Pipe Networks

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Monroe L. Weber-Shir k S chool of Civil and Environmental Engi neering Pipe Networks Pipeline systems pipe networks measurements manifolds and diffusers Pumps You are here

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Pipe Networks. Pipeline systems pipe networks measurements manifolds and diffusers Pumps. You are here. Pipeline systems: Pipe networks. Water distribution systems for municipalities Multiple sources and multiple sinks connected with an interconnected network of pipes. - PowerPoint PPT Presentation

Transcript of Pipe Networks

Page 1: Pipe Networks

Monroe L. Weber-Shirk

School of Civil and

Environmental Engineering

Pipe NetworksPipe Networks

Pipeline systemspipe networksmeasurementsmanifolds and diffusers

Pumps

Pipeline systemspipe networksmeasurementsmanifolds and diffusers

Pumps

You are here

Page 2: Pipe Networks

Pipeline systems:Pipe networks

Pipeline systems:Pipe networks

Water distribution systems for municipalities Multiple sources and multiple sinks connected

with an interconnected network of pipes. Computer solutions!

KYpipes WaterCAD CyberNET EPANET

Water distribution systems for municipalities Multiple sources and multiple sinks connected

with an interconnected network of pipes. Computer solutions!

KYpipes WaterCAD CyberNET EPANET http://www.epa.gov/ORD/NRMRL/wswrd/epanet.html

Page 3: Pipe Networks

Water Distribution System Assumption

Water Distribution System Assumption

Each point in the system can only have one _______

The pressure change from 1 to 2 by path a must equal the pressure change from 1 to 2 by path b

Each point in the system can only have one _______

The pressure change from 1 to 2 by path a must equal the pressure change from 1 to 2 by path b

a

p1

V12

2g z1

p2

V22

2g z2 hL

p1

V12

2g z1

p2

V22

2g z2 hL

p2

p1

V1a

2

2g z1

V2a

2

2g z2 hLa

p2

p1

V1a

2

2g z1

V2a

2

2g z2 hLa

b

1 2pressurepressure

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hLahLb hLahLb

a

b

1 2Pressure change by path aPressure change by path a

Water Distribution System Assumption

Water Distribution System Assumption

Pipe diameters are constant Model withdrawals as occurring at nodes so

V is constant

Pipe diameters are constant Model withdrawals as occurring at nodes so

V is constant

Or sum of head loss around loop is _____.Or sum of head loss around loop is _____.zerozero(Need a sign convention)

V1a

2

2g z1

V2a

2

2g z2 hLa

V1b

2

2g z1

V2b

2

2g z2 hLb

V1a

2

2g z1

V2a

2

2g z2 hLa

V1b

2

2g z1

V2b

2

2g z2 hLb

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Pipes in ParallelPipes in Parallel

AA BB

Q1Q1

QtotalQtotal

energyenergy

proportionproportion

Find discharge given pressure at A and B ______& ____ equation add flows

Find head loss given the total flow assume a discharge Q1’ through pipe 1

solve for head loss using the assumed discharge using the calculated head loss to find Q2’

assume that the actual flow is divided in the same _________ as the assumed flow

Find discharge given pressure at A and B ______& ____ equation add flows

Find head loss given the total flow assume a discharge Q1’ through pipe 1

solve for head loss using the assumed discharge using the calculated head loss to find Q2’

assume that the actual flow is divided in the same _________ as the assumed flow

Q2Q2

S-JS-J

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Networks of PipesNetworks of Pipes

____ __________ at all nodes The relationship between head

loss and discharge must be maintained for each pipe Darcy-Weisbach equation

_____________

Exponential friction formula _____________

____ __________ at all nodes The relationship between head

loss and discharge must be maintained for each pipe Darcy-Weisbach equation

_____________

Exponential friction formula _____________

A0.32 m3/s 0.28 m3/s

?

b

a

1 2

Mass conservationMass conservation

Swamee-JainSwamee-Jain

Hazen-WilliamsHazen-Williams

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Network AnalysisNetwork Analysis

Find the flows in the loop given the inflows and outflows.The pipes are all 25 cm cast iron (=0.26 mm).

Find the flows in the loop given the inflows and outflows.The pipes are all 25 cm cast iron (=0.26 mm).

A B

C D0.10 m3/s

0.32 m3/s 0.28 m3/s

0.14 m3/s200 m

100 m

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Network AnalysisNetwork Analysis

Assign a flow to each pipe link Flow into each junction must equal flow out

of the junction

Assign a flow to each pipe link Flow into each junction must equal flow out

of the junction

A B

C D0.10 m3/s0.10 m3/s

0.32 m3/s0.32 m3/s 0.28 m3/s0.28 m3/s

0.14 m3/s0.14 m3/s

0.320.320.000.00

0.100.10

0.040.04

arbitraryarbitrary

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Network AnalysisNetwork Analysis

Calculate the head loss in each pipe Calculate the head loss in each pipe

f=0.02 for Re>200000f=0.02 for Re>200000 hf

8fLgD5 2

Q2

hf

8fLgD5 2

Q2

fh kQ Q=fh kQ Q=

339)25.0)(8.9(

)200)(02.0(825

1

k 339

)25.0)(8.9(

)200)(02.0(825

1

k

k1,k3=339k2,k4=169k1,k3=339k2,k4=169

A B

C D0.10 m3/s

0.32 m3/s 0.28 m3/s

0.14 m3/s

1

4 2

3

hf134.7m

hf20.222m

hf3 3.39m

hf4 0.00m

hfii1

4

31.53m

hf134.7m

hf20.222m

hf3 3.39m

hf4 0.00m

hfii1

4

31.53m

Sign convention +CW

Page 10: Pipe Networks

Network AnalysisNetwork Analysis

The head loss around the loop isn’t zero Need to change the flow around the loop

the ___________ flow is too great (head loss is positive)

reduce the clockwise flow to reduce the head loss

Solution techniques Hardy Cross loop-balancing (___________ _________) Use a numeric solver (Solver in Excel) to find a change

in flow that will give zero head loss around the loop Use Network Analysis software

