Chapter 2 Elementary Programming - Timlintimlin.net/csm/cis254/02slide.pdf · To write Java...
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Chapter 2 Elementary Programming
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Motivations
In the preceding chapter, you learned how to
create, compile, and run a Java program. Starting
from this chapter, you will learn how to solve
practical problems programmatically. Through
these problems, you will learn Java primitive data
types and related subjects, such as variables,
constants, data types, operators, expressions, and
input and output.
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Objectives To write Java programs to perform simple computations (§2.2).
To obtain input from the console using the Scanner class (§2.3).
To use identifiers to name variables, constants, methods, and classes (§2.4).
To use variables to store data (§§2.5–2.6).
To program with assignment statements and assignment expressions (§2.6).
To use constants to store permanent data (§2.7).
To name classes, methods, variables, and constants by following their naming conventions (§2.8).
To explore Java numeric primitive data types: byte, short, int, long, float, and double (§2.9.1).
To perform operations using operators +, -, *, /, and % (§2.9.2).
To perform exponent operations using Math.pow(a, b) (§2.9.3).
To write integer literals, floating-point literals, and literals in scientific notation (§2.10).
To write and evaluate numeric expressions (§2.11).
To obtain the current system time using System.currentTimeMillis() (§2.12).
To use augmented assignment operators (§2.13).
To distinguish between postincrement and preincrement and between postdecrement and predecrement (§2.14).
To cast the value of one type to another type (§2.15).
To describe the software development process and apply it to develop the loan payment program (§2.16).
To represent characters using the char type (§2.17).
To represent a string using the String type (§2.18).
To obtain input using the JOptionPane input dialog boxes (§2.19).
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Introducing Programming with an
Example
Listing 2.1 Computing the Area of a Circle
This program computes the area of the circle.
ComputeArea
RunIMPORTANT NOTE: (1) To enable the buttons, you must
download the entire slide file slide.zip and unzip the files into a
directory (e.g., c:\slide) . (2) You must have installed JDK and set
JDK’s bin directory in your environment path (e.g., c:\Program
Files\java\jdk1.7.0\bin in your environment path. (3) If you are
using Office 2010, check PowerPoint2010.doc located in the same
folder with this ppt file.
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Trace a Program Executionpublic class ComputeArea {
/** Main method */
public static void main(String[] args) {
double radius;
double area;
// Assign a radius
radius = 20;
// Compute area
area = radius * radius * 3.14159;
// Display results
System.out.println("The area for the circle of radius " +
radius + " is " + area);
}
}
no valueradius
allocate memory
for radius
animation
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Trace a Program Executionpublic class ComputeArea {
/** Main method */
public static void main(String[] args) {
double radius;
double area;
// Assign a radius
radius = 20;
// Compute area
area = radius * radius * 3.14159;
// Display results
System.out.println("The area for the circle of radius " +
radius + " is " + area);
}
}
no valueradius
memory
no valuearea
allocate memory
for area
animation
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Trace a Program Executionpublic class ComputeArea {
/** Main method */
public static void main(String[] args) {
double radius;
double area;
// Assign a radius
radius = 20;
// Compute area
area = radius * radius * 3.14159;
// Display results
System.out.println("The area for the circle of radius " +
radius + " is " + area);
}
}
20radius
no valuearea
assign 20 to radius
animation
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Trace a Program Executionpublic class ComputeArea {
/** Main method */
public static void main(String[] args) {
double radius;
double area;
// Assign a radius
radius = 20;
// Compute area
area = radius * radius * 3.14159;
// Display results
System.out.println("The area for the circle of radius " +
radius + " is " + area);
}
}
20radius
memory
1256.636area
compute area and assign it
to variable area
animation
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Trace a Program Executionpublic class ComputeArea {
/** Main method */
public static void main(String[] args) {
double radius;
double area;
// Assign a radius
radius = 20;
// Compute area
area = radius * radius * 3.14159;
// Display results
System.out.println("The area for the circle of radius " +
radius + " is " + area);
}
}
20radius
memory
1256.636area
print a message to the
console
animation
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Reading Input from the Console
1. Create a Scanner object
Scanner input = new Scanner(System.in);
2. Use the methods next(), nextByte(), nextShort(),
nextInt(), nextLong(), nextFloat(), nextDouble(), or nextBoolean() to obtain to a string, byte, short, int, long, float, double, or boolean value. For example,
System.out.print("Enter a double value: ");
Scanner input = new Scanner(System.in);
double d = input.nextDouble();ComputeAreaWithConsoleInput
Run
ComputeAverage
Run
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Identifiers
An identifier is a sequence of characters that consist of
letters, digits, underscores (_), and dollar signs ($).
