UCSD NANO106 - 07 - Material properties and tensors
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Transcript of UCSD NANO106 - 07 - Material properties and tensors
Properties of Materials and TensorsShyue Ping OngDepartment of NanoEngineeringUniversity of California, San Diego
Readings¡Chapter 1 of Properties of Materials
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
2
Einstein notation¡ Summation implied over repeated
indices
¡ Examples
¡ Refer to handout 8 for more details.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
xiyi = xiyii=1
3
∑ = x1y1 + x2y2 + x3y3
Dot product: x ⋅ y = xiyiMatrix product: y = Axyi = aij x j
“I have made a great discovery in mathematics;
I have suppressed the summation sign every
time that the summation must be made over an
index which occurs twice...”
3
Material properties¡A physical property is a relationship between two
measured quantities.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
Equilibriumproperties
Transportproperties
Hystereticproperties
Irreversiblebreakdownproperties
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Heckman Diagram
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
Electrical properties
Thermal properties
Mechanical properties
Tensors are the mathematics of choice to represent properties.
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Tensors¡Tensors are geometric objects that describe linear
relations between vectors, scalars, and other tensors.
¡Can be thought of as multi-dimensional arrays. The rank of a tensor is the number of independent indices:¡ Rank 0: Scalar¡ Rank 1: Vector¡ Rank >= 2: Tensors
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Examples of Tensors
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
Q =CΔTRank Property Equation
0 Heat capacity
1 Pyroelectricity
2 Electrical conductivity
3 Piezoelectricity
4 Elasticity and compliance
Q =CΔT
ΔPi = piΔT
ji =σ ikEk
Pi = dijkσ jk
σ ij = cijklεklHow many components are there for each rank?
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Transformation of Orthogonal Axes¡ In the first part of the course, we went through the
transformation of basis vectors / reference frames. This is a similar, but simpler concept.
¡ Material properties are typically measured in Cartesian axes. For example, you typically measure the current and electric field in a set of orthogonal axes and the conductivity tensor relates the current in a direction to the components of the electric field in each direction.
¡ To understand the effect of symmetry on properties, we need to know how tensors transform under various operations, e.g., rotation, reflection, inversion, etc.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
ji =σ ikEkTypically, indices refer to Cartesian directions
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Notation¡We will use Z1, Z2, and Z3 to refer to the x, y and z
Cartesian axes. Transformed axes are denoted with as Zi’.
¡As per standard notation, the cartesian basis vectors are denoted as ex, ey, ez or e1, e2, e3, the latter is used with the more compact Einstein summation notation.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Direction cosine¡ The direction cosines of a
vector are the cosines of the angles between the vector and the three coordinate axes.
¡ Component contributions of the basis to the unit vector.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
vv= cosa ⋅ ex + cosb ⋅ ey + cosc ⋅ ez
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Direction cosine tensor¡ Consider the transformation of a set of
orthogonal axes Z1, Z2, and Z3 to another set of orthogonal axes Z1’, Z2’, and Z3’.
¡ The relationship between the new basis vectors and old basis vectors are given by:
¡ where aij is the direction cosine between ei’and ej.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
e1!
e2!
e3!
"
#
$$$$$
%
&
'''''
=
a11 a12 a13
a21 a22 a23
a31 a32 a33
"
#
$$$$
%
&
''''
e1
e2
e3
"
#
$$$$
%
&
'''' or simply ei! = aijej
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Properties of the direction cosine tensor¡ Orthogonal¡ Norm of each row and column must = 1, e.g.,
¡ Rows and columns are mutually perpendicular, e.g.,
¡ More compactly, in Einstein notation,
¡ Inverse is simply the transpose. Hence,
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
a112 + a12
2 + a132 =1 and a11
2 + a212 + a31
2 =1
a11a21 + a12a22 + a13a23 = 0 and a11a12 + a21a22 + a31a32 = 0
aikajk = δik = akiakj
e1
e2
e3
!
"
####
$
%
&&&& =
a11 a21 a31
a12 a22 a32
a13 a23 a33
!
"
####
$
%
&&&&
e1'
e2'
e3'
!
"
#####
$
%
&&&&&
or simply ei ='= ajiej'
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Quick Review of Point Symmetry Operations¡ Rotation
¡ Reflection/Mirror
¡ Inversion
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
e1!
e2!
e3!
