J$ A..:l~ - ECED Mansoura · 1-a) Draw phasor diagram for a cylindrical rotor alternator with...

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Mansoura University Faculty of Engineering 2 nd - Year Exam. Electrical Eng. Dept. Time: 1.5 Hours "~'J~\ ~!<2;j 2012 ~JU\ -~~ (JJ'J\ s:..»ll) 44~\ ~'J'Jl ..;1#-1" ANSWER ALL THE FOLLOWING QUESTIONS: :J 9'J1 J\'~ :~ L..&~ JSJ ~)!.::JI (.)-QlyJl ~ 01.S-, lSjljiJl ~ ~-' b=-. 11" )lSjlji~.)'Lfj Ub1y l!=- .ll"..Jl ~ )WI (.)-QlyJl l>~ v (Volt) : 230 228.8 227.5 225.5 224 222 220 215.5 215 I (Ampere): 0 25 50 75 100 125 150 200 250 209.5 2e .ll"..Jl ~ )WI (.)-QlyJl ~ v (Volt) : 240 237.5 235 232 228.5 224.5 220 218 208.5 I (Ampere): 0 25 50 75 100 125 150 175 200 : ~I 1") 100 ~ JSJ ~I ~-'~-" 1"-,1 0.03 ~ JSJ ~I ~-'~ 01.SI~t! ,~I 250..Jk> ~I ~I 01.$ I~I .llyo J$ A..:l~ lS~1 .)\;ill IjS-,~..):JI ~I (I) (J-,-* ~ ~41 0-'~) , 21"~"..Jl ~1.llI (.)-QlyJl ~ (y) (J-,-* ~ ~l:;..1 u-'~) . 21" ~yJl.)lfj J5.l~liA!l\-, wl.;JY ~I ~~.) ~ (<;:) :~WI JI.J...JI 220 o*.)~ 0-0 ~~I lS~ .~yJl~..)A ~ 4--ojc. y....u~ ~I-, ,~jS...)A ~.J:1~ t.jjlji ~~ ~~} ~ ~I ~-,ti.JI ~ L.o. ~~ to.)-,::. 1000 ~~ .... u~ ~~ ,~150 o)~ t.J'Lfj h~-, ,wl~ '1"-,\ 110 ~ J4wJ1~-'~-' I"Ji 0.1 ~ ~I ~-'~ .~~ /0.)-'::' 800.)) ~yJI ~ 15 V, lOA, 85 W. ·~I~I~ " . Ul.JI * 01ft) .y.li.a 0.8 o.)~ J,..Gt..o,ljc..Jf:lAi 16 o)~)fo. ~ t.j~~,ljc. tj..J-iLilIWAll * (I) .wl..,9 200 ..Jk> ~I~)'I .~I~J,..~~ (y) . ~I 1~ ~ o~lli..ll~ (w) .0AYI 0 j::,3 J,..Gt..o ,ljc. ~1 0~liS.l144 (w) Good Luck With My Best Wishes PROF.Dr. A.R.A.Amin .r " -c, " / 1 '. I

Transcript of J$ A..:l~ - ECED Mansoura · 1-a) Draw phasor diagram for a cylindrical rotor alternator with...

Mansoura UniversityFaculty of Engineering 2nd

- Year Exam.Electrical Eng. Dept. Time: 1.5 Hours

"~'J~\ ~!<2;j 2012 ~JU\ -~~ (JJ'J\ s:..»ll) 44~\ ~'J'Jl..;1#-1"ANSWER ALL THE FOLLOWING QUESTIONS:

: J 9'J1 J\'~: ~ L..&~ JSJ ~)!.::JI (.)-QlyJl ~ 01.S-,lSjljiJl ~ ~-' b=-. 11" )lSjlji~.)'Lfj Ub1y

l!=- .ll"..Jl ~ )WI (.)-QlyJl l>~

v (Volt) : 230 228.8 227.5 225.5 224 222 220 215.5 215I (Ampere): 0 25 50 75 100 125 150 200 250 209.5

2e .ll"..Jl ~ )WI (.)-QlyJl ~

v (Volt) : 240 237.5 235 232 228.5 224.5 220 218 208.5I (Ampere): 0 25 50 75 100 125 150 175 200