An identifier must start with a letter, an underscore (_),
or a dollar sign ($). It cannot start with a digit.
– An identifier cannot be a reserved word. (See Appendix A,
“Java Keywords,” for a list of reserved words).
An identifier cannot be true, false, or
null.
An identifier can be of any length.
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Variables
// Compute the first area
radius = 1.0;
area = radius * radius * 3.14159;
System.out.println("The area is “ +
area + " for radius "+radius);
// Compute the second area
radius = 2.0;
area = radius * radius * 3.14159;
System.out.println("The area is “ +
area + " for radius "+radius);
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Declaring Variables
int x; // Declare x to be an
// integer variable;
double radius; // Declare radius to
// be a double variable;
char a; // Declare a to be a
// character variable;
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Assignment Statements
x = 1; // Assign 1 to x;
radius = 1.0; // Assign 1.0 to radius;
a = 'A'; // Assign 'A' to a;
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Declaring and Initializing
in One Step
int x = 1;
double d = 1.4;
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Named Constants
final datatype CONSTANTNAME = VALUE;
final double PI = 3.14159;
final int SIZE = 3;
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Naming Conventions
Choose meaningful and descriptive names.
Variables and method names:
– Use lowercase. If the name consists of several
words, concatenate all in one, use lowercase
for the first word, and capitalize the first letter
of each subsequent word in the name. For
example, the variables radius and area, and
the method computeArea.
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Naming Conventions, cont.
Class names:
– Capitalize the first letter of each word in the name. For example, the class name ComputeArea.
Constants:
– Capitalize all letters in constants, and use underscores to connect words. For example, the constant PI and MAX_VALUE
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Numerical Data Types
Name Range Storage Size
byte –27 to 27 – 1 (-128 to 127) 8-bit signed
short –215 to 215 – 1 (-32768 to 32767) 16-bit signed
int –231 to 231 – 1 (-2147483648 to 2147483647) 32-bit signed
long –263 to 263 – 1 64-bit signed
(i.e., -9223372036854775808 to 9223372036854775807)
float Negative range: 32-bit IEEE 754
-3.4028235E+38 to -1.4E-45
Positive range:
1.4E-45 to 3.4028235E+38
double Negative range: 64-bit IEEE 754
-1.7976931348623157E+308 to -4.9E-324
Positive range:
4.9E-324 to 1.7976931348623157E+308
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Numeric Operators
Name Meaning Example Result
+ Addition 34 + 1 35
- Subtraction 34.0 – 0.1 33.9
* Multiplication 300 * 30 9000
/ Division 1.0 / 2.0 0.5
% Remainder 20 % 3 2
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Integer Division
+, -, *, /, and %
5 / 2 yields an integer 2.
5.0 / 2 yields a double value 2.5
5 % 2 yields 1 (the remainder of the division)
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Remainder Operator
Remainder is very useful in programming. For example, an even number % 2 is always 0 and an odd number % 2 is always 1. So you can use this property to determine whether a number
is even or odd. Suppose today is Saturday and you and your friends are going to meet in 10 days. What day is in 10 days? You can find that day is Tuesday using the following expression:
Saturday is the 6th day in a week
A week has 7 days
After 10 days
The 2nd day in a week is Tuesday (6 + 10) % 7 is 2
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Problem: Displaying Time
Write a program that obtains hours and
minutes from seconds.
DisplayTime Run
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NOTE
Calculations involving floating-point numbers are
approximated because these numbers are not stored
with complete accuracy. For example,
System.out.println(1.0 - 0.1 - 0.1 - 0.1 - 0.1 - 0.1);
displays 0.5000000000000001, not 0.5, and
System.out.println(1.0 - 0.9);
displays 0.09999999999999998, not 0.1. Integers are
stored precisely. Therefore, calculations with integers
yield a precise integer result.
