Solutions
description
Transcript of Solutions
Solutions
Mechanisms and Phenomena, Separations,
andConcentration Problems
Solutions
How they form, What they do, Separations,
andConcentration Problems
Standards• 6. Solutions are homogeneous mixtures of two or more
substances. As a basis for understanding this concept: • a. Students know the definitions of solute and solvent.• 6. b. Students know how to describe the dissolving process at
the molecular level by using the concept of random molecular motion.
• 6. c. Students know temperature, pressure, and surface area affect the dissolving process.
• 6. d. Students know how to calculate the concentration of a solute in terms of grams per liter, molarity, parts per million, and percent composition.
• 6. e.* Students know the relationship between the molality of a solute in a solution and the solution’s depressed freezing point or elevated boiling point.
• 6. f.* Students know how molecules in a solution are separated or purified by the methods of chromatography and distillation.
Examples of Chemical Change vs. Physical Change
Burning BoilingRusting FreezingBread Rising MeltingPhotosynthesis Mixing
Salt dissolving in H2O Salt precipitating from H2O
Chemical ChangeChemical changes occur when the atoms in
a substance change their electron configurations.
Chemical changes are often noticeable due to the appearance of a new substance or the release or absorption of energy (light, heat, electricity).
Reaction SymbolsSymbol Meaning(s), (l), (g) Substance is a solid, liquid, or gas(aq) Aqueous, substance is dissolved in H2O
“Produces” or “makes”“Produces” through reversible reaction
heat or Δ Heat is added to the reactants
Pt A catalyst is used to speed up the reaction
Definitions• Heterogeneous – a mixture with large
particles (clumps of molecules or ions). • Homogeneous – a mixture with very small
particles (individual molecules or ions).
• Solution – a homogeneous mixture of two or more substances. (ex. salt in water)Solvent – the main ingredient of a solution. (ex.
water)Solute – the other ingredients dissolved into the
solvent. (ex. salt)
More Definitions• Solution – a homogeneous mixture of two or more
substances. (ex. salt in water)Solvent – the main ingredient of a solution. (ex. water)Solute – the other ingredients dissolved into the
solvent. (ex. salt)• Colloid – a heterogeneous mixture of two or more
substances with medium-sized particles. Usually stable. (ex. whipping cream, mayonnaise, Jell-O)
• Suspension – a heterogeneous mixture of two or more substances with larger-sized particles. Usually unstable. (ex. clay in water, smoke in air)
Diffusion of Gases
Ionic compounds
Ionic compounds
Ionic compounds
Polar molecules
OHH
+ +
–
OH
H+
+
–
O
HH+
+
–
Ionic compounds
Na+ Cl–
Na+ Cl–
Na+ Cl–
Na+ Cl–
Cl–
Na+
Na+Cl–
NaCl Dissolved in Water
OHH
+ +
–
OH
H +
+
–O HH+
+
–
Cl–
OH H
++
–
NaCl Dissolved in Water
OH H
++
–
OH
H++
–
OH
H ++
– Na+
OHH
+ +
–
NaCl Dissolved in Water
NaCl Dissolved in Water
Sucrose Dissolved in Water
PrecipitatePrecipitate – A solid that comes out of the
solution.
Iron (II) hydroxide benzoic acid
Precipitate
lead (II) nitrate
Concentrations• Concentration – how much solute is dissolved
within a certain amount of solution. • g solute/L solution• ppm – parts per million (mass)• ppb – parts per billion • Molarity (M) – mol solute/L solution• Molality – mol solute/kg solvent• % composition = mass solute/mass total
Concentrations Examples
ppm – parts per million (mass)
Molarity (M) =
g soluteL solution
= 3.7 g NaCl1 L solution
=
mol solute L solution =
3.0 mol MgCl2
1 L solution= 3.0 M MgCl2 solution
25 g LiF1,000,000 g solution = 25 ppm (mass)
Concentrations Examples
Molality – mol solute/kg solvent
% composition = mass solute/mass total
Concentration Example #1 • If 12 moles of KCl are dissolved in a 3 L
solution with water, what is the molarity of the KCl solution?
12 mol KCl3 L solution = 4 M KCl solution
Concentration Example #2 • How many moles of sodium chloride (NaCl)
are dissolved in 5 L of NaCl solution with a concentration of 3M?
5 L solution1
x 3 mol NaCl1 L solution = 15 mol NaCl
OR3 mol NaCl1 L solution = x mol NaCl
5 L solution
Solubility• soluble – something that can dissolve into a
solution. • insoluble – something that cannot dissolve
into a solution. • saturated – no more solute can dissolve into
the solution. • unsaturated – more solute can still dissolve
into the solution.
Solubility• supersaturated – more than the normal
amount of solute is dissolved in the solution. A slight change may force the excess solute to precipitate out of solution.
