C++ basic programs

Problem : Read any number from the user, then print positive if it is positive.

Program

#include <iostream.h>void main() {

int Num;cout<<"\n Please Enter an integer number:";cin>>Num;if (Num > 0)

cout<<" Positive\n";}

Write a program that reads a mark, if mark is 60 or greater, the program prints PASS, else it will print FAIL#include <iostream.h>

void main() {int mark;cout<<"\n Please Enter your mark: ";cin>>mark;if (mark>=60)cout<<" PASS\n";else cout<<"FAIL\n";

}

Problem : Read any number from the user, then print positive if it is positive and print negative otherwise.

Program


int Num;cout<<"\nPlease Enter Number:";cin>>Num;if (Num < 0)

cout<<"\nNegative\n";else

cout<<"\nPositive\n";}

Problem : Read Two numbers from the user, then print the greatest one.

Program#include <iostream.h>void main() {

int x,y;cout<<"\nPlease Enter two numbers:";cin>>x>>y;cout<<"Max = ";if (x > y)

cout<<x<<endl;else

cout<<y<<endl;}

Problem : Read three numbers to print the smallest one.


int a, b, c;cout<<"\nPlease Enter three numbers:";cin>>a>>b>>c;cout<<"\nMin= ";if ((a < b) && (a < c))

cout<<a;if ((b < a) && (b < c))

cout<<b;if ((c < a) && (c < b))

cout<<c;cout<<endl;

}

Problem : Read number, if it is positive, Add number 10 to it and print the Number “is positive”, but otherwise, subtract number 10 from it and print the Number “is negative”.


int Number;cout<<"\nPlease enter Number:";cin>>Number;if (Number>0) {

Number = Number + 10;cout<<Number<<" is Positive\n";}

else {Number = Number - 10;cout<<Number<<" is Negative\n";}

}

Problem : Print the word “Amman” five times. Program#include <iostream.h>void main( ) {

for (int i=1; i<=5; i++) cout<<"Amman\n";

}

Another Program#include <iostream.h>void main() {

for (int i=5; i>=1; i--) cout<<"Amman\n";

}

Problem : Print the following numbers.1 3 5 7 9 11

Program#include <iostream.h>void main( ) {

for (int k=1; k<=11; k+=2) cout<<k<<“\t”;

cout<<endl;}

Problem : Print the following numbers.20 17 14 11 8 5 2

Program


for (int m=20; m>=2; m-=3) cout<<m<<“\t”;

cout<<endl;}

Problem : Print the following numbers.1 2 3 4 … n(entered by user)

Program


int n;cout<<"\nPlease enter the upper limit:";cin>>n;for (int i=1; i<=n; i++)

cout<<i<<“\t”;cout<<endl;

}

Problem : Print the following numbers.L (entered By user) (L+1) (L+2) … U (entered By user)


int L,U;cout<<"\nPlease enter the Lower limit:";cin>>L;cout<<"\nPlease enter the Upper limit:";cin>>U;for (int i=L; i<=U; i++)

cout<<i<<“\t”;cout<<endl;

}

Problem : Read five numbers from the user and print the positive numbers only.


int num;for (int i=1; i<=5; i++)

{ cout<<"\nPlease Enter No"<<i<<':'; cin>>num; if (num > 0)

cout<<num; }

}

Problem : Compute and print S, Where Sum = 1+ 3+ 5+ 7+ … + n


int Sum=0, n;cout<<"\nPlease Enter n";cin>>n;for (int i=1; i<=n; i+=2)

Sum+=i;cout<<"\nSum="<<Sum<<endl;

}

Problem : Compute and print the summation of any 10 numbers entered by the user.

Program


int S=0, N;for (int i=10; i>=1; i--) {

cout<<"\nPlease Enter the next number:";cin>>N;S+=N;}

cout<<"\nS="<<S<<endl;}

A program to find n!

#include <iostream.h>void main( ) {int Fact=1,n;cout<<“Enter an integer to find its factorial”;cin>>n;for (int j=n; j>=1; j--)Fact *= j;cout<<n<<"!= "<<Fact<<endl;} Try it on n = 17 ???

