Solutions & Solubility Vocabulary. agitation ___ is the act of stirring, shaking, or mixing.
Solutes and Solubility. Mixture Mixtures: made from physically mixing two or more substances...
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Transcript of Solutes and Solubility. Mixture Mixtures: made from physically mixing two or more substances...
Mixture
• Mixtures: made from physically mixing two or more substances together without a chemical reaction occurring.
• Mixing ionic compounds with water forms aqueous solutions of dissolved ions.
• The polar water molecules attract to the ions, tearing them apart from other ions and holding them away from other ions.
• This is called molecule-ion attraction.
O-
2
H+
H+
O-
2
H+
H+
O-
2
H+
H+
O -2
H+
H+
O -2H
+H
+
O-2
H+
H+
O-
2H+
H+
O-
2
H+
H+
O-2H+
H+
O-
2H+
H+
O-
2H+
H+
O-2
H+
H+
O-
2
H+
H+
O-
2
H+
H+
Na+
Cl-
Na+
Cl- Na+
Cl-
Na+
Cl-Na
+Cl-
Na+
Cl-
Na+
Cl-
Na+
Cl-
Na+
Cl- Na+
Cl- Na+
Cl-
Na+
Cl- Na+
Cl- Na+
Cl-
O-2
H+
H+
O-
2
H+
H+
O-2
H+
H+ O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
O-
2
H+
H+
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+
Na+ Cl-Na+ Cl- Na+
Na+ Cl-Na+ Cl-
Na+ Cl-
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
O -2
H +
H +
O-
2
H+
H+
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-Na+
Na+ Cl-
Na+ Cl-
Na+ Cl-
Na+ Cl-Na+
Na+ Cl-Na+ Cl-
O -2H +
H +
O-2
H+
H+
O-2
H+ H+
O-2
H+
H+
O-2 H+
H+
O-2
H+
H+
O-2
H+
H+
Na+
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
Cl- O-2
H+
H+
O-2
H+
H+
O-2H+
H+
O-2
H+
H+
Na+
O-2
H+
H+
O-2
H+
H+
O-2
H+
H+
Cl-
O-2
H+H+
O-2
H+
H+
O-2H+
H+
O-2
H+
H+ Partially positive ends of
the water molecules (hydrogen) attracts to the negatively charged
chloride ions.
Partially negative ends of
molecules (oxygen) attracts to the positively charged sodium
ions.
MOLECULE – ION ATTRACTION
Solubility• The quantity of solute that can be added to a
quantity of solvent to make a saturated solution at a given temperature and pressure.
Solubility Curve• Solubility Curve – a graphical representation of
the amount of substance that can dissolve into 100 g of water at a specific temperature (Celsius)
Y-axis: Solubility of substance
(g/100 g H2O)
X-axis: Temperature (Celsius)
Substances: Compound being
dissolved in water (H2O)
Interpreting a Solubility Curve• Each point on the solubility curve shows how many
grams can be dissolved at a specific temperature:
Each line shows how much
substance can dissolve as a
function of the temperature of
the solution.
Using a Solubility CurveHow many grams of potassium bromide (KBr) can dissolve in 100 grams of water at 20°C?
70g
Answer: 70 grams of KBr can
dissolve in 100g of water at
20°C
Practice Using Solubility CurveHow many grams of potassium nitrate (KNO3) can dissolve in 100 g of water at 60°C?
Answer: 130 g of KNO3 can dissolve in 100 g of H2O
130g
Solution Concentration • Saturated: The solution
holds as many dissolved particles as it can possibly hold
• Unsaturated: The solution holds fewer solute particles than can theoretically be dissolved, can add more solute.
• Supersaturated: A very rare situation where the solution holds more solute than is theoretically possible, unstable situation where the excess will precipitate if the solution is agitated
Saturated / Unsaturated / Supersaturated
• Saturated: solute = solubility• Unsaturated: solute < solubility
• Supersaturated: solute > solubility
NaNO3
Saturated
Unsaturated
Supersaturated
Factors Affecting Solubility
1) Temperature• For solid and liquid solutes, solubility in water
increases as temperature increases• For gaseous solutes, solubility in water decreases
as temperature increases
2) Pressure• For gaseous solutes, solubility increases as
pressure increases• Pressure does not affect solid or liquid solutes
3) Nature of Solute and Solvent (Like Dissolves Like)
• Polar solutes dissolve in polar solvents• Nonpolar solutes dissolve in nonpolar solvents
Factors Affecting Solubility
Checking for understanding
1. Explain the difference between saturated, unsaturated, and supersaturated solutions2. Explain how pressure and temperature affect solubility
Concentration and molarity• a measure of the amount of solute dissolved in
a given quantity of solvent• A concentrated solution has a large amount of
solute• A dilute solution has a small amount of solute
2. Parts Per Million (ppm)• Number of grams of solute in
1 million gram of solvent• One unit of concentration
used in pollution measurements that involve very low concentration
g solute g solvent
= ppm X 1,000,000
• A chemical analysis shows that there are 2.2 mg of lead in exactly 500 g of water. Convert this measurement to parts per million.
mass of solute: 2.2 mgmass of solvent: 500 gparts per million = ?
