Physics 201 Chapter 13 Lecture 1physics.wisc.edu/.../lecture_notes/Chapter_13_L1.pdf · Physics 201...
Transcript of Physics 201 Chapter 13 Lecture 1physics.wisc.edu/.../lecture_notes/Chapter_13_L1.pdf · Physics 201...
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Physics 201Chapter 13Lecture 1
Fluid Statics Pascal’s Principle Archimedes Principle (Buoyancy)
Fluid Dynamics Continuity Equation Bernoulli Equation
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Fluids
Atmospheric PressureEven when there is no breeze air molecules are continuously
bombarding everything around - results in pressure
normal atmospheric pressure = 1.01 x 105 Pa (14.7 lb/in2)
Pressure (P)P = Force/Area [N/m2]
1 N/m2 = 1 Pascal (Pa)
Density = Mass/Volumeρ = M / V units = kg/m3
Pressure variation with depthP = ρ g h
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Density & Pressure are related by the Bulk Modulus
LIQUID: incompressible (density almost constant)
GAS: compressible (density depends a lot on pressure)
Compressiblity
B =Δp
(−ΔV /V )
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Variation of pressure with depth
m = ρV; V = Ah⇒ m = ρAh
P =FA=mgA
; i.e., P =ρAh( )gA
⇒ P = hρg
True for all shapes of containers
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Pascal’s Principle A change in pressure in an enclosed fluid is
transmitted undiminished to all the fluid and to its container.
This principle is used in hydraulic system P1 = P2
(F1 / A1) = (F2 / A2)
F2
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Pascal’s Principle
This principle is used in hydraulic system P1 = P2
(F1 / A1) = (F2 / A2) Can be used to achieve a mechanical advantage F2 = F1 (A2 / A1)
» Work done is the same: height by which the surface A2 rises is smaller than the change in the height of surface with area A1.
F1
A1
F2A2
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Using Fluids to Measure Pressure
1 atm = 760 mm (29.9 in) Hg = 10.3 m (33.8 ft) H20
• Use Barometer to measure Absolute Pressure
Barometer Top of tube evacuated (p=0) Bottom of tube submerged into pool of mercury
open to atmosphere (p=p0) Pressure dependence on depth:
• Use Manometer to measure Gauge Pressurep0
Δh
Manometerp1 Measure pressure of volume (p1) relative to the
atmospheric pressure (≡ gauge pressure ) The height difference (Δh) measures the gauge
pressure: Δh =(p1 − p0 )
ρg
h =p0
ρg
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Measurement of Pressure
Manometer If both sides of an U-tube are open to atmosphere
the levels of the fluid are the same on both sides If one side is connected to a “pressurized side” the
level difference between the two sides can be used to measure pressure.
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Measuring the tire pressure:Is this a manometer or a barometer?
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Measuring Blood Pressure Blood pressure is quite high, 120/80 mm of Hg Use higher density fluid in a manometer: Mercury
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ArchimedesObject immersed in a fluid is subject to a “buoyant force”.
Force on sides cancel
Force on top Ft = ρghT A
Force on bottom Fb = ρghB A
ΔF = ρg A Δh
FB = (mg)disp
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ArchimedesObject immersed in a fluid is subject to a “buoyant force”.
Force on sides cancel
Force on top Ft = ρghT A
Force on bottom Fb = ρghB A
ΔF = ρg A Δh
FB = (mg)disp
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Float
Weight of object = ρ0gV
Buoyant force is the weight of the displaced fluid
Weight of fluid = ρfgV
Displace just enough fluid such that forces = 0!
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Archimedes PrincipleBuoyant Force (B)
weight of fluid displaced (P=F/A, P=ρgh)» B = ρfluid g Vdisplaced
» W = ρobject g Vobject
» object sinks if ρobject > ρfluid
» object floats if ρobject < ρfluid
» Eureka!
If object floats….» B=W» Therefore ρfluid g Vdisplaced = ρobject g Vobject
» Therefore Vdisplaced/Vobject = ρobject / ρfluid
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Float Buoyant force is the weight of the displaced fluid Weight of object = ρIceVtotal gWeight of fluid = ρSeaWatergVsubmersed
Displace just enough fluid such that forces = 0!
