SLRB Pipe Culvert
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Transcript of SLRB Pipe Culvert
Page 1
DESIGN OF SLRB PIPE CULVERT @ KM 23.905 ON - D-12 DISTRIBUTORY OF LINK CANAL-- KOIL SAGAR LIFT IRRIGATION SCHEME STAGE - II
HYDRAULIC PARTICULARS OF CANAL
HYDRAULIC PARTICULARS U/S Units D/S Units
Discharge required 0.57 cumec 0.57 cumecDischarge designed 0.608 cumec 0.608 cumecBed width 1.80 M 1.80 MFull supply depth 0.55 M 0.55 MFree board 0.45 M 0.45 MSide slopes 1.5:1/1.5:1 1.5:1/1.5:1Bed fall I in 2500 I in 2500Value of n 0.025 0.025Canal bed level ( CBL) 365.096 365.096Full supply level ( FSL) 365.646 365.646Top bund level (TBL) 366.096 366.096Height of drop --- 0 MVelocity of flow 0.421 m/s 0.421 m/sGround level 367.393 Top width of Banks L/R 5/1.5 5/1.5
Road Level Existing 367.393 OKRevise RL
Dia of proposed pipe NP3 d 1 mThickness of pipe 0.115 mProposed Road width 4.25 mLength of the pipe proposed 5 mSill level of pipe 365.096Available depth of cushion 1.182 m
OK
Depth of Flow in pipe D 0.55 m
D/d 0.55
Area of flowd/2 0.5D-d/2 0.05Cos Q 0.1Q 84.22309992Q 168.4462sector Area 0.368 sqmTriangle Area 0.025 sqmnon flow area 0.343 sqmFlow Area 0.443 sqm
Velocity through pipe 1.3724605 m/s> 0.842 twice the velocityOK
Trench widthOuter dia pipe d1 1.23d1/4 0.3075d1/3 0.41Min 0.15
Free working space on each side 0.15 m
0.3075 m365.4035
365.0960.3075 m
364.7885Design of Head wall 1.53
Height of live load surcharge 2.297 mIRC Class A Loading
Vide IRC Bridge equalivalent height of surchrge for single Lane single lane bridge 0.2 14.3
4.7139 m 1 8.52 5.13 3.84 3
Length of abutment 4.5 m 6 2.2for SLRB Bridges 8 1.7
L'=Length of retaining wall 9.891 10 & above 1.4Say 9.9 m
Page 2
Actual surchrage 4.7139 *(L/L')*(1+sinQ)/(1-SinQ)*1/3*(1600/2100)1.770964726 m
Design of Head Wall367.693
TOP WIDTH : 0.375 367.393 WALL TOP LEVEL : 367.693 FOUNDATION TOP LEVEL : 365.096 FOUNDATION BOTTOM LEVEL : 364.789 EARTH SIDE WIDTH : 1.350 W1 W3 W4
EARTH SIDECONCRETE OFFSET : 0.150 Height of wall : 2.597 W2Thickness of the foundation : 0.308 WEIGHT OF CONCRETE/Masonry : 2.400 WEIGHT OF SOIL : 2.100 Horizantal Earth Coefficient : 0.134 A + 365.096 VERTICAL EARTH COEEFICENT : 0.039 W5 + 364.789 bottom width : 1.725 BTotal width of bottom foundation 2.025 0.38 1.35 0.150
1.732.025
TAKING MOMENTS AT (A):Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)W1 0.375 2.597 2.400 2.337 1.538 3.594 W2 0.500 1.350 2.297 2.400 3.721 0.900 3.349 W3 0.500 1.350 2.297 2.100 3.256 0.450 1.465 PV 0.0385 2.100 13.412 1.084 0 0.000
TOTAL VERTICAL FORCE 10.399 PH 0.1337 2.100 13.412 3.766 0.919 3.460
TOTAL 11.868
Base Width = 1.725 mLever arm = M / V = Total Moment / Vertical force = 1.141 mEccentricity = Lever arm-Base width/2 = 0.279 mEccentricity Limit = b / 6 = 0.288 Stress on Concrete :Direct stress = total vertical force/base width = 6.028
Bending stress = 5.845
STRESSES ON CONCRETE
max.stress = Direct stress + Bending stress = 11.87
Min. stress Direct stress - Bending stress = 0.18 TAKING MOMENTS ABOUT (B):Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)W1 As calculated above 2.337 1.613 3.769 W2 As calculated above 3.721 1.050 3.907 W3 As calculated above 3.256 0.525 1.709 W4 0.150 2.297 2.100 0.724 0.075 0.054 W5 2.025 0.308 2.400 1.494 1.013 1.513 Pv 0.0385 2.100 16.008 1.294 0.000 0.000
