Goh_EC7_Pile_CPG_July2013.pdf

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CPG In-House Course on Pile design (EC7 and SS EN 1997-1:2010 Singapore National Annex to Eurocode 7) - July 2013 A/P Anthony Goh Nanyang Technological University E il t h@ t d Email: ctcgoh@ntu.edu.sg CPG EC7 course (Goh) 1 References Bauduin, C.M. (2001). Design procedure according to Eurocode 7 and analysis of the test results. Proc. Symposium on Screw Piles – Installation and design in stiff clay, Brussels, Balkema, pp.275-303. Bond, A. and Harris, A. (2008). Decoding Eurocode 7. Taylor & Francis. f C G ( ) Dept of Communities and Local Government, UK (2006). A designers’ simple guide to BS EN 1997. Driscoll R., Scott, P . and Powell J. (2008). EC7 implications for UK Driscoll R., Scott, P . and Powell J. (2008). EC7 implications for UK practice. Eurocode 7 Geotechnical design. CIRIA C641. Frank, R., Bauduin C., Driscoll, R., Kawadas, M., Krebs Ovesen, N., Orr, T. d Sh B (2004) D i G id t EN 1997 1 E d 7 and Schuppener, B. (2004). DesignersGuide to EN 1997-1 Eurocode 7: Geotechnical design – General rules. Thomas Telford. Simpson B. and Driscoll, R. (1998) Eurocode 7 a commentary . BRE. Tomlinson M. and Woodward, J. (2008). Pile design and construction practice. 5 th edition. Taylor & Francis. 2 CPG EC7 course (Goh)

Transcript of Goh_EC7_Pile_CPG_July2013.pdf

  • CPG In-House Course onPile design (EC7 and SS EN 1997-1:2010

    Singapore National Annex to Eurocode 7)- July 2013

    A/P Anthony GohNanyang Technological University

    E il t h@ t dEmail: [email protected]

    CPGEC7course(Goh) 1

    References

    Bauduin, C.M. (2001). Design procedure according to Eurocode 7 andanalysis of the test results. Proc. Symposium on Screw Piles Installationand design in stiff clay, Brussels, Balkema, pp.275-303.

    Bond, A. and Harris, A. (2008). Decoding Eurocode 7. Taylor & Francis.f C G ( ) Dept of Communities and Local Government, UK (2006). A designers

    simple guide to BS EN 1997.

    Driscoll R., Scott, P. and Powell J. (2008). EC7 implications for UK Driscoll R., Scott, P. and Powell J. (2008). EC7 implications for UKpractice. Eurocode 7 Geotechnical design. CIRIA C641.

    Frank, R., Bauduin C., Driscoll, R., Kawadas, M., Krebs Ovesen, N., Orr, T.d S h B (2004) D i G id t EN 1997 1 E d 7and Schuppener, B. (2004). Designers Guide to EN 1997-1 Eurocode 7:

    Geotechnical design General rules. Thomas Telford.

    Simpson B. and Driscoll, R. (1998) Eurocode 7 a commentary. BRE.p , ( ) y Tomlinson M. and Woodward, J. (2008). Pile design and constructionpractice. 5th edition. Taylor & Francis.

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  • SINGAPORENATIONALANNEX

    CPGEC7course(Goh) 3

    NAtoSSEN19971:2010

    SINGAPORENATIONALANNEXS G O ONAtoSSEN19971:2010SingaporeNationalAnnextoEurocode7:GeotechnicaldesignP t 1 G l l

    NA 2 Nationally Determined Parameters

    Part1:Generalrules

    NA.2 Nationally Determined ParametersAs indicated in Table NA.1, only Design Approach 1 is to b d i Sibe used in Singapore.

    The values given in the Tables in Annex A of this National Annex replace the recommended values in Annex A of SS EN 1997-1 : 2010.

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  • For example, Table A.NA.7 replaces Table A.7

    Resistance Symbol Set

    Table A.NA.7 Partial resistance factors (R) for bored piles for the STR and GEO limit states

    Resistance Symbol SetR1 R4 without explicit

    verification of SLSA)R4 with explicit

    verification of SLSA)

    Base b 1.0 2.0 1.7Shaft (compression)

    s 1.0 1.6 1.4T t l/C bi d 1 0 2 0 1 7Total/Combined (compression)

    t 1.0 2.0 1.7Shaft in tension s;t 1.0 2.0 1.7A) The lower values in R4 may be adopted (a) if serviceability is verified by load tests (preliminary and/or working)

    carried out on more than 1% of the constructed piles to loads not less than 1.5 times the representative load forwhich they are designed, or (b) if settlement is explicitly predicted by a means no less reliable than in (a), or (c)if settlement at the serviceability limit state is of no concern.

    SS NA permits the use of different R4 values dependingon the verification of SLS

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    on the verification of SLS

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    For example, Table A.NA.7 replaces Table A.7

    Table A.7 Partial resistance factors (R) for bored piles

    Resistance Symbol SetR1 R4R1 R4

    Base b 1.25 1.6Shaft (compression)

    s 1.0 1.3 Total/Combined (compression)

    t 1.15 1.5(compression)Shaft in tension s;t 1.25 1.6

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  • DefinitionsActions on the foundations (Clause 2.4.2(4)) Earth and groundwater pressuresg p Weight of soil, rock and water Dead and imposed loading from structure Dead and imposed loading from structure Imposed loading from ground movements (eg. swelling,

    shrinkage, down-drag)g , g)

    Ground properties (Clause 2.4.3) from field or laboratory tests (directly or by correlation from field or laboratory tests (directly or by correlation,

    theory or empiricism) Takes into account effects of time, stress level and Takes into account effects of time, stress level and

    deformation etc

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    Definitions

    Geometrical data (Clause 2.4.4(1)P) Include slope of the ground surface, groundwaterp g , g

    levels and structural dimensions

    Characteristic values of Geotechnical parameters(Clause 2.4.5.2) Selected from the a ailable information (eg SI report) Selected from the available information (eg. SI report) Based on a cautious estimate of the data made within

    the zone influenced by stresses transmitted to thethe zone influenced by stresses transmitted to the ground

    Less than most probable values (most situations) Higher than most probable where higher values have an

    unfavourable effect on the foundation behaviour (eg. down drag)

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    down-drag)CPGEC7course(Goh)

  • Definitions

    Ultimate Limit States (Clause 2.4.7.1) for foundations STR: internal failure or excessive deformation of the STR: internal failure or excessive deformation of the

    structure

    GEO f il i d f ti f th d GEO: failure or excessive deformation of the ground

    Model Factors (Clause 2.4.7.1(6))

    M d l f t b li d t th d i l fModel factors may be applied to the design value of aresistance or the effect of an action to ensure that theresults of the design calculation model are either accurateresults of the design calculation model are either accurateor err on the safe side.

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    Design Approach 1 (Clause 2.4.7.3.4.2(1)P)STR limit state failure or excessive deformation of the

    structureGEO limit state failure or excessive ground deformation

    Ensure that:

    Design effects of actions Ed design resistance Rd

    Design Approach 1

    C bi ti 1 A1 + M1 + R1Combination 1: A1 + M1 + R1Combination 2: A2 + M2 + R1

    A = action; M = material properties; R = ground resistance

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  • Design Approach 1 (Clause 2.4.7.3.4.2(1)P)

    Combination 1: A1 + M1 + R1

    Combination 2: A2 + M2 + R1

    Clause 2.4.7.3.4.2(2)P Note 2 If it is obvious thatone combination governs the design, it is notnecessary to perform full calculations for the othercombination.

    Often Combination 2 will govern the geotechnicalOften Combination 2 will govern the geotechnicalsizing and Combination 1 will govern the structuraldesign

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    design.

    GEO and STR ULS calculations (Design Approach 1) Clause 2.4.7.3.2 and 2.4.7.3.3Clause 2.4.7.3.2 and 2.4.7.3.3

    Ed RdE = design value of the effects of all the actionsEd = design value of the effects of all the actions{ }dMkrepFd aXFEE ;/; =R = design al e of the corresponding gro nd and/or str ct re{ }dMkrepFd aXFRR ;/; =Rd = design value of the corresponding ground and/or structure

    { } RdkrepFd aXFRR = /;;For piles and anchorages Frep Representativevalueofanactionrep pF PartialfactorforanactionXk Characteristicvalueofamaterial (ground)propertyM Partialfactorforthematerialpropertyad DesignvalueofageometricalpropertyR Partialfactorforthe resistanceoftheground

    12

    R a t a acto o t e es sta ce o t e g ou d

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  • Serviceability Limit State (Clause 2.4.8) y ( ) Partial factors normally taken as 1.0 (Clause2.4.8(2))( ))

    Verification for serviceability limit states shallyrequire that

    Ed Cd

    where Cd = the limiting design value of the relevant

    d d

    d g gserviceability criterion (Clause 2.4.8(1)P)

    or be done through the method given in 2.4.8(4).

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    2 4 8(4) It may be verified that a sufficiently low2.4.8(4). It may be verified that a sufficiently lowfraction of the ground strength is mobilised to keepdeformations within the required serviceability limitsdeformations within the required serviceability limits,provided this simplified approach is restricted todesign situations where:design situations where: a value of the deformation is not required to checkth i bilit li it t tthe serviceability limit state; established comparable experience exists withsimilar ground, structures and application method.

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  • Limiting values of movements of foundations (Clause 2.4.9(4)P Note)(Clause 2.4.9(4)P Note) In the absence of specified limiting values, Annex H

    (informative) may be used.

    Annex H For normal structures with isolated foundations,total settlements of up to 50 mm are often acceptable.p pAlso provides guidelines for Maximum relative rotation.

    Annex F Sample methods for settlement evaluation (basedAnnex F Sample methods for settlement evaluation (based on elasticity theory)

    7.6.4. Vertical displacements of pile foundations (serviceability of supported structures) 7 6 4 1 NOTE For piles bearing in medium to dense soils and for7.6.4.1 NOTE For piles bearing in medium-to-dense soils and fortension piles, the safety requirements for the ultimate limit statedesign are normally sufficient to prevent a serviceability limit state

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    in the supported structure.

    Pile Foundation Design (Design Approach 1)

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  • 7.2 Limit states

    (1)P The following limit states shall be considered ..... :

    loss of overall stability; bearing resistance failure of the pile foundation; uplift or insufficient tensile resistance of the pile foundation; failure in the ground due to transverse loading of the pile foundation; structural failure of the pile in compression, tension, bending, buckling

    or shear;or shear; combined failure in the ground and in the pile foundation; combined failure in the ground and in the structure; excessive settlement; excessive settlement; excessive heave; excessive lateral movement;

    unacceptable vibrations unacceptable vibrations.

