Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13,...

11
Chapter 4 (CIC) and Chapter 5, 8 (CTCS) • Read in CTCS Chapter 5.1,3-4, 8.9 • Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69

Transcript of Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13,...

Page 1: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Chapter 4 (CIC) and Chapter 5, 8 (CTCS)

• Read in CTCS Chapter 5.1,3-4, 8.9

• Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69

Page 2: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Global Warming (CO2) Fuel• Fuel’s are typically fossil fuels (crude oil, coal)

• Gasohol is a mixture of ethanol and gasolineCH2=CH2 + H2O CH3CH2OH

C6H12O6 CH3CH2OH + CO2

• Does EtOH give same performance as gasoline? Does EtOH give the same amount of energy per gram?

• 1st Law – If we have Conservation of Energy, why are worried about depleting our resources?

Page 3: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Annual US Energy Consumption From Various Sources

Page 4: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Combustion• All but two of those energy sources were based

on combustion giving CO2 as a byproduct• Energies can be obtained from a calorimeterQ: Determine the heat of combustion for a gram

of natural gas (CH4) compared to a gram of butane (C4H10) if their heats of combustion are –802.3 and –2658.4 kJ/mol respectively.

A:-50.01 kJ/g and –45.74kJ/g

Page 5: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Energy Diagram

Reactants

ProductsEnt

halp

y

Reaction Progress

Hrxn

Page 6: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

• Where does the exothermic energy come from?

• When bonds are broken, energy is required• When bonds are made, energy is released• Compare the bond strengths in the equation

above (See Table 8.4 - pg 289)• The products are:

– More stable– Lower in Energy– Have stronger bonds

H

CH

H

+ 2O O O C O O2H HH +

Page 7: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

• CO2 and H2O are too stable (have bonds that are too strong) to decompose and give off more energy

Q: Could you use ozone as a fuel? How much energy is released/g of ozone? (Use bond energies to calculate)

A: -2.11 J/g (-2.96 kJ/g according to Hºf)

• Bond Energies are averages of gas moleculesHºf – enthalpy of formation in standard state (º)

Page 8: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

Q: Using bond energies, calculate the heat of reaction for the combustion of molecular hydrogen and 1 mol of oxygen to form gaseous products

A: -485 kJ (actual = -483.6 kJ)

Q: Would you expect a more endo- or exo-thermic reaction if the products were liquid?

Page 9: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

• H2O(g) H2O(l) H = negative,WHY?

• 2 H2(g) + O2(g) 2 H2O(l)

• Can’t use bond energies!Hºrxn = -571.7 kJ

• Spontaneity (G)– If you have a large negative H, you can assume

spontaneity

Q: What are some of the strongest bonds?

Page 10: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

• Triple: NN, CO; Double: C=O; Single: O-H, Si-O

• This suggests that these bonds would have trouble reacting

2 CO + O=O 2 O=C=O Hºrxn= -566 kJ

• Explosives– Should have many weak bonds– Ideally have all atoms of reaction self contained– Need to be stable enough to work with– Should create gaseous molecules

Page 11: Chapter 4 (CIC) and Chapter 5, 8 (CTCS) Read in CTCS Chapter 5.1,3-4, 8.9 Problems in CTCS: 5.3, 13, 15, 22, 23, 29, 35, 90, and 8.63, 65, 67, 69.

• Nitroglycerin

• What are the products of decomposition?

Q: What is the Hrxn/mol of nitro? (why not Hºrxn?)

A: -1782 kJ

CH2 O

HC

CH2

O

O

NO2

NO2

NO2