Projectile Motion

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Projectile Motion Projectile motion: a combination of horizontal motion with constant horizontal velocity and vertical motion with a constant downward acceleration due to gravity. Projectile motion refers to the motion of an object that is thrown, or projected, into the air at an angle. We restrict ourselves to objects thrown near the Earth’s surface as the distance traveled and the maximum height above the Earth are small compared to the Earth’s radius so that gravity can be considered to be constant.

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Projectile Motion. Projectile motion: a combination of horizontal motion with constant horizontal velocity and vertical motion with a constant downward acceleration due to gravity. - PowerPoint PPT Presentation

Transcript of Projectile Motion

Page 1: Projectile Motion

Projectile Motion

Projectile motion: a combination of horizontal motion with constant horizontal velocity and vertical motion with a constant downward acceleration due to gravity. Projectile motion refers to the motion of an object that is thrown, or projected, into the air at an angle. We restrict ourselves to objects thrown near the Earth’s surface as the distance traveled and the maximum height above the Earth are small compared to the Earth’s radius so that gravity can be considered to be constant.

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Horizontal Component of Velocity

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Horizontal and Vertical

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Projectile Motion

The motion of a projectile is determined only by the object’s initial velocity and gravity. The vertical motion of a projected object is independent of its horizontal motion. The vertical motion of a projectile is nothing more than free fall.The one common variable between the horizontal and vertical motions is time.

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Path of a Projectile

A projectile moves horizontally with constant velocity while being accelerated vertically. A right angle exists between the direction of the horizontal and vertical motion; the resultant motion in these two dimensions is a curved path. The path of a projectile is called its trajectory.

The trajectory of a projectile in free fall is a parabola.

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Path of a Projectile

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Path of a Projectile

vo = initial velocity or resultant velocity

vx = horizontal velocityvyi = initial vertical velocityvyf = final vertical velocityR= maximum horizontal distance (range)x = horizontal distancey = change in vertical positionyi = initial vertical positionyf = final vertical position = angle of projection (launch angle)H = maximum heightg = gravity = 9.8 m/s2

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Path of a Projectile

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Path of a Projectile

The horizontal distance traveled by a projectile is determined by the horizontal velocity and the time the projectile remains in the air. The time the projectile remains in the air is dependent upon gravity. Immediately after release of the projectile, the force of gravity begins to accelerate the projectile vertically towards the Earth’s center of gravity.

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Path of a Projectile

The velocity vector vo changes with time in both magnitude and direction. This change is the result of acceleration in the negative y direction (due to gravity). The horizontal component (x component) of the velocity vo remains constant over time because there is no acceleration along the horizontal direction

The vertical component (vy) of the velocity vo is zero at the peak of the trajectory. However, there is a horizontal component of velocity, vx,

at the peak of the trajectory.

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Path of a Projectile

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Path of a ProjectileIn the prior diagram, r is the position vector of the projectile. The position vector has x and y components and is the hypotenuse of the right triangle formed when the x and y components are plotted. The velocity vector vot would be the displacement

of the projectile if gravity were not acting on the projectile.

The vector 0.5gt2 is the vertical displacement of the projectile due to the downward acceleration of gravity.

Together, this determines the vertical position for the projectile:

Δy = (vy·t) – (0.5·g·t2)

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Path of a Projectile

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Acceleration of a Projectile

g

g

g

g

g

x

y

Acceleration points down at 9.8 m/s2 for the entire trajectory of all projectiles.

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Velocity of a projectile

vo

vf

v

v

v

x

y

Velocity is tangent to the path for the entire trajectory.

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Position graphs for 2-D projectiles

x

y

t

y

t

x

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Velocity graphs for 2-D projectiles

t

Vy

t

Vx

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Acceleration graphs for 2-D projectiles

t

ay

t

ax

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Fig. 04.24

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Problem Solving: Projectile Motion

Analyze the horizontal motion and the vertical motion separately. If you are given the velocity of projection, vo, you may want to resolve it into its x and y components. Think for a minute before jumping into the equations. Remember that vx remains constant throughout the trajectory, and that vy = 0 m/s at the highest point of any trajectory that returns downward.

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Horizontal velocity component:

vx is constant because there is no acceleration in the horizontal direction if air resistance is ignored.

cos ox vv

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Vertical velocity component:

At the time of launch:

After the launch:

If vy positive, direction of vertical motion is up; if vy negative, direction of vertical motion is down; if vy = 0, projectile is at highest point.

sin oyi vv

tgvv oyf sin

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Horizontal position component:

If you launch the projectile horizontally: then vo = vx

vyi = 0 m/s = 0o

tθcosvx

tvx

o

x

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Vertical position component:

2oif

2yiif

if

tg0.5tθsinvyy

tg0.5tvyy

yyΔy

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Relationship Between Vertical and Horizontal Position:

this equation is only valid for launch angles in the range 0 < < 90

22o

2

θcosv2

gxθtanxyΔ

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Range (total horizontal displacement)

g

θcosθsin2vR

θcosθsin2θ)(2sin

:formulaangledouble

g

θ2sinvR

2o

2o

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Maximum Height

g2

θsinvH

22o

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When Do The Range & Maximum Height Equations Work?

Works when y = 0.

Does not work when y 0.

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Determining vo from vx and vy

If the vertical and horizontal components of the velocity are known, then the magnitude and direction of the resultant velocity can be determined.Magnitude: 22

yxo vvv

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Determining vo from vx and vy

Direction: from the horizontal

Direction: from the vertical

x

y1

v

vtanθ

y

x1

v

vtanθ

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Range and Angle of Projection

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Range and Angle of Projection

The range is a maximum at 45 because sin (2·45) = 1.For any angle other than 45, a point having coordinates (x,0) can be reached by using either one of two complimentary angles for , such as 15 and 75 or 30 and 60 .

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Range and Angle of Projection

The maximum height and time of flight differ for the two trajectories having the same coordinates (x, 0).

A launch angle of 90° (straight up) will result in the maximum height any projectile can reach.

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For Objects Shot Horizontally:

vx constant

y negative; y = - height

tvxsm

0vtx

v

x

yix

2tg5.0y

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Zero Launch angle

A zero launch angle implies a perfectly horizontal launch.

vo

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For Objects Shot Horizontally:

When hits at bottom: Vyf should be negative vo = resultant velocity

2yf

2xo

yf

vvv

tgv

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For Objects Shot Horizontally:

with horizontal:

with vertical:

x

yf1

v

vtan

yf

x1

vv

tan

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For Situations in Which y = 0 m

2yi

x

ox

oyi

22o

2o

tg5.0tvy

tR

v

cosvv

sinvv

g2sinv

H

g2sinv

R

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For Situations In Which y Positive

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For Situations In Which y Positive

At any point in the flight:

sinvvcosvv oyiox

2yf

2xo

x

x

yiyf

22o

2

2yi

vvv

ttanconsv

tvx

tgvv

cosv2

gxtanxy

tg5.0tvy

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For Situations In Which y Negative

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For Situations In Which y Negative

At launch:After launch:

When it hits ground:

sinvvcosvv oyiox

22o

2

2yi

x

cosv2

gxtanxy

tg5.0tvy

tvx

2

yf2

xo

yiyf

x

vvv

tgvv

ttanconsv