it is an ionic compound.
16. The oxidation state of Cr in ( ) ( )2 3 6 66 2[ ] ,Cr H O Cl Cr C H and
( ) ( ) ( ) ( )2 22 2 3K Cr CN O O NH respectively are
a) +3 ,+2, and +4 b) +3,0 and +6 c) +3,0 and +4 d) +3,+4 and +6
Sol: C
( ) ( )2 6 3 6 0 1 3 0
3
Cr H O Cl x
x
+ × + − × = = +
( )6 6 2Cr C H
Benzene is a neutral molecule hence oxidiation State of Cr =0
( ) ( ) ( ) ( )2 2 32 2k Cr CN O O NH
4X = +
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17. Hydrogen peroxide oxidises ( ) 4
6Fe CN
− to ( ) 3
6Fe CN
− in acidic medium but reduces
( ) 3
6Fe CN
− to ( ) 4
6Fe CN
− in alkaline medium. The other products formed are respectively
a) ( ) ( )2 2 2H O O and H O OH −+ + b) ( )2 2 2H O and H O O+
c) ( )2 2H O and H O OH −+ d) ( )2 2 2H O O and H O+
Sol : B
( ) ( )4 3
2 2 26 6
HFe CN H O Fe CN H O+− −
+ → +
( ) ( )3 4
2 2 2 26 6
OHFe CN H O Fe CN H O O+− −
+ → + +
18. Glucose on prolonged heating with HI gives:
a) 1-Hexene b) Hexanoic acid c) 6-iodhexanal d) n-Hexane
Sol; D
cos HIGlu e n hexane∆→ − , complete reduction takes place
19. The predominant from of histamine present in human blood is ( ), 6.0apK Histidine =
a) b)
c) d)
Sol : C
Since aPk is 6.0, it is weakly acidic in nature exist as cation
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20. The recommended concentration of fluoride ion in drinking water is upto 1ppm as fluoride ion is
requried to make teeth enamel harder by converting ( ) ( )4 2 23 .Ca PO Ca OH to
a) ( ) ( )2 23 .CaF Ca OH b) ( )4 22
3 .Ca PO CaF
c) ( ){ }223 .Ca OH CaF d) [ ]2CaF
Sol: B
It converts to fluorapatite ( )( )4 223 Ca PO CaF
21. Consider the following reaction and statments:
( ) ( )3 2 3 3 34 3Co NH Br Br Co NH Br NH
+ − + → + I) Two isomers are produced if the rectant complex ion is a cis iosmer
II) Two isomers are produced if the rectant complex ion is a trans- isomer
III) Only one iosmer is produced if the rectant complex ion is a trans-isomer
IV) Only one isomer is produced if the rectant complex ion is a cis-isomer
The correct statments are :
a) I and III b) III and IV c) II and IV d) I and II
Sol: A
3NH 3NH 3NHBr BrBr Br3H N 3H N
Br Br Br
CO
CO CO
CO CO
3NH 3NH3NH
3NH 3NH3NH
3NH 3NH 3NH
3NH 3NHBr−
Br−
Meridonial
Br
Facial
Br Br
Br BrBr
3H N
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22. The trans alkenes are formed by the reduction of alkynes with
a) 4NaBH b) 3/ .Na liq NH
c) Sn HCl− d) 2 4/ ,H Pb C BaSO
Sol : B
Birch Reduction
23. The ratio of mass percent of C and H of an organic compound ( )X Y ZC H O is 6 : 1 If one mol
ecule of the above compound ( )X Y ZC H O contains half as much oxygen as requried to burn one
molecule of compound X YC H completely to 2CO and 2H O The empirical formula of compounds
X Y ZC H O is :
a) 2 4C H O b) 3 4 2C H O c) 2 4 3C H O d) 3 6 3C H O
Sol : C
12100 %
4100 %
xof c
M
of HM
× =
× =
% 6
% 112
100 6
1100
C
Hx
My
M
=
×=
×
2Y x=
2Y x= confirm with options 1,3, and 4 but based on no.of oxygen atom present as
2 4 2 2 23 2 2C H O CO H O+ → +
2 4 3 2 2 2
32 2
2C H O O CO H O+ → +
