Stochastic Structural Dynamics Lecture-32€¦ · pv n n d n ( , ) ( , ) Spectral pseudo velocity...
Transcript of Stochastic Structural Dynamics Lecture-32€¦ · pv n n d n ( , ) ( , ) Spectral pseudo velocity...
111
Stochastic Structural Dynamics
Lecture-32
Dr C S ManoharDepartment of Civil Engineering
Professor of Structural EngineeringIndian Institute of ScienceBangalore 560 012 India
Probabilistic methods in earthquake engineering-1
2
We have developed methods to study systems governed by
,
where 0 & 0 are specified,and is a vectorrandom process.The analysis has included characterization of responsemomen
MX CX KX F X X G t
X X G t
Recall
ts, pdf-s of system states, and reliability measures.
The equations governing the behavior of structures subjected to earthquake support motions have formsimilar to the above equation.Therefore, what are the issues that we need to considerafresh?
3
Focus: uncertainties in vibratory response of structures during an earthquake
• Stochastic models for ground motions• Response spectrum, PSD and time histories• Modal combination rules• Seismic risk analysis• Performance based structural design (PBSD)
Aim:• To introduce the basic ideas and facilitate future self‐study
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When, where, and how earthquakes occurEarthquakes The details of ground motion
The effect of ground motion on structure
Uncertainties in earthquake engineering problems
Dynamic responseDamage and loss
555
Duhamel's integral
Alternatives for earthquake load specification
Time histories
Power spectral density Response spectra
Monte Carlo simulations
Spectralestimation
Spectrumcompatibleaccelerograms
Extreme value theory
Spectrum compatibe PSDusing extreme value theory
Not suited forreliability analysis
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References
• R W Clough and J P Penzien, 1993, Dynamics of structures, McGraw Hill, NY
• N C Nigam and S Narayanan, 1994, Applications of random vibrations, Narosa, New Delhi
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Response spectra
8
Effect based model for earthquake ground acceleration
Equation governing total displacement( ) ( ) 0
Relative displacement ( ) ( ) ( )
2
t t tg g
tg
g
mv c v v k v v
v t v t v t
mv cv kv mv
v
Response spectrum
2 ( )gv v v t
9
0
0
0
0
1( ) exp[ ( )]sin[ ( )][ ( )]
1 exp[ ( )]sin[ ( )] ( )
0.1
1( ) exp[ ( )]sin[ ( )] ( )
( ) ( ) exp[ ( )]cos[ ( )]
( )
t
d gd
t
d gd
dt
n n gn
t
g n
g
v t t t mv dm
t t v d
v t t t v d
v t v t t d
v
0
exp[ ( )]sin[ ( )]t
nt t d
10
2
2
0
0
( ) ( ) ( ) 2
( ) (2 1) ( ) exp[ ( )]sin[ ( )]
2 ( )exp[ ( )]cos[ ( )]
Systems with the same and respond identically
t t tg g n n
tt
n g n n
t
n g n n
n
c kv t v v v v v vm m
v t v t t d
v t t d
Remark
to the same ground motion.
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Response quantities of interest
( ) :Maximum relative displacementForce in the spring (column) and hence the stresses
in the column are proportional to ( )
( ) :Of interest in the study of secondary
t
v t
v t
v t
systemsPounding of adjacent buildings
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2
2
( ) [ ( ) ( )] ( )
( )( )( )
( ) base shear
( ): has units of acceleration (pseudo-acceleration)
seismic coefficient
Weight of the building seismic
ts g
n
s
n
f t k v t v t kv t
m v tA tmA t Wg
f t
A t v t
A tg
Force in the spring
coefficient= base shearBase shear height of the building= base moment
13
2 2 2
2 20
1 1( ) ( )2 2
1 [ ( )] ( )2 2
strain energy stored: has units of velocity
pseudo-velocity
n
n
n
U kv t m v t
mm v t V t
Uv t
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Let a family of sdof systems with damping {η} and natural frequencies {ωn} be subjected to a given ground acceleration.
Let us determine the peak responsesover time as a function of {η} and {ωn}.
