Study designs: Case-control studies

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3/2/2011 Case-control studies 1 Study designs: Case- control studies Victor J. Schoenbach, PhD home page Department of Epidemiology Gillings School of Global Public Health University of North Carolina at Chapel Hill www.unc.edu/epid600/ Principles of Epidemiology for Public Health (EPID600)

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Principles of Epidemiology for Public Health (EPID600). Study designs: Case-control studies. Victor J. Schoenbach, PhD home page Department of Epidemiology Gillings School of Global Public Health University of North Carolina at Chapel Hill www.unc.edu/epid600/. From my uncle. - PowerPoint PPT Presentation

Transcript of Study designs: Case-control studies

Page 1: Study designs:  Case-control studies

3/2/2011 Case-control studies 1

Study designs: Case-control studies

Victor J. Schoenbach, PhD home page

Department of EpidemiologyGillings School of Global Public Health

University of North Carolina at Chapel Hill

www.unc.edu/epid600/

Principles of Epidemiology for Public Health (EPID600)

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From my uncleAre you the weakest link?

Below are four (4) questions.

You have to answer them instantly.

You can't take your time, answer all of them immediately. OK?

Let's find out just how clever you really are.

Ready?

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Question 1

You are participating in a race.

You overtake the second person.

Question: What position are you in?

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Question 1 – answer

If you answer that you are first, then you are absolutely wrong!

Answer: If you overtake the second person and you take his place, you are second!

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On to question 2

Try not to screw up on the next question.

To answer the second question, don't take as much time as you took for the first question.

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Question 2

Question: If you overtake the last person, then you are …?

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Question 2 – answer

Answer: If you answered that you are second to last, then you are wrong again.

Tell me, how can you overtake the LAST person?! …?

You're not very good at this are you?

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On to question 3

The third question is very tricky math!

Note: This must be done in your head only.

Do NOT use paper and pencil or a calculator.

Try it.

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Question 3 – what is the total?

Take 1000 and add 40 to it.

Now add another 1000.

Now add 30.

Add another 1000.

Now add 20.

Now add another 1000.

Now add 10.

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Question 3 – answer

Did you get 5,000? The correct answer is actually 4,100.

Don't believe it? Check with your calculator!

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On to question 4

Today is definitely not your day.

Maybe you will get the last question right?

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Question 4

Mary's father has five daughters: 1. Nana, 2. Nene, 3. Nini, 4. Nono.

Question: What is the name of the fifth daughter?

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Question 4 – answer

Answer: Nunu? NO! Of course not. Her name is Mary. Read again.

(“Mary's father has five daughters.…”)

You ARE the WEAKEST LINK!!!!!! Good-bye!!!

(With Love, Your Uncle)

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Plan for this lecture

• Confidence intervals and significance tests (read only)

• Incidence density and cumulative incidence (brief)

• Attributable risk (brief)

• Theoretical overview of case-control studies as a complement to the traditional perspective

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Confidence intervals & significance tests

• Everything you’ve been told so far about confidence intervals and statistical significance is probably misleading, including this statement.

• I am not licensed to teach statistics, so what I say on this topic mustn’t leave this room!

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Confidence intervals

• “a plausible range of values for the unknown population parameter”

Michael Oakes, Statistical inference, p.52

• Exact interpretation is problematic

• We are more confident that a 95% interval covers the parameter than a 90% interval, but the 95% interval is wider (provides a less precise estimate)

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Significance tests

“It might be argued that the significance test, if properly understood, does no harm. This is, perhaps, fair comment, but anyone who appreciates the force of the case presented in this chapter will realize that equally, it does very little good.”

Michael Oakes, Statistical inference, p.72

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Incidence rate and incidence proportion

[incidence density and cumulative incidence]

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100% 0%

T0 Time T1

Population at risk

ID = - slope (relative to height)

IR (ID) and IP in a closed cohort

} CI

}1 – CI

T0 T1

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Attributable risk

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Attributable risk

Assume that we know a causal factor for a disease.