"
#
$$$$$
%
&
'''''
=cosθ sinθ 0−sinθ cosθ 00 0 1
"
#
$$$
%
&
'''
e1e2e3
"
#
$$$$
%
&
''''
e1!
e2!
e3!
"
#
$$$$$
%
&
'''''
=1 0 00 1 00 0 −1
"
#
$$$
%
&
'''
e1e2e3
"
#
$$$$
%
&
''''
e1!
e2!
e3!
"
#
$$$$$
%
&
'''''
=−1 0 00 −1 00 0 −1
"
#
$$$
%
&
'''
e1e2e3
"
#
$$$$
%
&
''''
Anti-clockwise rotation about z-axis
Reflection about xy-plane
e1!
e2!
e3!
"
#
$$$$$
%
&
'''''
=cosθ −sinθ 0sinθ cosθ 00 0 1
"
#
$$$
%
&
'''
e1e2e3
"
#
$$$$
%
&
''''
Clockwise rotation about z-axis
Note that this is opposite from the definition for rotation matrices for points / vectors!
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Standard settings¡ Crystallographic axes and cartesian property measurement
axes do not always coincide.
¡ IEEE standard settings¡ Triclinic: Z3 is chosen parallel to c, and Z2 is normal to the ac plane
(010). Z1 lies in the (010) plane and is perpendicular to Z2 and Z3.¡ Monoclinic: Z2 is chosen parallel to the b [010] axis with twofold
symmetry and perpendicular to mirror plane. Z3 is chosen along c, and Z1 is perpendicular to Z2 and Z3.
¡ Orthorhombic: Select unit cell in which c < a < b. Z1, Z2, and Z3 are chosen as a, b, and c, respectively.
¡ Trigonal and Hexagonal: Z3 is along the c-axis [001] with three-fold / six-fold symmetry. Z1 axis is parallel to a-axis [100], a crystallographic direction, with Z2 completing the right-handed orthogonal set.
¡ Tetragonal: Z3 is parallel to c-axis with four-fold symmetry. Z1 and Z2are parallel to a and b, respectively.
¡ Cubic: Z1, Z2, and Z3 parallel to a, b, and c, respectively.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Curie Symmetry Principle¡Thus far, we have dealt only with symmetry of the
crystal.
¡When dealing with properties, we need to consider both the symmetry of the crystal, as well as the symmetry of the “cause”.
¡Examples:¡ Most materials are polycrystalline, and the processing of
these materials create anisotropy in properties.¡ The externally applied “force”, e.g., an electric field, has a
different symmetry from the underlying symmetry of the crystal.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Curie Symmetry Principle¡ The Curie symmetry principle is the causality relation between the
symmetry of the cause and that of the effect. The principle is composed of three parts:¡ If certain causes yield the known effects, the symmetry elements of the
causes should be contained in the generated effects.¡ If the known effects manifest certain dissymmetry (absence of symmetry
elements), this latter should be contained in the causes which have generated those effects.
¡ The converse to these two previous propositions is not true, at least in practical: i.e., the effects may have higher symmetry than the causes which generate these effects.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
!K = K∩G
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Curie symmetries
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Example of application of the Curie Symmetry Principle¡ Consider crystal with space group . It has a fourfold inversion axis (which
contains in itself also a two-fold rotation axis), and two two-fold rotation axes. The symmetry of the electric field is , which has an infinite-fold rotation axis containing every possible rotation axes of lower symmetry, and an infinite number of intersecting mirror planes.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
42m
∞m
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Curie symmetries of processed materials
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
Material Curie Symmetry
Polycrystalline metals / ceramics with randomly oriented grainsOrganic left- or right-handed crystallitesUniaxially hot-pressed polycrystallinematerialsUniaxially hot-pressed left-or right-handedpolycrystallinematerials
∞∞m
∞∞
∞mm
∞2
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Transformation of Tensors
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Materials Properties as Tensors¡A material property is an expression of the response
of a material to the application of a generalized “force” by a generalized “displacement”.
