Lista2 Luiz Fernando
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Exercise 1 (Sound and Sources of Sound): For a one-dimensional problem the perfect gas equation and the momentum equation given below can be simplified as follows:
Linearise these two equations.
Utilizando o método da pertubação para linearizar as equações do gás perfeito e da quantidade de movimento, obtemos:
Temos que , e são constantes no tempo e no espaço. Assumindo que , e
são pequenos, podemos negiglenciar os termos de segunda ordem. Substituindo na equação do gás perfeito:
(1)
Substituindo na equação da quantidade de movimento:
(2)
Exercise 2 (Sound and Sources of Sound): 11Equation Section (Next)Someone tries
to estimate the distance to a storm by measuring the time delay T=7s between
lightning and thunder. The wind is blowing at an average speed of 100km/h.
Calculate the distance when
a) the effect of the wind is neglected,
b) the thunder is propagating against the wind,
c) the thunder is propagating with the wind.
Para uma atmosfera padrão ao nivel do mar:
, e ,
a) Negligênciando a influência do vento:
b) Os trovões estão propagando contra o vento:v = 100 / 3,6 =27.8
a) Os trovões estão se propagando com o vento:v = 100 / 3,6 =27.8
Exercise 3 (Sound and Sources of Sound):22Equation Section (Next) Consider a
time-harmonic plane wave at 1kHz. Calculate the frequency perceived by an
observer moving with the flow:
a) the wave is propagating upstream with M = 0:25,M = 0:5,M = 0:75,
b) the wave is propagating downstream with M = 0:25,M = 0:5,M = 0:75
Equação da onda harmônica :
Assumindo é constante e dependendo da direção do fluxo, temos:
Assim,
Para a onda se propagando na direção contrária ao fluxo,
Para M = 0.25
f '=1000∗(1+0.25)=1250Hz
Para M = 0.5
f '=1000∗(1+0.5)=1500Hz
Para M = 0.75
f '=1000∗(1+0.75)=1750Hz
Para a onda se propagando na direção do fluxo,
Para M = 0.25
f '=1000∗(1−0.25)=750Hz
Para M = 0.5
f '=1000∗(1−0.5)=500Hz
Para M = 0.75
f '=1000∗(1−0.75)=250Hz
Exercise 4 (Sound and Sources of Sound):33Equation Section (Next)44Equation
Section (Next) Describe the Lighthill Theory of Aerodynamic Sound (physics and
equations).
The sound generated by turbulence is usually called aerodynamic sound, which
is a very small byproduct of the motion of unsteady flows of high Reynolds number.
The source of aerodynamic sound was given the exact form by Lighthill. Lighthill
exactly transformed the set of fundamental equations, Navier-Stokes and continuity
equations, to an inhomogeneous wave equation whose inhomogeneous term plays the
role of the source:
(1)
where the tensor is called Lighthill’s tensor and is defined by
(2)
Here, denotes the speed of sound in a stationary acoustic medium, the air
pressure with the average , the air density with the average , and the
viscous stress tensor. It is considered that the sound wave is generated by the
quadrupole source distribution in turbulence given by the inhomogeneous term in RHS
of Equation 1 and propagates like that in the stationary acoustic medium, even though
turbulence exists. This interpretation is called Lighthill’s acoustic analogy.
Since the dissipation by can be ignored for a high Reynolds number and
adiabaticity is well held as
(3)
then the first term of Equation 2, , becomes the major term of the source. Further,
particle velocities of the sound are usually sufficiently small compared with those of the
real flow and so the source term is well approximated by that obtained from
incompressible fluid with and . Then, the sound source is given by
(4)
where and are respectively given by
(5)
(6)
For two dimensional(2D) fluid, it is further reduced into
(7)
In calculation of Lighthill’s source for 3D and 2D models, we will use the above
formulae later. For exactly incompressible fluid, an analogue to Lighthill’s equation is
written by a Poisson equation
(8)
As the analogy to the static electric field, a static pressure field is created by the
source term in RHS corresponding to the main term of Lighthill’s quadrupole source,
but the propagation speed of pressure distortion is infinite due to incompressibility. For
compressible fluid, the pressure distortion propagates at a finite speed, then the term
should be added to LHS of Equation 8 and Lighthill’s Equation 1 with the
approximations Equation 3 and Equation 4 is obtained again. Since the compressible
portion of a dynamical variable is extremely small compared with its incompressible
portion, then Lighthill’s equation Equation 1 may be well approximated in turbulence
by Equation 8.
Exercise 5 (Sound and Sources of Sound):55Equation Section (Next) Write down
the equations for the farfield pressure radiated by:
a) Monople source
(1)
b) Dipole source
(2)
c) Quadrupole source
Figure 1 – (a) Lateral quadrupole and (b) longitudinal quadrupole
Lateral
Longitudinal
Where is the fluid density, is the speed of sound, is the wave number, is the
distance from source to observation point, and and are the distances between each
pole as shown in figure 1. is a constant, termed the complex source strength and
represents the volume of fluid displaced by the source at the rate:
where is the velocity at some point on the surface of the source. For a pulsating
sphere the source strength is real, and equals the product of surface area and surface
velocity: . The pressure amplitude does not depend on angle; the
pressure produced by a monopole is the same at all points a distance r from the source.