2.2 mg 1000 mg 1 g
= 2.2 x 10-3 g
2.2 x 10-3 g500 g
X 1,000,000 = 4.4 ppm
g solute g solvent
= ppm X 1,000,000
• Helium gas, 3.0 x 10-4 g is dissolved in 200.0g of water. Express this concentration in ppm.
mass of solute: 3.0 x 10-4 gmass of solvent: 200.0 gparts per million = ?
200 g X 1,000,000 = 1.5ppm
3.0 x 10-4 g
g solute g solvent
= ppm X 1,000,000
3. % by mass
% mass = g of soluteg of solution
x 100 %
4. % by volume
% volume = mL of solutemL of solution
• Percent by volume is often used to describe the concentration of alcohol in alcoholic beverages or in medications containing alcohol.
x 100 %
What is the percentage by mass of a solution made by dissolving 0.49 g of potassium sulfate in 12.70 g of water?
0.49 K2SO4
12.70g water
=
0.49 g of K2SO4
12.70g water + 0.49 g K2SO4 x 100 %
=3.7% K2SO4 by mass
% mass = g of soluteg of solution
=
• A 50.0 mL sample of an aqueous ethanol solution is distilled to yield 33.2 mL of ethanol. What is the percent by volume of ethanol in this solution?
% volume= mL of solutemL of solution
x 100 %
=66.4% ethanol by volume
33.2 mL of ethanol50.0 mL solution
x 100 %=
5. Molarity (M)
• Molarity (M) is a concentration unit of a solution expressed as moles of solute dissolved per liter of solution.
M = Moles of soluteLiters of solution
• What is the molarity of a potassium chloride solution that has a volume of 400.0 mL and contains 85.0 g KCl?
solute = 85 g KCl
solution = 400 mL
74.55 g KCl
1 mol KCl= 1.14 mol KCl
1000 mL
1 L= 0.4 L
= 2.85 MM = Moles L M =
1.14 mol 0.4 L
• An aqueous solution of sodium carbonate, Na2CO3, contains 53 g of solute in 215 mL of solution. What is it concentration (M)?
solute = 53 g Na2CO3
solution = 215 mL
105.99 g Na2CO3
1 mol Na2CO3 = 0.5 mol Na2CO3
1000 mL
1 L= 0.215 L
= 2.3 MM = Moles L
M = 0.5 mol0.215 L
• How many moles of sugar are dissolved in 202 mL of a 0.150 M solution?
Molarity = 0.150 M
mol = M · L = (0.150 mol/L)(0.202 L)= 0.0303 mol C12H22O11
solution= 202ml1000ml1L = 0.202 L
M = Moles L
• A mass of 98 g of sulfuric acid, H2SO4, is dissolved in water to prepare a 0.50 M solution. What is the volume of the solution in liters ?
Molarity = 0.50 Msolute = 1.0mol H2SO4
= 2.0 L H2SO4
solute = 98 g H2SO4
98.08 g H2SO4
1 mol H2SO4= 1.0 mol H2SO4
mol = M · L
M = Moles L
L = Moles M
= 1.0mol
0.50 M
5. Molality (m or molal)
• Solute in moles and the mass of solvent in kilograms;
Density of water = 1 g/ 1 mL
1 mL = 1 g 1 L = 1 Kg 1000 g = 1 Kg
For water only!
m = Moles of solute Kg of solvent
What is the molality of a solution with 9.3 mole of NaCl in 450 g of water?mols of solute = 9.3 mol
9.3 mol
0.45 Kg = 21 m
solution= 450g1000g1Kg = 0.45kg
m = Moles kg
m =
• Determine the molality of a solution of 560. g of acetone, CH3COCH3, in 620 g of water.
9.6 mol
0.62 Kg = 15.5 m
solute = 560g CH3COCH3 58.09g1 mol
= 9.6 mol CH3COCH3
solution= 620g1000g1Kg = 0.62kg
m = Moles kg
=
Checking for understandingFormula Resulting units
g of solute/100mL of solventParts per million% by mass% by volumeMolarity Molality
Concentration of Solution• Dilution is the process of preparing a less concentrated
solution from a more concentrated one.
moles of solute before dilution = moles of solute after dilution
MiVi = MfVf
Making a Dilute Solution
Timberlake, Chemistry 7th Edition, page 344
initial solution
removesample
diluted solution
same number ofmoles of solutein a larger volume
mix
moles ofsolute
How would you prepare 60.0 mL of 0.2 MHNO3 from a stock solution of 4.00 M HNO3?