TOTAL VERTICAL FORCE 12.827 Ph 0.1337 2.100 16.008 4.495 1.042 4.683
TOTAL MOMENTS 15.635
Base Width = 2.025 mLever arm = M / V = Total Moment / Vertical force = 1.219 mEccentricity = Lever arm-Base width/2= 0.206 mEccentricity Limit = b / 6 = 0.337 Stress on Concrete : Direct stress = total vertical force/base width = 6.334
Bending stress = 3.875
STRESSES ON SOIL
max.stress = Direct stress + Bending stress = 10.21
Min. stress Direct stress - Bending stress = 2.46
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
Page 3
HYDRAULIC PARTICULARS OF CANAL
HYDRAULIC PARTICULARS U/S Units D/S Units
Discharge required 0.939 cumec 0.549 cumecDischarge designed 0.994 cumec 0.65 cumecBed width 1.90 M 1.60 MFull supply depth 0.70 M 0.60 MFree board 0.45 M 0.45 MSide slopes 1.5:1/1.5:1 1.5:1/1.5:1Bed fall I in 2500 I in 2500Canal bed level ( CBL) 384.697 383.497Full supply level ( FSL) 385.397 384.097Top bund level (TBL) 385.847 384.547Height of drop --- 1.2 MVelocity of flow 0.482 m/s 0.482 m/sGround level
Hydraulic calculations
Height of drop = 1.200 m
Throat width =1.9 m i.e. equal to bed width
Crest Level :( as per cl.8.2.3, eq-3,manual on canal falls)
Cd = coefficient of discharge = 1.84
LT = (Assumed) = 0.70 mD = 0.454
= 0.994 * 0.7 ^(1/6)/(1.84* 1.9 ))^(3/5)) 0.454
Depth of water (including velocity head) =0.454
U/S TEL =Va = U/S velocity = 0.482 m/sec
= 0.482 ^2/(2*9.81)0.012
U/S TEL = 385.397 + 0.012385.409
(as per cl.8.2.4, manual on canal falls)crest level = U/S TEL - D
385.409 - 0.454384.955
The height of crest above U/S CBL = 384.697 - 384.9550.258
DESIGN OF1.20 M VERTICAL DROP AT Km 6.040 on - D-5 DISTRIBUTORY OF LINK CANAL KOIL SAGAR LIFT IRRIGATION SCHEME STAGE - II
HL =
BT =
Q = Cd BTD3/2 X ( D/LT)1/6
D = [(Q x LT 1/6)/(Cd x B)]3/5
U/S FSL+Va2/2g
Va 2/2g
Page 4
= 0.4 x 0.7 0.280.258 < 0.28
Hence safeCistern Level and Length(as per cl.8.5.1.1, manual on canal falls)Depth of Cistern = 1/4 ( HL x D)2/3
= 1/4( 1.2 x 0.454 )^2/3= 0.167
Provide = 0.170 m
Minimum depth of cistern shall be 0.15m below D/S bed levelHence reduced level of cistern = 383.497 - 0.17
= 383.327(as per cl.8.5.1.1, manual on canal falls)Length of cistern = 5(HL x D)1/2
= 5( 1.2 x 0.454 )^1/2= 3.689 m 3.68943631
Provide = 3.700 mThe cistern is to be joined to the D/S bed level at a slope of 1:1
Scour depth calculation(a) Discharge per unit length (q) = Designed discharge
= 0.523
= 1.346x ( 0.523= 0.874 m
© Maximum scour depth = 1.5 x 0.874= 1.3 m
(d) depth of cut off below u/s CBL = U/S F.S.L - 1.5 x scour depth385.397 - 1.311384.086 - 384.697
= 0.61 mE. U/S scour level = 385.397 - 1.3
= 384.086 366.314(F)Depth of cut off below d/s CBL = 384.097 - 1.311
382.786 - 383.497= 0.71 m
provide = 0.70 m(g) D/S scour level = 383.497 - 0.70
= 382.797
(as per cl.9.3., manual on canal falls)Depth of curtain wall at the D/S end of cistern
D/S FSD/2= 0.6 \ 2 m= 0.300 m
Actually provided depth = 0.70 m
Length of Crest 0.55 x 384.955 - 383.327= 0.70 m
Actually provided = 0.70 m
hL = height of crest
