VLSM (Subnetting Classfull)

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    Notacin CIDR CIDR = Classless InterDomain Routing

    IP: 10 .0.5.8MS: 255.0.0.0 (Predeterminada)

    ------------------------------- /8

    Clase AIP CIDR 10.0.5.8 /8

    IP: 172 .16.8.5MS: 255.255.255.0 (Personalizada)

    --------------------------------- /24

    Clase Sin ClaseIP CIDR 172.16.8.5 /24

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    IP: 172 .16.240.78MS: 255.255.255.248 (Personalizada)

    ------------------------------------- /29

    Clase Sin ClaseIP CIDR 172.16.240.78 /29

    IP: 192 .168.20.7MS: 255.255.255.0 (Predeterminada)

    ------------------------------------- /24

    Clase CIP CIDR 192.168.20.7 /24

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    Subnetting:

    Mtodo para poder dividir una red principal desde una perspectiva lgica

    Puede ser de 2 tipos:

    Subnetting Classfull Divisin lgica igual para todas las subredes

    Subnetting Classless Divisin lgica diferente en cada subred segn sea necesari

    Entonces para esto se requiere manejar un nuevo concepto: VLSM

    VLSM Variable Length Subnetting

    Mscara de Subred de Longitud Variable

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    Mask

    (Mscara de Subred Personalizada)

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    Requerimiento: Crear 6 subredes

    Existen 2 mtodos:

    1) Mtodo Tradicional (m < 5)

    Paso 1: Determinar el N de bits necesarios para crear las 6 subredes (m)

    6 (base 10) --------> m (base 2) 128 64 32 160 0 0 0

    Paso 2: Calcular la Nueva Mscara de Subred (VLSM)

    M. Subred Predeterminada /16 255.255.0.0

    M. Subred Personalizada: 255 255 0

    128 64 32 160 0 0 0

    1 1 1

    128 64 32 224

    M. Subred Personalizada: 255 255 224

    Paso 3: Determinar las Subredes requeridas (6 ID's Subred)

    Id Red Principal 172.16.0.0 Clase "B"

    6 Subredes: 172 16 0 0

    128 64 32 16 80 0 0 0 0

    Tabla de Verdad 0 0 0 = 0

    0 0 1 = 32

    N Combinaciones 0 1 0 = 64

    Red Principal "B" : 172.16.0.0 /16

    m = 3

    m = 3

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    2 ^ m 0 1 1 = 96

    2 ^ 3 = 8 1 0 0 = 128

    1 0 1 = 160

    1 1 0 = 192

    1 1 1 = 224

    Paso 4: N Hosts Totales x Subred (n)

    172 16 0 0(8) (8) = 16 bits disponibl

    128 64 32 16 8 40 0 0 0 0 0

    n = 16 - m 16 - 3 =

    N Host Totales x Subred = 2 ^ n = 2 ^ 13

    N Hosts Disponibles x Subred = (2 ^ n) - 2 =

    Paso 5: IP's Validas x SubredPrimer Host Ultimo Host

    S1 172.16.32.0 172.16.32. 1 ~ 172.16.63. 254

    S2 172.16.64.0 172.16.64. 1 ~ 172.16.95. 254

    S3 172.16.96.0 172.16.96. 1 ~ 172.16.127. 254

    S4 172.16.128.0 172.16.128. 1 ~ 172.16.159. 254

    S5 172.16.160.0 172.16.160. 1 ~ 172.16.191. 254S6 172.16.192.0 172.16.192. 1 ~ 172.16.223. 254

    2) Mtodo Rpido / gil (m >= 5)

    2Ultima IP es broadcast (no es 255)

    Primera IP no puede ser cero

    m = 3 (5 bits)

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    Id Red Principal 172.16.0.0 Clase "B"

    6 Subredes: 172 16 0

    128 64 32 16

    0 0 0 0

    FI: Factor de Incremento: 32FI

    S1 172.16. 0.0 + 32 172.16.32.0S2 172.16. 32 .0 + 32 172.16.64.0S3 172.16. 64 .0 + 32 172.16.96.0S4 172.16. 96 .0 + 32 172.16.128.0S5 172.16. 128 .0 + 32 172.16.160.0S6 172.16. 32 .0 + 32 172.16.192.0

    m = 3

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    8 4 2 10 1 1 0

    0 (base 10)

    8 4 2 10 0 0 0

    0 CIDR:/19

    4 2 10 0 0

    S1S2 S1 172.16.32.0S3 S2 172.16.64.0

    m = 3

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    S4 S3 172.16.96.0S5 S4 172.16.128.0S6 S5 172.16.160.0S7 S6 172.16.192.0S8

    es

    2 10 0

    13

    = 8192 hosts

    (2 13) - 2 = 8190 hosts

    8190 Hosts

    8190 Hosts

    8190 Hosts

    8190 Hosts

    8190 Hosts

    8190 Hosts

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    0

    8 4 2 1

    0 0 0 0

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    Requerimiento: Enrutamiento RIP v2

    Clase "B": 172.16. 0.0 (Id Red) Cul es el valor de "n"?