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Exponent Operations
System.out.println(Math.pow(2, 3));
// Displays 8.0
System.out.println(Math.pow(4, 0.5));
// Displays 2.0
System.out.println(Math.pow(2.5, 2));
// Displays 6.25
System.out.println(Math.pow(2.5, -2));
// Displays 0.16
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Number Literals
A literal is a constant value that appears directly in the program. For example, 34, 1,000,000, and 5.0 are literals in the following statements:
int i = 34;
long x = 1000000;
double d = 5.0;
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Integer LiteralsAn integer literal can be assigned to an integer variable as
long as it can fit into the variable. A compilation error
would occur if the literal were too large for the variable to
hold. For example, the statement byte b = 1000 would
cause a compilation error, because 1000 cannot be stored
in a variable of the byte type.
An integer literal is assumed to be of the int type, whose
value is between -231 (-2147483648) to 231–1
(2147483647). To denote an integer literal of the long
type, append it with the letter L or l. L is preferred because
l (lowercase L) can easily be confused with 1 (the digit
one).
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Floating-Point Literals
Floating-point literals are written with a decimal
point. By default, a floating-point literal is treated
as a double type value. For example, 5.0 is
considered a double value, not a float value. You
can make a number a float by appending the letter f
or F, and make a number a double by appending
the letter d or D. For example, you can use 100.2f
or 100.2F for a float number, and 100.2d or 100.2D
for a double number.
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Scientific Notation
Floating-point literals can also be specified in
scientific notation, for example, 1.23456e+2,
same as 1.23456e2, is equivalent to 123.456, and
1.23456e-2 is equivalent to 0.0123456. E (or e)
represents an exponent and it can be either in
lowercase or uppercase.
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Arithmetic Expressions
)94
(9))(5(10
5
43
y
x
xx
cbayx
is translated to
(3+4*x)/5 – 10*(y-5)*(a+b+c)/x + 9*(4/x + (9+x)/y)
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How to Evaluate an Expression
Though Java has its own way to evaluate an
expression behind the scene, the result of a Java
expression and its corresponding arithmetic expression
are the same. Therefore, you can safely apply the
arithmetic rule for evaluating a Java expression.
3 + 4 * 4 + 5 * (4 + 3) - 1
3 + 4 * 4 + 5 * 7 – 1
3 + 16 + 5 * 7 – 1
3 + 16 + 35 – 1
19 + 35 – 1
54 - 1
53
(1) inside parentheses first
(2) multiplication
(3) multiplication
(4) addition
(6) subtraction
(5) addition
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Problem: Converting Temperatures
Write a program that converts a Fahrenheit degree
to Celsius using the formula:
FahrenheitToCelsius Run
)32)((95 fahrenheitcelsius
Note: you have to write
celsius = (5.0 / 9) * (fahrenheit – 32)
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Problem: Displaying Current TimeWrite a program that displays current time in GMT in the
format hour:minute:second such as 1:45:19.
The currentTimeMillis method in the System class returns
the current time in milliseconds since the midnight, January
1, 1970 GMT. (1970 was the year when the Unix operating
system was formally introduced.) You can use this method
to obtain the current time, and then compute the current
second, minute, and hour as follows.
ShowCurrentTime
Run
Elapsed
time
Unix Epoch
01-01-1970
00:00:00 GMT
Current Time
Time
System.currentTimeMills()
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Shortcut Assignment Operators
Operator Example Equivalent
+= i += 8 i = i + 8
-= f -= 8.0 f = f - 8.0
*= i *= 8 i = i * 8
/= i /= 8 i = i / 8
%= i %= 8 i = i % 8
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Increment and
Decrement Operators
Operator Name Description
++var preincrement The expression (++var) increments var by 1 and evaluates
to the new value in var after the increment.
var++ postincrement The expression (var++) evaluates to the original value
in var and increments var by 1.
--var predecrement The expression (--var) decrements var by 1 and evaluates
to the new value in var after the decrement.
var-- postdecrement The expression (var--) evaluates to the original value
in var and decrements var by 1.
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Increment and
Decrement Operators, cont.
int i = 10;
int newNum = 10 * i++;
int newNum = 10 * i;
i = i + 1;
Same effect as
int i = 10;
int newNum = 10 * (++i);
i = i + 1;
int newNum = 10 * i;
Same effect as
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Increment and
Decrement Operators, cont.
Using increment and decrement operators makes
expressions short, but it also makes them complex and
difficult to read. Avoid using these operators in expressions
that modify multiple variables, or the same variable for
multiple times such as this: int k = ++i + i.