: ~I 1") 100 ~ JSJ ~I ~-'~-" 1"-,1 0.03 ~ JSJ ~I ~-'~ 01.SI~t!,~I 250..Jk> ~I ~I 01.$ I~I.llyo J$ A..:l~ lS~1.)\;ill IjS-,~..):JI ~I (I)

(J-,-* ~ ~41 0-'~) , 21"~"..Jl ~1.llI (.)-QlyJl ~ (y)(J-,-* ~ ~l:;..1 u-'~) . 21"~yJl.)lfj J5.l~liA!l\-, wl.;JY ~I ~~.) ~ (<;:)

:~WI JI.J...JI220 o*.)~ 0-0 ~~I lS~ .~yJl~..)A ~ 4--ojc.y....u~ ~I-, ,~jS...)A~.J:1~ t.jjlji ~~

~~} ~ ~I ~-,ti.JI ~ L.o. ~~ to.)-,::. 1000 ~~ ....u~ ~~ ,~150 o)~ t.J'Lfjh~-, ,wl~'1"-,\ 110 ~ J4wJ1~-'~-' I"Ji 0.1 ~ ~I ~-'~ .~~ /0.)-'::'800.)) ~yJI ~

15 V, lOA, 85 W.·~I~I~" .

Ul.JI *01ft) .y.li.a 0.8 o.)~ J,..Gt..o,ljc..Jf:lAi 16 o)~)fo. ~ t.j~~,ljc. tj..J-iLilIWAll * (I).wl..,9200 ..Jk> ~I~)'I.~I~J,..~~ (y)

. ~I 1~ ~ o~lli..ll~ (w).0AYI 0j::,3 J,..Gt..o,ljc. ~1 0~liS.l144 (w)

Good Luck With My Best WishesPROF.Dr. A.R.A.Amin

.r " -c, "

/ 1'. I

Mansoura University.Faculty Of Engineering.Electrical Engineering Dept.

Electric MachineTime allowed: 3 Hours3/6/2012

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Mansoura University.Faculty Of Engineering.Electrical Engineering Dept.

Electric MachineTime allowed: 3 Hours3/6/2012

Final Term ExamFodd Grad Electronic Department

Answer All Question.

First Question: (15 Marks)1-a) Draw phasor diagram for a cylindrical rotor alternator with armature

current lagging, leading, and unity pf. discusses the various parametersinvolved in it. Explain how the diagram can be applied a synchronousmotor.

1-b) A 3 MVA, 11kv, 50 Hz, star-connected cylindrical rotr alternator 4 pole, has60 slot, with 2 conductor/slot and having armature winding of the two layertype, the winding are chorded by 2 slots, the experimental result of open-circuit and short circuit test is plotted.Find flux at full load 0.8 p.f. lagging, by using: Synchronous impedancemethod; ampere-turn method. Neglect armature resistance.

8 T7 1-~3 1-

----- 5J-

> I~r

0 4 +~><l.)Cl)ro-C.0...

3

o

T

300

[250 i~ 200 ~

~150-32

100 -(3t

50 ~eno

5 10 20 25 30 35field current

15 40 45 50 55

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Second Question: (20 Marks)2-a) i- from test of synchronous machine, find equivalent circuit.

ii- from test of induction machine, find equivalent circuit.2-b) Explain the operation principle and draw the power flow of a 3-phase

induction machine at the following operation cases:i- Starting period, ii- No-Load condition,iii- Running at rated load with slip (s) iv- Running at negative slip

then, prove that: Pg: PCU2 : Pm = 1:s : 1-S

Third Question: (20 Marks)3-a) Explain why single phase induction motors are not self starting? State and

compare between the various type of them?3-b) Explain (with help of net diagrams) the starting method adopted for:

i-Three-phase induction motor (squirrel-cage and slip ring).ii-Three-phase synchronous machine.

3-c) A 415 V, 50 Hz, 6 pole, delta connected three phase induction motorconsumes 70 Watt with line current of 112.5A and runs at slip 3 %. If thestator iron losses is 3 KW, windage and friction losses 2 KW and statorresistance 0.1O/ph, and rotor reactance 1O/ph. Calculate:a- Rotor cupper loss; b- Mechanical power;c- Developed shaft torque; d- maximum torque;

d- Efficiency

With my Beast Wishes

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