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Definitions
0
0
02
( , ) max | ( ) | Spectral relative displacement
( , ) max | ( ) | Spectral relative velocity
( , ) max | ( ) | Spectral absolute acceleration
( , ) ( , ) Spectral pseudo
d n t
v n tt
a n t
pa n n d n
S v t
S v t
S v t
S S
acceleration
( , ) ( , ) Spectral pseudo velocitypv n n d nS S
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Definitions
Sd(ωn,η)Sv(ωn,η)Sa(ωn,η)Spa(ωn,η)Spv(ωn,η)
as a function of ωn with η as a parameter is called the responsespectrum for
Relative displacementRelative velocityAbsolute accelerationPseudo accelerationPseudo velocity
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Connotes "frequency" on -axis."Frequency" often refers to the frequency parameter used in
defining Fourier transform. In this context we talk oftime and frequency domain representations of s
x
Spectrum
ignals.In the context of response spectrum "frequency" is not the
Fourier frequency but the natural frequencies of a familyof sdof systems.Often period is plotted on the -axis.x
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2
2
2
0 0
0
0
2 ( )
lim ( )
lim max | ( ) | max | ( ) |
lim ( , ) max | ( ) |
max | ( ) |
ZPA: zero
n
n
n
n
n n g
n g
n gt t
pa n gt
gt
v v v v t
v v t
v t v t
S v t
v t ZPA or PGA
Limiting behavior of the spectra as
period accelerationPGA: peak ground acceleration
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0
0 00
0
0
0 0
0
1( ) exp[ ( )]sin[ ( )] ( )
sin[ ( )]lim ( ) lim ( )
( ) ( ) ( )
lim ( ) ( )
lim max | ( ) |
n n
n
n
nt
d gd
td
gd
t
g g
g
t
v t t t v d
tv t v d
t v d v t
v t v t
v t
Limiting behavior of response spectra as
0
0 0
max | ( ) |
lim ( , ) max | ( ) |n
gt
d n gt
v t
S v t
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00
00
00
0
0 (0, ) max ( )sin ( )
(0, ) max ( )cos ( )
(0, ) (0, ) except for very small .
0 (0, ) max ( )sin ( )
(0, ) max
t
pv n g nt
t
v n g nt
pv n v n n
t
a n n g nt
pa n
S v t d
S v t d
S S
S v t d
S
0
( )sin ( )
(0, ) (0, ) (0, )
0 & 0 0.2 (0, ) (0, )
t
n g nt
a n pa n pv n
a n pv n
v t d
S S S
S S
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( , ) ( , )
1( , ) ( , )
( , ) ( , )
log ( , ) log ( , ) log
log ( , ) log ( , ) log
pv n n d n
d n pv nn
a n n pv n
d n pv n n
a n pv n n
S S
S S
S S
S S
S S
Tripartite plots( , ), ( , ) & ( , )d n pv n pa nS S S
22
Natural period s
log ,pvS T log ,dS T
log ,paS T
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Why so many response spectra?• Each response spectrum provides a physically
meaningful quantity
Peak deformation
Peak strain energy
Peak force in the springBase shearBase moment
),( ndS ),( npvS
),( npaS
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The shape of the response spectrum can be approximated more readily for design purposes with the aid of all three spectral quantities than any one of them taken alone.
Helps in understanding characteristics of response spectra.
Helps in constructing response spectra.
Helps in relating structural dynamics concepts to building codes.
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Smooth design response spectra
Natural period s
,paS Tg
PGAZPA
1.0
Soil conditionDamping
PGA : arrived at based on seismic hazard analysis
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Factors that influence response spectrum at a given site
• Source mechanism• Epicentral distance• Focal depth• Geological conditions• Richter’s magnitude• Soil condition• Damping and stiffness of the system
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Duhamel's integral
Alternatives for earthquake load specification
Time histories
Power spectral density Response spectra
Monte Carlo simulations
Spectralestimation
Spectrumcompatibleaccelerograms
Extreme value theory
Spectrum compatibe PSDusing extreme value theory
Not suited forreliability analysis
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2
0
2
zero mean, stationary, Gaussian random process;
~ 0,
max
exp
exp2
m
n n n g
g
g gg
m t T
X
x
x
x x x x
x t
x t N S
X x t
P T
How to generate a response spectrum compatible with a given PSD?
2
2
22
22 2
2
with &
x
x gg
x gg
H S d
H S d
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2
2
12
2
For a given probability , the corresponding is given by
exp exp2 2
22 ln ln
Let , be the given pseudo-acceleration response spectrum.
x
x x
xx
x
n n
p
p T
pT
R
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2 2
We interpret , as the - th percentile point.
2, 2 ln ln (typically =84%)
n n
xn n n x
x
R p
R p pT
303030
2
22
2
zero mean, stationary, Gaussian random process;
~ 0,
To a first approximation we assume
n n n g
g
g gg
x g
x x x x
x t
x t N S
H S
How to generate a PSD compatible with a given response spectrum?