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Assignment Expressions and
Assignment Statements
Prior to Java 2, all the expressions can be used as
statements. Since Java 2, only the following types of
expressions can be statements:
variable op= expression; // Where op is +, -, *, /, or %
++variable;
variable++;
--variable;
variable--;
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Numeric Type Conversion
Consider the following statements:
byte i = 100;
long k = i * 3 + 4;
double d = i * 3.1 + k / 2;
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Conversion Rules
When performing a binary operation involving two
operands of different types, Java automatically
converts the operand based on the following rules:
1. If one of the operands is double, the other is
converted into double.
2. Otherwise, if one of the operands is float, the other is
converted into float.
3. Otherwise, if one of the operands is long, the other is
converted into long.
4. Otherwise, both operands are converted into int.
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Type Casting
Implicit casting
double d = 3; (type widening)
Explicit casting
int i = (int)3.0; (type narrowing)
int i = (int)3.9; (Fraction part is truncated)
What is wrong? int x = 5 / 2.0;
byte, short, int, long, float, double
range increases
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Problem: Keeping Two Digits After
Decimal Points
Write a program that displays the sales tax with two digits after the decimal point.
SalesTax Run
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Casting in an Augmented Expression
In Java, an augmented expression of the form x1 op=
x2 is implemented as x1 = (T)(x1 op x2), where T is
the type for x1. Therefore, the following code is
correct.
int sum = 0;
sum += 4.5; // sum becomes 4 after this statement
sum += 4.5 is equivalent to sum = (int)(sum + 4.5).
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Software Development Process
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
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Requirement Specification
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
A formal process that seeks to understand
the problem and document in detail what
the software system needs to do. This
phase involves close interaction between
users and designers.
Most of the examples in this book are simple,
and their requirements are clearly stated. In
the real world, however, problems are not
well defined. You need to study a problem
carefully to identify its requirements.
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System Analysis
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
Seeks to analyze the business
process in terms of data flow, and
to identify the system’s input and
output.
Part of the analysis entails modeling
the system’s behavior. The model is
intended to capture the essential
elements of the system and to define
services to the system.
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System Design
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
The process of designing the
system’s components.
This phase involves the use of many levels
of abstraction to decompose the problem into
manageable components, identify classes and
interfaces, and establish relationships among
the classes and interfaces.
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IPO
Requirement
Specification
System
Analysis
System
Design
Input, Process, Output
Testing
Implementation
Maintenance
Deployment
The essence of system analysis and design is input,
process, and output. This is called IPO.
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Implementation
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
The process of translating the
system design into programs.
Separate programs are written for
each component and put to work
together.
This phase requires the use of a
programming language like Java.
The implementation involves
coding, testing, and debugging.
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Testing
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
Ensures that the code meets the
requirements specification and
weeds out bugs.
An independent team of software
engineers not involved in the design
and implementation of the project
usually conducts such testing.
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Deployment
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
Deployment makes the project
available for use.
For a Java applet, this means
installing it on a Web server; for a
Java application, installing it on the
client's computer.
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Maintenance
Requirement
Specification
System
Analysis
System
Design
Testing
Implementation
Maintenance
Deployment
Maintenance is concerned with
changing and improving the
product.
A software product must continue to
perform and improve in a changing
environment. This requires periodic
upgrades of the product to fix newly
discovered bugs and incorporate changes.
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Problem:
Computing Loan Payments
ComputeLoan Run
This program lets the user enter the interest
rate, number of years, and loan amount, and
computes monthly payment and total
payment.
12)1(11
arsnumberOfYeerestRatemonthlyInt
erestRatemonthlyIntloanAmountmentmonthlyPay
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Character Data Type
char letter = 'A'; (ASCII)
char numChar = '4'; (ASCII)
char letter = '\u0041'; (Unicode)
char numChar = '\u0034'; (Unicode)
Four hexadecimal digits.
NOTE: The increment and decrement operators can also be used
on char variables to get the next or preceding Unicode character.
For example, the following statements display character b.
char ch = 'a';
System.out.println(++ch);
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Unicode Format
Java characters use Unicode, a 16-bit encoding scheme
established by the Unicode Consortium to support the
interchange, processing, and display of written texts in the
world’s diverse languages. Unicode takes two bytes,
preceded by \u, expressed in four hexadecimal numbers
that run from '\u0000' to '\uFFFF'. So, Unicode can
represent 65535 + 1 characters.
