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Effective Polyakov line actions from the relative weights method
Jeff Greensite and Kurt Langfeld Lattice 2013Mainz, GermanyJuly 2013
arXiv: 1301.4977, 1305.0048, and in progressStart with lattice gauge theory, and integrate out all d.o.f. subject to the constraint that the Polyakov lines are held fixed. In temporal gauge:
Motivation:
possible insight into the deconfinement transition
address the sign problem
PLAs with a chemical potential solve by dual representation, stochastic quantization, reweighting, mean field
The problem is to find the PLA corresponding to lattice QCD. Effective Polyakov Line Action (PLA) Previous work:
Strong coupling + hopping parameter expansions: Langelage et al. (2012)
Inverse Monte Carlo: Heinzl et al. (2005)
Demon method: Gocksch & Ogilvie (1985) , Velytsky (2008), Wozar et al (2008)
A crucial test: compare Polyakov line correlators
in both the effective PLA and the underlying lattice gauge theory.
We do not believe that an accurate agreement has been demonstrated, at leastup to now, in any of these approaches.
The method lets us compute dSP/d , where parametrizes a path through the space of all Polyakov line holonomies {Ux(), all x}.
From such derivatives, we try to deduce SP itself. Relative Weights MethodLet Ux and Ux be two configurations, corresponding to 0- and 0 + respectively. Define the PLA difference
and lattice actions (in temporal gauge) with fixed holonomies
so that, e.g.
Then
where the notation refers to a VEV in the probability distribution
We then have
But which derivatives will help us to determine SP ? Start with SU(2). The PLA can only depend on the Polyakov lines
Fourier expand
We compute
via relative weights at a typical point in field configuration space, i.e. a thermalized configuration generated by lattice Monte Carlo.
Differentiation wrt Fourier componentsProcedure
generate a thermalized lattice configuration U(x) by the usual lattice Monte Carlo, and set
Fourier decompose Px= Tr[Ux] and set ak=0. Call this . Construct
Compute
by the relative weights method.
and corresponding holonomies Ux , Ux , with Here is a plot of
Note that it is independent of SP is quadratic in ak SP is bilinear in Px . SP is bilinear in Px=2.2 , 243 x 4 lattice volume take
with
so
(relative factor of 2: ) lattice momentum
large kL data fits a straight line
which determines c1 , c2 , and at large kL .
If it were true that at all kL , it would mean that
which is long-range (violates Svetitsky-Yaffe assumption). make the simplest modification:
and determine rmax from a fit to the kL 0 data. rmax = 3 works nicely.
with c1 , c2 , rmax determined from the dSP/dak data.
So, how well does it work? The obvious test: compare correlators
in both the effective theory, and the underlying lattice gauge theory. Effective Polyakov Line Action=2.2, 243 x 4
Agreement to O(10 -5) !
The data fits c1 - 2c2kL2 over the whole range, which implies
a nearest-neighbor coupling. A test at strong-coupling: = 1.2 The result, compared to SP determined from a lowest-order strong coupling expansion at =1.2, is
We now add a fixed-modulus scalar field to the action, breaking the Z2 center symmetry:
we work at = 0.75 and = 2.2 on a 243 X 4 lattice as before.
This time, the PLA picks up a Z2-symmetry breaking term which is linear in Px
The first term is linear in a0 , which we can determine from the dS/da0 data. Adding a Matter Field
This is the dS/da0 data at
=2.2 , = 0.75 , 243 X 4
shown over a large (upper) and small (lower) range of .
The coefficient c0 of the linear term in SP is determined from the intercept with the y-axis.
Our effective theory gives the blue triangles c0 = 0.0236(14). We get a perfect fit if we use a value c0 = 0.02165 (red circles) about 1.4 from our estimate. As before, generate a thermalized configuration, extract the Polyakov lines, Fourier decompose, and set one momentum mode, ak=0. The resulting configuration is . Then construct
and from these the corresponding holonomies Ux and Ux . This is not quite as straightforward as for SU(2), but it can be done.
Then we compute by relative weights.
A complication
The data indicates, in addition to the bilinear term, also the presence of a quadrilinear term. Preliminary results for SU(3)
SU(2) SU(3) we find
with kernel
and constants c1 , c2 , rmax , q1 , q2 determined from the data. Results including off-axis points, at
= 5.6 , t = 6 and = 5.5 , t = 4 (includes off-axis points)
Once we have obtained the PLA SP at =0 , we get the PLA at 0 by a simple substitution:
uestion: Why is that the right thing to do?
nswer: This is the correct substitution to all orders in the gauge coupling and hopping parameter h . It is reasonable to assume that it holds in general.
Given SP at finite chemical potential, we can apply any of the methods used so far on Polyakov line actions:
dual representation, stochastic quantization, reweighting, mean field..
to solve the theory. Relevance to the Sign Problem in a strong coupling/hopping parameter expansion:
where
In the same way:
comparing the two expansions at = 0 and 0 , we see that to all orders in coupling and hopping parameter h
It means that once we have found the PLA at = 0 , the PLA at 0 follows from a simple substitution. Other values of and Nt in SU(3) for the pure gauge theory.
Add in a scalar field breaking the Z3 symmetry. Find the corresponding action SP , and determine transition points in the T- plane by one of the applicable methods.