Solubility Graph
Solubility Graph
Solubility Graph
Electrical Conductivity• Distilled water does not conduct electricity• Electrolytes – dissolved salts or acids that
allow water to conduct electricity because of positive or negative ions.
Diluting Solutions• While the molarity (M) and the volume (V)
may change, the number of moles (M × V) will not change.
M1 × V1 = M2 × V2 before after
Diluting Example #1• 5.0 liters of a 3.0 M NaCl solution is diluted so
the volume of the solution is now 30 liters. What is the molarity of the diluted solution?
M1 × V1 = M2 × V2 (3.0 M) × (5.0 L) = M2 × (30 L)
15 = 30 M2
0.5 M = M2
30 30
Like Dissolves Like• Polar molecules dissolve polar molecules.
Water, alcohols, vinegar• Nonpolar molecules dissolve nonpolar
molecules. Fats, oils, gasoline
• Usefulness of soap in washing off greasy hands comes from soap molecules having both polar and nonpolar ends.
Factors that Affect Solubility • Surface Area – Smaller particles have more
surface area than larger particles. Surface area allows the solute to dissolve faster.
Factors that Affect Solubility • Surface Area – Smaller particles have more
surface area than larger particles. Surface area allows the solute to dissolve faster.
Factors that Affect Solubility • Stirring – increases solute’s contact with low
concentration solvent. The solute dissolves faster.
• Temperature – Higher temperatures usually allow more solids to dissolve in liquids but less gases.
• Pressure – Higher pressures usually allow more gases to dissolve in liquids.
Gas Dissolved in Water
Concentration Effects(aka Colligative Properties)
• Depressed Freezing Point (anti-freeze, salting the roads and sidewalks in winter) – freezes at a lower temperature because of the solute.
• Elevated Boiling Point (anti-boil radiator fluid) – boils at a higher temperature because of the solute.
Separations • Decanting – carefully pouring the solution from a
container while leaving the precipitate.• Centrifugation – spinning a suspension very fast so the
precipitate settles on the bottom. • Filtration – using a filter to trap the precipitate while the
solution passes through. • Evaporation – heating and evaporating out the solvent
so only the solute remains. • Chromatography – Utilizing different substances’ varying
attraction to certain materials so one substance travels faster than the other.
• Distillation – Separating 2 liquids heating them both and having them boil out at their different boiling points.
Decanting • Decanting – carefully pouring the solution
from a container while leaving the precipitate.
Centrifugation• Centrifugation – spinning a suspension very
fast so the precipitate settles on the bottom.
Filtration • Filtration – using a filter to trap the precipitate
while the solution passes through.
Evaporation • Evaporation – heating and evaporating out
the solvent so only the solute remains.
Chromatography • Chromatography – Utilizing different
substances’ varying attraction to certain materials so one substance travels faster than the other.
Distillation • Distillation – Separating 2 liquids heating
them both and having them boil out at their different boiling points.
Concentration Example #3• Pure gold nuggets are very rare. Instead most
mining companies settle for rocks that contain only small amount of gold. If a 1,000 g rock contains 200 mg of gold, then what is the concentration in parts per million of gold in the rock?
200 mg Au1,000 g rock
= 0.200 g Au1,000 g rock
x
= 200 ppm Au (mass)
200 g Au1,000,000 g rock
1,0001,000
=
Concentration Example #3• Pure gold nuggets are very rare. Instead most
mining companies settle for rocks that contain only small amount of gold. If a 1,000 g rock contains 200 mg of gold, then what is the concentration in parts per million of gold in the rock?
200 mg Au1,000 g rock
x 1 g1,000 mg
x = 106
1,000 106
1,000
= 200 ppm Au (mass)
200 g Au1,000,000 g rock
Concentration Example #4• 11.1 g of CaCl2 are dissolved within a 500 mL
solution with water. What is the molarity of the CaCl2 solution?
11.1 g CaCl2
500 mL solutionx 1 mol CaCl2
111 g CaCl2
x
= 0.2 M CaCl2 solution
1,000 mL 1 L
=
Carbonated Soda
Under High pressure Under Normal Pressure
Save for Equilibrium Shifts Unit since technically there is an unstable acid compound that CO2 forms in solution.
NeFONCBBe
He
Li
H
Kr
ArCl
Br
XeI
SPSiMg Al
Ca
Na
K
NeFONCBBe
He
Li
H
Kr
ArCl
Br
XeI
SPSiMg Al
Ca
Na
K
Bad Example #X • Carbon dioxide (CO2) is present in a mixture of
gases at STP with a concentration of 500 ppm. If there are a 44.8 L of the gas mixture , how many moles of carbon dioxide?
44.8 L mixture 1
x
= 0.001 mol CO2
500 mol CO2
106 mol mixture1 mol mixture22.4 L mixture
x
4 e– in valence shell
Solubility Graph