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    7.3.1 Actions and design situations Axial loading Transverse (horizontal) loading( ) g

    7.3.2 Actions due to ground displacement lid ti ( ti ki f i ti ) consolidation (negative skin friction) swelling or heave (tension pile) lateral loading from adjacent surcharge or embankment lateral loading from adjacent surcharge or embankment

    Analysis of Geotechnical action (Clause 7.3.2.1(3)P):y ( ( ) ) pile-soil interaction analysis (t-z or p-y analysis); or upper-bound force exerted on the pile by the ground

    t i l l t d d t t d timovement is calculated and treated as an action

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  • Clause 2.4.7.3.4.2(2)P

    Combination 1: A1 + M1 + R1

    Combination 2: A2 + (M1 or M2) + R4

    In combination 2, set M1 is used for calculating resistancesof piles (or anchors) and set M2 for calculating

    nfa o rable actions on piles eg o ing to negati e skinunfavourable actions on piles eg. owing to negative skinfriction

    Clause 2.4.7.3.4.2 (2) Note 2 If it is obvious that onecombination governs the design, it is not necessary to

    f f ll l l ti f th th bi ti

    A = action; M = material properties; R = ground resistance

    perform full calculations for the other combination.

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    A = action; M = material properties; R = ground resistanceCPGEC7course(Goh)

    7.4.1 Design methods g

    (1)P The design shall be based on one of the following approaches:

    the results of static load tests, which have been demonstrated, bymeans of calculations or otherwise, to be consistent with other relevantexperience;experience;

    empirical or analytical calculation methods whose validity has beendemonstrated by static load tests in comparable situations;demonstrated by static load tests in comparable situations;

    the results of dynamic load tests whose validity has beendemonstrated by static load tests in comparable situations;demonstrated by static load tests in comparable situations;

    the observed performance of a comparable pile foundation, providedh hi h i d b h l f i i i i dthat this approach is supported by the results of site investigation and

    ground testing.

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  • Design methods for pile foundations (Clause 7.4.1(P))

    Method Comments

    Staticloadtests# Validity mustbedemonstratedbycalculations orothermeanstobeconsistentwithotherrelevantexperiences.

    Empiricaloranalyticalcalculations

    Validity mustbedemonstratedbystaticloadtestsincomparable situationscalculations comparablesituations.

    Dynamic impact tests# Validitymustbedemonstratedbystaticloadtestsincomparablesituations.p

    Piledrivingformulaeorwaveequationanalysis#

    Validity mustbedemonstratedbystaticloadtestsincomparablesituations, andgroundstratificationhasbeendetermineddetermined.

    Observation Observedperformanceofcomparablepilefoundation;mustbesupportedbyresultsofSI andgroundtesting.

    # Usually applies to trial (preliminary) piles and theresults of tests on these piles are used to design the

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    results of tests on these piles are used to design theworking piles.

    7 4 1(3) Static load tests may be carried out on trial piles installed for7.4.1(3) Static load tests may be carried out on trial piles, installed for test purposes only, before the design is finalised, or on working piles, which form part of the foundation.

    Trial piles (installed for test purposes only, before thedesign is finalised); preliminary piledesign is finalised); preliminary pile.

    Working piles (which form part of the permanentfoundation works); Test load must be at least equal); qto the design load (Clause 7.5.2.3(2)P).

    UK experience Most contracts tests on trial piles are impractical asthere is insufficient lead time between the main piling works and the testprogrammes. Preliminary tests are seldom carried out on piles withp g y psimilar widths and lengths, which makes it difficult to derive a sensiblemean test result. In many tests, the ultimate load is obtained fromextrapolation of the load-displacement curve, adding further to the

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    extrapolation of the load displacement curve, adding further to theuncertainty in any calculated mean (Bond and Harris, 2008).

  • 7.5 Pile load tests

    7.5.1(1)P Pile load tests shall be carried out in the following situations:

    when using a type of pile or installation method for which there is no when using a type of pile or installation method for which there is nocomparable experience;

    when the piles have not been tested under comparable soil andwhen the piles have not been tested under comparable soil andloading conditions;

    when the piles will be subject to loading for which theory andexperience do not provide sufficient confidence in the design. The piletesting procedure shall then provide loading similar to the anticipatedloading;g;

    when observations during the process of installation indicate pilebehaviour that deviates strongly and unfavourably from the behaviour

    i i d h b i f h i i i i i d hanticipated on the basis of the site investigation or experience, and whenadditional ground investigations do not clarify the reasons for thisdeviation.

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    (2) Pile load tests may be used to:

    assess the suitability of the construction method; assess the suitability of the construction method;

    determine the response of a representative pile and thesurrounding ground to load both in terms of settlement and limit load;surrounding ground to load, both in terms of settlement and limit load;

    to allow judgement of the overall pile foundation.

    Clause 7.5.1(4)P and (5)P) If one pile load test is carried out located where the

    most ad erse gro nd conditions are belie ed tomost adverse ground conditions are believed to occur. If this is not possible, an allowance shall bemade when deriving the characteristic value of themade when deriving the characteristic value of the compressive resistance.

    If more than one pile load test is carried out locations must be representative of the site of the pilefoundation and one of the test piles shall be locatedwhere the most adverse ground conditions are

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    where the most adverse ground conditions arebelieved to occur.

  • 7.5.2 Static load tests

    7.5.2.1 Loading procedure (1)P Measurements during static load tests must allow (1)P Measurements during static load tests must allow

    conclusions about deformation, creep and rebound ofthe piled foundation. ...the piled foundation. ... Trial piles measurements must be able to draw conclusions# about the ultimate failure load.

    (4)Tensile pile test should be carried out to failure (as brittle failure can occur).

    # However, it should be understood that it is not alwaysnecessary to bring trial piles to failure: the common practicenecessary to bring trial piles to failure: the common practiceof deriving the ultimate failure load by extrapolating theload-displacement curve can be used. (Frank et al. 2004)

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    load displacement curve can be used. (Frank et al. 2004)

    7.5.2.2 Trial piles(1)P The number of trial piles required to verify the design shall depend on thefollowing: the ground conditions and their variability across the site; the Geotechnical Category of the structure, if appropriate; previous documented evidence of the performance of the same type of pile insimilar ground conditions; the total number and types of pile in the foundation design.

    (2)P The ground conditions at the test site shall be investigated thoroughly. Thed th f b i fi ld t t h ll b ffi i t t t i th t f th ddepth of borings or field tests shall be sufficient to ascertain the nature of the groundboth around and beneath the pile tip. All strata likely to contribute significantly to pilebehaviour shall be investigated.

    (3)P The method used for the installation of the trial piles shall be fully documentedin accordance with 7.9.

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  • 7.5.2.3 Working Pile(2)P Test load must be at least equal to the design load for the foundation(2)P Test load must be at least equal to the design load for the foundation.

    7.5.3 Dynamic load tests

    (1)Dynamic load tests may be used to estimate the compressive(1)Dynamic load tests may be used to estimate the compressiveresistance provided an adequate site investigation has been carried outand the method has been calibrated against static load tests on the samet f il f i il l th d ti d i bl iltype of pile, of similar length and cross-section, and in comparable soilconditions, (see 7.6.2.4 to 7.6.2.6).

    (2)P If more than one type of dynamic test is used, the results of differenttypes of dynamic test shall always be considered in relation to each other.

    (3) Dynamic load tests may also be used as an indicator of theconsistency of the piles and to detect weak piles.

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    7.5.4 Load test report

    (1)P It shall be specified that a factual report shall be written for all loadtests. Where appropriate, this report shall include:

    a description of the site; a description of the site; the ground conditions with reference to ground investigations; the pile type;

    d i ti f th il i t ll ti d f bl t d description of the pile installation and of any problems encounteredduring the works;

    a description of the loading and measuring apparatus and the reactionsystem;

    calibration documents for the load cells, the jacks and the gauges; the installation records of the test piles;p ; photographic records of the pile and the test site; test results in numerical form; time-displacement plots for each applied load when a step loadingtime displacement plots for each applied load when a step loading

    procedure is used; the measured load-displacement behaviour;

    reasons for any departures from the above requirements

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    reasons for any departures from the above requirements .

  • Limit states (axially loaded piles) Clause 7.6.1.1(1)P( y p ) ( ) ULS of compressive or tensile failure of a single pile ULS of compressive or tensile failure of the pile ULS of compressive or tensile failure of the pile

    foundation as a whole

    ULS of collapse or severe damage to a supportedstructure caused by excessive displacement orstructure caused by excessive displacement or

    differential displacements of the pile foundation

    SLS in the supported structure caused by displacementof the pilesp

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    Ultimate compression limit state (Clause 7.6.1.1(3)) It is often difficult to define an ultimate limit state from a load settlement plot. Settlement of the pile head = 10% of pile base diameter is used as the failure criterionpile base diameter is used as the failure criterion.

    Serviceability Limit State (Clause 2.4.8(2)) Partial factors normally taken as 1.0

    Serviceability of supported structure Clause 7 6 4 1 (2) Note- Clause 7.6.4.1 (2) Note

    For piles bearing in medium-to-dense soils and for tensionpiles, the safety requirements for the ultimate limit statepiles, the safety requirements for the ultimate limit statedesign are normally sufficient to prevent a serviceability limitstate in the supported structure.

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  • 7.6.2 Compressive ground resistance

    7.6.2.1 General(1)P To demonstrate that the pile foundation will support the design load

    i h d f i i f il h f ll i i liwith adequate safety against compressive failure, the following inequality shall be satisfied for all ultimate limit state load cases and load combinations:

    Fc;d Rc;d

    Fc;d = design axial compression load on a pileor a group of piles

    Rc;d = compressive resistance

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    (3)P For piles in groups, two failure mechanisms shall be(3)P For piles in groups, two failure mechanisms shall betaken into account: compressive resistance failure of the piles individually; compressive resistance failure of the piles and the soilcontained between them acting as a block.

    The design resistance shall be taken as the lower valuecaused by these two mechanisms.caused by these two mechanisms.

    (4) The compressive resistance of the pile group acting asa block may be calculated by treating the block as a singlepile of large diameter.

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  • (5)P The stiffness and strength of the structure connectingthe piles in the group shall be considered when deriving thethe piles in the group shall be considered when deriving thedesign resistance of the foundation.

    (6) If the piles support a stiff structure, advantage may betaken of the ability of the structure to redistribute loadbetween the piles. A limit state will occur only if a significantnumber of piles fail together; therefore a failure modeinvolving only one pile need not be consideredinvolving only one pile need not be considered.