Conceptually, the “attributable risk” for that factor is:

1. difference in risk or incidence between exposed and unexposed people or

2. difference in risk or incidence between total population and unexposed people

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Attributable risk

Attributable risk can be presented as:

1. an “absolute” number, e.g., “80,000, or 20 per 100 cases/year of stroke are attributable to smoking”

2. a “relative” number, e.g., “20% of stroke cases are attributable to smoking”.

(analogy: a wage increase in a part-time job: $ increase, % increase in wage, % increase in income)

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For relative measures, think of % of cases

R1 R1 – R0 =

"Attributable

R0 R0 n0 R0 n1

risk"

n0 n1

People

Incidence rate or proportions

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For relative measures, think of % of cases

R1 R1 – R0 =

"Attributable

R0 R0 n0 R0 n1

risk"

n0 n1

Substitute population

Caseload

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For relative measures, think of % of cases

R1 R1 – R0 =

"Attributable

R0 R0 n0 R0 n1

risk"

n0 n1

Caseload

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Case-control studies

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Case-control studies• Traditional view: compare

- people who get the disease - people who do not get the disease

• “Controls” a misnomer, derived from faulty analogy to controls in experiment

• Modern conceptualization: controls are a “window” into the “study base”

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Case-control studies

Cases Controls

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Population at risk (N=200)

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O

Week 1

O

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O

Week 2

O

O

OO

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O

OO

Week 3

O

O

O

O

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Incidence rate(“incidence density”)

Number of new casesIR = –––––––––––––––––––

Population time

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Incidence rate(“incidence density”)

Number of new cases 7IR = ––––––––––––––––––– = ––––––

Population time ?

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Incidence rate(“incidence density”)

Population time at risk:

200 people for 3 weeks = 600 person-wks

But 2 people became cases in 1st week

3 people became cases in 2nd week

2 people became cases in 3rd week

Only 193 people at risk for 3 weeks

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Incidence rate(“incidence density”)

Assume that:

2 people who became cases in 1st week were at risk for 0.5 weeks each = 2 @ 0.5 = 1.0

3 people who became cases in 2nd week were at risk for 1.5 weeks each = 3 @ 1.5 = 4.5

2 people who became cases in 3rd week were at risk for 2.5 weeks each = 2 @ 2.5 = 5.0

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Incidence rate(“incidence density”)

Total population-time =

Cases occuring during week 1: 1.0 p-w

Cases occuring during week 2: 4.5 p-w

Cases occuring during week 3: 5.0 p-w

Non-cases: 193 x 3 = 579.0 p-w

589.5 p-w

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Incidence rate(“incidence density”)

7 IR = –––––– = 0.0119 cases / person-wk 589.5

average over 3 weeks

Number of new casesIR = –––––––––––––––––––

Population time

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Incidence proportion(“cumulative incidence”)

Number of new casesCI = –––––––––––––––––––

Population at risk

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Incidence proportion(“cumulative incidence”)

73-week CI = –––– = 0.035 200

Number of new casesCI = –––––––––––––––––––

Population at risk

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Can estimate incidence in people who are “exposed”

O

Week 1

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Can estimate incidence in people who are “exposed”

O

Week 2

OO

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Can estimate incidence in people who are “exposed”

O

Week 3

OO

O

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Can estimate incidence in people who are “unexposed”

O

Week 1

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Can estimate incidence in people who are “unexposed”

O

Week 2

O

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Can estimate incidence in people who are “unexposed”

O

Week 3

OO

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Entire population, week 1

O

O

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Entire population, week 2

O

OO

O

O

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Entire population, week 3

O

OO

OO

O

O

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Incidence rate(“incidence density”)

Number of new casesIR = –––––––––––––––––––

Population time

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Incidence ratein exposed during three weeks

4 4 IR = –––––––––––––– = –––– = 0.018 / wk 74.5 + 73 + 71.5 219

Number of new casesIR = –––––––––––––––––––

Population time

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Incidence ratein unexposed during three weeks

3 3IR = –––––––––––––––––– = ––––– = 0.008 / wk

124.5 + 123.5 + 122.5 370.5

Number of new casesIR = –––––––––––––––––––

Population time

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Compare incidence rates in exposed and unexposed

0

0.005

0.01

0.015

0.02

Exposed Unexposed

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Difference between incidence rates in exposed and unexposed

Incidence rate difference (IRD, IDD)

= (0.018 – 0.008) / wk

= 0.010 / week

How to interpret?