hL should be< 0.4of FSD i.e
(b) Scour depth R = 1.346 x (q2/f)1/3 where f = silt factor = 1
2/1)^(1/3)
0.55 x (R.L of crest - R.L of cistern)1/2 =
Page 5
Crest wall Thickness at base 0.5 x (R.L of crest - R.L of cistern) = 0.5 x 384.955 - 383.327
= 0.814Provided = 0.814 m
Floor length of upstream approach = 1.5 x(U/S TBL - U/S CBL)= 1.5 x 385.847 - 384.697= 1.725 m
Provided = 1.725 m
Floor length from Exit Gradient consideration(As per clause 9.5.1 of canal falls manual)Safe exit gradient = 1 in 4
Max static head H = Difference between crest level and D/S bed level= 384.955 - 383.497= 1.458
The D/S curtain wall depth, d = 0.70 m
Total length of impervious floor b = 0.15 1.725 0.70 3.70 0.15= 6.425 m
Provide = 6.425 mα = b/d
= 6.425 \ 0.70= 9.179
λ =
= (1+ (1+ 9.179
= 5.116
== 0.241
Allowed GE 1 in 4 0.241 < 0.25Hence safe
UPLIFT PRESSURESAt U/S cut off wall
α = b/d= (Floor length / D/S cut off)= 6.425 \ 0.70= 9.179
λ = 5.116
== (1/180)cos^-1(( 5.116 2)/ 5.116
= ( 5.116 -2 )\ 5.116= 0.609= cos^-1 0.609= 52.502
= 1/180 x 52.502 x 100= 29.168 %
= 100 - 29.17= 70.832 %
(1+(1+α2)1/2)/22)^(1/2))/2
Exit gradient Ø H/D x 1(π x λ1/2)
ΦE (1/π)cos-1 ((λ-2)/λ)
(λ-2)/λ
cos-1((λ-2)/λ) ⁰
ΦE ⁰
ΦC
Page 6
Floor thicknessAt D/S face of crest WallLength from D/S cut off to the face of crest wall
= 6.425 0.15 + 1.725 + 0.700= 3.850
percentage pressure at toe of the crest == 29.17 + 70.83 - 29.17 x 3.850 \ 6.425
54.134 %Floor thickness at D/S face of crest wall = Percentage of pressure @ D/S toe x head acting /100
pressure acting = crest level - D/S CBL= 384.955 - 383.497= 1.458
Floor thickness taking 100% up lift= 54.13 x 1.458 x 1 / (1.4 x 100) Density of concrete - density of water
= 0.564 2.4 - 1
provide = 0.564 = 0.565 1.4
At the Middle of the floorLength of D/S cut off to the middle of floor = 3.850 \2 0.025
= 1.950percentage pressure at the middle of floor = 29.17 + 70.83 - 29.17 x 1.950 \ 6.425
= 41.813 %Thickness of the floor = 41.813 x 1.458 x 1/(100x1.4)
= 0.435 mProvide = 0.436 m
ΦE+(ΦC-ΦE) x length from D/S cut off / floor length
Design of drop wall
TOP WIDTH : 0.700
WALL TOP LEVEL : 384.955
FOUNDATION TOP LEVEL : 383.252 STRESS ON CONCRETE(t/m2)
FOUNDATION BOTTOM LEVEL : 382.952
EARTH SIDE WIDTH : 0.200 MAX. STRESS 7.760
CONCRETE OFFSET : 0.150 MIN. STRESS 0.820
Height of wall : 1.703 BASE WIDTH 0.900
Thickness of the foundation : 0.300 STRESS ON SOIL(t/m2)
WEIGHT OF CONCRETE/Masonry : 2.400
WEIGHT OF SOIL : 2.100
Horizantal Earth Coefficient : 0.1337 MAX.STRESS 7.160
VERTICAL EARTH COEEFICENT : 0.0385
bottom width : 0.900 MIN. STRESS 1.760
Total width of bottom BASE WIDTH 1.200
foundation : 1.200
+ 384.955
W1 W3 W4
EARTH SIDE
1.703 W2
A + 383.252
0.300 W5 + 382.952
B
0.150 0.70 0.20 0.150
0.90
1.200
TAKING MOMENTS AT (A):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 0.700 1.703 2.400 2.861 0.550 1.574
W2 0.500 0.200 1.703 2.400 0.409 0.133 0.054
W3 0.500 0.200 1.703 2.100 0.358 0.067 0.024
PV 0.0385 2.100 2.901 0.235 0 0.000
TOTAL VERTICAL FORCE 3.862
PH 0.1337 2.100 2.901 0.814 0.681 0.555
DESIGN OF1.20 M VERTICAL DROP AT Km 6.040 on - D-5 DISTRIBUTORY OF LINK CANAL KOIL SAGAR LIFT IRRIGATION SCHEME STAGE - II
