Radiation Heat Transfer Experimentcourses.washington.edu/me331afe/Radiation_Exp_Cochran.pdf ·...
Transcript of Radiation Heat Transfer Experimentcourses.washington.edu/me331afe/Radiation_Exp_Cochran.pdf ·...
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Radiation Heat Transfer ExperimentThermal Network Solution with TNSolver
Bob CochranApplied Computational Heat Transfer
Seattle, [email protected]
ME 331 Introduction to Heat TransferUniversity of Washington
November 15, 2016
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Outline
I Radiation ExperimentI Math ModelI Thermal Network Model for TNSolverI A Sample TNSolver Calculation
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Radiation Experiment OverviewRadiation Experiment
I Boil water with a radiative heaterI Measure temperatures and evaporation rateI Determine the heat flux from heater to target using boiling
curve and measured temperaturesI Determine view factors and simulate heat transfer with
TNSolver model
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Radiation Experiment Test FixtureRadiation Experiment
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Heater GeometryRadiation Experiment
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Shield GeometryRadiation Experiment
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Target GeometryRadiation Experiment
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MeasurementsRadiation Experiment
For each target material:
I Heater temperatureI Water evaporation rateI Ambient air temperatureI Distance from target to heater
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Convection CorrelationsMath Model
The heat flow rate is:
Q = hA(Ts − T∞)
where h is the heat transfer coefficient, Ts is the surfacetemperature and T∞ is the fluid temperature.Correlations in terms of the Nusselt number are often used todetermine h:
Nu =hLc
kh =
kNuLc
where Lc is a characteristic length associated with the fluid flowgeometry.
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External Natural Convection: Horizontal Plate UpMath Model
The heat transfer coefficient for laminar flow, 104 . RaL . 107,from a hot plate, Ts > T∞, is (see [LM74] and [RL01]):
NuL = 0.54Ra1/4L (1)
and for turbulent flow, 107 . RaL . 1011, from a hot plate is:
NuL = 0.15Ra1/3L (2)
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External Natural Convection: Horizontal Plate UpMath Model
For a cold plate, Ts < T∞, 104 . RaL . 109, the correlation is(see [LM74] and [RL01]):
NuL = 0.52Ra1/5L (3)
Then the Rayleigh number, RaL, where L = A/P, is:
RaL = GrPr =gρ2cβL3 (Ts − T∞)
kµ=
gβL3 (Ts − T∞)
να(4)
Note that the fluid properties are evaluated at the filmtemperature, Tf :
Tf =Ts + T∞
2(5)
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External Natural Convection: Horizontal Plate DownMath Model
The heat transfer coefficient for laminar flow, 104 . RaL . 107,from a cold plate, Ts < T∞, is (see [LM74] and [RL01]):
NuL = 0.54Ra1/4L (6)
and for turbulent flow, 107 . RaL . 1011, from a cold plate is:
NuL = 0.15Ra1/3L (7)
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External Natural Convection: Horizontal Plate DownMath Model
For a hot plate, Ts > T∞, 104 . RaL . 109, the correlation is(see [LM74] and [RL01]):
NuL = 0.52Ra1/5L (8)
Then the Rayleigh number, RaL, where L = A/P, is:
RaL = GrPr =gρ2cβL3 (Ts − T∞)
kµ=
gβL3 (Ts − T∞)
να(9)
Note that the fluid properties are evaluated at the filmtemperature, Tf :
Tf =Ts + T∞
2(10)
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External Natural Convection: Inclined Plate UpMath Model
Hot
θ
g
Cold
θ
StableUnstable
L L
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External Natural Convection: Inclined Plate UpMath Model
Stable Case, Ts < T∞:
The Nusselt number correlation for natural convection flow froma vertical plate (see [CC75]), with Rayleigh number:
RaL = GrPr =(g cos θ)ρ2cβL3 (Ts − T∞)
kµ
Note that the fluid properties are evaluated at the filmtemperature, Tf :
Tf =Ts + T∞
2
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External Natural Convection: Inclined Plate UpMath Model
Unstable Case, Ts > T∞:
The approach of Raithby and Hollands [RH98] is used. In thisapproach the heat transfer coefficient is evaluated for both avertical plate with g cos θ (see the stable case) and a horizontalplate with g cos(90− θ). The maximum of the two is then used.
