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    Method of Joints Example

    Using the method of joints, determine the

    force in each member ofthe truss.

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    Method of Joints Example

    Draw the free bodydiagram of the truss and

    solve for the equations

    x x

    x

    y y

    y

    0

    0 lb

    0 2000 lb 1000 lb

    3000 lb

    F C

    C

    F E C

    E C

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    Method of Joints

    Example

    Solve the moment about C

    C

    y

    0 2000 lb 24 ft 1000 lb 12 ft 6 ft

    10000 lbC 3000 lb 10000 lb 7000 lb

    M E

    E

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    Method of Joints

    Example

    Look at joint A

    y AD

    AD AD

    x AD AB AB

    AB AB

    40 2000 lb

    52500 lb 2500 lb C

    3 30 2500 lb

    5 51500 lb 1500 lb T

    F F

    F F

    F F F F

    F F

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    Method of Joints

    Example

    Look at joint D

    y AD DB DB

    DB DB

    x AD DB DE

    DE

    DE DE

    4 4 4 40 2500 lb5 5 5 5

    2500 lb 2500 lb T

    3 30 5 5

    3 32500 lb 2500 lb

    5 5

    3000 lb 3000 lb C

    F F F F

    F F

    F F F F

    F

    F F

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    Method of Joints

    Example

    Look at joint B

    y BD BE

    DE

    DE DE

    x BD BA BE BC

    BC

    BC DE

    4 4

    0 1000 lb5 54 4

    2500 lb 1000 lb5 53750 lb 3750 lb C

    3 305 5

    3 32500 lb 1500 lb 3750 lb

    5 5

    5250 lb 5250 lb T

    F F F

    F

    F F

    F F F F F

    F

    F F

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    Method of Joints

    Example

    Look at joint E

    y EB EC

    DE

    EC EC

    x EB ED EC

    EC

    EC EC

    4 4

    0 10000 lb5 54 4

    3750 lb 10000 lb5 58750 lb 8750 lb C

    3 305 5

    3 33750 lb 3000 lb

    5 5

    8750 lb 8750 lb C

    F F F

    F

    F F

    F F F F

    F

    F F

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    Method of Joints

    Example

    Look at joint C to check the

    solution

    y CE

    x CE CB x

    40 7000 lb

    54

    8750 lb 7000 lb 0 OK!5

    305

    38750 lb 5250 lb 0 0

    5

    F F

    F F F C

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    Method of Joints Class Problem

    Determine the forces BC,

    DF and GE. Using themethod of Joints.

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    Method of Sections -Truss

    The method of joints is most effective whenthe forces in all the members of a truss are tobe determined. If however, the force is onlyone or a few members are needed, then themethod of sections is more efficient.

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    Few simple guidelines of section truss analysis :

    Pass a section through a maximum of 3 members ofthe truss, 1 of which is the desired member where itis dividing the truss into 2 completely separate parts,

    At 1 part of the truss, take moments about the point(at a joint) where the 2 members intersect and solvefor the member force, using M = 0,

    Solve the other 2 unknowns by using the equilibriumequation for forces, using Fx = 0 and Fy = 0 .

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    Method of Sections -Truss

    If we were interested inthe force of member CE.We can use a cutting lineor section to breakup thetruss and solve by takingthe moment about B.

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    Method of Sections Example

    Determine the forces in members FH, GH and GIof the roof truss.

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    Method of Sections Example

    Draw a free body diagram and solve for thereactions.

    RAx

    RAy

    L

    x Ax

    Ax

    y

    Ay

    0

    0 kN

    0

    20 kN

    F R

    R

    F

    L R

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    Method ofSections Example

    Solve for themoment at A.

    RAx

    RAy

    L

    A

    Ay

    6 kN 5 m 6 kN 10 m 6 kN 15 m

    1 kN 20 m 1 kN 25 m 30 m

    7.5 kN

    12.5 kN

    M

    L

    L

    R

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    Method of Sections Example

    Solve for the member GI. Take a cut between thethird and fourth section and draw the free-bodydiagram.

    HI HI

    HI

    1 o

    8 m 10 m8 m

    15 m 10 m 15 m

    5.333 m

    8 mtan 28.1

    15 m

    l l

    l

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    Method of Sections

    Example

    The free-body diagram of

    the cut on the right side.

    H GI

    GI GI

    1 kN 5 m 7.5 kN 10 m 5.333 m

    13.13 kN 13.13 kN T

    M F

    F F

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    Method of Sections Example

    Use the line of action of the forces and take the momentabout G it will remove the F GI and F GH and shift F FH to the

    perpendicular of G.

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    Method ofSections Example

    Take the moment at G

    G

    oFH

    FH FH

    1 kN 5 m 1 kN 10 m 7.5 kN 15 m

    cos 28.1 8 m

    13.82 kN 13.82 kN C

    M

    F

    F F

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    Method of Sections Example

    Use the line of action of the forces and take the momentabout L it will remove the F GI and F FH and shift F GH to point

    G.

    1 o5 mtan 133.25.333 m

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    Method ofSections Example

    Take the moment at L

    oL GH

    GH GH

    1 kN 5 m 1 kN 10 m cos 43.2 15 m

    1.372 kN 1.372 kN C

    M F

    F F

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    Method of Sections Class Problem

    Determine the forces in members CD and CE using method of sections.

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    Homework (Due 2/24/03)

    Problems:

    6-34, 6-37, 6-38, 6-40, 6-45, 6-63

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    Truss Bonus Problem

    Determine whether themembers are unstable,

    determinate orindeterminate.

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    Truss Bonus Problem

    Determine the loads ineach of the members.

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    Truss Bonus Problem

    Determine the loads ineach of the members.

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    Truss Bonus Problem

    Determine the loads ineach of the members.