Unicode \u03b1 \u03b2 \u03b3 for three Greek
letters
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Problem: Displaying Unicodes
Write a program that displays two Chinese characters and three Greek letters.
DisplayUnicode Run
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Escape Sequences for Special Characters
Description Escape Sequence Unicode
Backspace \b \u0008
Tab \t \u0009
Linefeed \n \u000A
Carriage return \r \u000D
Backslash \\ \u005C
Single Quote \' \u0027
Double Quote \" \u0022
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Appendix B: ASCII Character Set
ASCII Character Set is a subset of the Unicode from \u0000 to \u007f
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ASCII Character Set, cont.
ASCII Character Set is a subset of the Unicode from \u0000 to \u007f
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Casting between char and
Numeric Types
int i = 'a'; // Same as int i = (int)'a';
char c = 97; // Same as char c = (char)97;
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Problem: Monetary Units
This program lets the user enter the amount in
decimal representing dollars and cents and output
a report listing the monetary equivalent in single
dollars, quarters, dimes, nickels, and pennies.
Your program should report maximum number of
dollars, then the maximum number of quarters,
and so on, in this order.
ComputeChange Run
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Trace ComputeChange
int remainingAmount = (int)(amount * 100);
// Find the number of one dollars
int numberOfOneDollars = remainingAmount / 100;
remainingAmount = remainingAmount % 100;
// Find the number of quarters in the remaining amount
int numberOfQuarters = remainingAmount / 25;
remainingAmount = remainingAmount % 25;
// Find the number of dimes in the remaining amount
int numberOfDimes = remainingAmount / 10;
remainingAmount = remainingAmount % 10;
// Find the number of nickels in the remaining amount
int numberOfNickels = remainingAmount / 5;
remainingAmount = remainingAmount % 5;
// Find the number of pennies in the remaining amount
int numberOfPennies = remainingAmount;
1156remainingAmount
remainingAmount
initialized
Suppose amount is 11.56
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Trace ComputeChange
int remainingAmount = (int)(amount * 100);
// Find the number of one dollars
int numberOfOneDollars = remainingAmount / 100;
remainingAmount = remainingAmount % 100;
// Find the number of quarters in the remaining amount
int numberOfQuarters = remainingAmount / 25;
remainingAmount = remainingAmount % 25;
// Find the number of dimes in the remaining amount
int numberOfDimes = remainingAmount / 10;
remainingAmount = remainingAmount % 10;
// Find the number of nickels in the remaining amount
int numberOfNickels = remainingAmount / 5;
remainingAmount = remainingAmount % 5;
// Find the number of pennies in the remaining amount
int numberOfPennies = remainingAmount;
1156remainingAmount
Suppose amount is 11.56
11numberOfOneDollars
numberOfOneDollars
assigned
animation
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Trace ComputeChange
int remainingAmount = (int)(amount * 100);
// Find the number of one dollars
int numberOfOneDollars = remainingAmount / 100;
remainingAmount = remainingAmount % 100;
// Find the number of quarters in the remaining amount
int numberOfQuarters = remainingAmount / 25;
remainingAmount = remainingAmount % 25;
// Find the number of dimes in the remaining amount
int numberOfDimes = remainingAmount / 10;
remainingAmount = remainingAmount % 10;
// Find the number of nickels in the remaining amount
int numberOfNickels = remainingAmount / 5;
remainingAmount = remainingAmount % 5;
// Find the number of pennies in the remaining amount
int numberOfPennies = remainingAmount;
56remainingAmount
Suppose amount is 11.56
11numberOfOneDollars
remainingAmount
updated
animation
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Trace ComputeChange
int remainingAmount = (int)(amount * 100);
// Find the number of one dollars
int numberOfOneDollars = remainingAmount / 100;
remainingAmount = remainingAmount % 100;
// Find the number of quarters in the remaining amount
int numberOfQuarters = remainingAmount / 25;
remainingAmount = remainingAmount % 25;
// Find the number of dimes in the remaining amount
int numberOfDimes = remainingAmount / 10;
remainingAmount = remainingAmount % 10;
// Find the number of nickels in the remaining amount
int numberOfNickels = remainingAmount / 5;
remainingAmount = remainingAmount % 5;
// Find the number of pennies in the remaining amount
int numberOfPennies = remainingAmount;
56remainingAmount
Suppose amount is 11.56
11numberOfOneDollars
2numberOfOneQuarters
numberOfOneQuarters
assigned
animation
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Trace ComputeChange
int remainingAmount = (int)(amount * 100);
// Find the number of one dollars
int numberOfOneDollars = remainingAmount / 100;
remainingAmount = remainingAmount % 100;
// Find the number of quarters in the remaining amount
int numberOfQuarters = remainingAmount / 25;
remainingAmount = remainingAmount % 25;
// Find the number of dimes in the remaining amount
int numberOfDimes = remainingAmount / 10;
remainingAmount = remainingAmount % 10;
// Find the number of nickels in the remaining amount
int numberOfNickels = remainingAmount / 5;
remainingAmount = remainingAmount % 5;
// Find the number of pennies in the remaining amount
int numberOfPennies = remainingAmount;
6remainingAmount
Suppose amount is 11.56
11numberOfOneDollars
2numberOfQuarters
remainingAmount
updated
animation
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The String Type The char type only represents one character. To represent a string
of characters, use the data type called String. For example,
String message = "Welcome to Java";
String is actually a predefined class in the Java library just like the
System class and JOptionPane class. The String type is not a
primitive type. It is known as a reference type. Any Java class can
be used as a reference type for a variable. Reference data types
will be thoroughly discussed in Chapter 8, “Objects and Classes.”