    255.255.0.0 (Mascara Subred) Entonces n = 16

    Cuntos hosts vlidos puede tener la red especificada?

    (2 ^ n) - 2 = (2 ^ 16) - 2 = 65,534 hosts

    Paso 1: Calcular el valor de "n" necesario para tener 8,000 hosts

    (2 n) - 2 >= 8,000

    2 ^ n >= 8,002

    n ~ 13

    Entonces:

    Paso 2: Calcular el nuevo valor de la mscara de subred

    M. Subred Predeterminada /16 255.255. 0.0

    M. Subred Personalizada: 255 255

    128 64 320 0 0

    1 1 1128 64 32

    M. Subred Personalizada: 255 255

    Paso 3: Calcular las Subredes respectivas (1 Subnetting) para 8,000 hosts

    Id Red Principal 172.16.0.0 Clase "B"

    Red Principal "B" : 172.16.0.

    m = 16 bits - 13 bits (n)

    m = 3

    m = 3

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    N Subredes Totales = 2 ^ m =

    N Subredes Disponibles = (2 ^ m) - 2 =

    6 Subredes: 172 16

    128 64 320 0 0

    FI: Factor de Incremento: 32FI

    S1 172.16.0.0 + 32

    S2 172.16.32.0 + 32

    S3 172.16.64.0 + 32S4 172.16.96.0 + 32

    S5 172.16.128.0 + 32

    S6 172.16.160.0 + 32

    N hosts vlidos x subred: (2 ^ n) - 2

    IP's Validas x Subred:

    S1 172.16.32.0 /19

    Paso 4: Calcular las Subredes respectivas (2 Subnetting) para 4,000 hosts

    Subred elegida: 172.16.64.0 /19

    Subred: 172.16.64 .0 (Id Subred) Cul es el valor de "n"?255.255.224.0 (Mascara Subred) Entonces n = 13

    Cuntos hosts vlidos puede tener la subred especificada?

    (2 ^ n) - 2 = (2 ^ 13) - 2 = 8,190 hosts

    Subred elegida:

    m = 3

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    Paso 4a: Calcular el valor de "n" necesario para tener 4,000 hosts

    (2 n) - 2 >= 4,000

    2 ^ n >= 4,002

    n ~ 12

    Entonces:

    Paso 4b: Calcular el nuevo valor de la mscara de subred

    M. Subred Personalizada /19 255.255. 224 .0

    M. Subred Personalizada: 255 255

    128 64 321 1 1

    1 1 1128 64 32

    M. Subred Personalizada: 255 255

    Paso 4c: Calcular las Subredes respectivas del 2 Subnetting para 4,000 hosts

    Id Subred 172.16.64.0

    N Subredes Totales = 2 ^ m =

    2 Subredes: 172 16

    128 64 320 1 0

    m = 13 bits - 12 bits (n)

    m = 1

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    FI: Factor de Incremento: 16FI

    S1 172.16.64.0 + 0

    S2 172.16.64.0 + 16

    N hosts vlidos x subred: (2 ^ n) - 2 =

    IP's Validas x Subred:Primer Host

    S1 172.16.64.0 /20 172.16.64. 1

    Paso 5: Calcular las Subredes respectivas (3 Subnetting) para 2,000 hosts

    Subred elegida: 172.16.80.0 /20

    Subred: 172.16.80 .0 (Id Subred) Cul es el valor de "n"?255.255.240.0 (Mascara Subred) Entonces n = 12

    Cuntos hosts vlidos puede tener la subred especificada?

    (2 ^ n) - 2 = (2 ^ 12) - 2 = 4,094 hosts

    Paso 5a: Calcular el valor de "n" necesario para tener 2,000 hosts

    (2 ^ n) - 2 >= 2,000

    2 ^ n >= 2,002

    n ~ 11

    Entonces:

    Paso 5b: Calcular el nuevo valor de la mscara de subred

    M. Subred Personalizada /20 255.255. 240 .0

    Subred elegida:

    m = 12 bits - 11 bits (n)

    m = 1

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    M. Subred Personalizada: 255 255

    128 64 321 1 1

    1 1 1128 64 32

    M. Subred Personalizada: 255 255

    Paso 5c: Calcular las Subredes respectivas del 3 Subnetting para 2,000 hosts

    Id Subred 172.16.80.0

    N Subredes Totales = 2 ^ m =

    2 Subredes: 172 16

    128 64 320 1 0

    FI: Factor de Incremento: 8FI

    S1 172.16.80.0 + 0

    S2 172.16.80.0 + 8

    N hosts vlidos x subred: (2 ^ n) - 2 =

    IP's Validas x Subred:Primer Host

    S1 172.16.80.0 /21 172.16.80. 1

    Subred elegida:

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    Paso 6: Calcular las Subredes respectivas (4 Subnetting) para 2 hosts

    Subred: 172.16.88.0 /21

    Subred: 172.16.88 .0 (Id Subred) Cul es el valor de "n"?255.255.248.0 (Mascara Subred) Entonces n = 11

    Cuntos hosts vlidos puede tener la subred especificada?