MiVi = MfVf
Mi = 4.00 mol/L Mf = 0.200mol/L Vf = 0.06 L Vi = ? L
Vi =MfVf
Mi
=(0.200mol/L ) ( 0.06L)
(4.00 mol/L)= 0.003 L = 3 mL HNO3
3 mL of HNO3 + 57 mL of water= 60 mL of solution
How to mix a Standard Solution
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 480
Wash bottle
Volume marker(calibration mark)
Weighedamount of solute
Process of Making a Standard Solution from Liquids
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 483
In an experiment, a student needs 250.0 mL of a 0.100 M CuCl2 solution. A stock solution of 2.00 M CuCl2 is available.
How much of the stock solution is needed?
To make the solution:
1) Pipet 12.5 mL of stock solution into a 250.0 mL volumetric flask.
2) Carefully dilute with water to the calibration mark.
MiVi = MfVf
Mi = 2.00 mol/L Mf = 0.100mol/L Vf = 250.0mL Vi = ? L
Vi =MfVf
Mi
=(0.100mol/L ) ( 2.50L)
(2.00 mol/L)= 0.0125 L = 12.5 mL CuCl2
Preparing Solutions
How to prepare 500 mL of 1.54 M NaCl solution–mass 45.0 g of NaCl– add water until total
volume is 500 mL500 mL
volumetricflask
500 mLmark
45.0 g NaClsolute
500 mLvolumetric
flask
Preparing Solutions
500 mL of 1.54M NaCl
500 mLwater
45.0 gNaCl
– mass 45.0 g of NaCl– add water until total volume is
500 mL
– mass 45.0 g of NaCl– add 0.500 kg of water
500 mLmark
1.54m NaCl in 0.500 kg of water
molality molarity
Colligative Properties
• A property that depends only upon the number of solute particles (concentration), and not upon their identity.
• Three Important Colligative Properties of Solutions.– Vapor-pressure lowering– Boiling-point elevation– Freezing-point depression
Vapor-Pressure Lowering• Vapor pressure: is the
pressure exerted by a vapor that is in dynamic equilibrium with its liquid in a closed system.– A solution that contains
a solute that is nonvolatile (not easily vaporized) always has a lower vapor pressure that the pure solvent.
• This is true because in a solution, solute particles reduce the number of free solvent particles able to escape the liquid.
Freezing-Point Depression
• Freezing-Point Depression: The difference in temperature between the freezing point of a solution and the freezing point of the pure solvent (water).– The presence of a solute in water disrupts the
formation of the orderly pattern of ice. – Therefore more kinetic energy must be withdrawn
from a solution than from the pure solvent to cause the solution to solidify.
– Solution containing solute causes decrease in freezing point.
Boiling-Point Elevation• Boiling Point: The temperature
at which the vapor pressure of the liquid phase equals atmospheric pressure.
• Boiling-Point Elevation: The difference in temperature between the boiling point of a solution and the boiling point of the pure solvent.
Boiling-Point Elevation• Because of the decrease in
vapor pressure, additional kinetic energy must be added to raise the vapor pressure of the liquid phase of the solution to atmospheric pressure to initiate boiling.
• The boiling point of a solution is higher than the boiling point of the pure solvent.
1) The higher the concentration of solute is, the higher the boiling point and the lower the freezing point will be.Which of the following solutions will boil at the
highest temperature?a) 100 g NaCl in 1000 g of water b) 100 g NaCl in 500 g waterc) 100 g NaCl in 250 g of water d) 100 g NaCl in 125 g of water
The answer is D because it has the highest concentration
2) The more particles that a solute ionizes into, the higher the boiling point and the lower the freezing point will be.
Which of the following solutions will boil at the highest temperature?
a) 1 mole C6H12O6 in 500 g of water
b) 1 mole KBr in 500 g of waterc) 1 mole MgF2 in 500 g of water
d) 1 mole AlCl3 in 500 g of water
The answer is D because AlCl3 breaks into 4 particles, the most of any of the choices.
Electrolyte
• Most ionic compounds and many acids dissolve well in water.
• These are called electrolytes, because they cause the solution to conduct electricity due to the free-moving ions.
• They ionize 100% in water to yield ions in a reaction that resembles a decomposition reaction.
• The reaction is called dissociation, and it is a physical change, not a chemical change.
• The more ions a solute breaks up into, the higher the boiling point and the lower the freezing point of the solution will be.
Electrolytes Free moving ions will conduct
electricityNaCl(s) Na+1(aq) + Cl-1
(aq)
2 moles ofdissolved ions total
Nonelectrolytes
• Substances formed from covalent bonding do not dissolve into ions upon entering the water.
• These include polar molecules that dissolve, but do not ionize.
• These include sugar (C6H12O6, C12H22O11), antifreeze (CH2OHCH2OH ) and alcohol (C2H5OH).
• These have less impact on the melting and boiling point of a solution than ionic compounds do, because they do not break up any further.
NonelectrolyteC12H22O11 (s) C12H22O11 (aq)
No ions are formed, so
no electricity can be
conducted.One mole of sucrose dissolves to form one mole of dissolved sucrose.