No of oxygen atom is X Y ZC H O is half the oxygen atoms consumed in combination of X YC H
corresponds to 2 4 3C H O
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24. Phenol reacts with methyl chlorformate in the presence of NaOH to form product A. A reacts with
2Br to form product B. A and B are respectively
a)
b)
c)
d)
Sol: B
O HΘ
→ 3- -||
Cl C OCH
O
→
OH OΘ
Br
3
||O
O C CH− −3
||O
O C O CH− − −
2Br
ortho,para directing grow
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25. The major product of the following reaction is
a) b)
c) d)
Sol: C
Here 2E mechanism for elimination of HX takes place
26. Which of the following lines correctly show the temperature dependence of equilibrium constant, K,for an exothermic reaction
a) B and C b) C and D c) A and D d) A and B
Sol: D
0
0 0 0
ln
G RTmk
GK
RT
G H T S
∆ = −∆= −
∆ = ∆ − ∆
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0 0
lnH T S
KRT
∆ − ∆= −
As reaction is exothermic H Ve∆ = −
0 0H I SlmK
R T R
∆ ∆ = +
y mx c= +
The graph is a straight line with +ve slope
Hence graph A
0
0
H ve
S ve
∆ =−∆ =+
Hence graph B
0
0
H ve
S ve
∆ = −∆ = −
27. The major product formed in the following reaction is:
a) b)
c) d)
0
0
H ve
S ve
∆ = −∆ = +
0
0
H ve
S ve
∆ = −∆ = −
1/T
A
Bln k
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Sol : C
O
O
HI
Heat
3|H
O CH⊕
−
O
I
OH
3 3 2CH OH CH CH I+ +
I −
I −
28. An aqueous solution contains an unknown concentration of 2Ba + .When 50mL of a 1M solution of
2 4Na SO is added, 4BaSO just beigns to precipitate The final volume is 500mL The solubility
product of 4BaSO is 101 10−× What is the original concentration of 2Ba +
a) 92 10 M−× b) 91.1 10 M−× c) 101.0 10 M−× d) 95 10 M−×Sol: B
24 1 1No moles of SO M V− = in 50ml
24 500mn of SO in ml−
22 14
5 101000 10
500M of SO
−− −×= × =
2810 500
BaM in ml solution+
−=
2 2450 500m mn Ba in ml n Ba in ml+ +=
1 21 2
11
1000 1000450 500
101000 1000
V VM M
M −
× = ×
× = ×
91 1.1 10M M−= ×
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29. At 0518 C the rate of decomposition of a sample of gaseous acetaldehyde, initially at a pressure of
363 Torr, was 1.00Torr 1s− when5% had reacted and 0.5Torr 1s− when 33% had reacted The order
of the reaction is
a) 3 b) 1 c) 0 d) 2
Sol: D
1 1xR KP=
11
51.00
100
xp
K P× = × −
1
95
100
x
k p = ×
2 2xR KP=
67 3630.5
100
x
k× = ×
1 1
2 2
95 3631 100
0.5 67 363100
x
x
x
R P
R P
× = = =
×
( )952 1.41
67
xx = =
1
22 2 2x
x
= = =
30. For 1 molal aqueous solution of the following compounds, whihc one will shoe the highest freezingpoint?
a) ( )2 2 25Co H O Cl Cl H O b) ( )2 2 24
.Co H O Cl Cl H O
c) ( )2 3 233Co H O Cl H O d) ( )2 36
Co H O Cl Colligative property
Sol: C
1f f
f
T ik m
T i
∆ =
∆
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For ( )2 2 25[ ]Cl .Co H O Cl H O i=3
( )2 2 24[ ]Cl.Co H O Cl H O i=2
( )2 2 24[ ]3Co H O Cl H O i=1
( )2 36[ ]ClCo H O i=4
Greater the i value
Greater the fT∆ value
Hence lower the fT
Hence fT∆ = d > a > b > c
Hence fT = c > b > a > d
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