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Net Radiation Method for EnclosuresMath Model
I The enclosure geometry is approximated by a set of Nideal surfaces
I Diffuse gray emission/absorptionI Diffuse gray reflectionsI Each surface is isothermal, with uniform heat flux
1
2
3
4
5
6
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View Factor PropertiesMath Model
Summation Rule (Equation (10.12), page 539 in [LL16]):
N∑i=1
Fij = 1
Reciprocity Rule (Equation (10.15), page 540 in [LL16]):
AiFij = AjFji
Addition of View Factors for Subdivided Surfaces (seeExample 10.4, page 550 in [LL16]):
Fi(j) =N∑
k=1
Fik
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Oppenheim Network for Three SurfacesMath Model
1
23
eb3
eb1
eb2
J1
J2J3
1−ε1ε1A1
1−ε2ε2A2
1−ε3ε3A3
1A1F13
1A1F12
1A2F23
A.K. Oppenheim, ”Radiation Analysis by the Network Method,”Transactions of the ASME, vol. 78, pp. 725–735, 1956
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TNSolver Thermal Network ModelTNSolver Input File
water
target
shield
heater
h-e
t-e
h-t
h-s
s-e
t-w
env
env
t-s
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External Natural Convection (ENC): Horizontal PlateUpTNSolver Input File
Qij = hA(Ts − T∞)
Heat transfer coefficient, h, is evaluated using the correlationfor external natural convection from horizontal plate facing up.
Begin Conductors! Ts Tinf! label type nd_i nd_j parameters
(S) ENChplateup (S) (S) (S) (R) (R) ! mat, L=A/P, A
End Conductors
Note that Ra, Nu and h are reported in the output file.21 / 31
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External Natural Convection (ENC): Horizontal PlateDownTNSolver Input File
Qij = hA(Ts − T∞)
Heat transfer coefficient, h, is evaluated using the correlation forexternal natural convection from horizontal plate facing down.
Begin Conductors! Ts Tinf! label type nd_i nd_j parameters
(S) ENChplatedown (S) (S) (S) (R) (R) ! mat, L=A/P, A
End Conductors
Note that Ra, Nu and h are reported in the output file.22 / 31
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External Natural Convection (ENC): Inclined Plate UpTNSolver Input File
Qij = hA(Ts − T∞)
Heat transfer coefficient, h, is evaluated using the correlation forexternal natural convection from horizontal plate facing down.
Begin Conductors! Ts Tinf! label type nd_i nd_j parameters(S) ENCiplateup (S) (S) (S) (R) (R) (R) (R) ! mat, H, L=A/P,
! angle, A
End Conductors
Note that Ra, Nu and h are reported in the output file.
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Radiation EnclosureTNSolver Input File
Each radiation enclosure is described by the surface labels,emissivities, areas and the view factor matrix [F ]:
Begin Radiation Enclosure
! label emiss area view factor matrix entries(S) (R) (R) (R ...)
End Radiation Enclosure
The generated radiation conductors are reported in the outputfile.
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Example Input FileTNSolver Input File
Begin Solution Parameters
title = Radiation Heat Transfer Experiment - Black Targettype = steadynonlinear convergence = 1.0e-8maximum nonlinear iterations = 50
End Solution Parameters
Begin Conductors
! Conduction through the beaker wall, 0.1" thick pyrex glasst-bbin conduction targ bbin 0.14 0.00254 0.024829 ! k L A
! Convection from beaker to water! label type nd_i nd_j mat L A
t-w ENChplateup bbin water water 0.04445 0.02483! Convection from target to air! label type nd_i nd_j mat L A
t-air ENChplatedown targ env air 0.0889 0.0248! Convection from outer shield to air! label type nd_i nd_j mat H L=A/P theta A
s-air ENCiplateup s_out env air 0.0508 0.0364 48.0 0.056439! Conduction from inner to outer side of shield
shield conduction s_in s_out steel 0.001 0.056439 ! mat L A
End Conductors
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Example Input File (continued)TNSolver Input File
Begin Radiation Enclosure
! surf emiss A Fijhtr 0.92 0.06701 0.0 0.1264 0.68415 0.0 0.1893targ 0.95 0.02482 0.34132 0.0 0.00603 0.1031 0.5494s_in 0.28 0.05643 0.81231 0.00265 0.12278 0.0 0.0622s_out 0.28 0.05643 0.0 0.0453 0.0 0.0 0.9546env 1.0 0.1184 0.10711 0.1151 0.02965 0.4547 0.2933
End Radiation Enclosure
Begin Boundary Conditions
! type Tb Node(s)fixed_T 23.0 envfixed_T 88.3 waterfixed_T 515.0 htr
End Boundary Conditions
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Black Target Test DataSample Simulation
Heater Emissivity = 0.92 @ 500 CTarget Emissivity = 0.95 (black) @ 150 C
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Black Target Water Evaporation RateSample Simulation
MATLAB: polyfit(time, vol, 1)
Evaporation Rate = 0.093793E-6 m3/s
Water density (at 88.3 C) ρ = 967 kg/m3
Water latent heat of vaporization, hfg = 2,256,000 J/kg
Q = 967*0.093793E-6*2,256,000 = 205 W
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Black Target View Factors, FijSample Simulation
Target to heater distance = 0.15m
Area (m2) Emissivity, εheater 0.06701 0.92target 0.02483 0.95shield 0.05644 0.28env 0.1185 1.0
View Factor Matrix, [F ]
heater target s in s out envheater 0 0.1265 0.6842 0 0.1894target 0.3413 0 0.006039 0.1032 0.5494s in 0.8123 0.002657 0.1228 0 0.06224s out 0 0.0454 0 0 0.9546env 0.1071 0.1151 0.02965 0.4547 0.2934
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Thermal Network SolutionSample Simulation
targ175.2896 C
bbin93.4483 C
t-bbin112.002 W
env23 C
t-air14.9925 W
targ-env27.4748 W
s_out271.9509 C
targ-s_out-1.8498 W
s_in272.0268 C
targ-s_in-0.50431 W
water88.3 C
t-w112.002 W
s-air149.2228 W
s_out-env69.0466 W
s_in-env6.1532 W
shield219.9199 W
s_in-s_out7.8806e-07 W
htr515 C
htr-targ152.1152 W
htr-env311.067 W
htr-s_out0.19928 W
htr-s_in226.5773 W
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Conclusion
I Radiation experiment overviewI Math model components for heat transfer analysisI TNSolver input file specificsI Sample simulation results for an experimental data set
Questions?
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Appendix
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Surface Properties for Radiation Heat TransferAppendix
I All surfaces emit thermal radiation.I The emittance, ε, is the ratio of actual energy emitted to
that of a black surface at the same temperature.I All radiation impinging on a surface will either be reflected,
absorbed or transmitted.I Reflectance or reflectivity, ρ, is the amount reflected.I Absorptance or absorptivity, α, is the amount absorbed.I Transmittance or transmissivity, τ , is the amount
transmitted through the material.
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Surface Properties for Radiation Heat Transfer(continued)Appendix
Summation property for all incident radiation:
ρ+ α+ τ = 1
An opaque surface has τ = 0, so ρ+ α = 0.
Kirchoff’s law provides that ε = α for gray, diffuse surfaces.
Diffuse is a modifier which means the property is not a functionof direction.
Gray is a modifier indicating no dependence on wavelength.
Spectral is a modifier which means dependence on wavelength.
Specular is a modifier which means mirror-like reflection.
