Hollowblock slabs.pdf
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Hollow Block Slabs
2
R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Hollow Block Slabs (definitions) Hollow blocks are used
to fill portions of theslab thickness; thisresults in deeper armfor the reinforcement while saving theamount of concreteand hence the own
weight of the slab.The reinforcement is located between the
blocks inside the ribs.Blocks may be concrete blocks or styro-foam
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Hollow Block Slabs (definitions)
When the ribs are inone direction then it isa one-way hollow block
slab, regardless of therectangularity; r.
When ribs are in bothdirections then it is atwo-way hollow block
slab.
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Advantages & Disadvantages Advantages
Reducing slab weight by reducing amount of concrete below neutral axis.
Ease of construction, especially when all beamsare hidden beams.
Economic for spans > 5m with moderate liveload: hospitals, office and residential buildings.
Improved insulation for sound and heat.
Disadvantages Not economic for small spans Not suitable for heavy loads or dynamic loads. Difficult to repair or strengthen
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
One-Way Hollow Block Slabs
8282520Clear span (Ln /t)
cantileverContinuous
both ends
Continuous
one end
Simply
supportedSupport condition
Ribs are in one direction only
For spans less than 10m or cantilevers less than 2m long.
St. 400/600; for other grades divide values by
+
6504.0
y f
b e
ts
t
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Cross ribs Cross ribs are used when the live load ≥
3kN/m2 or Span > 5m.
Threecross ribs
One crossrib
One crossrib
NoCross Sibs
>3kN/m2> 3kN/m2≤ 3kN/m2≤ 3kN/m2Live Load
>7m4m – 7m>5m≤ 5mSpan
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Minimum Dimensions
e ≤ 700mm b = t/3 ≥ 100mm t s = e/10 ≥ 50mm
b e
ts
t
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Loading
Own weight including blocks’ weight. Flooring Live Load
b e
ts
t
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Loading
Own Weight including blocks’ weight (kN/m2)
1.200.704.784.103.803.303.363.03
Twoway
Oneway
Twoway
Oneway
Twoway
Oneway
Twoway
Oneway
Foam Blocks500x400x200
Concrete Blocks400x200x250
Concrete Blocks400x200x200
Concrete Blocks400x200x150
b e
ts
t
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Load Distribution Factors for Two-way When LL ≤ 5 kN/m2 or when the compression
flange is incomplete.
0.0530.0630.0770.0930.1130.1400.1720.2120.2620.3330.396β
0.8490.8300.8060.7780.7460.7060.6600.6060.5430.4730.396α
2.01.91.81.71.61.51.41.31.21.11r
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Load Distribution Factors for Two-way
When LL > 5 kN/m2
0.0590.0720.0860.1070.1330.1660.2030.2580.3280.4050.500β
0.9410.9280.9140.8930.8670.8340.7970.7420.6720.5950.500α
2.01.91.81.71.61.51.41.31.21.11r
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Calculate Bending Moments Two spans
When LL ≤ DL, andthe difference betweenspans is not more than20%; then the bendingmoment could becalculated as following.
W = wu for limit statedesign method.
& w = w for allowablestresses designmethod.
w
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
More than two spans
Spans differences are not more than 20%
LL ≤ DL
Calculate Bending Moments
W
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Using Design Aids Charts (flexure)
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Design for Shear
Shearing stresses should be less than the concrete shear capacityand, hence, minimum shear reinforcement could be used.
)(q
q.
4.0Aent;reinforcemshearMinimum
) / (q16.0qcapacity;shearConcrete
.qstress;Shearing
2
cu
umins,
2
ucu
u
mmsb f
mm N f
t b
Q
y
c
cu
u
=
≥=
=
γ
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r
1 5 ,
2 0 1 2
Minimum Reinforcement
5φ6mm/m’ perpendicular to ribs.
4φ6mm/m’ parallel to ribs.
Bottom reinforcement = rib mainreinforcement.
Top reinforcement = ½ bottomreinforcement
Stirrups
Rib reinf.
Slab reinf.
In top slab
In Cross rib
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R C D e s i g n 2 - D r . H a n y N e s s i m
M o n d a y ,
O c t o b e r 1 5 ,
2 0 1 2
Minimum Reinforcement
Stirrups
Rib reinf.
Slab reinf.
In Main rib
(as beams)
≥
≥
=
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s t e e ls t e e l
s t e e ld e f o r m e d
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Example