Lesson 9.1-9.2 WS SOLUTIONS
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Lesson 9.1-9.2 WS SOLUTIONS
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Lesson 9.1-9.2 WS SOLUTIONS. Worksheet SOLUTIONS. a. 3. x. a. 4. 3. 3. C = (11, -1). 5.7. 3. x. 6.8. 4.2426. 7.8393. 3. Hypotenuse should be the longest side of a right triangle. 3. 4. R. 15. P. 20. Q. Worksheet SOLUTIONS. RIGHT ∆. ACUTE ∆. RIGHT ∆. RIGHT ∆. 7. 2.5. - PowerPoint PPT Presentation
Transcript of Lesson 9.1-9.2 WS SOLUTIONS
Lesson 9.1-9.2 WSSOLUTIONS
Worksheet SOLUTIONS
5625−5184=𝑎2
441=𝑎2
√ 441=𝑎
21=𝑎
752=722+𝑎2196−64=𝑎2
132=𝑎2
√132=𝑎
142=82+𝑎2
a
𝑝2=441+132
𝑝=√57 3
𝑝2=212+√1322
𝑝2=57 3
3
676−576=𝑎2
100=𝑎2
√100=𝑎
262=242+𝑎2
100−36=𝑥2
𝑥=√64
102=62+𝑥2
𝑥2=64
a
𝑎=10𝑥=8
39=126 𝑥
39=3 𝑥13=𝑥
x
h2=169+36
h=√205
h2=132+62
h2=205
h≈14.32 𝑖𝑛
𝐴=126∗√ 40
𝐴=3∗√ 40
49−9=h2
40=h2
√ 40=h
72=32+h2
3
𝐴≈18.97 𝑓𝑡 2
3
4
C = (11, -1)
𝐴𝐵=√25𝐴𝐵2=32+42
𝐴𝐵=5
6.8
13.4−7.7=5.7
5.7
6.82=5.72+𝑥2
x
46.24=32.49+𝑥2
13.75=𝑥2
√𝟏𝟑 .𝟕𝟓=𝒙𝐴=𝑏∗h
𝐴=13.4∗√13.75𝑨≈𝟒𝟗 .𝟔𝟗𝒄𝒎𝟐
3
3
𝑅𝑇 2=18𝑅𝑇=√18
𝑅𝑇 2=32+32
𝑅𝑇=𝑇𝑈=√18
𝑅𝑈 2≈32+(7.2426)2𝑆𝑇 +𝑇𝑈=𝑺𝑼=3+√18≈7.2426
𝑅𝑈 2≈61.4552𝑹𝑼 ≈𝟕 .𝟖𝟑𝟗𝟑
4.2426 7.8393
𝑅𝑉 2≈32+(15 .0819)2
𝑅𝑉 2≈236 .4637𝑹𝑽 ≈𝟏𝟓 .𝟑𝟖𝐜𝐦
𝑟2=16𝑟=4
4
Hypotenuse should be the longest side of a right triangle
3
PQ
R
15
20
𝑅𝑄2=152+202
𝑅𝑄2=225+400𝑅𝑄2=625𝑅𝑄=25
𝐴=1215∗20
𝐴=150 𝑖𝑛2
Worksheet SOLUTIONS
1202=982+762
14400=9604+577614400<15380
ACUTE ∆
2212=2042+852
48841=41616+722548841=48841
RIGHT ∆
52=4.82+1.4
25=23.04+1.96
25=25RIGHT ∆
822=802+182
6724=6400+3246724=6724
RIGHT ∆
7
3.5
72¿3.52+𝑥2
𝒙
49−12.25=𝑥2
36.75=𝑥2
√36.75=𝑥𝟔 .𝟎𝟔𝟐𝟐≈ 𝑥
A≈ ½ *7*
A ≈ 21.2177
2.5
42.25=36+6.256.52=62+2.52
42.25=42.25
Pyth thm works
90°
452=72+𝑥2
2025−49=𝑥2
1976=𝑥2
√1976=𝑥
4 4.45≈𝑥
3
4
6
6❑2 32+42
36≠9+16 NOT a Rectangle
5❑2 32+42
25=9+16 YES a Rectangle
Cannot be determined – No hypotenuse given