2
22
12 22
&2
g
n n n gg n n n gg n
n n
xn
x
d
H S S
313131
2 43
2
2, 2 ln ln2
To a first approximation we thus get
,.
1ln ln
gg nn n n
nn n
n n ngg n
nn
SR p
T
RS
pT
3232
2
2 2
22
22 2
(1) Set iteration N=1(2) Start with the initial guess on the PSD given by
,
1ln ln
(3)Evaluate and using
&
n n nNn
nn
x x
Nx gg
Nx gg
RS
pT
H S d
H S d
Steps
3333
12
2 2
21
2(4)Evaluate , 2 ln ln .
(5)Obtain an improved estimate of PSD using
( )( ) ( )( )
(6)Stop iterations if the PSD function has converged; if not go to
N xn n n x
x
N NN
R pT
RS SR
step 3.
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0 100 200 300 400 500 600 7000
2
4
6
8
10
12
14
16
Frequency rad/s
Acc
eler
atio
n m
/s2
Target
Derived
Pseudo acceleration response spectrum
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0 100 200 300 400 500 600 7000
0.05
0.1
0.15
0.2
0.25
0.3
0.35
Frequency rad/s
PS
D (
m2 /s
4 )/(r
ad/s
)Derived
Used
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0 2 4 6 8 10 12 14 16 18 20-5
0
5
0 2 4 6 8 10 12 14 16 18 20-5
0
5
0 2 4 6 8 10 12 14 16 18 20-5
0
5
Acc
eler
atio
n m
/s2
0 2 4 6 8 10 12 14 16 18 20-5
0
5
0 2 4 6 8 10 12 14 16 18 20-5
0
5
Time s
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0 2 4 6 8 10 12 14 16 18 20-0.2
0
0.2
0 2 4 6 8 10 12 14 16 18 20-0.2
0
0.2
0 2 4 6 8 10 12 14 16 18 20-0.2
0
0.2
Vel
ocity
m/s
0 2 4 6 8 10 12 14 16 18 20-0.2
0
0.2
0 2 4 6 8 10 12 14 16 18 20-0.2
0
0.2
Time s
38
0 2 4 6 8 10 12 14 16 18 20
-0.020
0.02
0 2 4 6 8 10 12 14 16 18 20
-0.020
0.02
0 2 4 6 8 10 12 14 16 18 20
-0.020
0.02
Dis
plac
emen
t m
0 2 4 6 8 10 12 14 16 18 20
-0.020
0.02
0 2 4 6 8 10 12 14 16 18 20
-0.020
0.02
Time s
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Variance(σ2) = 1.0893 m2/s4
Std. deviation (σ ) = 1.0437 m/s2
3σ = 3.1311 m/s2
Time history no. Maximum ( m/s2)
Minimum ( m/s2)
1. 4.5063 -3.8202
2. 3.4130 -3.4098
3. 3.3419 -3.5512
4. 3.7498 -3.5094
5. 3.4756 -3.1706
Zero Peak Acceleration (ZPA) =3.2530 m/s2
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-4 -3 -2 -1 0 1 2 3 4 50
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
Acceleration m/s2
Pro
babi
lity
Normal
Simulation
PDF of the simulated samples of ground acceleration
41
0 100 200 300 400 500 600 7000
0.05
0.1
0.15
0.2
0.25
0.3
0.35
Frequency rad/s
PS
D (
m2 /s
4 )/(r
ad/s
)Target
Simulation
PSD function from 100 samples of ground acceleration
42
0 1 2 3 4 5 60
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
Acceleration m/s2
Pro
babl
ity
Simulation
Gumbel
43
Response spectrum method providesmaximum response of sdof systems asa function of natural frequencies anddamping ratios.How to deal with mdof systems?
MDOF systems can be decomposed into a set of Hope :
uncoupled sdof oscillators.How can this be taken advantage of?
