MAT 2720 Discrete Mathematics Section 8.7 Planar Graphs .
-
Upload
loreen-harper -
Category
Documents
-
view
234 -
download
4
Transcript of MAT 2720 Discrete Mathematics Section 8.7 Planar Graphs .
MAT 2720Discrete Mathematics
Section 8.7
Planar Graphs
http://myhome.spu.edu/lauw
Goals
Define Planar Graphs The conditions for a graph to be
planar•Series Reductions
•Homeomorphic Graphs
Example 1
The following are 2 ways of drawing the same graph, K4.
Definition
A graph is planar if it can be drawn in the plane without its edges crossing.
Definition
A graph is planar if it can be drawn in the plane without its edges crossing.
K4 is planar
K5 is NOT planar
K3,3 is NOT planar
Faces of a Planar Graph
Euler’s Formula for Graphs
If G is a connected, planar graph with e edges, v vertices, and f faces, then f=e-v+2
Euler’s Formula for Graphs
If G is a connected, planar graph with e edges, v vertices, and f faces, then f=e-v+2
Example 2
K3,3 is NOT planar
Example 2
Suppose K3,3 is planar
1. Every cycle has at least 4 edges.
Example 2
Suppose K3,3 is planar
1. Every cycle has at least 4 edges.
2.The no. of edges that bound faces is at least 4f (with some edges counted twice).
f=e-v+2
Observations
A graph contains K3,3 or K5 as a subgraph is NOT planar.
Observations
A graph contains a graph “somewhat” similar to K3,3 or K5 as a subgraph is NOT planar.
Definitions (simplified)
Edges in Series
Series Reductiona
c
b
a
c
b
a
c
Homeomorphic
Two graphs are homeomorphic if they can be reduced to isomorphic graphs by a sequence of series reduction.
Example 3
The following graphs are homeomorphic.
a
b
c
d
Finally…Kuratowski’s Theorem
A graph is planar iff it does not contain a subgraph homeomorphic to K3,3 or K5 .
Example 3
Show that the following graph is not planar.
Example 3
Key: Locate the subgraph homeomorphic to K3,3 or K5
Example 3: Formal Solutions
Eliminating edges (a,b),
(f,e), and (g,h)eliminating
vertices g and h
Example 3: Formal Solutions
Eliminating edges (a,b),
(f,e), and (g,h)eliminating
vertices g and h
Since the graph contains a subgraph homeomorphic to K3,3, it is not planar