¡Generalized “Forces”:¡ Stress¡ Temperature gradients¡ Electric fields
¡Generalized “Displacements”¡ Strain¡ Heat flow¡ Current density
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Example: Rank-2 tensor¡Consider the response displacement q to a force
p.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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p
qIn general, p ≠ q (not parallel)but we can make the assumption thatq ∝ pfor small forces and displacements (think of Taylor's series). If we denote rij as the response of component i of p to component j of q, then
q =r11 r12 r13
r21 r22 r23
r31 r32 r33
#
$
%%%%
&
'
((((p
or qi = rij pj
Recap: Transformation of Orthogonal Axes¡ Recall that in the previous lesson, we showed
that for a transformation of orthogonal axes, we have
¡ where aij is the direction cosine between ei’ and ej. Note the use of the orthogonality property of the direction cosine tensor, which allows us to use the transpose aji as the inverse transformation.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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ei! = aijej
ei = ajiej!
Transformation of a 2nd rank tensor
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Consider qi = rij pjWhen we switch to a new set of orthogonal axes (and hence basis vectors), the vectors q, p and the tensor r must transform to new values. Let's denote this as
qi! = rij!pj!
How can rij! be evaluated in terms of the original rij using the direction cosines?Let's see what happens to the components qi and pj first. Using the direction cosinematrix, we can write
qi! = aimqm = aimrmn pn = aimrmnajn pj!
Note the use of new dummy indices m and n to distinguish it from the i and jwe have used so far. It is absolutely important to keep proper track of the indices!!
Hence, rij! = aimajnrmn
Matrix form¡Now that we have gone through the exercise
using Einstein notation, can we do the same using matrices?
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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rij! = aimajnrmn is equivalent to !R = ARAT
Dummy indices
How do higher rank tensors transform?
¡For a second rank tensor,
¡Using the above as a template, we can deduce that an n-rank tensor with transform as
¡(capital letters are dummy indices)
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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rij! = aimajnrmn
rijklm… ' = aiIajJakKalLamM…rIJKLM…
Example: 4th rank tensor¡Consider the compliance tensor
¡ It transforms as
¡Each element has 5 x 81 terms. You have 81 elements. So a total of 5 x 81 x 81 = 32805 terms! (clearly the Einstein notation is a lot more compact…)
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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εij = sijklσ kl
sijkl ' = aiIajJakKalLsIJKL
Method of Direct Inspection¡Useful algorithm to deduce value of a transformed
tensor element.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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X1X2X3
Consider a point with coordinates X1X2X3
Let's consider how a product of this point XiX j will transform under an orthogonal axis transformation.
Xi!Xj! = aimXmajnXn = aimajnXmXn
Recall that the law of transformation of a 2nd rank tensor is
rij! = aimajnrmni.e., the transformation of a 2nd rank tensor is analogous tothe transformation of a product of coordinates! Note that retaining the order is *important*.
Application of Method of Direction Inspection
¡Consider a 4-fold rotation about the Z3 axis.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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X1
X2
X3
X1’
X2’X3’
Blackboard
Application of Method of Direction Inspection, contd.¡ Algorithm can be generalized to higher ranked tensors.
¡ Consider the same coordinate transformation, but let’s say we want to know the value of a 4th rank compliance tensor s1231 after the transformation
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Blackboard
Neumann’s Principle¡Neumann's principle, or principle of symmetry,
states that, if a crystal is invariant with respect to certain symmetry elements, any of its physical properties must also be invariant with respect to the same symmetry elements, or otherwise stated, the symmetry elements of any physical property of a crystal must include the symmetry elements of the point group of the crystal.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Demonstration of the power of applying Neumann’s principle
¡ Consider the transformation of any tensor under inversion symmetry. We have
¡ A general tensor will transform as
¡ We see that for odd-rank tensors,
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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X1! = −X1X2! = −X2X3! = −X3
By the method of direct inspection, we see that
Xi!Xj!Xk!…= (−1)n XiX jXk…
rijk… ' = (−1)n rijk…
rijk… ' = −rijk…
Demonstration of the power of applying Neumann’s principle¡ If a crystal has inversion symmetry, that means that the tensor
property measured under that symmetry must be invariant under inversion. Hence,
¡ For even-ranked tensors, we have
¡ For odd-ranked tensors, we have , which is true only if .
¡ Hence, all odd-ranked tensor properties disappear in all crystals with an inversioncenter, i.e., centrosymmetric point groups!
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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rijk… ' = (−1)n rijk… = rijk…
rijk… ' = rijk… = rijk…
rijk… ' = −rijk… = rijk…rijk… = 0
We have just derived a very general and broad rule about material properties just by considering a single
symmetry operation!
Effect of symmetry on rank 2 tensors¡ To make things more concrete, let’s consider the conductivity tensor
(though the results we derive are going to be applicable to all rank-2 tensors).