Throw in quark fields. First heavy, then light. Again try to solve the resulting PLA at 0 to find the phase diagram. Next Steps
expSP [Ux]
=
DU0(x, 0)DUkD
x
[Ux U0(x, 0)]eSL
G(x y) = PxP y
xtypicalconfiguration
Configuration Space of U
SP = SP [Ux] SP [U x ]
SL[U] SL
U0(x, 0) = U
x
SL[U
] SLU0(x, 0) = U
x
eSP =
DUkD eS
L
DUkD eSL
=
DUkD exp[SL SL]eS
L
DUkD eSL
=exp[SL SL]
exp[SL]DUkD eS
L
dS
d
=0
S
Px = a0 +1
2
q =0
aq cos(q x) + bq sin(q x)
SPak
ak=
Px =1
2Tr[Ux]
SPak
ak=
SPak
Px
f = 1
Ux = U0(x, 0)
P x = (1
2ak) cos(k x) + f Px
P x = (+1
2ak) cos(k x) + f Px
-1.5
-1
-0.5
0
0.5
1
1.5
2
0 0.5 1 1.5 2 2.5 3 3.5
(L-3
dS P
/da k
)/_
kL
L=24 data with _ rescaling
_=.05_=.10_=.15_=.20
1
1
L3
SPak
ak=
vs.
SP =1
2c1x
P 2x 2c2xy
PxQ(x y)Py
Q(x y) = 1L3
k
Q(kL)eik(xy)
1L3
dSP [Ux(ak)]
dak
ak=
=
(12c1 2c2 Q(kL)) kL = 0
2( 12c1 2c2 Q(0)) kL = 0 .
x
cos2(k x) = 12L3 ,
x
1 = L3
Q(kL) = kL
Q(x y) =
2Lxy
-0.06-0.04-0.02
0 0.02 0.04 0.06 0.08
0.1 0.12
0 0.5 1 1.5 2 2.5 3 3.5
L-3 d
S P/d
a k
kL
L=24 data at _=0.05
datafit
kL =
4 3i=1
sin2(1
2ki)
(1
2c1 2c2kL)
Q(kL) kL
Q(x y) = 2L
xy|x y| rmax
0 |x y| > rmax
-0.08-0.06-0.04-0.02
0 0.02 0.04 0.06 0.08
0.1
0 0.5 1 1.5 2 2.5 3 3.5
L-3 d
S P/d
a k
kL
L=24 data and finite range kernel
datafit using Q(k)
SP =1
2c1x
P 2x 2c2xy
PxQ(x y)Py
Q(x y) = 2L
xy|x y| rmax
0 |x y| > rmax
G(R) = PxPy with R = |x y|
0 4 8 12 16 20 24R
1e-06
0.0001
0.01
1
G(R)
lattice YMeffective theory
On-axis Polyakov line correlators, L=24
= 2.25
= 2.3
0 2 4 6 8 10 12 14 16R
0.0001
0.001
0.01
0.1
1
G(R)
lattice YMeffective theory
SU(2) 163x4 beta=2.25
0 2 4 6 8 10 12 14 16R
0.01
0.1
G(R)
lattice YMeffective theory
SU(2) 163x4 beta=2.30
rmax =10
rmax =13
-0.04
-0.02
0
0.02
0.04
0.06
0.08
0.1
0 0.5 1 1.5 2 2.5
(L-3
dS P
/da k
)/_
kL
`=1.2, L=16
datak2 fit
Q(x y) =2L
xy
SP =
0.02859(3)
x
3i=1 PxPx+ relative weights
0.02850
x
3i=1 PxPx+ strong coupling
( = 1.2)
SL = plaq
1
2Tr[UUUU ] +
x,
1
2Tr[(x)U(x)(x+ )]
SP = c0x
Px +1
2c1x
P 2x 2c2xy
PxQ(x y)Py ,
-0.8
-0.6
-0.4
-0.2
0
0.2
0.4
0.6
0.8
-0.2 -0.15 -0.1 -0.05 0 0.05 0.1 0.15 0.2
L-3 d
S P/d
a 0
_
gauge-Higgs k=0 data, L=24
datalinear fit
-0.2-0.15
-0.1-0.05
0 0.05
0.1 0.15
0.2 0.25
-0.04 -0.02 0 0.02 0.04
L-3 d
S P/d
a 0
_
gauge-Higgs k=0 data, L=24
datalinear fit
0 4 8 12 16 20 24R
0.01
1
G(R)
eff theory: c0=0.021654latt SU(2) + Higgseff theory: c0=0.0236
On-axis Polyaov line correlators, L=24
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0 0.05 0.1 0.15 0.2
L-3 d
S P/d
a 0
_
kL=0 data, linear fit
datafit
0 0.5
1 1.5
2 2.5
3 3.5
4 4.5
0 0.05 0.1 0.15 0.2 0.25 0.3
L-3 d
S P/d
a 0
_
kL=0 data, linear fit
datafit
1e-07
1e-06
1e-05
0.0001
0.001
0.01
0.1
1
0 1 2 3 4
G(R)
R
Polyakov line correlators, `=5.6, L=16, T=6
eff actionlattice SU(3)
1e-05
0.0001
0.001
0.01
0.1
1
0 1 2 3 4 5
G(R)
R
Polyakov line correlators, `=5.5, L=16, Nt=4
eff action on axisLuscher-Weisz
SP [Ux, Ux] = S
=0P [e
NtUx, eNtUx]
expS=0P [Ux, U
x]=
DUkDD exp
SL[Ux, U
x, Ui(x),,]
=D
cDNpD
2N2
pDhp
DPD[Ux, U
x]
PD[Ux, Ux] = TrU
w1x1 TrU
w2x2 ...TrU
wnxn TrU
w1y1 TrU
w2y2 ...TrU
wmym
expSP [Ux, U
x]=
DUkDD exp
SL[e
NtUx, eNtUx, Ui(x),,]
=D
cDNpD
2N2
pDhp
DPD[e
NtUx, eNtU x]
SP [Ux, Ux] = S
=0P [e
NtUx, eNtUx]