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Difference in incidence rates

Incidence rate difference (IRD) = (0.018 – 0.008) / wk = 0.010 / week

“The rate in the exposed was 0.010 / week greater than the rate in the unexposed.”

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Relative difference in incidence rates in exposed and unexposed

Relative incidence rate difference

0.018 – 0.008 = –––––––––––– = 2.25 – 1 = 1.25 0.008

How to interpret?

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Relative difference in incidence rates

Relative incidence rate difference

0.018 – 0.008 = –––––––––––– = 2.25 – 1 = 1.25 0.008

“The rate in the exposed was 125% greater than the rate in the unexposed.”

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Ratio of incidence rates in exposed and unexposed

0.018Incidence rate ratio = –––––– = 2.25 (IRR, IDR) 0.008

How to interpret?

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Ratio of incidence rates

0.018Incidence rate ratio = –––––– = 2.25 (IRR, IDR) 0.008

“The rate in the exposed was 2.25 times the rate in the unexposed.” [not “times greater”]

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Estimating IRR and CIR with the Odds Ratio

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Odds odds = probability / (1 – probability)

odds = risk / (1 – risk)

(most commonly)

Risk 0.010 0.050 0.100 0.20 0.80 Odds 0.010 0.053 0.111 0.25 4.00

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For small probability, odds ≈ probability

0

0.2

0.4

0.6

0.8

1

1.2

0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10

Odds

Small p

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Odds = probability / (1 – probability)

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60Odds

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OddsAny ratio of two natural numbers can be regarded as an odds:

Exposed: 20

Unexposed: 30

Total: 50

Odds of exposure: 20/50 divided by 30/50

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Incidence rate ratio (a.k.a. “incidence density ratio”)

can be expressed as a ratio of odds

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Incidence rate ratio

IR in exposed IR1 IRR = ––––––––––––––– = –––– IR in unexposed IR0

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Incidence rate ratio

IR1 Exposed cases / Exp PT IRR = –––– = –––––––––––––––––––––––––

IR0 Unexposed cases / Unexp PT

(PT = “population time”)

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Incidence density ratio is a ratio of exposed to unexposed cases . . .

IR1 Exposed cases / Exp PT IRR = –––– = –––––––––––––––––––––––– IR0 Unexposed cases / Unexp PT

Exposed cases / Unexposed cases = ––––––––––––––––––––––––––––– Exposed PT / Unexposed PT

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. . . divided by a ratio of exposed to unexposed population-time

IR1 Exposed cases / Exp PT IRR = –––– = –––––––––––––––––––––––– IR0 Unexposed cases / Unexp PT

Exposed cases / Unexposed cases = –––––––––––––––––––––––––––– Exposed PT / Unexposed PT

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Ratio of exposed to unexposed cases = “exposure odds” in cases

Exposed cases / Unexposed casesIRR = ––––––––––––––––––––––––––––––– Exp Person-time / Unexp Person-time

“Exposure odds” in cases = –––––––––––––––––––––––––– “Exposure odds” in population

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Ratio of exposed to unexposed population-time = “exposure odds”

Exposed cases / Unexposed casesIRR = –––––––––––––––––––––––––––––––– Exp Person-time / Unexp Person-time

“Exposure odds” in cases = ––––––––––––––––––––––––––– “Exposure odds” in population

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Count exposed and unexposed cases

O

OO

OO

O

O

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From before: Exposed:

4 4IR = –––––––––––––– = –––– = 0.018 / wk 74.5 + 73 + 71.5 219

Unexposed:

3 3 IR = –––––––––––––––––– = ––––– = 0.008 / wk 124.5 + 123.5 + 122.5 370.5

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Exposure odds in cases

= Exposed cases / Unexposed cases

= (4/7) / (3/7) = 4 / 3

= 1.33

The exposure odds in cases are 1.33

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From before: Exposed:

4 4ID = –––––––––––––– = –––– = 0.018 / wk 74.5 + 73 + 71.5 219

Unexposed:

3 3 ID = –––––––––––––––––– = ––––– = 0.008 / wk 124.5 + 123.5 + 122.5 370.5

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Exposure odds in population-time

= Exp. person-time / Unexp. person-time

= (74.5 + 73 + 71.5) / (124.5 + 123.5 + 122.5 )

= 219 / 370.5

= 0.59

The exposure odds in population-time are 0.59

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So incidence rate ratio can be expressed as a ratio of odds

“Exposure odds” in cases IRR = ––––––––––––––––––––––––– “Exposure odds” in population

1.33 = –––––– = 2.25 (same as earlier) 0.59

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O

OO

OO

O

O

Can we estimate exposure odds in the population by taking a sample?

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Take sample of “risk set” –“density controls” – week 1

O

O

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Take sample of “risk set” –“density controls” – week 2

O

OO

O

O

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Take sample of “risk set” –“density controls” – week 3

O

OO

OO

O

O

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Now estimate incidence rate ratio using the “density controls”

IR1 Exposed cases / Unexposed cases IRR = –––– = ––––––––––––––––––––––––––– IR0 Exposed PT / Unexposed PT

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Estimating the population odds with the odds in the control group

Exposed cases / Unexposed cases IDR = ––––––––––––––––––––––––––––––– Exposed controls / Unexposed controls

We call this the “exposure odds ratio” (OR).

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Exposure odds ratio = estimates incidence rate ratio (a.k.a. IDR)

1.33 1.33 OR = ––––– = ––––– = 2.22 6 / 10 0.60

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Odds ratio from a 2 x 2 table

Cases Controls

Exposed a b

Unexposed c d

a / c ad Odds ratio = ––––– = ––– b / d bc

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Odds ratio from a 2 x 2 table

Cases Controls

Exposed 4 6

Unexposed 3 10

4 / 3 (4) (10)Odds ratio = –––––– = ––––––– 6 / 10 (6) (3)

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What about incidence proportion in a cohort? (“cumulative incidence”)

Number of new cases3-week CI = –––––––––––––––––––

Population at risk

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Population at risk – baseline

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Entire population, week 3

O

OO

OO

O

O

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Cumulative incidence in exposed

Number of new exposed cases3-week CI = –––––––––––––––––––––––––––

Exposed population at risk

4 3-week CI = –––– = 0.053 75

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Cumulative incidence in unexposed

Number of new unexposed cases3-week CI = ––––––––––––––––––––––––––––

Unexposed population at risk

3 3-week CI = –––– = 0.024 125

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Compare incidence proportions in exposed and unexposed

0

0.01

0.02

0.03

0.04

0.05

0.06

Exposed Unexposed

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Difference in incidence proportions between exposed and unexposed

3-wk cumulative incidence difference (CID)

= (0.053 – 0.024)

= 0.029

How to interpret?

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Difference in incidence proportions

3-wk cumulative incidence difference (CID) = (0.053 – 0.024) = 0.029

“The 3-week cumulative incidence in the exposed was 0.029 greater than in the unexposed.”

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Relative difference in incidence proportions for exposed and unexposed

3-wk cumulative incidence relative difference

(0.053 – 0.024) 0.029 = –––––––––––––– = –––––– = 1.22 0.024 0.024

How to interpret?

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Relative difference in incidence proportions

3-wk cumulative incidence relative difference

(0.053 – 0.024) 0.029 = –––––––––––––– = –––––– = 1.22 0.024 0.024

“The 3-week CI in the exposed was 122% greater than in the unexposed.”

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Ratio of incidence proportions for exposed and unexposed

3-week cumulative incidence ratio (CIR) = (0.053 / 0.024) = 2.22

How to interpret?

