DSCI5180 Spring2013 Quizzes1-6

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    slide 1

    DSCI 5180: Introduction to the BusinessDecision Process

    Spring 2013 Dr. Nick !"nge#opou#os

    Exam 1 review:

    Quizzes 1-6

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    2

    POP QUIZ #1

    1. Probabilities under the Normal Distribution

    are typically calculated:

    A. After standardization of the random variable

    . !"ter applyin re$erse standardi%ation

    &. y as'in e(perts to estimate itD. )ithout the use o" computers or calculators

    *. )ithout loo'in at a Z table

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    +

    POP QUIZ #1

    2. ,he number that corresponds to a tail

    probability o" - is usually calculated:

    !. !"ter standardi%ation o" the random $ariable

    B. After applying reverse standardization

    &. y as'in e(perts to estimate itD. )ithout the use o" computers or calculators

    *. )ithout loo'in at a Z table

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    /

    POP QUIZ #1

    +. In pro$idin inter$al estimates "or 0 the tdistribution applies:

    !. )hen sample si%es are lare n +34

    . )hen sample si%es are small n 5 +340

    reardless o" the distribution o" 6

    &. )hen the pop. st. de$iation 4 is 'no7nD. When the pop. st. deviation () in unknown

    *. )hen the sample st. de$iation s4 is un'no7n

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    -

    POP QUIZ #1/. P%14 and P%5 814 are related as "ollo7s:

    !. P%14 9 P%5 814 1

    B. P(z!) " P(z# $!)

    &. P%14 3.- 8 P%5 814

    D. P%14 9 P%5 814 3.-

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    ;

    POP QUIZ #1

    -. ,he probability that a consumer

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    >

    POP QUIZ #2

    1. )hich one o" the $ariables listed you

    e(pect to "ollo7 a Normal distribution:

    !. ?i%e o" craters on planet @ars

    . ?i%e o" earth

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    A

    POP QUIZ #2

    2. )hich one o" the $ariables listed you

    e(pect to "ollo7 an *(ponential

    distribution:

    A. +ize of ,raters on planet -ars

    . ! personBs heiht&. ! personBs 7eiht

    D. ! personBs intellience IQ4

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    C

    POP QUIZ #2

    +. ,he &entral imit ,heorem states that:

    A. When sample sizes are large (n )/ the

    distribution of 0$bar is appro&. normal

    . )hen sample si%es are small n 5 +340 the

    distribution o" 68bar is appro(. normal

    &. )hen the pop. st. de$iation 4 is 'no7n0 thedistribution o" 68bar is appro(. normal

    D. )hen the pop. st. de$iation 4 in un'no7n0the distribution o" 68bar is appro(. normal

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    POP QUIZ #2

    /. In statistical in"erence0 7hen the sample

    si%e increases:

    !. ,he con"idence inter$al remains the same

    . ,he con"idence inter$al e(pands becomes

    7ider4

    1. %he ,onfiden,e interval shrinks ("be,omes

    narrower)

    D. ,he standard de$iation o" (8bar increases

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    POP QUIZ #2

    -. In hypothesis testin0 the null hypothesis is

    reEected 7hen:

    !. P8$alue alpha

    B. P$value # alpha

    &. !lpha 5 critical $alueD. !lpha critical $alue

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    POP QUIZ #+

    1. ,he "itted reression line is typically

    calculated by minimi%in the sum o":

    !. ,he s

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    1+

    POP QUIZ #+

    2. In the "itted line e

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    1/

    POP QUIZ #+

    +. In the "itted line e

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    1-

    POP QUIZ #+

    /. @?* is used as an estimator "or:

    !. ,he reression slope. ,he y8intercept

    &. ,he mean o" the disturbance error4

    D. %he varian,e of the disturban,e (error)*. ,he st. de$iation o" the disturbance error4

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    POP QUIZ #+

    -. !s part o" reression analysis0 7hy do 7e

    7ant to test 7hether or not 1 3

    !. It is the 7ay to see i" the y8intercept is %ero. It is the 7ay to see i" the assumptions hold

    1. 5t is the way to see if 0 and 6 are linearly

    related

    D. It is the 7ay to see i" 6 is the only possible

    predictor "or F

    *. It is the 7ay to see i" the t distribution holds

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    1>

    POP QUIZ #/

    1. ,he relationship bet7een &O?, and

    NU@POG,? is sini"icant i":

    !. ,he G8s

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    1A

    POP QUIZ #/

    2. ased on the reression output belo70

    Predictor Coef SE Coef T P

    Constant 16594 2687 6.18 0.000

    NUMPOTS 650.17 66.91 9.72 0.000

    !. ,he constant is probably e

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    POP QUIZ #/

    +. ,estin the slope o" NU@POG,? "or

    sini"icance0 the derees o" "reedom are:

    A. n $ 3

    . n 8 1

    &. n

    D. !l7ays e

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    POP QUIZ #/

    /. ! C- &.I. "or a reression slope is

    al7ays:

    !. ?ymmetrical around b3

    B. +ymmetri,al around b!

    &. &alculated usin the J distributionD. &alculated usin the % distribution

    *. Non8symmetrical

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    POP QUIZ #/

    -. ,o test 7hether a relationship bet7een 6 and

    F is positi$e0 7e need to test:

    !. K3: 3 3 $s. Ka: 3 3. K3: 1 3 $s. Ka: 15 3

    1. ;(< !" vs. ;a< !

    D. K3: 1 3 $s. Ka: 1L 3*. K3: 3 3 $s. Ka: 3L 3

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    POP QUIZ #-

    1. Ge"errin to the !NOM! table0 ??, is

    i$en as:

    !. ??, ??G 8 ??*

    . ??, ??G

    &. ??, ??*D. ++% " ++: = ++4

    *. ??, ??G ??*

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    2+

    POP QUIZ #-

    2. ,he &oe""icient o" Determination iscomputed as:

    !. G ??G ??,

    . G ??G ??*

    1. :3

    " ++: > ++%D. G2 ??, ??G

    *. G2 ??, ??*

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    POP QUIZ #-

    +. ,he Geression J test is desined to e(amine:

    A. Whether or not !"

    . )hether or not 3 3

    &. )hether or not 1 3 3

    D. )hether or not 1 1

    *. )hether or not 3 1

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    POP QUIZ #-

    /. In simple reression0 is it al7ays necessary

    to conduct an J test

    !. Fes0 the in"ormation pro$ided by an J test isuni

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    2;

    POP QUIZ #-

    -. Ge"er to the communication nodes e(ample. Is Nodes

    a sini"icant predictor "or Cost !NOM! table i$en belo74

    So!rce "# SS MS # P

    e$ression 1 1751268%76 1751268%76 94.41 0.000esid!a& Error 12 222594146 18549512

    Tota& 1% 197%862521

    !. Fes0 because the J $alue is less than 3.3-

    B. 6es/ be,ause the p value is less than .'&. No0 because the J $alue is $ery lare

    D. No0 because the p $alue is $ery small

    *. No0 because the J $alue is larer than the p $alue

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    2>

    POP QUIZ #;

    1. ,he reression model assumptions re"er to:

    A. %he errors. ,he y8intercept

    &. ,he slope coe""icients

    D. !ll coe""icients0 includin y8intercept andslopes

    *. ,he derees o" "reedom

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    2A

    POP QUIZ #;

    2. !nalysis o" @eddicorp ?ales produced the"itted line listed belo7. Ko7 do youinterpret the slope "or onus

    S'(ES ) * 516 + 2.47 '", + 1.86 -ONUS

    !. *ach 1 o" onus increases ?ales by 1.A;

    B. 4a,h ?! of Bonus in,reases +ales by

    ?!/@/ if Adv is kept ,onstant

    &. *ach 133 o" onus increases ?ales by 1A;

    D. *ach 1 in ?ales increases onus by 1.A;

    *. *ach 1.A; in ?ales increases onus by 1

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    2C

    POP QUIZ #;

    +. ased on the reression output belo70Predictor Coef SE Coef T P

    Constant *516.4 189.9 *2.72 0.01%

    '", 2.47%2 0.275% 8.98 0.000

    -ONUS 1.8562 0.7157 2.59 0.017

    !. Only !DM is a sini"icant predictor "or ?ales

    . Only onus is a sini"icant predictor "or ?ales

    1. Both AD and Bonus are signifi,ant predi,tors for +ales

    D. Neither !DM nor onus are sini"icant predictors "or ?ales

    *. ,he constant is neati$e0 there"ore there is an in$erse

    relationship bet7een ?ales and !DM or onus

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    +3

    POP QUIZ #;

    /. ,he @ultiple Geression J test is desined to

    e(amine:

    !. )hether or not 1 3

    . )hether or not 3 3

    &. )hether or not 3 1 3

    D. )hether or not 3 1 3

    4. Whether or not !" 3" C "

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    +1

    POP QUIZ #;

    -. )hen you remo$e an e(planatory $ariable "rom a

    reression model0

    !. G2

    7ill al7ays increase0 but G2

    H adEusted may decreaseB. :3will always de,rease/ but :3 adEusted may in,rease

    &. G27ill al7ays increase0 but G2H adEusted may or may not

    increase

    D. oth G 2and G2H adEusted 7ill al7ays increase*. oth G 2and G2H adEusted 7ill al7ays decrease