44
Building frame under earthquake support motion
45
Equation of motion for total displacement
00
)()(
0
0
0
0
000000 11
3
2
1
33
3322
221
3
2
1
33
3322
221
3
2
1
3
2
1 txctxk
xxx
kkkkkk
kkk
xxx
cccccc
ccc
xxx
mm
m gg
Relative displacement ggg xxyxxyxxy 332211
Equation of motion for relative displacement
g
g
g
xmxmxm
yyy
kkkkkk
kkk
yyy
cccccc
ccc
yyy
mm
m
3
2
1
3
2
1
33
3322
221
3
2
1
33
3322
221
3
2
1
3
2
1
0
0
0
0
000000
Tg txMKYYCYM
111
)(
46
2
2
0
( )
1 1 1
2
2 1, 2, ,
( ) exp( )[ cos sin ]
(
g
T
T T Tn n n
T T T Tg
n n n n n n n g
T
n n n n dn n dnt
n g
MY CY KY M x t
Y Z
M I K Diag C Diag
M Z C Z K Z M x
z z z x n n
M
z t t A t B t
x
) ( )nh t d
47
1
1 0
2
01
1
Displacement: ( ) ( )
{exp( )[ cos sin ] ( ) ( ) }
Elastic forces:
Base shear:
Overturing moment:
N
k kn nn
tN
kn n n n dn n dn n g nn
s
N
snn
N
o n snn
y t z t
t A t B t x h t d
F KY K Z M Z
V F
M x F
48
2
{1} ( )
{1} ( ) ( )
{1}
2 ( )
modal participation factor or modal excitation factor
g
t t
tn n n n n n g n g
tn
nn n n n n n g
n
n
MV CV KV M v t
V Z M M K KM z C z K z M v t v t
M
z z z v tM
49
2
0
1 1
1
0
2 ( )
1( ) exp[ ( )]sin[ ( )] ( )
( ) ( )
( ) ( ) ( ) ( )
Put ( ) ( )
max ( ) ( , ) m
n n g
t
n n gn
nn n
np p
nk kn n k kn n
n n np
nkn kn k kn n
nn
kn n kn D n nt T
v v v v t
v t t t v d
z t v tM
V Z V t z t V t v tM
V t v tM
v t S
0ax ( ) ?kt TV t
50
0
2
2
2
Spring force( ) ( )
Recall
( ) [ ]
( ) [ ] { ( )}
( ) { ( )}
max ( ) ?
s
n n n
s n
ns n n
n
ns n
st T
n
F t KV t K Z
K M
F t M Z
F t M v tM
F t M a tM
F t
51
1
11
1
22
0
21 2
2
1
( ) 1 ( )
1 ( )
Recall {1} 1
( )
( )( )
( )
( ); ma x ?
N
B si si
nB n
n
t t
t nB n N
n
NN
N
N
Bt T
nB n
n n
V F t F t
V M a tM
M M
a tM
a tMV a t
M
a tM
V t t tM
Va
Base shear
52
2
2
1
The quantity has units of mass and is called
the effective modal mass.
Prove that total mass.
Total mass: 1 1
1 1
1
1
1 1
n
n
Nn
n n
T
t tn n
n nn n n n
n n
T
M
MM M
Z M M Z
M M Z M Z
M Z ZM M
M M
Note :
2
1 21
1 n
n
Nn n
T Nnn n
MM
M QEDM M
53
0(0, ) ; (0, ) 0; ( , ) 0; ( , ) 0
, ,
(0, ) 0; (0, ) 0; ( , ) 0; ( , ) 0
iv
g
g
ivg
EIy my cyy t x t y t EIy L t EIy L t
y x t z x t x t
EIz mz cz mx t
z t z t EIz L t EIz L t
Modal combination rules : what is the basic problem?
gx t
54
12
0
0
Eigenfunction expansion
,
with 2 ; 1, 2, ,
What we know based on response spectrum based analysis?
We know max ; 1, 2, , .
What we wish to know?
max ,
n nn
n n n n n n n g
nt T
t T
z x t a t x
a a a x t n
a t n
z x t
0 1max n nt T n
a t x
55
0 100 200 300 400 500 600 7000
2
4
6
8
10
12
14
16
Frequency rad/s
Acc
eler
atio
n m
/s2
Target
Derived
56
0 01 1max max
The extrema of for =1,2, , are likely tooccur at different times and they may have different signs.Response spectra do not contain infor
n n n nt T t Tn n
n
a t x x a t
a t n
Difficulty
Remarks
0 1
mation on times atwhich extrema occur nor do they store the signs of the extrema.
max can occur at a time instant * at which none
of ; =1,2, , need to attain their respective extr
n nt T n
n
a t x t
a t n
emum
values.
57
0 1
0
How best to obtain max in terms of
max , and the modal characteristics of the vibrating
system?
Modal characteristics: natural frequencies, mode s
n nt T n
nt T
a t x
a t
Problem of modal combination rules
hapes,modal damping ratios, and participation factors.
These rules are formulated based on methods of random vibration analysis.