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Characteristics of Real SurfacesAppendix
Figure borrowed from M.F. Modest, Radiative Heat Transfer, second edition, Academic Press, New York, 200335 / 31
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View Factor PropertiesMath Model
Summation Rule (Equation (10.12), page 539 in [LL16]):
N∑i=1
Fij = 1
Reciprocity Rule (Equation (10.15), page 540 in [LL16]):
AiFij = AjFji
Addition of View Factors for Subdivided Surfaces (seeExample 10.4, page 550 in [LL16]):
Fi(j) =N∑
k=1
Fik
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Net Radiation Method for EnclosuresAppendix
I The enclosure geometry is approximated by a set of Nideal surfaces
I Diffuse gray emission/absorptionI Diffuse gray reflectionsI Each surface is isothermal, with uniform heat flux
1
2
3
4
5
6
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Oppenheim Network for Three SurfacesAppendix
1
23
eb3
eb1
eb2
J1
J2J3
1−ε1ε1A1
1−ε2ε2A2
1−ε3ε3A3
1A1F13
1A1F12
1A2F23
A.K. Oppenheim, ”Radiation Analysis by the Network Method,”Transactions of the ASME, vol. 78, pp. 725–735, 1956
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The Surface RadiosityAppendix
Radiosity, Ji , for surface i is:
Ji = εiσT 4i︸ ︷︷ ︸
emmision
+ ρiGi︸︷︷︸reflected irradiation
Surface irradiation, Gi is:
Gi =N∑
i=1
FijJj
Then noting that ρi = 1− εi , the equation for the radiosity fromsurface i is:
Ji − (1− εi)
(N∑
i=1
FijJj
)= εiσT 4
i
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System of Equations for the RadiosityAppendix
Rearrangement of the radiosity equation for surface i leads to:
N∑i=1
[δij − (1− εi)Fij
]Jj = εiσT 4
i
Combining the radiosity equations for each surface in theenclosure leads to a system of equations:
[A] {J} = {b}Where:
Aij = δij − (1− εi)Fij
bi = εiσT 4i
The surface temperature, Ti , is provided by the solution of theenergy conservation equation.
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Application of Radiosity to Heat Conduction EquationAppendix
Once the radiosity, Ji is known for a surface, the irradiation isevaluated:
Gi =N∑
i=1
FijJj
This is then used to evaluate the net radiant thermal energy forsurface i :
qi |radiation = εiσT 4i − αiGi
This heat flux boundary condition is then applied to the energyconservation equation solution so that updated surfacetemperatures can be determined.Iteration between the energy equation and the radiosity iscontinued until convergence.
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Matrix Form of the Radiosity EquationAppendix
N∑i=1
[δij − (1− εi)Fij
]Jj = εiσT 4
i
([I]− [ρ][F ]) {J} = [ε] {Eb}where, for N = 3:
{J} =
J1J2J3
{σT 4
}=
σT 4
1σT 4
2σT 4
3
= {Eb} =
Eb1Eb2Eb3
[ε] =
ε1 0 00 ε2 00 0 ε3
[F ] =
F11 F12 F13F21 F22 F23F31 F32 F33
[I] =
1 0 00 1 00 0 1
[ρ] =
ρ1 0 00 ρ2 00 0 ρ3
= [I]− [ε] =
1− ε1 0 00 1− ε2 00 0 1− ε3
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Enclosure Heat Flow from RadiosityAppendix
([I]− [ρ][F ]){J} = [ε]{Eb}
Using the definition of radiosity:
{J} = [ε]{Eb}+ [ρ]{G} = [ε]{Eb}+ [ρ][F ]{J}
and the net surface heat flux (α = ε):
{q} = [ε]{Eb} − [α]{G} = [ε]{Eb} − [ε][F ]{J}
then some algebraic manipulation leads to:
([I]− [F ][ρ])[ε]−1{q} = ([I]− [F ]){Eb}
or,{q} = [ε]([I]− [F ][ρ])−1([I]− [F ]){Eb}
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Exchange Factor, FAppendix
The exchange factor concept is based on proposing that thereis a parameter, Fij , based on surface properties and enclosuregeometry, that determines the radiative heat exchange betweentwo surfaces [Hot54, HS67] :
Qij = AiFijσ(T 4i − T 4
j )