    (7) If the piles support a flexible structure, it should be(7) If the piles support a flexible structure, it should beassumed that the compressive resistance of the weakestpile governs the occurrence of a limit state.

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    (8) Special attention should be given to possible failure ofedge piles caused by inclined or eccentric loads from theedge piles caused by inclined or eccentric loads from thesupported structure.

    (9)P If the layer in which the piles bear overlies a layer ofweak soil, the effect of the weak layer on the compressiveresistance of the foundation shall be considered.

    (10)P The strength of a zone of ground above and below(10)P The strength of a zone of ground above and belowthe pile base shall be taken into account when calculatingthe pile base resistance.the pile base resistance.

    NOTE This zone may extend several diameters above andbelow the pile base. Any weak ground in this zone has arelatively large influence on the base resistance.

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  • (11) Punching failure should be considered if weak ground ispresent at a depth of less than 4 times the base diameterpresent at a depth of less than 4 times the base diameterbelow the base of the pile.

    (12)P Where the pile base diameter exceeds the shaftdiameter, the possible adverse effect shall be considered.

    (13) For open-ended driven tube or box-section piles withopenings of more than 500 mm in any direction and withoutopenings of more than 500 mm in any direction, and withoutspecial devices inside the pile to induce plugging, the baseresistance should be limited to the smaller of:resistance should be limited to the smaller of:

    the shearing resistance between the soil plug and theinside face of the pile;

    the base resistance derived using the cross-sectional areaof the base

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    of the base.

    Compressive Ground Resistance (Clause 7.6.2)

    Fc;d Rc;dFc;d = design axial compression load on a pile

    or a group of pilesg p pRc;d = compressive resistance

    Fc;d should include the weight of the pile.Weight of piles is considered as permanent action.Rc;d should include the overburden pressure of the soil at the foundation basefoundation base.However, these two items may be disregarded if theycancel approximately.

    36

    pp y

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  • They may not cancel if: (a) downdrag is significant, (b) they y ( ) g g ( )soil is very light, or (c) the pile extends above the groundsurface. (Clause 7.6.2.1(2))

    For structures having sufficient stiffness and strength totransfer loads from weak to strong piles a reductiontransfer loads from weak to strong piles, a reductionfactor of 1.1 may be introduced. Clauses 7.6.2.2(9) and7.6.2.3(7). See Tables A.NA.9 and A.NA.10.( )

    Pile base resistance shall take into account the strength

    See Clause 7 8 for Structural design of piles

    above and below the pile base. Clauses 7.6.2.1(9) to (11).

    See Clause 7.8 for Structural design of piles

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    Rc;d = compressive resistance, shall be derived either from:

    k;bk;sd;c

    RRR += or t

    k;bk;s

    t

    k;td;c

    RRRR

    +==P

    bs tt Clause 7.6.2.2(14)

    Partial factor on shaft resistanceRefer to Tables A.NA.6, 7 and 8

    WRs

    s Partialfactoronshaftresistanceb Partial factoronbaseresistance Partial factor on total characteristic

    R

    t PartialfactorontotalcharacteristicresistanceRt;k

    Th l f i i ll d h d i iRb The left equation is normally used when designingby calculation. The right equation is used whenthe shaft and base components cannot be

    CPGEC7course(Goh) 38

    determined separately.

  • Rc;d = compressive resistance

    k;bk;sd;c

    RRR += or t

    k;bk;s

    t

    k;td;c

    RRRR

    +==P

    bs tt

    The differences of the partial factor valuesbetween driven, bored and CFA piles is mainly

    WRs

    , p yrelated to the increasing probability of unexpectedeffects during pile installation adversely affectingthe pile bearing capacity (Bauduin 2001)

    R

    the pile bearing capacity (Bauduin 2001).

    SS NA permits the use of different R4l d di th ifi ti fRb values depending on the verification of

    SLS (Tables A.NA.6 to 8)

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    Table A.NA.6 Partial resistance factors (R) for driven piles for the STR and GEO limit states

    Resistance Symbol SetR1 R4 without

    explicit ifi ti f

    R4 with explicit verification of

    SLS A)verification of SLS A)

    SLS A)

    Base b 1.0 1.7 1.5Shaft (compression) 1 0 1 5 1 3Shaft (compression) s 1.0 1.5 1.3Total/Combined (compression)

    t 1.0 1.7 1.5Shaft in tension s;t 1.0 2.0 1.7A) The lower values in R4 may be adopted (a) if serviceability is verified by load tests (preliminary

    and/or working) carried out on more than 1% of the constructed piles to loads not less than 1.5ti th t ti l d f hi h th d i d (b) if ttl t i li itltimes the representative load for which they are designed, or (b) if settlement is explicitlypredicted by a means no less reliable than in (a), or (c) if settlement at the serviceability limitstate is of no concern.

    SS NA permits the use of different R4 values depending on the verification of SLS With no testing (relying solely on calculation), a higher level of reliability is needed in the calculations.

    40

    s eeded t e ca cu at o s

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  • Table A NA 7 Partial resistance factors ( ) for bored piles for the STR

    Resistance Symbol Set

    Table A.NA.7 Partial resistance factors (R) for bored piles for the STR and GEO limit states

    Resistance Symbol SetR1 R4 without explicit

    verification of SLSA)R4 with explicit

    verification of SLSA)

    Base b 1.0 2.0 1.7Shaft (compression)

    s 1.0 1.6 1.4Total/Combined (compression)

    t 1.0 2.0 1.7Shaft in tension s;t 1.0 2.0 1.7A) The lower values in R4 may be adopted (a) if serviceability is verified by load tests (preliminary and/or working)

    carried out on more than 1% of the constructed piles to loads not less than 1.5 times the representative load forwhich they are designed, or (b) if settlement is explicitly predicted by a means no less reliable than in (a), or (c)if settlement at the serviceability limit state is of no concern.y

    SS NA permits the use of different R4 values depending on the verification of SLS

    41CPGEC7course(Goh)

    Table A.NA.8 Partial resistance factors (R) for continuous flight auger CFA piles for the STR and GEO limit states

    Resistance Symbol SetR1 R4 without explicit R4 with explicit

    p

    pverification of SLS A)

    pverification of SLS A)

    Base b 1.0 2.0 1.7Shaft 1 0 1 6 1 4Shaft (compression)

    s 1.0 1.6 1.4Total/Combined (compression)

    t 1.0 2.0 1.7Shaft in tension s,t 1.0 2.0 1.7A) The lower values in R4 may be adopted (a) if serviceability is verified by load tests

    (preliminary and/or working) carried out on more than 1% of the constructed piles to loads not(preliminary and/or working) carried out on more than 1% of the constructed piles to loads notless than 1.5 times the representative load for which they are designed, or (b) if settlement isexplicitly predicted by a means no less reliable than in (a), or (c) if settlement at theserviceability limit state is of no concern.

    SS NA permits the use of different R4 values depending on the verification

    42

    SS NA permits the use of different R4 values depending on the verification of SLS

    CPGEC7course(Goh)

  • Draft Malaysian Standard (2011)( )

    CPGEC7course(Goh) 43

    Summary of partial factors (NA to SS EN 1997-1:2010)

    Combination 1 Combination 2Without explicit

    verification of SLS A)With explicit

    verification of SLS A)

    A1 M1 R1 A2 M1 R4 A2 M1 R4Action Permanent Unfav 1.35 1.00 1.00

    Fav 1.00 1.00 1.00Variable Unfav 1.50 1.30 1.30

    Soil Tan 1.00 1.00 1.00c 1.00 1.00 1.00cu 1.00 1.00 1.00Unit wt. 1.00 1.00 1.00

    Driven Piles Base 1.00 1.70 1.50Shaft (comp) 1.00 1.50 1.30Total 1.00 1.70 1.50

    Bored Piles & CFA

    Base 1.00 2.00 1.70& CFA Shaft (comp) 1.00 1.60 1.40

    Total (comp) 1.00 2.00 1.70A) The lower values in R4 may be adopted (a) if serviceability is verified by load tests (preliminary and/or working) carried out onmore than 1% of the constructed piles to loads not less than 1.5 times the representative load for which they are designed, or (b) if

    44

    settlement is explicitly predicted by a means no less reliable than in (a), or (c) if settlement at the serviceability limit state is of noconcern.

    CPGEC7course(Goh)

  • Ultimate compressive resistance by calculationfrom Ground Test results

    Clause 7.6.2.3.

    Two calculation methods:

    Clause 7.6.2.3.

    Two calculation methods:

    Model pile: procedure (Clause 7 6 2 3(5)P) Model pile : procedure (Clause 7.6.2.3(5)P) Alternative procedure (Clause 7.6.2.3(8))

    45CPGEC7course(Goh)

    Ultimate compressive resistance by calculation from

    Model Pile method assumes a fictitious pile of the

    Ground Test results (Clause7.6.2.3(5)P)

    Model Pile method assumes a fictitious pile of thesame cross-section and length as proposed for the projectis installed at the location of each borehole or in-situ test.The shaft resistance and the base resistance arecalculated for the mean and minimum soil parameters for

    h b h l t t fil Th t t f theach borehole or test profile. The two components of theresistance are then divided by a correlation factor which depends on the number of ground test profiles onwhich depends on the number of ground test profiles onthe site.

    correlation factor 3 and 4 from Table A.NA.10

    46CPGEC7course(Goh)

  • Clause 7.6.2.3(5)

    )R()R(RRModel pile method

    ==

    +=+=4

    mincal;c

    3

    meancal;ccal;c

    cal;scal;bk;sk;bk;c

    )R(;

    )R(MinR

    RR)RR(R (7.8)

    correlation factor 3 and 4 from Table A.NA.10depending on number of profiles n

    meancalsmeancalbmeancalscalbmeancalc RRRRR )()()()( ;;;;; +=+=min;;min; )()( calscalbcalc RRR += min;;min; )()( calscalbcalc RRR +

    Table A.NA.10 Correlation factors () to derive characteristic values of the resistance of axially loaded piles from ground test results (n - number of profiles of tests)loaded piles from ground test results (n number of profiles of tests)

    for n = 1 2 3 4 5 7 10 3 1.55 1.47 1.42 1.38 1.36 1.33 1.3034 1.55 1.39 1.33 1.29 1.26 1.20 1.15 NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values of 3 and 4 may be divided by 1.1, provided that 3 is never less than 1.0, see EN 1997-1 7.6.2.3(7).

