Lecture 26: WED 18 MAR
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Transcript of Lecture 26: WED 18 MAR
Lecture 26: WED 18 Lecture 26: WED 18 MARMARCh30Ch30..4–6
Induction and InductanceInduction and Inductance
Physics 2102Spring 2007
Jonathan Dowling
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A Changing Magnetic Field Produces a Current in a Wire Loop
dA
Faraday’s LawFaraday’s Law• A time varying magnetic
FLUX creates an induced EMF
• Definition of magnetic flux is similar to definition of electric flux
B
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E =−dΦB
dt
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ΦB =r B ⋅d
v A
S∫
• Take note of the MINUS sign!!
• The induced EMF acts in such a way that it OPPOSES the change in magnetic flux (“Lenz’s Law”).
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dv A
Some ApplicationsSome ApplicationsMagLev train relies on Faraday’s Law: currents induced in non-magnetic rail tracks repel the moving magnets creating the induction; result: levitation!
ELECTRIC Guitar pickups also use Faraday’s Law — a vibrating string modulates the flux through a coil hence creating an electrical signal at the same frequency.
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Start Your Engines: The Start Your Engines: The Ignition CoilIgnition Coil
• The gap between the spark plug in a combustion engine needs an electric field of ~107 V/m in order to ignite the air-fuel mixture. For a typical spark plug gap, one needs to generate a potential difference > 104 V!
• But, the typical EMF of a car battery is 12 V. So, how does a spark plug work??
spark
12V
The “ignition coil” is a double layer solenoid:
• Primary: small number of turns -- 12 V• Secondary: MANY turns -- spark plug
http://www.familycar.com/Classroom/ignition.htm
•Breaking the circuit changes the current through “primary coil”• Result: LARGE change in flux thru secondary -- large induced EMF!
Start Your Engines: The Start Your Engines: The Ignition CoilIgnition Coil
Transformer: P=iV
dA
Changing B-Field Produces Changing B-Field Produces E-Field!E-Field!
• We saw that a time varying magnetic FLUX creates an induced EMF in a wire, exhibited as a current.
• Recall that a current flows in a conductor because of electric field.
• Hence, a time varying magnetic flux must induce an ELECTRIC FIELD!
• A Changing B-Field Produces an E-Field in Empty Space!
B
dtdsdE B
C
Φ−=⋅∫
rr
To decide SIGN of flux, use right hand rule: curl fingers around loop, +flux -- thumb.
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dv A
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E ∝ i
ExampleExample • The figure shows two circular regions R1 &
R2 with radii r1 = 1m & r2 = 2m. In R1, the magnetic field B1 points out of the page. In R2, the magnetic field B2 points into the page.
• Both fields are uniform and are DECREASING at the SAME steady rate = 1 T/s.
• Calculate the “Faraday” integral for the two paths shown.
R1 R2
∫ ⋅C
sdE rrI
II
VsTrdt
dsdE B
C
14.3)/1)(( 21 +=−−=
Φ−=⋅∫ π
rrPath I:
[ ] VsTrsTrsdEC
42.9)/1)(()/1)(( 22
21 +=−+−−−=⋅∫ ππ
rrPath II:
B1
B2
Solenoid Example Solenoid Example • A long solenoid has a circular cross-section
of radius R.• The magnetic field B through the solenoid
is increasing at a steady rate dB/dt.• Compute the variation of the electric field
as a function of the distance r from the axis of the solenoid.
First, let’s look at r < R:
dtdBrrE )()2( 2ππ =
dtdBrE
2=
Next, let’s look at r > R:
dtdBRrE )()2( 2ππ =
dtdB
rRE2
2
=
magnetic field lines
electric field lines
B
Solenoid Example Cont.Solenoid Example Cont.
r
E(r)
r = R
Er<R =r2dBdt
∝ r
Er>R =R 2
2rdBdt
∝1 / r
Added Complication: Changing B Field Is Produced by Changing Current i in the Loops of Solenoid!
B =μ0nidBdt
=μ0ndidt
i
i
EB
Er<R =μ0nr2
didt
Er>R =μ0nR
2
2rdidt
SummarySummaryTwo versions of Faradays’ law:
– A time varying magnetic flux produces an EMF:
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E =−dΦB
dt
dtdsdE B
C
Φ−=⋅∫
rr–A time varying magnetic flux produces an electric field: