Pert Network
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Transcript of Pert Network
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PERT NETWORK
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CPM : CRITICAL PATH METHOD
PERT : USED FOR PROJECT PLANNING & MONITORING
GANTT CHART
EVENT
ACTIVITY
NETWORK
AOAACTIVITY ON ARROW
AONACTIVITY ON NODE
SLACK/FLOAT
CRITICAL PATH
t= Duration of activity
1 2
EF = ES + t LF = LS + t
LS = LFt Slack = LSES or LF - EF
ES LS EF LF
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EXPECTED COMPLETION TIME =+4+
6
STANDARD DEVIATION, = [ (b a)/6]2
NETWORK CONVENTION :
1. AOAACTIVITY ON ARROW
2
1 43
2. AON - ACTIVITY ON NODE
B
A
C
D
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RULES FOR COMPUTING EF(EARLIEST FINISH TIME) & LF(LATEST FINISH
TIME) IN NETWORK :
1.MOVING FORWARD FIND EF TIME (CHOOSING THE MAXIMUM AT ACTIVITY
INTERSECTION.
2.AT LAST NODE, MAXIMUM EF = LF
3.USE RETURN PATH TO FIND LF (CHOOSING MINIMUM AT EVERY
INTERSECTION.
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b
Problem 1. Project with following data are to be completed. Draw the network
and critical path.
(a)What is the minimum duration of the project?
(b)Draw the Gantt Chart for early start schedule
(c) Determine the peak requirement of money and day on which it occurs in
above schedule
ACTIVITY PREDECE-
SSORS
DURATION
(DAYS)
COST
(RS/DAY)
A - 2 50
B - 4 50
C A 1 40D B 2 100
E A,B 3 100
F E 2 60
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EF LF
EF LF
EF LF C=1
A=2 EF LF
t=0 E=3 F=2
B=4
D=2
EF LF
EF LF
4 4
7 7
1
3
4
5
2
0 0
9 9
4 4
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Activity Duration(t)
EF ES =
EF - t
LF LS =
LF - t
Event
Slack =
LSES
or
LF - EF
On
critical
path
A 2 2 0 4 2 2 No
B 4 4 0 4 0 0 Yes
C 1 5 4 9 8 4 No
D 2 6 4 9 7 3 No
E 3 7 4 7 4 0 Yes
F 2 9 7 9 7 0 Yes
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(c)
Peak requirement of money on 5thand 6thday for Rs.200/- Ans.
Day Activity Requirement of money(Rupees)
1 A + B 50 +50=100
2 A + B 50 + 50=100
3 B + C 50 + 40=90
4 B 50
5 D + E 100+100=200
6 D + E 100 + 100=200
7 E 100
8 F 60
9 F 60
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#2 (a)Draw the network using AON system and find critical path for the
project.
Activity Designation Predecessor Time in weeks
Design A - 21
Built prototype B A 5
Evaluate C A 7
Test prototype D B 2
Write
equipment
report
E C,D 5
Write method
report
F C,D 8
Write final
report
G E,F 2
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(b)Using 3 time estimates of activities, find probability of completing project
in 35 weeks.
Activity Time estimation
a=Most
optimistic time
b=Pessimistic
time
m=Most likely
time
A 10 12 28
B 4 4 10
C 4 6 14
D 1 2 3
E 1 5 9
F 7 8 9
G 2 2 2
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EF LF
EF LF
EF LF
EF LF
EF LF
EF LF
28 2836 36
38 38
33 36
28 28
26 26
21 21
A,21
C,7F,8
G,2
E,5D,2
B,5
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Activity Duration
(t)
EF ES=
EF - t
LF LS= LF -t Slack=
LS-ES
On
critical
pathA 21 21 O 21 0 0 Yes
B 5 26 21 26 21 0 Yes
C 7 28 21 28 21 0 Yes
D 2 28 26 28 26 0 Yes
E 5 33 28 36 31 3 No
F 8 36 28 36 28 0 Yes
G 2 38 36 38 36 0 Yes
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CRITICAL PATH :
THERE ARE TWO CRITICAL PATHS THROUGHOUT THE NETWORK :
ACFG and ABDFG
(b) Time Estimate
Activity a b m Expected
Project completion time
Te=(a+4m+b)/6
A 10 12 28 22.33B 4 4 10 8
C 4 6 14 11
D 1 2 3 2.5
E 1 5 9 7
F 7 8 9 8.16
G 2 2 2 2
Total expected completion time = 60.99 weeks
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#3 A project has following time schedule :
(a)Construct a PERT network
(b) Compute critical path and its duration
(c) Total Float for each activity
Activity : 1-2 1-3 1-4 2-5 3-6 3-7 4-6 5-8 6-9 7-8 8-9Time
(Months)
2 2 1 4 8 5 3 1 5 4 3
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EF LF EF LF
4
1
ES LS 2 EF LF EF LF EF LF
2 5 4
1 8 3
EF LF EF LF EF LF
3 5
(a) PERT network is shown above
2 7 6 11
0 0 2 2 7 8 11 12
1 710 10 15 15
1
2
3
4
7
5
8
96
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(b & c) Critical path : 136 - 9 with duration of 15 months
Activity Duration EF ES=
EF - t
LF LS =
LF - t
Total
Float =
LF - EF
1-2 2 2 0 7 5 5
1-3 2 2 0 2 0 0
1-4 1 1 0 7 6 6
2-5 4 6 2 11 7 5
3-6 8 10 2 10 2 03-7 5 7 2 8 3 1
4-6 3 4 1 10 5 6
5-8 1 7 6 12 11 5
6-9 5 15 10 15 10 0
7-8 4 11 7 12 8 1
8-9 3 14 11 15 12 1