    47

    CPGEC7course(Goh)

    Ultimate compressive resistance from Ground Test results

    Alternative method Ground test results (shear strength,cone resistance etc) for all test locations are first combinedcone resistance etc) for all test locations are first combined(assessed) to derive the characteristic values of the baseresistance and shaft resistance in the various strata based ona cautious assessment of the test results and withoutapplying the factors . (Clause 7.6.2.3(8))A model factor is introduced to account for uncertainty of thecalculation results

    Model factor = R;dcalculation results.

    The value of the model factor should be 1.4, except that it maybe reduced to 1.2 if the resistance is verified by a maintainedload test taken to the calculated unfactored ultimate

    48

    load test taken to the calculated, unfactored ultimateresistance.

    CPGEC7course(Goh)

  • Clause 7 6 2 3(8)

    Alternative method

    The characteristic values may be obtained by calculating:

    Clause 7.6.2.3(8)

    Rb;k = Ab qb;k and Rs;k = As;i qs;i;k (7.9)where qb;k and qs;i;k are characteristic values of base resistance and shaftfriction in the various strata i, obtained from values of ground parameters.

    NOTE If this alternative procedure is applied, the values of the partialfactors b and s recommended in Annex A may need to be corrected by amodel factor larger than 1 0 The value of the model factor may be set bymodel factor larger than 1.0. The value of the model factor may be set bythe National annex.

    This is the most common method for pile design in UK.

    49CPGEC7course(Goh)

    NA to SS EN 1997-1:2010A.3.3.2 Partial resistance factors for pile foundations

    For verifications of the structural (STR) and geotechnical (GEO) limit states of pile foundations, thevalues of the partial factors on resistance (R) should be those given in Table A.NA.6, Table A.NA.7 andTable A.NA.8. These values are used to convert characteristic resistances to design values for ultimateli it t t l l ti Th l i ti f th b hi h th h t i ti i tlimit state calculations. They apply irrespective of the process by which the characteristic resistancesare derived.

    Characteristic resistances may be derived from static load tests using EN 1997-1y g7.6.2.2 (7.6.3.2 for tensile loading), or from ground test results using EN 1997-1Equations 7.8 or 7.9 (7.17 or 7.18 for tensile loading). When the approach ofEquations 7.9 or 7.18 is used to derive the characteristic resistances, a modelfactor should be applied to the shaft and base resistance calculated usingcharacteristic values of soil properties by a method complying with EN 1997 -1,2.4.1(6). The value of the model factor should be 1.4, except that it may bereduced to 1.2 if the resistance is verified by a maintained load test taken to thecalculated, unfactored ultimate resistance.

    Model factor = Model factor = R;dRb;k = Ab qb;k and Rs;k = As;i qs;i;k (7.9)

    50CPGEC7course(Goh)

  • More than one profile of ground p gtest data?

    Number of profiles = n Calculate characteristic pile

    Yes No

    Number of profiles n

    l ti f t d

    Calculate characteristic pile resistance from this single

    profile of ground properties. Apply model factor R dcorrelation factor 3 and 4

    from Table A.NA.10 depending on n

    Apply model factor R;d. Apply partial factors b and s to determine design

    resistance Rc d.resistance Rc,d.

    Calculate characteristic pile A Aresistance for the different

    profiles; Determine minimum to be

    ;qA

    Rd;R

    k;bbk;b = d;R

    i;k;si;sk;s

    qAR

    =characteristic resistance

    Rc;cal. Apply partial factors b and

    t d t i d i

    k;sk;bd;c

    RRR +=

    51

    s to determine design resistance Rc;d.

    CPGEC7course(Goh)

    sb

    Ultimate compressive resistance from static

    load tests (Clause 7.6.2.2(8)P)

    = 2

    min;

    1

    ;;

    )(;

    )( mcmeanmckc

    RRMinR

    Table A.NA.9 Correlation factors () to derive characteristic values of the resistance of axially loaded piles from static pile load tests (n - number of tested piles)

    for n = 1 2 3 4 5 1 1.55 1.47 1.42 1.38 1.35 2 1.55 1.35 1.23 1.15 1.08 NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values 1 and 2 may be divided by 1.1, provided that 1 is never less than 1.0, see EN 1997-1 7.6.2.2(9).

    Usually applies to trial (preliminary) piles and the resultsof tests on these piles are used to design the workingpiles

    52CPGEC7course(Goh)

    piles.

  • 7.6.2.2 Compressive ground resistance from static load teststests

    (2)P Trial piles to be tested in advance shall be installed in(2)P Trial piles to be tested in advance shall be installed inthe same manner as the piles that will form the foundationand shall be founded in the same stratum.

    (3) If the diameter of the trial pile differs from that of theki il th ibl diff i f f ilworking piles, the possible difference in performance of piles

    of different diameters should be considered in assessing thecompressive resistance to be adoptedcompressive resistance to be adopted.

    CPGEC7course(Goh) 53

    (4) In the case of a very large diameter pile, it is oftenimpractical to carry out a load test on a full size trial pile.Load tests on smaller diameter trial piles may be consideredprovided that:provided that: the ratio of the trial pile diameter/working pile diameter is

    not less than 0.5;; the smaller diameter trial pile is fabricated and installed in

    the same way as the piles used for the foundation; the trial pile is instrumented in such a manner that the

    base and shaft resistance can be derived separatelyf hfrom the measurements.

    This approach should be used with caution for open-ended driven pilesThis approach should be used with caution for open ended driven pilesbecause of the influence of the diameter on the mobilisation of thecompressive resistance of a soil plug in the pile.

    CPGEC7course(Goh) 54

  • (5)P In the case of a pile foundation subjected to downdrag,the pile resistance at failure or at a displacement that equalsthe pile resistance at failure, or at a displacement that equalsthe criterion for the verification of the ultimate limit statedetermined from the load test results, shall be corrected. Thedetermined from the load test results, shall be corrected. Thecorrection shall be achieved by subtracting the measured, orthe most unfavourable, positive shaft resistance in thecompressible stratum and in the strata above, wherenegative skin friction develops, from the loads measured atthe pile headthe pile head.

    (6) During the load test of a pile subject to downdrag, positive(6) During the load test of a pile subject to downdrag, positiveshaft friction will develop along the total length of the pile andshould be considered in accordance with 7.3.2.2(6). Themaximum test load applied to the working pile should be inexcess of the sum of the design external load plus twice thedowndrag force

    CPGEC7course(Goh) 55

    downdrag force.

    (10)P The systematic and random components of thevariations in the ground shall be recognised in thevariations in the ground shall be recognised in theinterpretation of pile load tests.

    (11)P Th d f th i t ll ti f th t t il ( ) h ll(11)P The records of the installation of the test pile(s) shallbe checked and any deviation from the normal executionconditions shall be accounted forconditions shall be accounted for.

    CPGEC7course(Goh) 56

  • An important requirement stated in Eurocode 7 isthat the interpretation of the results of the pile loadtests must take into account the variability of theground over the site and the variability due todeviation from the normal method of pile installation.In other words, there must be a careful examinationof the results of the ground investigation and of thepile load tests results. The results of the pile loadtests might lead, for example, to differenthomogeneous parts of the site being identified,each with its own particular characteristic pilecompressive resistance. (Frank et al. 2004)

    CPGEC7course(Goh) 57

    Ultimate compressive resistance from dynamic impact tests/pile driving formulae/wave equation analysis (Clause 7.6.2.4 to 7.6.2.6)

    Table A.NA.11 Correlation factors ( ) to derive characteristic values of the

    = 6

    min;

    5

    ;;

    )(;

    )( mcmeanmckc

    RRMinR

    for n = 2 5 10 15 20

    ( )resistance of axially loaded piles from dynamic impact tests (n - number of tested piles)

    5 1.94 1.85 1.83 1.82 1.81 6 1.90 1.76 1.70 1.67 1.66 NOTE 1 The - values may be multiplied with a model factor of 0.85 when using dynamic impact tests with i l t hisignal matching.

    NOTE 2 The - values should be multiplied with a model factor of 1.10 when using a pile driving formula with measurement of the quasi-elastic pile head displacement during the impact. NOTE 3 The - values should be multiplied with a model factor of 1.20 when using a pile driving formula without measurement of the quasi-elastic pile head displacement during the impact. NOTE 4 If different piles exist in the foundation groups of similar piles should be considered separately whenNOTE 4 If different piles exist in the foundation, groups of similar piles should be considered separately when selecting the number n of test piles. The blow counts used in pile driving should be obtained from driving

    58CPGEC7course(Goh)

    The blow counts used in pile driving should be obtained from driving records of at least five piles (Clause 7.6.2.5(4)).

  • Pile Load test methodPileLoadtestmethodstaticloadtests Rc;m andn

    fil Applyb,s ort

    RTableA.NA.9andT bl A NA 6profiles1,2 Rc;d TableA.NA.6

    dynamic impacttests,piledriving

    Rc;m andnprofiles5,6

    Applyb,s ort Rc;dTableA.NA.11andTableA.NA.6, p g

    formulae, waveequation

    p 5, 6 c;d

    G d t t th dGroundtestmethodalternativemethod (single

    Applymodelfactor R d to

    Applyb,s R dTableA.NA.6

    method(singleprofile)

    factor R;d,toobtainRc;k

    Rc;dmodelpile Rc;cal andn Applyb,s TableA.NA.10method(nprofiles)

    profiles3,4 Rc;d andTableA.NA.6

    CPGEC7course(Goh) 59

    No.of staticloadtests groundtests dynamictestsSummary of correlation factors (NA to SS EN 1997-1:2010)

    tests

    mean min. mean min No.oftests

    mean min.

    1 2 3 4 5 61 1.55 1.55 1.55 1.55 --- --- ---2 1 47 1 35 1 47 1 39 2-4 1 94 1 902 1.47 1.35 1.47 1.39 2 4 1.94 1.903 1.42 1.23 1.42 1.334 1.38 1.15 1.38 1.295 1.35 1.08 1.36 1.26 5-9 1.85 1.76

    7 1 33 1 207 1.33 1.20

    10 1.30 1.15 10-14 1.83 1.7015-19 1.82 1.67

    60

    20 1.81 1.66CPGEC7course(Goh)

  • The SS NA (and BS NA) provide larger correlation factors toThe SS NA (and BS NA) provide larger correlation factors to those given in Annex A of SS EN 1997-1 : 2010.

    According to Bauduin (2001), the correlation factors arebased on a reference value of about 10% for the COV of thebased on a reference value of about 10% for the COV of thepile compressive resistance. For the COV less than 10%,the mean of the resistance should govern the design,whereas for COV greater than 10%, the lowest resistanceshould govern. See Example 2.

    61CPGEC7course(Goh)

    Example 1A (Axially loaded pile in clay single profile of ground test data) Pground test data)

    Piletype Boredpile

    P

    Pilelength(m) 30Pilewidth(m) 0.6

    ( )

    Rs

    cu;k (kPa)characteristicvalue 100Skinfriction 0.5Soil unit weight (kN/m3) 20

    RbSoil unitweight(kN/m ) 20Permanentverticalload(kN) 1000Variableverticalload(kN) 200

    Alternative method

    Note: For simplicity, Self Weight of pile is omitted in the calculationscalculations

    62CPGEC7course(Goh)

  • Pil t B d il P

    Combination 1: A1 + M1 + R1 Example 1A

    Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) characteristic value 100

    P

    cu;k (kPa)characteristicvalue 100Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 1000

    Rs

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    RbDesign Action (A1)A1 M1

    G;dst 1.35G;stb 1.0

    Design Action (A1)

    Design vertical action G;stbQ;dst 1.5cu 1.0

    gFc;d = 1000 x 1.35 + 200 x 1.5 = 1650 kN

    63CPGEC7course(Goh)

    Pil t B d il P

    Material Factors (M1) cu = 1.0, cu = cu;k Example 1A Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) characteristic value 100

    PA1 M1

    G;dst 1.35G 1.0cu;k (kPa)characteristicvalue 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 1000

    RsG;stb 1.0Q;dst 1.5cu 1.0

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    RbDesign Resistance (R1)Pile base resistance = 9cuPile shaft friction = cu = 0.5cu

    Design Resistance (R1)

    From Table A.NA.7 (Bored piles)

    Base resistance Rb = 9cuAb = 9(100)( x 0.62/4)= 254 kNShaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 30)

    R1

    Base b 1.0Shaft 1 0Shaft resistanc Rs 0.5cuAs 0.5(100)(0.6 x 30)

    = 2827 kNCompressive Resistance Rc;d = Rb;d + Rs;d

    Shaft (compression)

    s 1.0Total/Combined (compression)

    t 1.0

    64CPGEC7course(Goh)

  • Base resistance Rb = 9cuAb = 9(100)( x 0.62/4) = 254 kNShaft resistanc R = 0 5c A = 0 5(100)(0 6 x 30) = 2827 kN

    Example 1A

    Shaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 30) = 2827 kN

    (A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor = 1 4be corrected by a Model Factor R;d = 1.4Compressive Resistance Rc;d = Rb;d + Rs;d= (254/1 4 x 1 0) + (2827/1 4 x 1 0) = 2201 kN= (254/1.4 x 1.0) + (2827/1.4 x 1.0) = 2201 kN

    Over-design factor = R d / F d = 2201 / 1650 = 1.33 > 1Over design factor Rc;d / Fc;d 2201 / 1650 1.33 > 1 OKFrom Table A.NA.7 (Bored piles)

    R1

    Base b 1.0

    From Table A.NA.7 (Bored piles)

    ;qA

    RdR

    k;bbk;b = dR

    i;k;si;sk;s

    qAR

    =Base b 1.0Shaft (compression)

    s 1.0Total/Combined ( i )

    t 1.0

    d;R d;Rk;sk;b

    dcRR

    R +=65

    (compression)

    CPGEC7course(Goh)sb

    d;cR +

    Pil t B d il P

    Combination 2: A2 + M1 + R4 Example 1A

    Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) 100

    P

    cu;k (kPa) 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 1000

    Rs

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    RbDesign Action (A2)A2 M1

    G;dst 1.0G;stb 1.0

    Design Action (A2)

    Design vertical action G;stbQ;dst 1.3cu 1.0

    gFc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    66CPGEC7course(Goh)

  • Pil t B d il

    Material Factors (M1) cu = 1.0, cu = cu;k A2 M1G;dst 1.0Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) 100

    G;stb 1.0Q;dst 1.3cu 1.0

    cu;k (kPa) 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 1000

    R4 with explicit verification of SLS A)

    From Table A.NA.7 (Bored piles)

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    Design Resistance (R4)

    verification of SLS

    Base b 1.7Shaft (compression)

    s 1.4

    Pile base resistance = 9cuPile shaft friction = cu = 0.5cu

    Design Resistance (R4) ( p )Total/Combined (compression)

    t 1.7

    A) The lower values in R4 may be adopted (a) if serviceabilityis verified by load tests (preliminary and/or working) carriedout on more than 1% of the constructed piles to loads not lessthan 1.5 times the representative load for which they aredesigned, or (b) if settlement is explicitly predicted by a meansno less reliable than in (a) or (c) if settlement at the

    67

    no less reliable than in (a), or (c) if settlement at theserviceability limit state is of no concern.

    CPGEC7course(Goh)Example 1A

    Base resistance Rb = 9cuAb = 9(100)( x 0.62/4) = 254 kNShaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 20) = 2827 kN

    Example 1A

    (A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R;d = 1.4

    Compressive Resistance R d = Rb d + R d

    Compressive Resistance with SLS verification

    Compressive Resistance Rc;d Rb;d + Rs;d= 254/(1.7 x 1.4) + 2827/( 1.4 x 1.4) = 254/(2.38) + 2827/(1.96) = 1549 kN

    Over-design factor = Rc;d / Fc;d = 1549 / 1260 = 1.23 > 1 OK OKR4 with explicit

    verification of SLS A)

    Base 1 7;qA

    R k;bbk;b = i;k;si;sk;sqA

    R= Base b 1.7

    Shaft (compression)

    s 1.4Total/Combined (compression)

    t 1.7

    ;d;R

    k;b d;Rk;s k;sk;b RR

    68

    (compression)

    CPGEC7course(Goh)s

    k;s

    b

    k;bd;c

    RRR +=

  • Base resistance Rb = 9cuAb = 9(100)( x 0.62/4) = 254 kNShaft resistanc R = 0 5c A = 0 5(100)(0 6 x 20) = 2827 kN

    Example 1A

    Shaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 20) = 2827 kN(A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R;d = 1.4

    Compressive Resistance R = R + RCompressive Resistance without SLS verification

    y R;d

    Compressive Resistance Rc;d = Rb;d + Rs;d= 254/(2.0 x 1.4) + 2827/( 1.6 x 1.4) = 254/(2.8) + 2827/(2.24) = 1353 kN 254/(2.8) 2827/(2.24) 1353 kN

    Over-design factor = Rc;d / Fc;d = 1353 / 1260 = 1.07 > 1 OK OKR4 without explicit

    verification of SLS A)

    B 2 0Base b 2.0Shaft (compression)

    s 1.6Total/Combined ( i )

    t 2.0

    69

    (compression)

    CPGEC7course(Goh)

    Comparison with conventional FSExample 1A

    Base resistance Rb = 9cuAb = 9(100)( x 0.62/4) = 254 kNShaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 20) = 2827 kN

    Applied vertical load = 1000 + 200 = 1200 kN

    57.21200

    2827254FS =+=

    1200196951

    28273

    254Qallowable >=+= kN5.13120014982827254Q kN12001498

    0.23Qallowable >=+= kNor

    CPGEC7course(Goh) 70

  • Comparison with conventional FS (Bored piles)

    0251Q

    3QQ sballowable += 0.2~5.13

    Combination 2: A2 + M1 + R4 (with model factor = 1.4)

    Compressive Resistance with SLS verification

    Rc;d = Qb/(1.7 x 1.4) + Qs/(1.4 x 1.4) = Qb/(2.38) + Qs/(1.96)

    Compressive Resistance without SLS verification

    Rc;d = Qb/(2.0.x 1.4) + Qs/(1.6 x 1.4) = Qb/(2.8) + Qs/(2.24)

    CPGEC7course(Goh) 71

    Example 1B (Axially loaded pile in clay single profile of ground test data) Pof ground test data)

    Piletype Boredpile

    P

    Pilelength(m) 30Pilewidth(m) 0.6cu;k (kPa)characteristicvalue 100

    Rs

    ;

    Skinfriction 0.5Soil unitweight(kN/m3) 20Permanent vertical load (kN) 800

    RbPermanentverticalload(kN) 800Variableverticalload(kN) 400

    Note: Self Weight of pile is omitted in the calculations

    Effects of Load Combinations (Only CombinationEffects of Load Combinations (Only Combination 2 is considered in this example)

    72CPGEC7course(Goh)

  • Pil t B d il P

    Combination 2: A2 + M1 + R4 Example 1B

    Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) 100

    P

    cu;k (kPa) 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 800

    Rs

    Permanentverticalload(kN) 800

    Variableverticalload(kN) 400

    RbDesign Action (A2)A2 M1

    G;dst 1.0G;stb 1.0

    Design Action (A2)

    Design vertical action G;stbQ;dst 1.3cu 1.0

    gFc;d = 800 x 1.0 + 400 x 1.3 = 1320 kN

    73CPGEC7course(Goh)

    Pil t B d il

    Material Factors (M1) cu = 1.0, cu = cu;k A2 M1G;dst 1.0Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) 100

    G;stb 1.0Q;dst 1.3cu 1.0

    cu;k (kPa) 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 800

    R4 with explicit verification of SLS A)

    From Table A.NA.7 (Bored piles)

    Permanentverticalload(kN) 800

    Variableverticalload(kN) 400

    Design Resistance (R4)

    verification of SLS

    Base b 1.7Shaft (compression)

    s 1.4

    Pile base resistance = 9cuPile shaft friction = cu = 0.5cu

    Design Resistance (R4) ( p )Total/Combined (compression)

    t 1.7

    A) The lower values in R4 may be adopted (a) if serviceability is verifiedby load tests (preliminary and/or working) carried out on more than 1%of the constructed piles to loads not less than 1 5 times theof the constructed piles to loads not less than 1.5 times therepresentative load for which they are designed, or (b) if settlement isexplicitly predicted by a means no less reliable than in (a), or (c) ifsettlement at the serviceability limit state is of no concern.

