Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm,...

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Ch. 5 Gases!!!!!

Transcript of Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm,...

Page 1: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Ch. 5 Gases!!!!!

Page 2: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Pressure conversionsO Pressure – force per unit areaO Can be measured in atm, mmHg, torr,

kPa, psiO 1atm =760mmHg = 760torr =

101.3kPa= 14.7psiO Measured with a barometer

(atmospheric pressure) or a manometer (pressure within a container)

Page 3: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Main variables with gases

O Pressure (P)O Volume (V)O Temperature (T)O Moles (n)O Ideal gas constant (R) = 0.08206

Page 4: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Boyles, Charles, Gay Lussac, Combined, Avogadros

O Boyles: P1V1 = P2V2

O Charles: V1/ T1 = V2 / T2

O Gay Lussac: P1 / T1 = P2 / T2

O Combined: P1V1 = P2V2

T1 T2

O Avogadro: V1/n1 = V2/n2

Page 5: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Sample Questions1. A balloon is filled to a volume of

7.00 x 102mL at a temperature of 20.0°C. The balloon is then cooled at constant pressure to a temperature of 1.00 x 102K. What is the final volume of the balloon?

Page 6: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Sample Questions

2. An 11.2-L sample of gas is determined to contain 0.50 mol N2. At the same temperature and pressure, how many moles of gas would there be in a 20.0L sample?

Page 7: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Sample Questions

3. Suppose two 200.0L tanks are to be filled separately with the gases helium and hydrogen. What mass of each gas is needed to produce a pressure of 135 atm in its respective tank at 24°C?

Page 8: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Ideal Gas LawO PV = nRTO What units do each of the variables

have to be in for this law?O Sample Question: A 5.0L flask

contains 0.60g of O2 at a temperature of 22°C. What is the pressure (in atm) inside the flask?

Page 9: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Gas StoichiometryO 1 mole of ANY gas at STP = 22.4LO 22.4L is the “molar volume” of an

ideal gasO Use this conversion to skip using the

ideal gas law O Sample problem: A sample of

nitrogen gas has a volume of 1.75L at STP. How many moles are present?

Page 10: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Molar Mass of a Gas

O Molar mass = dRT P

O d = density (g/L)O R = ideal gas constantO T = temperatureO P = pressureO Sample: The density of a gas was measure at

1.50atm and 27°C and found to be 1.95g/L. Calculate the molar mass of the gas.

Page 11: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Dalton’s Law of Partial PressuresO Ptotal = P1 + P2 + P3

O P1, P2 and P3 are called partial pressures

O Ptotal can also be calculated if you know the total number of moles (ntotal)

O Ptotal = ntotal(RT/V)

O Mole fraction is also important to thisO Mole fraction (χ1) = n1/ntotal

O Mole fraction is directly related to partial pressure: χ1 = n1/ntotal = P1/Ptotal

Page 12: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Dalton’s Law Sample Question

1. The partial pressure of oxygen was observed to be 156 torr in air with a total atmospheric pressure of 743 torr. Calculate the mole fraction of O2 present.

Page 13: Ch. 5 Gases!!!!!. Pressure conversions O Pressure – force per unit area O Can be measured in atm, mmHg, torr, kPa, psi O 1atm =760mmHg = 760torr = 101.3kPa=

Another Sample Question

1. Mixtures of He and O2 can be used in scuba diving tanks to help prevent the “bends.” For a particular dive, 46L He at 25°C and 1.0atm and 12L O2 at 25°C and 1.0atm were pumped into a tank with a volume of 5.0L. Calculate the partial pressure of each gas and the total pressure in the tank at 25°C.