Reinforced Concrete Beam - Column Joint: Macroscopic Super...
Transcript of Reinforced Concrete Beam - Column Joint: Macroscopic Super...
Reinforced Concrete Beam-Column Joint: Macroscopic
Super-element models
-Nilanjan Mitra
(work performed as a PhD student while at University of Washington between 2001-2006)
Need for the study
Reinforced concrete beam column jointssubjected to earthquake loading
Experimental Investigation@ UW
I-280 Freeway, San Francisco, CAfollowing Loma Prieta Earthquake in 1989
Courtesy: NISEE, Univ. of California, Berkeley.
Loading in a joint region
Earthquake Loading of Beam-Column Joint
compression resultant (concrete and steel)
shear resultant (concrete)
Earthquake Loading of Beam-Column Joint
compression resultant (concrete and steel)
compression resultant (concrete and steel)
shear resultant (concrete)
shear resultant (concrete) tension resultant (steel)
anchorage bond stress acting on joint core concrete
compression force carried by joint core concrete
Internal load distribution in a joint
Macroscopic beam-column joint element models
Macroscopic beam-column joint element models
Macroscopic beam-column joint element models
shear panel
external node
internal node
rigid externalinterface plane
shown with finite widthto facilitate discussion
beam element
zero-width region
interface-shear spring
bar-slip spring
zero-length
zero-length
elem
ent
colu
mn
Proposed Beam-column super-element model• 4-noded 12-dof element• 8 bar-slip springs to simulate
anchorage failure• 4 interface-shear springs to simulate
shear transfer failure at joint interface• 1 shear-panel to simulate inelastic
action of shear within joint core
Note: The location of the bar-slipsprings is at the centroid of thetension-compression couple at nominalstrength of the beams.
[Mitra & Lowes; J. Structural Eng. ASCE, 2007: 133 (1): 105-20 ]
Joint element formulation: Kinematics
External, Internal and Component deformation
Joint element formulation: Equilibrium
External, Internal and Component forces
Solution of element state achieved by an iterative procedure and requires solving for zero reaction in the 4 internal degrees of freedom
Characterized by Response envelope Unload reload path Damage rules
Hysteretic one dimensional material model
deformation
load
(ePd1,ePf1)
(ePd4,ePf4)
(ePd3,ePf3)(ePd2,ePf2)
(eNd3,eNf3)(eNd2,eNf2)
(*,uForceP.ePf3)
(dmin,f(dmin))
(dmax,f(dmax))
(rDispP.dmax,rForceP.f(dmax))
(rDispN.dmin,rForceN.f(dmin))
(*,uForceN.eNf3)
(eNd1,eNf1)
(eNd4,eNf4)
Damage simulation in material model
-0.015 -0.01 -0.005 0 0.005 0.01 0.015-8
-6
-4
-2
0
2
4
6
8
deformation
load
without damagewith unloading stiffness damage
-0.015 -0.01 -0.005 0 0.005 0.01 0.015-8
-6
-4
-2
0
2
4
6
8
deformationlo
ad
without damagewith reloading stiffness damage
-0.015 -0.01 -0.005 0 0.005 0.01 0.015-8
-6
-4
-2
0
2
4
6
8
deformation
load
without damagewith strength damage
( ) ( )( )3 4
1 max 2i dα αδ α α χ= +
max minmax
max min
max. ,i id dd
def def
=
( ).f No of load cyclesχ =
( )f Accumulated Energyχ =
( )0 1 ki ik k δ= −
( ) ( ) ( )max max 01 f
iif f δ= −
( ) ( ) ( )max max 01 d
iid d δ= +
Damage simulation in material model
load historyi
monotonic
monotonic load history
dEE
EgE dE
χ = =
∫
∫
-0.015 -0.01 -0.005 0 0.005 0.01 0.015-8
-6
-4
-2
0
2
4
6
8
deformation
load
without damagewith all 3 damage rules
-0.015 -0.01 -0.005 0 0.005 0.01 0.015-5
-4
-3
-2
-1
0
1
2
3
4
5
deformation
load
with all 3 damages (Energy)with all 3 damages (Cyclic)
max4duu
χ =∑
Energy criterion
No. of load cycle criterion: rain-flow-counting algorithm
Shear-panel calibration
column
shear panel
• Shear panel envelope calibration• MCFT• Diagonal compression strut
• Compression envelope reduction
• Determination of hysteretic model parameters
Typical response envelope
Observed Simulated
Spec
imen
SE8
(S
teve
ns e
t al.
1987
)
-0.012 -0.008 -0.004 0 0.004 0.008 0.012-10
-8
-6
-4
-2
0
2
4
6
8
10
Shear strain
Shea
r st
ress
(MPa
)
Shear panel envelope calibration using proposedDiagonal compression strut mechanism
_ cosc strut strut strutstrut
jnt
f ww
ατ
⋅ ⋅=
• Mander et al. (1988) concrete
• Column longitudinal and joint hoop
steel confine the strut.
• Reduction in concrete to account for
perpendicular tensile stress to the strut
cyclic loading.