Problem : Compute and Print the value of M where M = 2 * 4 * 6 * … * n

Program

#include <iostream.h>void main( ) {

long M=1;int n;cout<<"please enter the upper Limit:";cin>>n;for (int i=2; i<=n; i+=2)

M *= i;cout<<"M= "<<M<<endl;

}

Problem : Draw the following shape***************

#include <iostream.h>void main( ) {

for (int raw=1; raw<=5; raw++) {for (int C=1; C<=raw; C++)

cout<<'*';cout<<endl; }

}

Nested for



for (int i=1; i<=5; i++) {for (int j=i; j<=5; j++)

cout<<'*';cout<<endl; }

}

Problem : display the multiplication table for the number 3.


for (int i=1; i<=10; i++)cout<<"3 x "<<i<<" = "<<3*i<<endl;

}

Problem : Print the word “Amman” five times. Program


int i=1;while (i<=5)

{cout<<"Amman\n";i++;}

}

Problem : Print the following numbers.1 3 5 7 9 11


int i=1;while (i <= 11) {

cout<<i<<'\t';i+=2; }

}

Remark:Write ((i+=2) <= 11 ) condition instead of the above one. What changes you have to do to produce the same output.

Problem : Print the following numbers.20 17 14 … n


int n, k=20;cout<<"Enter the lower limit:";cin>>n;while ( k >= n) {

cout<<k<<'\t';k -= 3; }

}

Remark:Write k-=3 instead of k in the above condition. What you have to do to produce the same output.

Problem : Read five numbers from the user and print the positive numbers only.

Program


int num, j=0;while ( j++ < 5 ) {

cout<<"Enter the next num:";cin>>num;if (num > 0)

cout<<num<<endl; }}

Problem : Compute and print S, Where Sum = 1+ 3+ 5+ 7+ … + n


int n, Sum=0, i=1;cout<<"Enter the upper limit:";cin>>n;while ( i <= n ) {

Sum += i;i += 2; }

cout<<"\nSum="<<Sum;}

Problem : Read 10 numbers by the user and compute and print the summation of numbers, which are divisible by 3.


int Num, Sum=0, i=1;while ( i <= 10 ) {

cout<<"Enter a number:";cin>>Num;if (Num % 3 == 0)

Sum += Num;i++; }

cout<<"\nSum="<<Sum;}

Problem : Compute and Print the value of M where M = 2 * 4 * 6 * … * n

Program


int N, M=1, i=2;cout<<"Enter the upper limit:";cin>>N;while ( i <= N ) {

M *= i;i += 2; }

cout<<"\nM="<<M;}

Nested Loops#include <iostream.h>void main() {

int i,j=1;while(j<=4){

i=1;while(i<=4){cout<<i<<"\t";i++;

}j++;

cout<<endl;}

}

1 2 3 41 2 3 41 2 3 41 2 3 4



int i=1;while (i<=5) {

int j=1;while (j<=i)

{cout<<'*';j++;}

cout<<endl;i++; }

}

Do .. While Technique

General Form:do {.Statement(s); .

} while (Condition) ;

Statements will be executed repeatedly while condition is true. When the condition become false, the loop will be terminated and the execution sequence will go to the first statement after the loop.

The loop body will be executed at least one.

Problem : Print the word “Amman” five times. Program


int i = 1;do {

cout<<"Amman\n";i++;

} while (i <= 5);}

Execute the following program#include <iostream.h>void main() {

int Choice, Num;do {

cout<<"\n Enter the New Number";cin>>Num;if (Num % 2 == 0)

cout<<Num<<" is Even\n";else

cout<<Num<<" is Odd\n";cout<<"Select your choice.\n";cout<<"1- Exit. (Terminate the Run)\n";cout<<"2- Enter New Number to Check.\n";cin>>Choice;

} while (Choice != 1);}

11 21 2 41 2 4 8

for (int i=1;i<=4;i++){int x=1; for(int j=1;j<=i;j++)

{cout<<x<<“ “; x=x*2;} cout<<endl;}

C++ basic programs

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