    74CPGEC7course(Goh)Example 1B

  • Base resistance Rb = 9cuAb = 9(100)( x 0.62/4) = 254 kNShaft resistanc Rs = 0.5cuAs = 0.5(100)(0.6 x 20) = 2827 kN

    Example 1B

    (A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R;d = 1.4

    Compressive Resistance R d = Rb d + R d

    Compressive Resistance with SLS verification

    Compressive Resistance Rc;d Rb;d + Rs;d= 254/(1.7 x 1.4) + 2827/( 1.4 x 1.4) = 254/(2.38) + 2827/(1.96) = 1549 kN

    Over-design factor = Rc;d / Fc;d = 1549 / 1320 = 1.17 > 1 OK OKR4 with explicit

    verification of SLS A)

    Base 1 7;qA

    R k;bbk;b = i;k;si;sk;sqA

    R= Base b 1.7

    Shaft (compression)

    s 1.4Total/Combined (compression)

    t 1.7

    ;d;R

    k;b d;Rk;s k;sk;b

    d;cRR

    R +=75

    (compression)

    CPGEC7course(Goh)sb

    d;cR +

    Comparison of Example 1A and 1B (Combination 2)

    Effects of Load Combinations (Only Combination 2 is considered in this example)

    Example 1A Example 1B

    Permanent vertical load (kN)

    1000 800

    Variable vertical load 200 400Variable vertical load (kN)

    200 400

    Over-design factor 1.23 1.17Over design factor 1.23 1.17Design Length (m) for 23.98 25.23 =1.0

    CPGEC7course(Goh) 76

  • Example 1C (Axially loaded pile in sand single profile of ground test data) Pof ground test data)

    Piletype Boredpile

    P

    1 mPilelength(m) 18Pilewidth(m) 0.6k characteristicvalue 35o

    Rs18 m

    kBearingcapacityfactorNq 49

    Pileinterfacefriction 35oSoil unit weight (kN/m3) 20

    Note: Self Weight of pile is omitted in the

    RbSoil unitweight(kN/m ) 20Permanentverticalload(kN) 1000Variableverticalload(kN) 200

    omitted in the calculations

    A1 M1Combination 1: A1 + M1 + R1

    Design Action (A1)

    Design vertical action

    G;dst 1.35G;stb 1.0Q d t 1.5

    77CPGEC7course(Goh)

    gFc;d = 1000 x 1.35 + 200 x 1.5 = 1650 kN

    Q;dst 1.5cu 1.0

    PPiletype BoredpilePilelength(m) 18

    Example 1C K0 = (1 sin)

    Rs

    1 m

    18

    Pilewidth(m) 0.6k characteristicvalueBearingcapacityfactorNq

    35o

    49

    il i f f i i 35

    D i R i t (R1)

    Rs18 mPileinterfacefriction 35oSoil unitweight(kN/m3) 20

    Pile base resistance = qb = Nqvb(Ab)Pile shaft friction = q = tan(A )

    Design Resistance (R1)

    From Table A.NA.7 (Bored piles)

    Rb

    Pile shaft friction = qs = h,averagetan(As)R1

    Base b 1.0Shaft 1 0

    ( p )

    = 20x1 + 17(20 ) = 190 kPa Shaft (compression)

    s 1.0Total/Combined (compression)

    t 1.0 vb = 20x1 + 17(20 w) = 190 kPah,average= 0.5vb(1 sin)

    Base resistance Rb = 49(vb)( x 0.62/4) Shaft resistance R = 0 5 b(1 sin)tan(0 6 x 18)

    78

    Shaft resistance Rs 0.5 vb(1 sin )tan(0.6 x 18) CPGEC7course(Goh)

  • Base resistance Rb = 49(vb)( x 0.62/4) = 2632 kN Shaft resistanc Rs = 0.5vb(1 sin)tan(0.6 x 18) = 962 kN

    Example 1C

    s vb( ) ( )(A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R d = 1.4Compressive Resistance Rc;d = Rb;d + Rs;d= (2632/1 4 x 1 0) + (962/1 4 x 1 0) = 2567 kN

    be corrected by a Model Factor R;d 1.4

    = (2632/1.4 x 1.0) + (962/1.4 x 1.0) = 2567 kN

    Over-design factor = R d / F d = 2567 / 1650 = 1.56 > 1Over design factor Rc;d / Fc;d 2567 / 1650 1.56 > 1 OKFrom Table A.NA.7 (Bored piles)

    R1

    Base b 1.0

    From Table A.NA.7 (Bored piles)

    ;qA

    R k;bbk;b =i;k;si;s

    k;sqA

    R =

    Base b 1.0Shaft (compression)

    s 1.0Total/Combined ( i )

    t 1.0

    d;R d;Rk;sk;b

    d;cRR

    R +=79

    (compression)

    CPGEC7course(Goh)

    sbd;c

    Pil t B d il

    Combination 2: A2 + M1 + R4 Example 1C

    Piletype Boredpile

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    A2 M1

    G;dst 1.0G;stb 1.0Q;dst 1.3cu 1.0

    Design Action (A2)

    Design vertical actionDesign vertical action Fc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    80CPGEC7course(Goh)

  • Base resistance Rb = 49(vb)( x 0.62/4) = 2632 kN Shaft resistanc Rs = 0.5vb(1 sin)tan(0.6 x 18) = 962 kN

    Example 1C

    (A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R;d = 1.4

    Compressive Resistance Rc;d = Rb;d + Rs;d

    Compressive Resistance with SLS verification

    p c;d b;d s;d= 2632/(1.7 x 1.4) + 962/( 1.4 x 1.4) = 2632/(2.38) + 962/(1.96) = 1597 kN

    Over-design factor = Rc;d / Fc;d = 1597 / 1260 = 1.27 > 1 OKR4 with explicit

    verification of SLS A)

    Base 1 7;qA

    R k;bbk;b = i;k;si;sk;sqA

    R= Base b 1.7

    Shaft (compression)

    s 1.4Total/Combined (compression)

    t 1.7

    ;d;R

    k;b d;Rk;s k;sk;b RR

    81

    (compression)

    CPGEC7course(Goh)s

    k;s

    b

    k;bd;c

    RRR +=

    Base resistance Rb = 49(vb)( x 0.62/4) = 2632 kN Shaft resistanc Rs = 0.5vb(1 sin)tan(0.6 x 18) = 962 kN

    Example 1C

    (A.3.3.2) For pile design from ground parameters, partial factors have to be corrected by a Model Factor R;d = 1.4

    Compressive Resistance R = R + R

    Compressive Resistance without SLS verification

    Compressive Resistance Rc;d = Rb;d + Rs;d= 2632/(2.0 x 1.4) + 962/( 1.6 x 1.4) = 2632/(2.8) + 962/(2.24) = 1369 kN 2632/(2.8) 962/(2.24) 1369 kN

    Over-design factor = Rc;d / Fc;d = 1369 / 1260 = 1.09 > 1 OK OKR4 without explicit

    verification of SLS A)

    B 2 0Base b 2.0Shaft (compression)

    s 1.6Total/Combined ( i )

    t 2.0

    82

    (compression)

    CPGEC7course(Goh)

  • Comparison with conventional FSExample 1C

    Base resistance Rb = 49(vb)( x 0.62/4) = 2632 kN Shaft resistanc Rs = 0.5vb(1 sin)tan(0.6 x 18) = 962 kN

    Applied vertical load = 1000 + 200 = 1200 kN

    00.31200

    9622632 =+=FS

    1200151951

    9623

    2632 >=+=allowableQ kN5.13

    120013589622632Q kN120013580.23

    >=+=allowableQ kNor

    CPGEC7course(Goh) 83

    Example 2 (Axially loaded pile in clay data from 3 boreholes) Pboreholes)

    Piletype Boredpile

    P

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) BH1 100

    Rs

    cu (kPa)BH1 100cu (kPa)BH2 110c (kPa) BH3 130

    Rbcu (kPa)BH3 130Skinfriction 0.5Soil unitweight 20 Note: Self Weight of pile is omitted in the calculationsg(kN/m3)

    Permanentverticall d (kN)

    1000

    omitted in the calculations

    M d l il th dload(kN)Variableverticalload(kN)

    200Model pile method

    84

    ( )

    CPGEC7course(Goh)

  • PCombination 1: A1 + M1 + R1 Example 2 P

    Design Action (A1)Rs

    Design vertical action

    Rb

    gFc;d = 1000 x 1.35 + 200 x 1.5= 1650 kN

    A1 M1

    G;dst 1.35G;stb 1.0G;stbQ;dst 1.5cu 1.0Material Factors (M1) cu = 1.0, cu = cu;k

    85CPGEC7course(Goh)

    Clause 7.6.2.3(5) Model pile method Example 2

    ==

    +=+=4

    min;

    3

    ;;

    ;;;;;

    )(;

    )()( calcmeancalccalc

    calscalbkskbkc

    RRMinR

    RRRRR (7.8)

    correlation factor 3 and 4 from Table A.NA.10 depending on number of profiles n

    RRRRR )()()()( meancalsmeancalbmeancalscalbmeancalc RRRRR )()()()( ;;;;; +=+=min;;min; )()( calscalbcalc RRR +=

    Table A.NA.10 Correlation factors () to derive characteristic values of the resistance of axially loaded piles from ground test results(n - number of profiles of tests)loaded piles from ground test results(n number of profiles of tests)

    for n = 1 2 3 4 5 7 10 3 1.55 1.47 1.42 1.38 1.36 1.33 1.3034 1.55 1.39 1.33 1.29 1.26 1.20 1.15 NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values of 3 and 4 may be divided by 1.1, provided that 3 is never less than 1.0, see EN 1997-1 7.6.2.3(7).

    86

    CPGEC7course(Goh)

  • Design Resistance (R1) cu (kPa)BH1 100cu (kPa)BH2 110

    Example 2

    Pile base resistance = 9cuPile shaft friction = cu = 0.5cu

    u

    cu (kPa)BH3 130Skinfriction 0.5

    Base resistance Rb = 9cuAb = 9(cu)( x 0.62/4) Shaft resistanc Rs = 0.5cuAs = 0.5(cu)(0.6 x 30)

    R1

    Base b 1.0Shaft s 1.0Shaft (compression)

    s 1.0Total/Combined (compression)

    t 1.0Rc;cal = Rb;d + Rs;d

    BH cu (kPa) Rb (kN) Rs (kN) Rc;cal (kN)

    BH1 100 254 2827 3081BH1 100 254 2827 3081

    BH2 110 280 3110 3390

    BH3 130 331 3676 4007

    87CPGEC7course(Goh)

    Design Resistance (R1) Rc;cal = Rb;d + Rs;dExample 2

    BH cu (kPa) Rb (kN) Rs (kN) Rc;cal (kN)

    BH1 100 254 2827 3081

    BH2 110 280 3110 3390BH2 110 280 3110 3390

    BH3 130 331 3676 4007

    (Rc;cal)mean = (3081+3390+4007)/3 = 3483 kN

    (Rc;cal)min = 3081 kN

    ==+=+= min;;;; )(;)()( calcmeancalclcalscalbkkbk RRMinRRRRRR ===+= 43;;;;

    ;)( calckskbkc MinRRRR

    88CPGEC7course(Goh)

  • Design Resistance (R1) Rc;cal = Rb;d + Rs;d Table A.NA.10 Example 2

    (Rc;cal)mean = 3483 kN

    (Rc;cal)min = 3081 kN

    ==

    +=+=4

    min;

    3

    ;;

    ;;;;;

    )(;

    )()( calcmeancalccalc

    calscalbkskbkc

    RRMinR

    RRRRR

    = Min {(3483/1.42) ; (3081/1.33)} = Min {2436; 2317} = 2317 kN

    BH cu (kPa) Rb (kN) Rs (kN) Rc;cal (kN)

    BH1 100 254 2827 3081

    BH2 110 280 3110 3390

    BH1 gives minimumBH2 110 280 3110 3390

    BH3 130 331 3676 4007

    Rs;k = 2827/1.33 kN Rb;k = 254/1.33 kNR1

    Base b 1.0Shaft s 1.0

    89

    Rc;d = Rb;k/b + Rs;k/s = 2317 kN (compression)Total/Combined (compression)

    t 1.0CPGEC7course(Goh)

    Note: The lowest value is the lowest of the total compressiveExample 2

    presistance, and not a combination of the lowest basecompressive resistance and the lowest shaft frictiond d d f th t tdeduced from another test.