TOTAL 2.207
Base Width = 0.900 m
Lever arm = M / V = Total Moment / Vertical force = 0.571 m
Eccentricity = Lever arm-Base width/2 = 0.121 m
Eccentricity Limit =b / 6 = 0.150
Stress on Concrete :
Direct stress = total vertical force/base width = 4.291
Bending stress = 3.473
STRESSES ON CONCRETE
max.stress = Direct stress + Bending stress = 7.764
Min. stress Direct stress - Bending stress = 0.818
TAKING MOMENTS ABOUT (B):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 As calculated above 2.861 0.700 2.003
W2 As calculated above 0.409 0.283 0.116
W3 As calculated above 0.358 0.217 0.077
W4 0.150 1.703 2.100 0.536 0.075 0.040
W5 1.200 0.300 2.400 0.864 0.600 0.518
Pv 0.0385 2.100 4.012 0.324 0.000 0.000
TOTAL VERTICAL FORCE 5.353
Ph 0.1337 2.100 4.012 1.127 0.981 1.105
TOTAL MOMENTS 3.860
Base Width = 1.200 m
Lever arm = M / V = Total Moment / Vertical force = 0.721 m
Eccentricity = Lever arm-Base width/2= 0.121 m
Eccentricity Limit =b / 6 = 0.200
Stress on Concrete : 0.167
Direct stress = total vertical force/base width = 4.460
Bending stress = 2.703
STRESSES ON SOIL
max.stress = Direct stress + Bending stress = 7.16
Min. stress Direct stress - Bending stress = 1.76
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
U/S WING & RETURN WALL
TOP WIDTH : 0.450
WALL TOP LEVEL : 367.693
FOUNDATION TOP LEVEL : 365.096 STRESS ON CONCRETE(t/m2)
FOUNDATION BOTTOM LEVEL : 364.796
EARTH SIDE WIDTH : 1.100 MAX. STRESS 12.490
CONCRETE OFFSET : 0.150 MIN. STRESS 0.440
Height of wall : 2.597 BASE WIDTH 1.550
Thickness of the foundation : 0.300 STRESS ON SOIL(t/m2)
WEIGHT OF CONCRETE/Masonry : 2.400
WEIGHT OF SOIL : 2.100
Horizantal Earth Coefficient : 0.1337 MAX.STRESS 9.100
VERTICAL EARTH COEEFICENT : 0.0385
bottom width : 1.550 MIN. STRESS 3.800
Total width of bottom BASE WIDTH 1.850
foundation : 1.850
+ 367.693
W1 W3 W4
EARTH SIDE
2.597
W2
A + 365.096
0.300 W5 + 364.796
B
0.150 0.45 1.10 0.150
1.55
1.850
TAKING MOMENTS AT (A):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 0.450 2.597 2.400 2.805 1.325 3.716
W2 0.500 1.100 2.597 2.400 3.428 0.733 2.514
W3 0.500 1.100 2.597 2.100 3.000 0.367 1.100
PV 0.0385 2.100 9.772 0.790 0 0.000
TOTAL VERTICAL FORCE 10.022
PH 0.1337 2.100 9.772 2.744 1.039 2.850
DESIGN OF1.20 M VERTICAL DROP AT Km 6.040 on - D-5 DISTRIBUTORY OF LINK CANAL KOIL SAGAR LIFT IRRIGATION SCHEME STAGE - II
TOTAL 10.180
Base Width = 1.550 m
Lever arm = M / V = Total Moment / Vertical force = 1.016 m
Eccentricity = Lever arm-Base width/2 = 0.241 m
Eccentricity Limit =b / 6 = 0.258
Stress on Concrete :
Direct stress = total vertical force/base width = 6.466
Bending stress = 6.026
STRESSES ON CONCRETE
max.stress = Direct stress + Bending stress = 12.492
Min. stress Direct stress - Bending stress = 0.440
TAKING MOMENTS ABOUT (B):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 As calculated above 2.805 1.475 4.137
W2 As calculated above 3.428 0.883 3.028
W3 As calculated above 3.000 0.517 1.550
W4 0.150 2.597 2.100 0.818 0.075 0.061
W5 1.850 0.300 2.400 1.332 0.925 1.232
Pv 0.0385 2.100 6.744 0.545 0.000 0.000
TOTAL VERTICAL FORCE 11.928
Ph 0.1337 2.100 6.744 1.894 1.339 2.535
TOTAL MOMENTS 12.544
