LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel)
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Transcript of LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel)
LATIHAN SOAL &
PENYELESAIANNYA(Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel)
Disusun oleh :KARLINA SARI (4101412031)ALIFA MUHANDIS S A (4101412084)RIA WINARTI NINGRUM (4101412180)
TASBIATUN (4101412 )
1. Graph each set of number and write each set as the intersection or union of two sets.
{x|x < -4 or x ≥ 4}
Penyelesaian :
Gambar grafik
-5 50
2. (a) Graph each set of points. (b) express set of numbers using set- builder notation and interval notation.Point having coordinates between -2 and 2, together with poins
with coordinates greater than 5.Penyelesaian :(a) Gambar grafik
(b) Set builder notation{x|-2 ˂ x ˂ 2 and x ˃ 5} = {x |-2 ˂ x < 2} U {x|x > 5}interval notation(-2,2) U (5,+~)
-5 50
3. (a) Graph each set of points. (b) express set of numbers using set-builder notation and interval notation.Point having coordinates less than -4, together with poins coordinates beetwen 0 and 4.
Penyelesaian :(a) Gambar grafik
(b) Set builder notation{x|x ˂ -4 and 0 < x < 4} = {x |x < -4} U {x|0 < x < 4}
interval notation(-~,-4) U (0,4)
-5 50
4. Write an equivalent pair of inequalities without using absolute value notation, solve, and graph the solution set.| x - 1 | ≤ 2Is equivalent to -2 ≤ x - 1 ≤ 2Penyelesaian : Gambar Grafik: -2 ≤ x - 1 ≤ 2 -1 ≤ x ≤ 3
-5 50
5. Write an equivalent pair of inequalities without using absolute value notation, solve, and graph the solution set. |2x - 3| ≤ 5Is equivalent to -5 ≤ 2x - 3 ≤ 5Penyelesaian : Gambar Grafik : -5 ≤ 2x-3 ≤ 5 -2 ≤ 2x ≤ 8 -1 ≤ x ≤ 4
-5 50
6. Write an equivalent pair of inequalities without using absolute value notation, solve, and graph the solution set.|3x + 2| ≤ 6Is equivalent to -6 ≤ 3x + 2 ≤ 6Penyelesaian : Gambar Grafik : -6 ≤ 3x + 2 ≤ 6-8 ≤ 3x ≤ 4
-5 50
7. Express each of the following as a single inequality using absolute value notation
-5 ≤ 2x - 1 ≤ 5
Is equivalent to | 2x - 1 | ≤ 5
8. Pembuktian teorema 1.6Penyelesaian :
If and are the endpoint of a segment and the point separates the segment into two parts length and then
and
where
•Menggunakan kesebangunan : = = = k = = k = dikalikan (k ( = x (k ( () dijumlahkan dengan k ( + = k (
•
9. Show that the two line segments whose endpoints are (8,-5), (5,7) and (0,-7), (8,-5) are perpendicular.Penyelesaian :
Titik (8,-5) dan (5,7) mempunyai gradien -4 sedangkan titik 90,-7) dan (8,-5) mempunyai gradien ¼ maka dua ruas garis tersebut tegak lurus karena hasil kali dua gradiennya -1
10. Graph each interval (-3,4)
Penyelesaian :
interval dari (-3,4) adalah -3 < x < 4
11. Show that the midpoint of the hypotenusa of a right triangle equidistant the vertices of the triangle. Hint : set vertex of right angle at (0,0) and the other vertices at (a,0) and (0,b).
Penyelesaian :
SEKIAN DAN
TERIMA KASIH