Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force...

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Classification of Forces • Action vs reaction • Internal vs external • Motive vs resistive • Force resolution – horizontal and vertical components • Simultaneous application of forces - vector summation
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Transcript of Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force...

Page 1: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Classification of Forces

• Action vs reaction

• Internal vs external

• Motive vs resistive

• Force resolution – horizontal and vertical components

• Simultaneous application of forces - vector summation

Page 2: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Types of external forces encountered by humans

• Gravitational force (weight = mg)• Ground Reaction Force (GRF)

– Vertical

– Horizontal (frictional)

• Frictional force (coefficient of friction) • Elastic force (coefficient of restitution)

• Centripetal force (mv2/r) • Buoyant force • Free body diagram - force graph

Page 3: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Force Plates – Measurement of ground

reaction forces

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While walking

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Cfr = Frf /Nof

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Coefficient of restitution – Relative velocity before and after impact:

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Coefficient of restitution – drop test

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Page 9: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Centripetal & Centrifugal forces

Cf = mv2/r

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Buoyant Force = weight of water displaced by abody. If weight of water displaced by your body is more than your body, then you will float. Your body will only sink down to the point where Wt = Bf

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Buoyant force = wtof water displaced

Will this person float? Rotate?

How can you tell?

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Free body diagrams:

Page 13: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Free body diagrams

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Force and Motion Relationships

• Instantaneous Effect of force on motion is to accelerate the object: F=ma

• Force applied through a distance: work-energy relationship

• Force applied through a time: impulse-momentum relationship

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Instantaneous Effect of Force on an Object

• Remember the concept of net force?• Need to combine, or add forces, to

determine net force • Newton’s third law of motion (F = ma)• Inverse dynamics – estimating net forces

from the acceleration of an object• Illustrations from Kreighbaum: Figures F.4,

F.5, and F.6 (pp 283-284)

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Vector Resolution Problems

• Projectile motion situations– Find horizontal velocity– Find vertical velocity

• Friction problems – Find horizontal force component (Friction)– Find vertical component (Normal)

• First step in adding, or combining vectors– When more than one force is acting on an object– When adding velocity vectors

Page 17: Classification of Forces Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components Simultaneous.

Vector resolution:

Turning comp = F•d•sinΘRadial comp = F•d•cosΘ(d = d•sinθ)

Vert comp = F•sinΘHoriz comp = F•cosΘ

Θ

Vert comp = F•sin•ΘHoriz comp = F•cos•Θ

Θ Θ

Θ

Θ

d

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Vector Addition Problems

• Combining forces– Net effect of two forces applied to any object– What is maximum safe speed for a curve?

• Centrifugal force, frictional force, & gravity

– What makes a spitball work?• Wind force and weight

• Combining velocities– In crossing a river, what direction is best?

• Velocity of water and swimmer

– In aviation, correcting for wind• air speed and ground speed

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Sum of two forces: Sum of two velocities:

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(May be deleted if your calculator providesresultant angle in a 0-360 deg system)

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Force Applied Through a Time: Impulse-Momentum Relationship

• Force applied through a time• Impulse - the area under the force-time curve• Momentum - total amount of movement (mass x velocity)• An impulse applied to an object will cause a change in its

momentum (Ft = mv)• Conservation of momentum (collisions, or impacts)

– in a closed system, momentum will not change

– what is a closed system?

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Impulse: areaunder force-time curve

Impulse produces a change in momentum (mV)

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Vertical impulse While Running: Area underForce-timecurve

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Anterioposterior(frictional) component of GRF: impulseIs area under Force-time curvePositive andNegative impulseAre equal ifHorizontal compOf velocity isconstant

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Conservation of momentum: when net impulse is zero (i.e. the system is closed), momentum does not change

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Conservation of momentum: is this a closed system?

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Force Applied Through a Distance: Work, Power, Energy

• Work - force X distance (Newton-meters, or Joules)– On a bicycle: Work = F (2r X N)– On a treadmill: Work = Weightd X per cent grade

• Power - work rate, or combination of strength and speed (Newton-meters/second, or watts)– On a treadmill: P = Weightd X per cent grade/ time– On a bicycle: P = F (2r X N) / time

• What about kilogram-meters/min?• Energy - capacity to do work

– kinetic, the energy by virtue of movement (KE = 1/2 mv2 ) – gravitational potential, energy of position (PE = Weight x height)– elastic potential, or strain, energy of condition (PE = Fd)

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Work while pedaling on bicycle:

From McArdle and Katch.Exercise Physiology

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Work while running on treadmill:

Note that %grade = tan θ X 100,and tan θ and sin θ are very similar below 20% grade

From McArdle and Katch. Exercise Physiology

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Calculating Power on a Treadmill• Problem: What is workload (power) of a 100 kg man running on a

treadmill at 10% grade at 4 m/s?• Solution:

– Power = force x velocity– Force is simply body weight, or 100 x 9.8 = 980 N– Velocity is vertical velocity, or rate of climbing

• Rate of climbing = treadmill speed x percent grade = 4 m/s x .1 = .4 m/s

– Workload, workrate, or power = 980N X .4 m/s = 392 Watts• Note: 4 m/s = 9 mph, or a 6 min, 40 sec mile

• Problem: Calculate your workload if you are running on a treadmill set at 5% grade and 5 m/s.– Answer for 200 lb wt is: 223 Watts

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Power running up stairs: Work rate = (weight X vertical dist) ÷ time

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Conservation of Energy• In some situations, total amount of mechanical energy

(potential + kinetic) does not change– Stored elastic energy converted to kinetic energy

• diving board

• bow (archery)

• bending of pole in pole vault

• landing on an elastic object (trampoline)

– Gravitational potential energy converted to kinetic energy• Falling objects

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Energy conservation – Case I : elastic potential (strain) and kinetic

Potential energy (FD) + Kinetic energy (1/2mv2) remains constant

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Energy conservation – Case II : gravitational potential and kinetic

Potential energy(Wh) + kineticenergy (1/2mv2) remains constant

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Linear Kinetics Formulae