    ++ min;;;; )(;)()( calcmeancalccalscalb RRMinRRRRRR

    R d = Rb k/b + R k/ = 2317 kN ===+= 4

    ;

    3

    ;;

    ;;;;; ;)( calckskbkc MinRRRR

    Design vertical action

    Rc;d Rb;k/b + Rs;k/s 2317 kN

    Fc;d = 1000 x 1.35 + 200 x 1.5 = 1650 kN

    Over-design factor = 2317 / 1650 = 1 40 > 1Over-design factor = 2317 / 1650 = 1.40 > 1 OK

    90CPGEC7course(Goh)

  • PCombination 2: A2 + M1 + R4 Example 2 P

    Design Action (A2)

    RsDesign vertical action F d = 1000 x 1.0 + 200 x 1.3

    Rb

    Fc;d 1000 x 1.0 + 200 x 1.3= 1260 kN

    A2 M1

    G;dst 1.0G;stb 1.0Material Factors (M1) cu = 1.0, cu = cu;k G;stbQ;dst 1.3cu 1.0

    Material Factors (M1)

    91CPGEC7course(Goh)

    Pil t B d il

    Material Factors (M1)A2 M1

    Example 2

    Piletype Boredpile

    Pilelength(m) 30Pilewidth(m) 0.6c (kPa) 100

    cu = 1.0, cu = cu;k G;dst 1.0G;stb 1.0Q;dst 1.3

    cu;k (kPa) 100

    Skinfriction 0.5Soil unitweight(kN/m3) 20

    Permanent vertical load (kN) 1000 R4 ith li it

    From Table A.NA.7 (Bored piles)cu 1.0

    Permanentverticalload(kN) 1000

    Variableverticalload(kN) 200

    Design Resistance (R4)

    R4 with explicit verification of SLS A)

    Base b 1.7Shaft 1 4

    Pile base resistance = 9cuPile shaft friction = cu = 0.5cu

    Design Resistance (R4) Shaft (compression)

    s 1.4Total/Combined (compression)

    t 1.7

    A) The lower values in R4 may be adopted (a) if serviceability is verifiedby load tests (preliminary and/or working) carried out on more than 1%of the constructed piles to loads not less than 1 5 times theof the constructed piles to loads not less than 1.5 times therepresentative load for which they are designed, or (b) if settlement isexplicitly predicted by a means no less reliable than in (a), or (c) ifsettlement at the serviceability limit state is of no concern.

    92CPGEC7course(Goh)

  • Design Resistance (R4)Rc;cal = Rb + Rs

    Example 2

    BH cu(kPa)

    Rb(kN)

    Rs(kN)

    Rc;cal (kN)

    BH1 100 254 2827 3081BH1 100 254 2827 3081

    BH2 110 280 3110 3390

    BH3 130 331 3676 4007

    (Rc;cal)mean = (3081+3390+4007)/3 = 3493 kN

    (Rc;cal)min = 3081 kN

    + )()( RRRR

    ==

    +=+=4

    min;

    3

    ;;

    ;;;;;

    )(;

    )()( calcmeancalccalc

    calscalbkskbkc

    RRMinR

    RRRRR

    93CPGEC7course(Goh)

    Design Resistance (R4) Rc;cal = Rb;d + Rs;d Table A.NA.10 Example 2

    (Rc;cal)mean = 3493 kN

    (Rc;cal)min = 3081 kN

    Mi {(3493/1 42) (3081/1 33)} Mi {2443 2317} 2317 kN

    (Rc;cal)min 3081 kN

    ==

    +=+=4

    min;

    3

    ;;

    ;;;;;

    )(;

    )()( calcmeancalccalc

    calscalbkskbkc

    RRMinR

    RRRRR

    = Min {(3493/1.42) ; (3081/1.33)} = Min {2443; 2317} = 2317 kN

    BH cu (kPa) Rb (kN) Rs (kN) Rc;cal (kN)

    BH1 100 254 2827 3081

    BH2 110 280 3110 3390

    BH3 130 331 3676 4007

    BH1 gives minimum

    R4 with explicit verification of SLS A)

    BH3 130 331 3676 4007

    Rs;k = 2827/1.33 kN Rb;k = 254/1.33 kNBase b 1.7Shaft (compression)

    s 1.4Total/Combined 1 7

    Rs;k 2827/1.33 kN Rb;k 254/1.33 kN

    Rc;d = Rs;k/b + Rb;k/s= 2827/(1.33 x 1.4) + 254/(1.33 x 1.7)

    94

    Total/Combined (compression)

    t 1.7 2827/(1.33 x 1.4) + 254/(1.33 x 1.7)= 1631 kN

    CPGEC7course(Goh)

  • Compressive Resistance with SLS verificationExample 2

    Design Resistance (R4)

    Rc;d = Rs;k/b + Rb;k/s = 2827/(1.33x1.4) + 254/(1.33x1.7) = 2827/(1.86) + 254/(2.26) = 1631 kN

    Design vertical action F = 1000 x 1 0 + 200 x 1 3 = 1260 kN

    Over-design factor = 1631 / 1260 = 1.29 > 1 Fc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    OKR4 with explicit

    verification of SLS A)

    Base b 1.7Shaft (compression)

    s 1.4Total/Combined 1 7

    95CPGEC7course(Goh)

    Total/Combined (compression)

    t 1.7

    Compressive Resistance without SLS verificationExample 2

    Design Resistance (R4)

    Rc;d = Rs;k/b + Rb;k/s = 2827/(1.33x1.6) + 254/(1.33x2.0) = 2827/(2.13) + 254/(2.66) = 1423 kN

    Design vertical action F = 1000 x 1 0 + 200 x 1 3 = 1260 kN

    Over-design factor = 1423 / 1260 = 1.13 > 1 Fc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    OKR4 without explicit

    verification of SLS A)

    Base b 2.0Shaft (compression)

    s 1.6Total/Combined t 1.7

    96CPGEC7course(Goh)

    (compression)t

  • According to Bauduin (2001), the correlation factors arebased on a reference value of about 10% for the COV of thepile compressive resistance. For the COV less than 10%,the mean of the resistance should govern the design,whereas for COV greater than 10% the lowest resistancewhereas for COV greater than 10%, the lowest resistanceshould govern.

    CPGEC7course(Goh) 97

    Example 3 (Axially loaded pile in clay data from 4 static pile load Pclay data from 4 static pile load tests, tested to failure)

    P

    Piletype BoredpilePile length (m) 30

    Rs

    Pilelength(m) 30Pilewidth(m) 0.6PileTest #1Rm (kN) 4000 RbmPileTest #2Rm (kN) 4200PileTest #3Rm (kN) 4500 Note: Self Weight of pile is omitted in the calculationsPileTest #4Rm (kN) 5000Permanentverticall d (kN)

    1000

    the calculations

    load(kN)Variableverticalload(kN)

    200

    98

    ( )

    CPGEC7course(Goh)

  • PCombination 1: A1 + M1 + R1 Example 3 P

    Design Action (A1)

    RsDesign vertical action Fc;d = 1000 x 1.35 + 200 x 1.5

    1650 kN

    Rb

    = 1650 kN

    A1 M1

    G;dst 1.35G;stb 1.0Material Factors (M1) G;stbQ;dst 1.5cu 1.0

    99CPGEC7course(Goh)

    Ultimate compressive resistance from static load tests Example 3

    )()( RR

    (Clause 7.6.2.2)

    = 2

    min;

    1

    ;;

    )(;

    )( mcmeanmckc

    RRMinR

    Table A.NA.9 Correlation factors () to derive characteristic values of the resistance of axially loaded piles from static pile load tests (n - number of tested piles)

    for n = 1 2 3 4 5 1 1.55 1.47 1.42 1.38 1.35 2 1.55 1.35 1.23 1.15 1.08 NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values 1 and 2 may be divided by 1.1, provided that 1 is never less than 1.0, see EN 1997-1 7.6.2.2(9).

    100CPGEC7course(Goh)

  • Design Resistance (R1) PileTest #1Rm (kN) 4000Pil T t #2 R (kN) 4200

    Example 3

    PileTest #2Rm (kN) 4200PileTest #3Rm (kN) 4500Pile Test #4 R (kN) 5000

    (Rc;m)mean = (4000+4200+4500+5000)/4 = 4425 kN

    PileTest #4Rm (kN) 5000

    (Rc;m)min = 4000 kN

    =

    min;;;

    )(;

    )( mcmeanmckc

    RRMinR

    = Min {(4425/1 38) ; (4000/1 15)} = Min {3207; 3478}

    21;

    Table A.NA.9

    = Min {(4425/1.38) ; (4000/1.15)} = Min {3207; 3478} = 3207 kN

    for n = 1 2 3 4 5 1 1.55 1.47 1.42 1.38 1.35 2 1.55 1.35 1.23 1.15 1.08

    101

    NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values 1 and 2 may be divided by 1.1, provided that 1 is never less than 1.0, see EN 1997-1 7.6.2.2(9).