The head loss around the loop isn’t zero Need to change the flow around the loop

the ___________ flow is too great (head loss is positive)

reduce the clockwise flow to reduce the head loss

Solution techniques Hardy Cross loop-balancing (___________ _________) Use a numeric solver (Solver in Excel) to find a change

in flow that will give zero head loss around the loop Use Network Analysis software

clockwiseclockwise

optimizes correctionoptimizes correction

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Numeric SolverNumeric Solver

Set up a spreadsheet as shown below. the numbers in bold were entered, the other cells are

calculations initially Q is 0 use “solver” to set the sum of the head loss to 0 by changing Q the column Q0+ Q contains the correct flows

Set up a spreadsheet as shown below. the numbers in bold were entered, the other cells are

calculations initially Q is 0 use “solver” to set the sum of the head loss to 0 by changing Q the column Q0+ Q contains the correct flows

∆Q 0.000pipe f L D k Q0 Q0+∆Q hfP1 0.02 200 0.25 339 0.32 0.320 34.69P2 0.02 100 0.25 169 0.04 0.040 0.27P3 0.02 200 0.25 339 -0.1 -0.100 -3.39P4 0.02 100 0.25 169 0 0.000 0.00

31.575Sum Head Loss

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Solution to Loop ProblemSolution to Loop Problem

A B

C D0.10 m3/s

0.32 m3/s 0.28 m3/s

0.14 m3/s

0.218

0.102

0.202

0.062

1

4 2

3

Q0+ Q

Better solution is software with a GUI showing the pipe network.Better solution is software with a GUI showing the pipe network.

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Pressure Network Analysis Software: WaterCAD™

Pressure Network Analysis Software: WaterCAD™

A B

C D0.10 m3/s

0.32 m3/s 0.28 m3/s

0.14 m3/s

0.218

0.102

0.202

0.062

1

4 2

3

junctionjunctionpipepipereservoirreservoir

Page 14: Pipe Networks

Network ElementsNetwork Elements

Controls Check valve (CV) Pressure relief valve Pressure reducing valve (PRV) Pressure sustaining valve (PSV) Flow control valve (FCV)

Pumps: need a relationship between flow and head Reservoirs: infinite source, elevation is not affected

by demand Tanks: specific geometry, mass conservation applies

Controls Check valve (CV) Pressure relief valve Pressure reducing valve (PRV) Pressure sustaining valve (PSV) Flow control valve (FCV)

Pumps: need a relationship between flow and head Reservoirs: infinite source, elevation is not affected

by demand Tanks: specific geometry, mass conservation applies

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Check ValveCheck Valve

Valve only allows flow in one direction The valve automatically closes when flow

begins to reverse

Valve only allows flow in one direction The valve automatically closes when flow

begins to reverse

closedopen

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Pressure Relief ValvePressure Relief Valve

Valve will begin to open when pressure in the pipeline ________ a set pressure (determined by force on the spring).

Valve will begin to open when pressure in the pipeline ________ a set pressure (determined by force on the spring).

pipelinepipelineclosedclosed

relief flow

openopen

exceedsexceeds

Low pipeline pressureLow pipeline pressure High pipeline pressureHigh pipeline pressure

Page 17: Pipe Networks

Pressure Regulating ValvePressure Regulating Valve

Valve will begin to open when the pressure ___________ is _________ than the setpoint pressure (determined by the force of the spring).

Valve will begin to open when the pressure ___________ is _________ than the setpoint pressure (determined by the force of the spring).

sets maximum pressure downstreamsets maximum pressure downstream

closed open

lesslessdownstreamdownstream

High downstream pressureHigh downstream pressure Low downstream pressureLow downstream pressure

Page 18: Pipe Networks

Pressure Sustaining ValvePressure Sustaining Valve

Valve will begin to open when the pressure ________ is _________ than the setpoint pressure (determined by the force of the spring).

Valve will begin to open when the pressure ________ is _________ than the setpoint pressure (determined by the force of the spring).

sets minimum pressure upstreamsets minimum pressure upstream

closed open

upstreamupstream greatergreater

Low upstream pressureLow upstream pressure High upstream pressureHigh upstream pressure

Similar to pressure relief valve

Page 19: Pipe Networks

Flow control valve (FCV)Flow control valve (FCV)

Limits the ____ ___ through the valve to a specified value, in a specified direction

Commonly used to limit the maximum flow to a value that will not adversely affect the provider’s system

Limits the ____ ___ through the valve to a specified value, in a specified direction

Commonly used to limit the maximum flow to a value that will not adversely affect the provider’s system

flow rateflow rate

Page 20: Pipe Networks

Pressure Break TanksPressure Break Tanks

In the developing world small water supplies in mountainous regions can develop too much pressure for the PVC pipe.

They don’t want to use PRVs because they are too expensive and are prone to failure.

Pressure break tanks have an inlet, an outlet, and an overflow.

Is there a better solution?

In the developing world small water supplies in mountainous regions can develop too much pressure for the PVC pipe.

They don’t want to use PRVs because they are too expensive and are prone to failure.

Pressure break tanks have an inlet, an outlet, and an overflow.

Is there a better solution?