• Strut force is converted to panel shear
stress as
2_
_3.62 2.82 1 0.39
0.45 0.39
c strut t t t
c Mander cc cc cc
t
cc
ff
ε ε εε ε ε
εε
= − + ∀ <
= ∀ ≥
Proposed concrete compression envelope reduction
0 1 2 3 4 5 60
0.2
0.4
0.6
0.8
1
εt / εcc
f c_ob
s / f c_
Man
der
Data with ρj > 0
Data with ρj = 0
Vecchio 1986Stevens 1991Hsu 1995Noguchi 1992Proposed eq. for ρ
j > 0
Proposed eq. for ρj = 0
2_
_0.36 0.60 1 0.83
0.75 0.83
c strut t t t
c Mander cc cc cc
t
cc
ff
ε ε εε ε ε
εε
= − + ∀ <
= ∀ ≥
0jρ =0jρ >Eq. for Eq. for
Comparison of MCFT and Diagonal Compression Strut model in shear-panel envelope calibration
0 0.5 1 1.5 2 2.50
0.5
1
1.5
2
2.5
φ
τ mcf
t_cy
clic
/ τ m
ax
0.55JFBYJFBY
0 0.5 1 1.5 2 2.50
0.5
1
1.5
2
φ
τ diag
onal
_stru
t / τ
max
JFBYJFBY
[Lowes, Altoontash and Mitra, J. Structural Eng. ASCE, 2005: 131 (6) ]
Transverse steel contribution to shear stress
Bar slip material model calibration
column
Bar-slip spring• Mechanistic model :- envelope
• Hysteretic model calibration
• Strength deterioration model
-2 0 2 4 6 8 10 12 14 16-1000
-500
0
500
1000
slip (mm)
bar-
spri
ng fo
rce
(kN
)
Typical response envelope
Bar slip mechanistic model
Assumptions for anchorage response of bond within the joint region:
• Bond stress uniform for elastic reinforcement, piecewise uniform for reinforcement
loaded beyond yield
• Slip is the relative movement of reinforcement bar with respect to the joint perimeter
• Slip is a function of strain distribution in the joint
• Bar exhibits zero slip at zero bar stress
2
0
2fsl
fsE b Eslip s y
b b
ldd x dx f fA E E d
τ π τ⋅= = ∀ <
⋅∫
( )0
e ye
e
l llyE b Y b
slip eb b hl
fd dd x dx x l dxA E E A E
τ π τ π+ ⋅ ⋅
= + + − ⋅ ⋅ ∫ ∫
22
2 2y y yeE Ys y
b b
f l ll f fE d E E dτ τ
= + + ∀ ≥Mechanistic model
Strength deterioration– Is activated once slip exceeds the slip level corresponding to ultimate stress
in the reinforcing bars.– Is observed upon reloading, with the result that bar-slip springs always
exhibit positive tangent stiffness.
0 5 10 15 200
1
2
3
4
5
specimen number
max
imum
slip
/
slip
with
anc
hora
ge le
ngth
equ
al to
join
t wid
th
BYJFBY
0 5 10 15 200
5
10
15
20
specimen number
Sim
ulat
ed m
axim
um b
ar-s
lip
BYJFBY
( )max, lim max,f f
i i ult i ultd d d dδ α δ= − ≤ ∀ ≥
Strength deterioration calibration for bar-slip spring
Steps for calibrating the joint model• Calculate moment curvature of beams and columns• From moment curvature analysis determine
• moment associated with first yield of the reinforcing bar• tension-compression couple distance at nominal yield strength• neutral axis depth at nominal yield strength
• Define joint elements parameters using joint geometry and tension-compression couple distance
• Determine concrete compression strut response• Mander model for concrete• Concrete strength reduction eq. proposed to account for perpendicular cracks
and cyclic loading• Hysteretic parameters defined for shear panel
• Determine bar-slip response• Mechanistic model for bond• Hysteretic parameters defined for bar-slip model
• Interface slip-springs are defined to be stiff and elastic
Concrete Stress-Strain(Compressive only, no tensile strength)
Reinforcing Steel Stress-Strain
Beam-Column Elements:Force based lumped plasticity element
Plastic Hinge region
Elastic region
Fiber discretisation
joint element
plastic hinge length
column axial load applied under load control
beam-column element
lateral load applied under displacement
control
Model simulationL
ab te
st
OpenSees Model
Validation study
-6 -4 -2 0 2 4 6-300
-200
-100
0
100
200
300
Drift (%)
Col
umn
shea
r (kN
)
-6 -4 -2 0 2 4 6-300
-200
-100
0
100
200
300
Drift (%)
Col
umn
shea
r (kN
)
-6 -4 -2 0 2 4 6-300
-200
-100
0
100
200
300
Drift (%)
Col
umn
shea
r (kN
)Specimen OSJ10:
Validation study discussion & conclusion• Failure mechanism
– For joints exhibiting JF (joint failure prior to beam yielding), 82% accurate.
– For joints exhibiting BYJF (beam yielding followed by joint failure), 89% accurate.
– For joints exhibiting BY (beam yielding), 94% accurate.• Initial and unloading stiffness
– For all joints, mean of simulated to observed ranges from 1.03 to 1.06 with an average C.O.V. = 0.15.
• Post-yield tangent stiffness– For joints that exhibit BYJF, mean ratio of simulated to observed is 1.0
with a C.O.V. = 0.22.• Maximum strength
– For all joints, mean of simulated to observed is 1.03 with a C.O.V. = 0.17.
• Drift at maximum strength– For all joints, mean of simulated to observed is 1.12 with a C.O.V. =
0.27.• Strength at final drift level
– For all joints, strength for final drift cycle is 1.04 with a C.O.V = 0.2.• Pinching ratio (ratio of strength at zero drift to maximum strength)
– For all joints, pinching ratio is 1.04 with a C.O.V = 0.12.