CE 382 L10 - Approximate Analysis
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Transcript of CE 382 L10 - Approximate Analysis
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Approximate Analysis ofStatically Indeterminate
Structures
Every successful structure mustbe capable of reaching stableequilibrium under its appliedloads, regardless of structuralbehavior. Exact analysis of indeterminate structures involvescomputation of deflections andsolution of simultaneousequations . Thus, computer programs are typically used.
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To eliminate the difficultiesassociated with exact analysis,preliminary designs of indeter-minate structures are often basedon the results of approximateanalysis.
Approximate analysis is basedon introducing deformationand/or force distribution
assumptions into a staticallyindeterminate structure, equalin number to degree of indeter-minacy, which maintains stable
equilibrium of the structure .
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No assumptions inconsistentwith stable equilibrium areadmissible in any approximateanalysis .
Uses of approximate analysisinclude:
(1) planning phase of projects,when several alternative designs
of the structure are usuallyevaluated for relative economy;
(2) estimating the various
member sizes needed to initiatean exact analysis;
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(3) check on exact analysisresults;
(4) upgrades for older structuredesigns initially based onapproximate analysis; and
(5) provide the engineer with a
sense of how the forcesdistribute through the structure.
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In order to determine the reac-tions and internal forces for indeterminate structures usingapproximate equilibrium me-
thods, the equilibrium equationsmust be supplemented byenough equations of conditionsor assumptions such that the
resulting structure is stable andstatically determinate .
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The required number of suchadditional equations equalsthe degree of static indeter-minacy for the structure , witheach assumption providing anindependent relationshipbetween the unknownreactions and/or internalforces .
In approximate analysis, theseadditional equations are basedon engineering judgment of appropriate simplifying assump-tions on the response of thestructure.
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Approximate Analysis of
a Continuous Beam forGravity Loads
Continuous beams and girdersoccur commonly in building floor systems and bridges. In theapproximate analysis of con-tinuous beams, points ofinflection or inflection point(IP) positions are assumedequal in number to the degreeof static indeterminacy .
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For continuous beam struc-tures, the degree of staticindeterminacy in bending ( Ib)equals
number of bendingreactions (vertical andmoment support reactions)
C = number of equationsof condition in bending
b bRI N C 2=
bRN =
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Each inflection point positionintroduces one equation of
condition to the static equilibri-um equations . Three strategiesare used to approximate thelocation of the inflection points:
1. qualitative displacementdiagrams of the beamstructure,
2. qualitative bending momentdiagrams ( preferred methodfor students ), and
3. location of exact inflectionpoints for some simplestatically indeterminatestructures.
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Approximate analysis of con-tinuous beams using the quali-tative deflection diagram isbased on the fact that the elasticcurve ( deflected shape ) of acontinuous beam can generallybe sketched with a fair degree of accuracy without performing anexact analysis . When the elasticcurve is sketched in this manner,the actual magnitudes of deflec-tion (displacements and rota-tions) are not accurately por-trayed, but the inflection pointlocations are easily estimatedeven on a fairly rough sketch.
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Qualitative bending momentdiagrams can also be used tolocate inflection points .Bending moments in spans withno loading are linear or constant;with point loading the spanbending moment equations arepiecewise linear; and withuniform loading the moments arequadratic. Remember, internalbending moments at interior support locations adjacent to oneor two loaded spans is negative .
Recall that zero momentlocations correspond to theinflection point locations .
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From the total set of inflectionpoints, select the needednumber to achieve a solutionby statics .
In the case of beams , there willnormally be enough inflectionpoints to reduce the structureto a statically determinatestructure and typically thereare more inflection points thanthe degree of indeterminacy .
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With the inflection points located
(equal in number to the degreeof static indeterminacy), theanalysis can proceed on thebasis of statics alone. Since an
inflection point is a zero momentlocation , it may be thought ofas an internal hinge forpurposes of analysis .
Some examples to guide thelearning and practice aregiven on the following pages.
Both the elastic curve andbending moment diagrams aregiven.
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Fixed-Fixed Beam Subjectedto a Uniform Load
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Fixed-Fixed Beam Subjectedto a Central Point Force
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Propped Cantilever BeamSubjected to a Uniform Load
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Propped Cantilever BeamSubjected to aCentral Point Force
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When considering problems thatdo not match the exact valuesgiven, some useful guides are:
Inflection points move
towards positions of reducedstiffness,
No more than one inflectionpoint can occur in an un-loaded span, and
No more than two inflectionpoints will occur in a loaded
span .
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Example Approximate Analysisof a Continuous Beam
L L
qEI = constant
IP1
IP2
L/3L
0.1 < 0.25
QualitativeDeflection Diagram
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Qualitative BendingMoment Diagram
-M
0.5 M
L/3
L
L/3 2L/3 L (1- )LV1 V2R1
M1
R 2 R3
FBD through IPs
q q
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3
2 3
q(1 )LR2
q(1 )LV R
2
=
= =
From the last FBD:
From the middle FBD:
2
1 2
1
2L q( L)V LV
3 2
3q LV4
= + +
=
2M 0=
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From the first FBD:
y 2 1 2F 0 R V q L V= = +
2qL
R (2 5 )4
= +
2
1 1 1L q L
M 0 M V3 4
= = =
y 1 1 3q LF 0 R V 4= = =
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Shear Force Diagram
R1
R2
-R 3
R2 + R 1
M1
-2M1
0.125q[(1- )L]2
(1- )L/2
Bending Moment Diagram
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Frame Example
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Trusses with Double
DiagonalsTruss systems for roofs, bridgesand building walls often containdouble diagonals in each panel ,which makes each panelstatically indeterminate .
Approximate analysis requiresthat the number of assump-tions introduced must equalthe degree of indeterminacy sothat only the equations of equi-librium are required to performthe approximate analysis.
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Since one extra diagonal exists
in each double diagonal panel,one assumption regarding theforce distribution between thetwo diagonals must be made in
each panel . If the diagonals areslender , it may be assumed thatthe diagonal members are onlycapable of resisting tensile
forces and that diagonalssubjected to compression canbe ignored since they aresusceptible to buckling , i.e.,
assume very small bucklingload and ignore post-bucklingstrength .
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Such an assumption is illustratedin Fig. DD.1(a). In Fig. DD.1(a),the total panel shear is assumedto be resisted by the tensiondiagonal as shown. Compres-sion diagonals are assumed toresist no loading . With thisassumption, the truss of Fig.DD.1 is statically determinate.
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28Fig. DD.1 Truss with Double
Diagonal Panels
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The assumption discussed in the
previous paragraph is generallytoo stringent , i.e., the compres-sion diagonals can resist aportion of the panel shear .
Figures DD.1(b) and (c) showtwo different assumptionsregarding the ability of the
compression diagonals to resistforce.
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Figure DD.1(b) shows the shear (vertical) components of thediagonal members assuming thatthe compression and tensiondiagonals equally resist thepanel shear .
Figure DD.1(c) shows thevertical force distribution amongthe compression and tensiondiagonals based on the tensiondiagonal resisting twice the forceof the compression diagonal or two-thirds of the panel shear .
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Any reasonable assumptioncan be made .
The compression diagonalassumptions for double diagonaltrusses can be mathematicallysummarized as:
C = T; 0 1
If P S = Panel Shear , then
T(1+ ) = P S
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Once the diagonal memberforces are determined, theremaining member forces inthe truss can be calculatedusing simple statics , i.e., themethod of sections and/or themethod of joints.