Mathcad - Modulacion AM
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Transcript of Mathcad - Modulacion AM
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8/11/2019 Mathcad - Modulacion AM
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Modulacin AM doble banda lateral con portadora DSBFC
Seal portadora
fc 20 103
:= [Hz] Frecuencia seal portadora
Ec 5:= [V]Fc t( ) Ec sin 2 fc t( ):= T
1
fc:=
0 5 10 4
1 10 3
1.5 10 3
6
4
2
0
2
4
6
Fc t( )
t
Seal moduladora
fm 2 103
:= [Hz] Frecuencia seal moduladora
Em 4:= [V]
Fm t( ) Em sin 2 fm t( ):=
0 5 10 4
1 10 3
1.5 10 3
7
5
3
1
1
3
5
7
Fm t( )
t
El coeficiente de modulacin m es mEm
Ec:= m 0.8=
Seal de frecuencias lateral superior
fm 2 103
:= [Hz] fc 20 103
:= [Hz]
5
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fusf fc fm+:= fusf 2.2 104
= [Hz] Frecuencia USB
Tusb1
fusf:=
Fusf t( ) mEc
2
cos 2 fusf t( ):= Eusf mEc
2
:= Eusf 2=
0 5 10 4
1 10 3
1.5 10 3
3
2
1
0
1
2
3
Fusf t( )
t
Seal de frecuencias de banda lateral inferior
fm 2 103
:= [Hz] fc 20 103
:= [Hz]
flsf fc fm:= flsf 1.8 104
= [Hz] Frecuencia USB
Tlsf1
flsf:=
Flsf t( ) m
Ec
2
cos 2
flsf t
( ):=
0 5 10 4
1 10 3
1.5 10 3
3
2
1
0
1
2
3
Flsf t( )
t
Finalmente la forma de onda modulada Vm(t) esta dada por:
Vam t( ) 1 m sin 2 fm t( )+( ) Ec sin 2 fc t( )( ):=
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0 5 10 4
1 10 3
1.5 10 3
10
8
64
2
0
2
4
6
8
10
Vam t( )
Fm t( ) 5+
Fm t( ) 5
t
Modulacin AM doble banda lateral s in portadora
Vam t( ) Flsf t( ) Fusf t( ):=
0 5 10 4
1 10 3
1.5 10 3
5
4
3
2
1
0
1
2
3
4
5
Vam t( )
t
7