Base Width = 1.850 m
Lever arm = M / V = Total Moment / Vertical force = 1.052 m
Eccentricity = Lever arm-Base width/2= 0.127 m
Eccentricity Limit =b / 6 = 0.308
Stress on Concrete : 0.167
Direct stress = total vertical force/base width = 6.447
Bending stress = 2.648
STRESSES ON SOIL
max.stress = Direct stress + Bending stress = 9.10
Min. stress Direct stress - Bending stress = 3.80
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
D/S WING & RETURN WALL
TOP WIDTH : 0.450
WALL TOP LEVEL : 384.547
FOUNDATION TOP LEVEL : 383.252 STRESS ON CONCRETE(t/m2)
FOUNDATION BOTTOM LEVEL : 382.952
EARTH SIDE WIDTH : 0.700 MAX. STRESS 4.070
CONCRETE OFFSET : 0.150 MIN. STRESS 2.140
Height of wall : 1.295 BASE WIDTH 1.150
Thickness of the foundation : 0.300 STRESS ON SOIL(t/m2)
WEIGHT OF CONCRETE/Masonry : 2.400
WEIGHT OF SOIL : 2.100
Horizantal Earth Coefficient : 0.1337 MAX.STRESS 4.130
VERTICAL EARTH COEEFICENT : 0.0385
Bottom width : 1.150 MIN. STRESS 2.900
Total width of bottom BASE WIDTH 1.450
foundation : 1.450
+ 384.547
W1 W3 W4
EARTH SIDE
1.295
W2
A + 383.252
0.300 W5 + 382.952
B
0.150 0.45 0.70 0.150
1.15
1.450
TAKING MOMENTS AT (A):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 0.450 1.295 2.400 1.399 0.925 1.294
W2 0.500 0.700 1.295 2.400 1.088 0.467 0.508
W3 0.500 0.700 1.295 2.100 0.952 0.233 0.222
PV 0.0385 2.100 1.677 0.136 0 0.000
TOTAL VERTICAL FORCE 3.574
PH 0.134 2.100 1.677 0.471 0.518 0.244
DESIGN OF1.20 M VERTICAL DROP AT Km 6.040 on - D-5 DISTRIBUTORY OF LINK CANAL KOIL SAGAR LIFT IRRIGATION SCHEME STAGE - II
TOTAL 2.267
Base Width = 1.150 m
Lever arm = M / V = Total Moment / Vertical force = 0.634 m
Eccentricity = Lever arm-Base width/2 = 0.059 m
Eccentricity Limit =b / 6 = 0.192
Stress on Concrete :
Direct stress = total vertical force/base width 3.108
Bending stress = 0.964
STRESSES ON CONCRETE
max.stress = Direct stress + Bending stress 4.071
Min. stress Direct stress - Bending stress = 2.144
TAKING MOMENTS ABOUT (B):
Force Particulars Magnitude Lever Moment
(T) Arm(M) (T-M)
W1 As calculated above 1.399 1.075 1.503
W2 As calculated above 1.088 0.617 0.671
W3 As calculated above 0.952 0.383 0.365
W4 0.150 1.295 2.100 0.408 0.075 0.031
W5 1.450 0.300 2.400 1.044 0.725 0.757
Pv 0.0385 2.100 2.544 0.206 0.000 0.000
TOTAL VERTICAL FORCE 5.096
Ph 0.1337 2.100 2.544 0.714 0.818 0.584
TOTAL MOMENTS 3.911
Base Width = 1.450 m
Lever arm = M / V = Total Moment / Vertical force = 0.767 m
Eccentricity = Lever arm-Base width/2= 0.042 m
Eccentricity Limit =b / 6 = 0.242
Stress on Concrete :
Direct stress = total vertical force/base width 3.514
Bending stress = 0.618
STRESSES ON SOIL
max.stress = Direct stress + Bending stress 4.13
Min. stress Direct stress - Bending stress = 2.90
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
(6 x vertical force x eccentricity) / b2 =
t/m2
t/m2
OFFICE NOTE
Subject :
Ref : 1. IVRCL letter No M/S IVRCL/Koil sagar/stage-II/link canal/2010-11/ Dt:
2. Dy.EE JLIP Sub - divn (3) letter No DEE/SD3/MBNR/ Dt :
It is submitted that design calculation of 1.50m vertical drop @ Km 2.20 on D-64
distributory of left canal are checked and found the following observations.