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The weight of a glass filled to the brim with water is Wb. A cube of ice is placed in it, causing some water to spill. After the spilled water is cleaned up, the weight of the glass with ice cube is Wa. How do the weights compare: 1. Wb > Wa. 2. Wb < Wa.3. Wb = Wa.
Archimedes’ Principle: The buoyant force on an object equals the weight of the fluid it displaces.
Weight of water displaced = Buoyant force = Weight of ice
Archimedes Principle
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QuestionSuppose you float a large ice-cube in a glass of water, and that after you place the ice in the glass the level of the water is at the very brim. When the ice melts, the level of the water in the glass will: 1. Go up causing the water to spill. 2. Go down.3. Stay the same.
Archimedes’ Principle: The buoyant force on an object equals the weight of the fluid it displaces.
Weight of water displaced = Buoyant force = Weight of ice
When ice melts it will turn into water of same volume
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Buoyancy
Two cups hold water at the same level. One of the two cups has plastic balls (projecting above the water surface) floating in it. Which cup weighs more?
Archimedes principle tells us that the cups weigh the same. Each plastic ball displaces an amount of water that is exactly
equal to its own weight.
Cup I Cup II
1) Cup I2) Cup II3) Both the same
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Two identical glasses are filled to the same level with water. Solid steel balls are at the bottom in one of the glasses. Which of the two glasses weighs more? 1. The glass without steel balls 2. The glass with steel balls 3. Both glasses weigh the same
The steel balls sink. The buoyant force equal to the weight of the displaced water is not sufficient to counter the weight of the steel balls. Therefore, the glass with steel balls weighs more.
Sunken Balls
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Imagine holding two identical bricks under water. Brick A is just beneath the surface of the water, while brick B is at a greater depth. The force needed to hold brick B in place is:
1. larger
2. the same as
3. smaller
than the force required to hold brick A in place.
The buoyant force on each brick is equal to the weight of the water it displaces and does not depend on depth.
Buoyant force and depth
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Fluid Flow
• Volume flow rate: ΔV/Δt = A Δd/Δt = Av (m3/s)
• Continuity: A1 v1 = A2 v2
i.e., flow rate the same everywhere
e.g., flow of river
Fluid flow without friction
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ProblemTwo hoses, one of 20-mm diameter, the other of 15-mm diameter are connected one behind the other to a faucet. At the open end of the hose, the flow of water measures 10 liters per minute. Through which pipe does the water flow faster? 1. The 20-mm hose 2. The 15-mm hose 3. Water flows at the same speed in both cases4. The answer depends on which of the two hoses comes first in the flow
When a tube narrows, the same volume occupies a greater length. For the same volume to pass through points 1 and 2 in a given time, the velocity must be greater at point 2. The process is reversible.
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Faucet
A stream of water gets narrower as it falls from a faucet (try it & see).
The velocity of the liquid increases as the water falls due to gravity. If the volume flow rate is conserved, them the cross-sectional area must decrease in order to compensate
A1
A2
V1
V2
The density of the water is the same no matter where it is in space and time, so as it falls down and accelerates because of gravity,the water is in a sense stretched, so it thins out at the end.
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Streamlines
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Continuity equation
Volume Flow rate
Mass flow rate
Δm1 = ρ1ΔV1 = ρ1Av1Δt
IM1 =Δm1
Δt= ρ1Av1
IV =ΔVΔt
= Av
Δm1
Δt=Δm2
Δt
IM 2 − IM1 =dm2
dt−dm1
dt=dm12
dt Continuity equation
In steady state
General case: mass may be accumulated or decreased in the volume between A1 and A2
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Bernoulli’s Equation
Pressure drops in a rapidly moving fluid whether or not the fluid is confined to a tube
For incompressible, frictionless fluid:
P +12ρv2 + ρgh = constant
12ρv2 = 1
2mv2
1V
=KEV
ρgh = mghV
=PEV
Bernoulli equation states conservation of energyFor Static Fluids:P1 + ρgh1 = P2 + ρgh2
Bernoulli's Principle (constant depth):P1 +12ρv1
2 = P2 +12ρv2
2