Muhammad Fahmi Sihab5213413077Windy Oktaviani5213413078Echa Cahya J.P5213413079Rizal Syahriar5213413081Tugas Utilitas

Buatlah desain rapid sand filter dengan kebtutuhan 3 MLD. Dengan asumsi sebagai berikut:>Rate of filtration 5000/lit/hr/m2. >Diameter of perforation 13 mm. >Length =1.5 times the width. >The discharge of a rectangular flat bottom through is given by 1.376bd3/2 water required = 3 MLD asumsi amount of wash water0.2-0.4%*dipilih asumsi 0.4%Maka, 0.4% dari water required= 0.4% x 3MLDx 3 MLD0.012 MLD total amount of wateer needed = water requiured + washing water total amount of water needed = 3 MLD +0.012 MLD= 3.012 MLD asumsi washing time dalam 1 hari (24 jam)*dipilih asumsi washing time = 50 menit (0.833333 jam)Filtration time = 24 jam washing time= 24 0.833333 jam= 23.16666667 jam menghitung Q tanpa washing timeQ = Q = = 0,130014388 ML/jamarea of filter bed = = = 26.002877 m2 >Mencari L dan B dengan asumsi jumlah unit yang dibangun sebanyak 1 unit*diketahui asumsi L = 1.5B>Area of filter bed (luas) = B x L 26.002877 m2 = B x 1.5B26.002877 m2 = 1.5 B2 B = 4.163562 m L = 1.5 x 4.163562 m = 6.245344 m>Design of laterals Total area of perforation = 0.2% of area filter = x B x L = x 4.163562 x 6.245344 = 0,052005755 m2 = 520.0576 cm2 Asumsi c/c distance of lateral 25 cm = 0.25 mNo. of lateral = = = 24,98137436 m nos = 25 nosAsumsi n = no. of perforations/each lateral Area of perforation = 520,0576 cm2Area of perforation = n./4.d2.no of laterar520,0576= n./4. 1,32.25 n = 3,920081061Crosesction area of laeral d perforation=1,3cm= = = Jadi untuk d lateral=d = 2,6 cm = 0,026 m

Crossection area of main drain = 2xtotal A lateral= 2 x n x= 265,33 cm

= 265,33 cmd = 18,38477631 cm= 0,183848 m

Length of lateral= lebar tanki d main drain in meter= 4,163562 - 0,183848= 3,979715 mL/d (cs area of lateral)= 6,245344 m / 0,026 mMemenuhi syarat >60

= 240,2055227 Asumsi rate of washing = 50 cm/menit = 0,0083 m/swash water discharge Q= A. v= L. B. v= 6,245344m . 4,163562m . 0,0083m/sQ= 0,21582 m3/sAsumsi c/c water through = 4number of water through= L/water through= 6,245344/4= 1,561335897 Dibulatkan menjadi 2Discharge in each through= Q/no of water through= 0,21582 m3/s / 2= 0,107911942 m3sAsumsi the widh of water through= 40 cm= 0,4 mdischarge in each through=discharge in through0,107911942 m3s=1.376(b)d3/2d3/2=0,196060942d=0,33