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Ratio of incidence proportions (“relative risk”, “risk ratio”)

3-week cumulative incidence ratio (CIR)

= (0.053 / 0.024) = 2.22

“The 3-week CI in the exposed was 2.2 times that in the unexposed.” [not “times greater than”]

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Ratio of incidence proportions, a.k.a. cumulative incidence ratio

CI1 Exposed cases / Exp PAR CIR = –––– = –––––––––––––––––––––––––– CI0 Unexposed cases / Unexp PAR

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Cumulative incidence ratio can also be expressed as a ratio of odds of

exposure in cases divided by . . .

CI1 Exposed cases / Exp PAR CIR = –––– = –––––––––––––––––––––––––– CI0 Unexposed cases / Unexp PAR

Exposed cases / Unexposed cases = ––––––––––––––––––––––––––––– Exp PAR / Unexp PAR

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. . . an odds of exposure in the population at risk (PAR)

CI1 Exposed cases / Exp PAR CIR = –––– = –––––––––––––––––––––––––– CI0 Unexposed cases / Unexp PAR

Exposed cases / Unexposed cases = ––––––––––––––––––––––––––––– Exp PAR / Unexp PAR

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So cumulative incidence ratio is also an odds ratio

CI1 Exposed cases / Unexposed cases CIR = ––– = ––––––––––––––––––––––––––– CI0 Exp PAR / Unexp PAR

Exposure odds in cases = ––––––––––––––––––––––––––––––– Exposure odds in population at risk

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Exposure odds in cases

= Exposed cases / Unexposed cases

= 4 / 3

= 1.33

(same as for incidence density ratio)

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Population at risk(before cases occur)

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Exposure odds in population at risk (before cases occur)

= Exposed PAR / Unexposed PAR

= 75 / 125

= 0.60

(slightly different from odds of exposure for person-time)

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So cumulative incidence ratio is also an odds ratio

CI1 Exposure odds in casesCIR = –––– = –––––––––––––––––––––––– CI0 Exposure odds in pop. at risk

1.333-week CIR = ––––– = 2.22 0.60

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So if can estimate exposure odds in PAR, may not need to analyze entire

cohort

“Case-cohort” or “case-base” design

Can be very advantageous if, for example, one wants to analyze specimens stored at baseline.

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Sample from population at risk (before cases occur)

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Exposure odds in controls

= Exp. controls / Unexp. controls

= 6 / 10

= 0.60

(expected value for the estimated odds)

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Cumulative incidence ratio

CI1 Exposed odds in cases CIR = ––– = ––––––––––––––––––––––– CI0 Exposure odds in population

1.33 3-wk CIR = exposure OR = ––––– = 2.22 0.6

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What if cannot sample population at risk?

• Draw controls from noncases at end of follow-up period

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Non-cases at end of follow-up

O

OO

OO

O

O

71

122

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Exposure odds in population at risk (after cases occur)

= Exposed noncases / Unexp. noncases

= 71 / 122

= 0.58

(slightly different from ratio of person-time and ratio of population at risk)

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Odds ratio

Exposed odds in cases OR = –––––––––––––––––––––––– Exposure odds in population

1.33 = ––––– = 2.29 0.58

(slightly larger than CIR)

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Draw controls from noncases

O

OO

OO

O

O

5

9

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Exposure odds in“cumulative” controls

= Exposed noncases / Unexp. noncases

= 5 / 9

(about) = 0.58

(Note: 5/9=0.555, but a larger “sample” would produce 0.58)

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Odds ratio

Exposed odds in cases OR = –––––––––––––––––––––––– Exposure odds in population

1.33 = ––––– = 2.29 0.58

(slightly larger than CIR)

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Case-control design is an efficient sampling technique

• Much more efficient, especially for rare outcomes

• Validity depends upon whether controls provide a clear view of population from which cases arise

• Susceptible to various sources of bias

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New Software for Psychics

“Notice to user: By breaking the seal of this envelope, you accept the terms of the enclosed license agreement.”

– Adobe Font Pack for Windows

Source: Willmott, Don, Abort, Retry, Fail? PC Magazine, June 14, 1994, 482.