    CPGEC7course(Goh)

    Design Resistance (R1)Example 3

    Design vertical action

    Rc;d = 3207 kN

    Design vertical action Fc;d = 1000 x 1.35 + 200 x 1.5 = 1650 kN

    Over-design factor = 3207 / 1650 = 1.94 > 1 OK

    R1

    Base b 1.0Shaft (compression)

    s 1.0Total/Combined (compression)

    t 1.0

    102

    (compression)

    CPGEC7course(Goh)

  • PCombination 2: A2 + M1 + R4 Example 3 P

    Design Action (A2)

    RsDesign vertical action Fc;d = 1000 x 1.0 + 200 x 1.3

    1260 kN

    Rb

    = 1260 kN

    A2 M1

    G;dst 1.0G;stb 1.0Material Factors (M1) G;stbQ;dst 1.3cu 1.0

    103CPGEC7course(Goh)

    Design Resistance (R4) PileTest #1Rm (kN) 4000Pil T t #2 R (kN) 4200

    Example 3

    PileTest #2Rm (kN) 4200PileTest #3Rm (kN) 4500Pile Test #4 R (kN) 5000PileTest #4Rm (kN) 5000

    (Rc;m)mean = (4000+4200+4500+5000)/4 = 4425 kN

    (Rc;m)min = 4000 kN

    = Min {(4425/1.38) ; (4000/1.15)} = Min {3207; 3478}

    Table A.NA.9

    {( ) ( )} { }= 3207 kN

    for n = 1 2 3 4 5 1 1.55 1.47 1.42 1.38 1.35 2 1.55 1.35 1.23 1.15 1.08

    104

    NOTE For structures having sufficient stiffness and strength to transfer loads from ''weak'' to "strong piles, values 1 and 2 may be divided by 1.1, provided that 1 is never less than 1.0, see EN 1997-1 7.6.2.2(9).

    CPGEC7course(Goh)

  • Design Resistance (R4)

    Compressive Resistance with SLS verification Example 3

    Design Resistance (R4)

    Rc;k = 3207 kN

    Design vertical action

    Compressive Resistance Rc;d = 3207/(1.7) = 1886 kN

    O d i f t 1886 / 1260 1 50 1

    Design vertical action Fc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    Over-design factor = 1886 / 1260 = 1.50 > 1 OK

    R4 with explicit verification of SLS A)

    B 1 7Base b 1.7Shaft (compression)

    s 1.4Total/Combined ( i )

    t 1.7

    105

    (compression)

    CPGEC7course(Goh)

    Design Resistance (R4)

    Compressive Resistance without SLS verification Example 3

    Design Resistance (R4)

    Rc;k = 3207 kN

    Design vertical action

    Compressive Resistance Rc;d = 3207/(2.0) = 1604 kN

    O d i f t 1604 / 1260 1 27 1

    Design vertical action Fc;d = 1000 x 1.0 + 200 x 1.3 = 1260 kN

    Over-design factor = 1604 / 1260 = 1.27 > 1 OK

    R4 without explicit verification of SLS A)

    B 2 0Base b 2.0Shaft (compression)

    s 1.6Total/Combined ( i )

    t 2.0

    106

    (compression)

    CPGEC7course(Goh)

  • Pile subjected to Downdrag (Negative skin friction)

    Two approaches:

    Clause 7.3.2.1(3)P

    o app oac es

    (a) the ground displacement is treated as an action. Aninteraction analysis (e.g., t-z method) is then carried out todetermine the forces, displacements and strains in the pile;

    (b) an upper bound to the force, which the ground couldtransmit to the pile shall be introduced as the design action.p g

    Downdrag is considered a permanent action

    CPGEC7course(Goh) 107

    Example 4 (Pile subjected to Downdrag)P surcharge

    Example 4

    Piletype BoredpilePilewidth(m) 0.3

    P

    5 m soft clayFD

    surcharge

    downdrag skinfrictionqD;k(kPa)characteristicvalue 20

    stiffclayskinfrictionqs;k(kPa) characteristic value

    50 R

    5 m soft clay

    18 m stiff clay

    FD

    (kPa)characteristicvalue

    Permanentverticalload(kN) 300

    Rs

    Rb

    y

    A surcharge is placed at ground level after pile installation, causing settlement ofthe soft clay and downdrag FD (negative skin friction) on the pile. The baseresistance Rb is assumed to be negligible.

    Note: For simplicity, Self Weight of pile is omitted in the calculations

    Any variable action may usually be ignored (Clause 7.3.2.2(7))

    E l M difi d f Si & D i ll (1998) E d 7 t

    y y y g ( ( ))In most cases, downdrag is only relevant for SLS

    108

    Example Modified from Simpson & Driscoll (1998) Eurocode 7 a commentary

    CPGEC7course(Goh)

  • il d il P surcharge

    Example 4

    Piletype BoredpilePilewidth(m) 0.3downdrag skinfrictionqD;k(kP ) h i i l

    20

    P

    5 m soft clayFD

    surcharge

    (kPa)characteristicvaluestiffclayskinfrictionqs;k(kPa)characteristicvalue

    50

    R

    5 m soft clay

    18 m stiff clay

    FD

    Permanentverticalload(kN) 300Rs

    Rb

    y

    The interaction between the pile shaft and the soft clay should take intoaccount the relative movement of the pile and the soil eg. using t-zmethod. This may result in negative skin friction that varies with depthand the location of the neutral point above the bottom of the layer.

    This approach is more complicated that assuming a maximum (limiting)downdrag load along the entire length of the pile in the settling layer.In this example, for simplicity the maximum downdrag load is assumed.

    109

    In this example, for simplicity the maximum downdrag load is assumed.

    CPGEC7course(Goh)

    Piletype BoredpilePile width (m) 0 3 P surcharge

    Example 4

    Pilewidth(m) 0.3downdrag skinfrictionqD;k(kPa)characteristicvalue

    20

    stiff clay skin friction q k 50

    P

    5 m soft clayFD

    surcharge

    stiffclayskinfrictionq s;k(kPa)characteristicvalue

    50

    Permanentverticalload(kN) 300 R

    5 m soft clay

    18 m stiff clay

    FD

    Rs

    Rb 0

    y

    Combination 1: A1 + M1 + R1

    A1 M1

    G;dst 1.35G;stb 1.0

    Design Action (A1)

    Total downdrag load = FD;k = (0.3)(5)qD;k G;stbQ;dst 1.5cu 1.0

    ; ;= (0.3)(5)(20) = 94.2 kNDesign value of downdrag load FD;d = GFD;kDesign vertical action

    g g D;d G D;k= 1.35 x 94.2

    110

    Fc;d = 300 x 1.35 + 94.2 x 1.35 = 532 kNCPGEC7course(Goh)

  • Piletype BoredpilePilewidth(m) 0.3 P surcharge

    Example 4

    ( )

    stiffclayskinfrictionqs;k(kPa)characteristicvalue

    50

    P

    5 m soft clayFD

    surcharge

    R

    5 m soft clay

    18 m stiff clay

    FD

    Combination 1: A1 + M1 + R1Design Resistance (R1) Rs

    Rb 0

    yDesign Resistance (R1)

    A.3.3.2 Model Factor R;d = 1.4C i R i t R R

    R1

    From Table A.NA.7 (Bored piles)

    Compressive Resistance Rc;d = Rs;d= (0.3)(18)50/( 1.0 x 1.4) = 606 kN

    R1

    Base b 1.0Shaft ( i )

    s 1.0Over-design factor = Rc;d / Fc;d= 606 / 532 = 1.13 > 1

    D i ti l ti

    (compression)Total/Combined (compression)

    t 1.0 OK

    111

    Design vertical action Fc;d = 300 x 1.35 + 94.2 x 1.35 = 532 kN

    CPGEC7course(Goh)

    Piletype BoredpilePilewidth(m) 0.3 P surcharge

    Example 4

    ( )

    downdrag skinfrictionqD;k(kPa)characteristicvalue

    20

    stiffclayskinfrictionqs;k 50

    P

    5 m soft clayFD

    surcharge

    s;k(kPa)characteristicvalue

    Permanentverticalload(kN) 300R

    5 m soft clay

    18 m stiff clay

    FD

    Rs

    Rb 0

    y

    Design Action (A2) and M2

    Combination 2: A2 + M2 + R4

    g ( )

    Total downdrag load = FD;k = (0.3)(5)qD;k= (0.3)(5)(20) = 94.2 kNDesign value of downdrag load F = ( )F

    Design vertical action

    A2 M2

    G;dst 1.01 0

    Design value of downdrag load FD;d = ()FD;k= 1.25 x 94.2 = 118 kN Design vertical action Fc;d = 300 x 1.0 + FD;d = 418 kN

    G;stb 1.0Q;dst 1.3 1.25M2 = 1 25 is considered an action factor because downdrag is

    112

    M2 1.25 is considered an action factor because downdrag isusually calculated by effective stress analysis (eg. method)

    CPGEC7course(Goh)

  • P surcharge

    Compressive Resistance with SLS verification Example 4 P

    5 m soft clayFD

    surchargeCombination 2: A2 + M1 + R4

    R

    5 m soft clay

    18 m stiff clay

    FDDesign Resistance (R4)

    A.3.3.2 Model Factor R;d = 1.4 Rs

    Rb 0

    yR;dCompressive Resistance Rc;d = Rs;d= (0 3)(18)50/( 1 4 x 1 4) = 433 kN

    From Table A NA 7 (Bored piles)

    = (0.3)(18)50/( 1.4 x 1.4) = 433 kN

    Over-design factor = Rc;d / Fc;d From Table A.NA.7 (Bored piles)Over design factor Rc;d / Fc;d= 433 / 418 = 1.04 > 1 OK R4 with explicit verification of SLS A)

    Base b 1.7Shaft (compression)

    s 1.4Total/Combined 1 7

    113

    Total/Combined (compression)

    t 1.7

    CPGEC7course(Goh)

    P surcharge

    Compressive Resistance without SLS verification Example 4 P

    5 m soft clayFD

    surchargeCombination 2: A2 + M1 + R4

    R

    5 m soft clay

    18 m stiff clay

    FDDesign Resistance (R4)

    A.3.3.2 Model Factor R;d = 1.4 Rs

    Rb 0

    yR;dCompressive Resistance Rc;d = Rs;d= (0 3)(18)50/( 1 4 x 1 6) = 379 kN

    From Table A NA 7 (Bored piles)

    = (0.3)(18)50/( 1.4 x 1.6) = 379 kNOver-design factor = Rc;d / Fc;d

    From Table A.NA.7 (Bored piles)= 379 / 418 = 0.91 < 1 Not OK R4 without explicit

    verification of SLS A)

    Base b 2.0Shaft (compression)

    s 1.6Total/Combined 2 0

    114

    Total/Combined (compression)

    t 2.0

    CPGEC7course(Goh)

  • Thank You

    115CPGEC7course(Goh)