F is known by many names in the literature: script-F, gray bodyconfiguration factor, transfer factor and Hottel called it theover-all interchange factor.For an enclosure with N surfaces, the net heat flow rate, Qi , forsurface i , is:
Qi =N∑
j=1
AiFij
(σT 4
i − σT 4j
)=
N∑j=1
AiFij(Ebi − Ebj
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Exchange Factor, F , PropertiesAppendix
Reciprocity:
AiFij = AjFji
Summation:
N∑j=1
Fij = εi
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Matrix Form of Enclosure Radiation with FAppendix
Qi =N∑
j=1
AiFij(Ebi − Ebj
){Q} = [A] ([ε]− [F ]) {Eb}
{q} = [A]−1 {Q} = ([ε]− [F ]) {Eb}
where, for N = 3:
{Q} =
Q1Q2Q3
[A] =
A1 0 00 A2 00 0 A3
[F ] =
F11 F12 F13F21 F22 F23F31 F32 F33
{Eb} =
σT 4
1σT 4
2σT 4
3
[ε] =
ε1 0 00 ε2 00 0 ε3
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Exchange Factors, F , from View Factors, FAppendix
The net heat flux using view factors, Fij , is:
{q} = [ε]([I]− [F ][ρ])−1([I]− [F ]){Eb}
The net heat flux using exchange factors, Fij , is:
{q} = ([ε]− [F ]) {Eb}
The two enclosure heat fluxes are equal, so equating gives:
([ε]− [F ]) {Eb} = [ε]([I]− [F ][ρ])−1([I]− [F ]){Eb}
([ε]− [F ]) = [ε]([I]− [F ][ρ])−1([I]− [F ])
[F ] = [ε]([I]− ([I]− [F ][ρ])−1([I]− [F ])
)See [IB63] for an early reference to this method.
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Linearization of Radiation ConductorsAppendix
The temperature is linearized using a two term Taylor seriesexpansion about the previous iteration temperature, T ∗:
T 4i ≈ (T ∗i )
4 + (Ti − T ∗i )4(T ∗i )3
T 4i ≈ 4(T ∗i )
3Ti − 3(T ∗i )4
T 4j ≈
(T ∗j)4
+(
Tj − T ∗j)
4(
T ∗j)3
T 4j ≈ 4
(T ∗j)3
Tj − 3(
T ∗j)4
The linearized form of the heat transfer rate is:
Qij = σFijAi
[4(T ∗i )
3Ti − 3(T ∗i )4 − 4
(T ∗j)3
Tj + 3(
T ∗j)4]
Qij = σFijAi
{4(T ∗i )
3Ti − 4(
T ∗j)3
Tj
}−σFijAi
{3(T ∗i )
4 − 3(
T ∗j)4}48 / 31
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References I
[BLID11] T.L. Bergman, A.S. Lavine, F.P. Incropera, and D.P.DeWitt.Introduction to Heat Transfer.John Wiley & Sons, New York, sixth edition, 2011.
[CC75] Stuart W. Churchill and Humbert H.S. Chu.Correlating equations for laminar and turbulent freeconvection from a vertical plate.International Journal of Heat and Mass Transfer,18(11):1323–1329, 1975.
[Hot54] H. C. Hottel.Radiant-heat transmission.In Heat Transmission [McA54], chapter 4, pages55–125.
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References II
[HS67] H. C. Hottel and A. F. Sarofim.Radiative Transfer.McGraw-Hill, New York, 1967.
[IB63] T. Ishimoto and J. T. Bevans.Method of evaluating script f for radiant exchangewithin an enclosure.AIAA Journal, 1(6):1428–1429, 1963.
[LL16] J. H. Lienhard, IV and J. H. Lienhard, V.A Heat Transfer Textbook.Phlogiston Press, Cambridge, Massachusetts, fourthedition, 2016.Available at: http://ahtt.mit.edu.
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References III
[LM74] J. R. Lloyd and W. R. Moran.Natural convection adjacent to horizontal surface ofvarious planforms.Journal of Heat Transfer, 96(4):443–447, 1974.
[McA54] W. H. McAdams.Heat Transmission.McGraw-Hill, New York, third edition, 1954.
[RH98] G. D. Raithby and K. G. T. Hollands.Natural convection.In Warren M. Rohsenow, James R Hartnett, andYoung I. Cho, editors, Handbook of Heat Transfer,chapter four, pages 4.1–4.99. McGraw-Hill, New York,third edition, 1998.
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References IV
[RL01] E. Radziemska and W. M. Lewandowski.Heat transfer by natural convection from anisothermal downward-facing round plate in unlimitedspace.Applied Energy, 68(4):347–366, 2001.
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