For the time being, you just need to know how to declare a String
variable, how to assign a string to the variable, and how to
concatenate strings.
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String Concatenation
// Three strings are concatenated
String message = "Welcome " + "to " + "Java";
// String Chapter is concatenated with number 2
String s = "Chapter" + 2; // s becomes Chapter2
// String Supplement is concatenated with character B
String s1 = "Supplement" + 'B'; // s1 becomes SupplementB
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Debugging
Logic errors are called bugs. The process of finding and
correcting errors is called debugging. A common approach
to debugging is to use a combination of methods to narrow
down to the part of the program where the bug is located.
You can hand-trace the program (i.e., catch errors by
reading the program), or you can insert print statements in
order to show the values of the variables or the execution
flow of the program. This approach might work for a
short, simple program. But for a large, complex program,
the most effective approach for debugging is to use a
debugger utility.
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Debugger
Debugger is a program that facilitates debugging.
You can use a debugger to
Execute a single statement at a time.
Trace into or stepping over a method.
Set breakpoints.
Display variables.
Display call stack.
Modify variables.
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JOptionPane Input
This book provides two ways of obtaining input.
1. Using the Scanner class (console input)
2. Using JOptionPane input dialogs
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Getting Input from Input Dialog Boxes
String input = JOptionPane.showInputDialog(
"Enter an input");
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Getting Input from Input Dialog Boxes
String string = JOptionPane.showInputDialog(
null, “Prompting Message”, “Dialog Title”,
JOptionPane.QUESTION_MESSAGE);
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Two Ways to Invoke the MethodThere are several ways to use the showInputDialog method. For the time being, you only need to know two ways to invoke it.
One is to use a statement as shown in the example:
String string = JOptionPane.showInputDialog(null, x,
y, JOptionPane.QUESTION_MESSAGE);
where x is a string for the prompting message, and y is a string for the title of the input dialog box.
The other is to use a statement like this:
JOptionPane.showInputDialog(x);
where x is a string for the prompting message.
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Converting Strings to Integers
The input returned from the input dialog box is a string. If you enter a numeric value such as 123, it returns “123”. To obtain the input as a number, you have to convert a string into a number.
To convert a string into an int value, you can use the static parseInt method in the Integer class as follows:
int intValue = Integer.parseInt(intString);
where intString is a numeric string such as “123”.
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Converting Strings to Doubles
To convert a string into a double value, you can use the
static parseDouble method in the Double class as follows:
double doubleValue =Double.parseDouble(doubleString);
where doubleString is a numeric string such as “123.45”.
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Problem: Computing Loan Payments
Using Input Dialogs
ComputeLoanUsingInputDialog Run
Same as the preceding program for computing loan
payments, except that the input is entered from the
input dialogs and the output is displayed in an
output dialog.
12)1(11
arsnumberOfYeerestRatemonthlyInt
erestRatemonthlyIntloanAmount
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Debugging in NetBeans
Supplement II.E, Learning Java Effectively with
NetBeans
Companion Website
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Debugging in Eclipse
Supplement II.G, Learning Java Effectively with
NetBeans
Companion Website