Surface Area

bb

l

lArea of Triangles =

bl

2

14

Area of Base = 2bSA

bl

2

14 2b

Surface Area

Cone

.Area = r

Area = r 2

SA = r r 2

Surface Area

Sphere

SA = 4 2 r

2 2

14 SA

Surface AreaFind the surface area of each figure.

1.

5 m

8 m

5 8 5

80 + 25

= 105 m2

2

2

14 SA bbl

SA

Surface AreaFind the surface area of each figure.

2.

3 m

7 m

2 3.14 3.143 7 3

3.14 3.1421 9

65.94 + 28.26

94.2 m2

SA

2 SA rr

Surface AreaFind the surface area of each figure.

3. 3,963 mi.

2 4 3.14 3,963

12.56 15,705,369

197,259,434.6 mi2

SA 2 4 r SA

Pg 536 10 – 6 #1 – 6, 7 – 17 Find the surface area of each space figure, to the nearest

square unit.

30 cm

20 cm1. SA = r r 2

2 3.14 3.1410 30 10

3.14 3.14300 100

942 + 314

1256 cm2

SA

Pg 536 10 – 6 #1 – 6, 7 – 17 Find the surface area of each space figure, to the nearest

square unit.

2.

9 cm

2 4 3.14 9

SA 2 4 r SA

12.56 81

1,017 cm2

Pg 536 10 – 6 #1 – 6, 7 – 17 Find the surface area of each space figure, to the nearest

square unit.

3.5.5 m

4 m

2 2

14 SA

4 5.5 4

44 + 16

= 60 m2

2

2

14 SA bbl

SA

Pg 536 10 – 6 #1 – 6, 7 – 17 Find the surface area of each space figure, to the nearest

square unit.

4. The base of a cone has radius 3 ft. Its slant height is 8 ft. Find the surface area of the cone.

SA = r r 2

2 3.14 3.143 8 3

3.14 3.1424 9

75.36 + 28.26

104 ft2

SA

Pg 536 10 – 6 #1 – 6, 7 – 17 Find the surface area of each space figure, to the nearest

square unit.

5. The length of the base of a square pyramid is 5 cm. Its slant height is 8 cm. Find the surface area of the square pyramid.

2 2

14 SA

5 8 5

80 + 25

= 105 cm2

2

2

14 SA bbl

SA

Pg 536 10 – 6 #1 – 6, 7 – 17 6. Which has the greater surface area, a cylinder with

height 2 in. and radius of base 2 in., or a sphere with radius 2 in.? Justify your answer.

2 in

2 in2 in

SA = 2rh + 2r2

SA = 2( )( ) + 222 2 2

SA = + 8 8 = 16 in 2

2 4 2 SA 2 4 r

SA

16 in2

Pg 536 10 – 6 #1 – 6, 7 – 17