    (2 ^ n) - 2 = (2 ^ 11) - 2 = 2,046 hosts

    Paso 6a: Calcular el valor de "n" necesario para tener 2 hosts

    (2 n) - 2 >= 2

    2 ^ n >= 4

    n ~ 2

    Entonces:

    Paso 6b: Calcular el nuevo valor de la mscara de subred

    M. Subred Personalizada /21 255.255.248.0

    M. Subred Personalizada: 255 255

    128 64 321 1 1

    1 1 1128 64 32

    M. Subred Personalizada: 255 255

    Paso 6c: Calcular las Subredes respectivas del 4 Subnetting para 2 hosts

    Id Subred 172.16.88.0

    m = 11 bits - 2 bits (n)

    m = 9 bits

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    N Subredes Totales = 2 ^ m =

    N Subredes Disponibles = (2 ^ m) - 2 =

    510 Subredes: 172 16

    128 64 32 160 1 0 1

    0 1 0 1128 64 32 16

    Factor de Incremento: 4 (Cuarto Octeto)

    S1 172.16.88.0S2 172.16.88.0S3 172.16.88.4S4 172.16.88.8S5 172.16.88.12

    S512

    N hosts vlidos x subred: (2 ^ n) - 2

    IP's Validas x Subred:

    S1 172.16.88.4 /30

    S2 172.16.88.8 /30

    S3 172.16.88.12 /30

    Sub

    ( Tercer

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    (n = N bits del Id Host)

    0 0 (base 10)

    16 8 4 2 10 0 0 0 0

    224

    224 0 CIDR:/19

    /16

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    2 ^ 3 = 8 subredes

    (2 ^ 3) - 2 = 6 subredes

    0 0

    16 8 4 2 10 0 0 0 0

    172.16.32.0

    172.16.64.0

    172.16.96.0172.16.128.0

    172.16.160.0

    172.16.192.0

    172.16.32.0

    = (2 ^ 13) - 2 = 8,190 hosts

    Primer Host Ultimo Host

    172.16.32. 1 ~ 172.16.63. 254 8190 Hosts

    (n = N bits del Id Host)

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    224 0 (base 10)

    16 8 4 2 10 0 0 0 0

    m = 11

    16 240

    240 0 CIDR:/20

    2 ^ 1 = 2 subredes

    64 0

    16 8 4 2 10 0 0 0 01

    m = 1

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    172.16.64.0 /20

    /20

    172.16.64.0 /20

    (2 12) - 2 = 4,094 hosts

    Ultimo Host

    ~ 172.16.79. 254 4094 Hosts

    (n = N bits del Id Host)

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    240 0 (base 10)

    16 8 4 2 11 0 0 0 0

    m = 1

    1 116 8 248

    248 0 CIDR:/21

    2 ^ 1 = 2 subredes

    80 0

    16 8 4 2 11 0 0 0 0

    1m = 1

    172.16.80.0 /21

    172.16.88.0 /21

    172.16.80.0 /21

    (2 11) - 2 = 2,046 hosts

    Ultimo Host

    ~ 172.16.87. 254 2046 Hosts

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    (n = N bits del Id Host)

    248 0 (base 10)

    16 8 4 2 1 128 641 1 0 0 0 0 0

    1 1 1 1 1 255 1 116 8 4 2 1 128 64

    255 252 CIDR:/30

    ( Tercer Octeto)

    m = 9

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    2 ^ 9 = 512 subredes

    (2 9) - 2 = 510 subredes

    88 0

    8 4 2 1 128 64 321 0 0 0 0 0 0

    1 0 0 0 0 0 08 4 2 1 128 64 32

    FI

    + 0 172.16.88.0 /30

    + 4 172.16.88.4 /30

    + 4 172.16.88.8 /30

    + 4 172.16.88.12 /30

    + 4 172.16.88.16 /30

    + 4 /30

    172.16.88.4 /30172.16.88.8 /30172.16.88.12 /30

    = (2 ^ 2) - 2 = 2 hosts

    Primer Host Ultimo Host

    172.16.88. 5 ~ 172.16.88. 6 2 Hosts

    172.16.88. 9 ~ 172.16.88. 10 2 Hosts

    172.16.88. 13 ~ 172.16.88. 14 2 Hosts

    edes elegidas:

    Octeto)

    m = 9

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    32 16 8 4 2 10 0 0 0 0 0

    1 1 1 1 25232 16 8 4

    ( Cuarto Octeto)

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    16 8 4 2 10 0 0 0 0

    0 0 016 8 4

    ( Cuarto Octeto)