¡ Recall the definition of the conductivity tensor as
¡ From the previous analysis, we have seen that for even-ranked tensors, the inversion symmetry does not impose any restriction on the tensor elements.
¡ Let us now analyze what forms the conductivity tensor can take for the various crystal systems. Note that we are only going to analyze the restrictions imposed by symmetry arguments only. Thermodynamic arguments can impose further restrictions (e.g., many rank-2 tensors are “symmetric” in that aij = aji) that we shall not consider here.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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ji =σ ikEk
Rank-2 tensors in triclinic crystals¡ The triclinic crystal system essentially has no further
symmetry (except for perhaps inversion).
¡ This means that the conductivity tensor has the general form:
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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σ ij =
σ11 σ12 σ13σ 21 σ 22 σ 23
σ 31 σ 32 σ 33
!
"
####
$
%
&&&&
Rank-2 tensors in monoclinic crystals¡ For monoclinic crystals, we have a two-fold
[010] rotation axis.
¡ Assume that the two-fold axis corresponds to the X2 direction (as per standard settings), under the two-fold rotation operation, we have
¡ Let’s consider how each of the nine elements in the conductivity tensor will transform under the two-fold rotation.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Blackboard
Rank-2 tensors in monoclinic crystals, contd.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Blackboard
Rank-2 tensors in orthorhombic crystals
¡ In orthorhombic systems, we have 2-fold rotations as well as mirror planes. To save some effort, let us just use the tensor that we have already derived for monoclinic crystals (the same symmetry restrictions apply) and impose additional symmetry restrictions from the mirror plane. Let’s consider the mirror plane in the a-b plane:
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Blackboard
Rank-2 tensors in tetragonal, hexagonal and trigonal crystals ¡ In these crystals, we have a >2-fold
rotation rotation about the Z3 axis. Let’s analyze these in a general manner.
¡ Recall that the rotation direction cosine tensor is of the form:
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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aij =cosθ sinθ 0−sinθ cosθ 00 0 1
"
#
$$$
%
&
'''
Hence,
X1( = X1 cosθ + X2 sinθ
X2( = −X1 sinθ + X2 cosθ
X3( = X3
Rank-2 tensors in tetragonal, hexagonal and trigonal crystals
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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Blackboard
Rank-2 tensors in tetragonal, hexagonal and trigonal crystals
¡Final form of rank 2 tensor in these crystal systems
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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σ ij =
σ11 0 00 σ11 00 0 σ 33
!
"
####
$
%
&&&&
Rank 2 tensors in cubic systems¡ Start from the tetragonal crystal system, and consider what would
happen if we impose additional four-fold rotation symmetry in the other two directions. Now, the four-fold rotation in Z3 enforces that
¡ Logic dictates that four-fold rotation axes in Z1 and Z2 will enforce respectively. Hence,
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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σ ij =
σ11 0 00 σ11 00 0 σ11
!
"
####
$
%
&&&&
σ11 =σ 22, σ 33 non zero and all other elements 0.
σ 22 =σ 33, and σ11 =σ 33
Summary of rank 2 tensors for all crystal systems
¡ Note that rank 2 tensors take these forms only when the measurement axes are based on the crystal axes as per the analysis. In a general direction, a rank 2 tensor has 9 non-zero components (though considerably fewer independent components, as we shall see later)
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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σ ij =
σ11 σ12 σ13σ 21 σ 22 σ 23
σ 31 σ 32 σ 33
!
"
####
$
%
&&&&
Triclinic
σ ij =
σ11 0 σ130 σ 22 0σ 31 0 σ 33
!
"
####
$
%
&&&&
Monoclinic
σ ij =
σ11 0 00 σ 22 00 0 σ 33
!
"
####
$
%
&&&&
Orthorhombic
σ ij =
σ11 0 00 σ11 00 0 σ 33
!
"
####
$
%
&&&&
Tetragonal, Trigonal, Hexagonal Cubic
σ ij =
σ11 0 00 σ11 00 0 σ11
!
"
####
$
%
&&&&
Lecture Summary¡ In this lecture, we started a foray into the transformation of
tensors.
¡ We looked at Neumann’s Principle, and demonstrated how just based on this very simple concept and symmetry considerations, we can know a lot about the form of a material property tensor.
NANO 106 - Crystallography of Materials by Shyue Ping Ong - Lecture 7
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