M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint,...

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M)–10–9 Solves problems on and off the coordinate plane lving distance, midpoint, perpendicular and parallel lines, or slope GSE: (G&M)–10–2 Makes and defends conjectures, constructs geometric guments, uses geometric properties, or across disciplines or contexts .g., Pythagorean Theorem G-CO.1 Know precise definitions of angle, circle, perpendicular line, parallel line, and line segment, based on the undefined notions of point, line, distance along a line, and distance around a circular arc.

Transcript of M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint,...

Page 1: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope

GSE:

M(G&M)–10–2 Makes and defends conjectures, constructs geometric arguments, uses geometric properties, or across disciplines or contexts (e.g., Pythagorean Theorem

G-CO.1 Know precise definitions of angle, circle, perpendicular line, parallel line, and line segment, based on the undefined notions of point, line, distance along a line, and distance around a circular arc.

Page 2: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

AA BB

Point A is at 1.5 and B is at 5.

So, AB = 5 - 1 1.5 = 3.55 = 3.5

Page 3: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Find the measure of PR

Ans: |3-(-4)|=|3+4|=7

Would it matter if I asked for the distance from R to P ?

Page 4: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

1) Pythagorean Theorem- Can be used on and off the coordinate plane

•2) Distance Formula – only used on the coordinate plane

Page 5: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

* Only can be used with Right TrianglesWhat are the parts to a RIGHT Triangle?1. Right angle2. 2 legs3. Hypotenuse

Right angle

LEG

Leg – Sides attached to the Right angle

Hypotenuse- Side across from the right angle. Always the longest side of a right triangle.

Page 6: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

222 )()()( hypotenuselegleg

Page 7: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Make a right Triangle out of the segment

(either way)

Find the length of each leg of the right Triangle.

Then use the Pythagorean Theorem to find the Original segment JT (the hypotenuse).

Page 8: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Find the length of CD using the Pythagorean Theorem

10

88.12164

164

10064

108

2

2

222

DC

DC

DC

DC

We got 8 by | -4 – 4|

We got 10 by | 6 - - 4|

Page 9: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Find the missing segment- Identify the parts of the triangle

5 in

13 inAns: 5 2 + X 2 = 13 2

Leg 2 + Leg 2 = Hyp 2

hyp

Leg

Leg

25 + X 2 = 169

X 2 = 144

X = 12 in

Page 10: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Lets Use the Pythagorean Theorem

Page 11: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

2122

12 yyxx

Identify one as the 1st point and one as the 2nd. Use the corresponding x and y values

(4-(-3))2 + (2-(5))2

(4+3)2 + (2-5)2

(7)2 +(-3)2

49+9 =58 ~ 7.6~

J (-3,5) T (4,2)

d =

x1, y1 x2, y2

Page 12: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Find the length of the green segment

Ans: 109 or approximately 10.44

Page 13: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.

Segments that have the same length.

If AB & XY have the same length,Then AB=XY,

butAB XY

Symbol for congruentfor congruent

Page 14: M(G&M)–10–9 Solves problems on and off the coordinate plane involving distance, midpoint, perpendicular and parallel lines, or slope GSE: M(G&M)–10–2 Makes.