1 H.P'S
H.P'S are verified with approved alignment and found correct & some corrections are made in discharge required, discharge designed, bed width, full supply depth,freeboard, side slopes, canal bed level in U/S & D/S, velocity of flow, height of drop etc
2 DESIGN CALCULATIONS
S.NO DESCRIPTION Remarks
1 2 3 4 51 Crest level 384.955 384.9552 cistern level 383.327 383.3273 cistern length in mts 3.7 3.74 Scour depth U/S 366.314 366.314 not shown in drawing
5 Scour depth D/S 382.797 382.797
6 0.70 0.707 Thickness of crest wall at base in mts 0.81 0.81
8 floor length of the U/S approach in mts 1.725 1.725
9 Exit gradient 0.243 0.24110 Floor thickness at the D/S face of the crest in mts 0.565 0.565
11 Floor thickness at middle of the floor 0.31 0.436
12 Stability calculation --- --- ---
13 drop wall stress on concrete --- --- ---
14 i) max stress in t/sqmt 7.75 7.76015 ii) min stress in t/sqmt 0.83 0.82016 Drop wall stress on soil --- --- ---
17 i) max stress in t/sqmt 6.66 7.16018 ii) min stress in t/sqmt 1.81 1.76019 U/S wing & return wall stress on concrete --- --- ---
20 i) max stress in t/sqmt 6.52 12.49021 ii) min stress in t/sqmt 0.41 0.44022 U/S wing & return wall stress on soil --- --- ---
23 i) max stress in t/sqmt 5.39 9.10024 ii) min stress in t/sqmt 1.43 3.80025 D/S wing wall (max section) stress on concrete --- --- ---
26 i) max stress in t/sqmt 12.66 #NAME?27 ii) min stress in t/sqmt 0.08 #NAME?
Design of 1.20M Vertical Drop @ KM 6.04 On D - 5 Distributory Linkt canal Koilsagar project Stage - II approval accorded regarding…
As per agency's calculations
As per Department calculations
length of the crest against the assumed length 0.74 in mts
assumed is accepted
permitted in between 0.20 to
0.25
due to error in calculation
1 Crest level 384.955 384.9552 cistern level 383.327 383.327
28 D/S wing wall (max section) stress on soil --- --- ---
29 i) max stress in t/sqmt 9.78 #NAME?30 ii) min stress in t/sqmt 2.36 #NAME?31 D/S wing & return wall stress on concrete --- --- ---
32 i) max stress in t/sqmt 5.78 4.07033 ii) min stress in t/sqmt 0.71 2.14034 D/S wing & return wall stress on soil --- --- ---
35 i) max stress in t/sqmt 4.84 4.13036 ii) min stress in t/sqmt 1.61 2.90037 thickness of the foundation --- --- ---
38 U/S wing wall in mts 0.15 0.30039 Drop wall in mts 0.15 0.30040 D/S wing wall (max section) inmts 0.15 #NAME?41 D/S wing wall in mts 0.15 0.30042 grade of concrete for foundation M-15
43 grade of concrete for apron M-15
44 M-15
on approval the designs and drawings will be corrected as per the calculations
noted in the column no(4) of the above.
submitted for perusal and approval please.
Executive Engineer
JLIP Division No.1 Mahabubnagar.
M-10 using 40mm metal
M-10 using 40mm metal
grade of concrete for abutment, wings, returns & drop wall
M-10 using 40mm metal max size graded metal
\
D/d 0 0.01 0.02 0.03 0.04 0.05 0.06 0.070 0 0.00130.1 0.0409 0.0470.2 0.1118 0.11990.3 0.1982 0.20740.4 0.29340.5 0.3930.6 0.4920.7 0.5870.8 0.6740.9 0.745
0.08 0.09