BASIC ELECTRICAL TECHNOLOGY DET 211/3 Chapter 7 Direct Current (DC) Motor & Direct Current (DC)...
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Transcript of BASIC ELECTRICAL TECHNOLOGY DET 211/3 Chapter 7 Direct Current (DC) Motor & Direct Current (DC)...
![Page 1: BASIC ELECTRICAL TECHNOLOGY DET 211/3 Chapter 7 Direct Current (DC) Motor & Direct Current (DC) Generator.](https://reader036.fdocuments.in/reader036/viewer/2022081513/56649d8e5503460f94a773f1/html5/thumbnails/1.jpg)
BASIC ELECTRICAL TECHNOLOGY
DET 211/3
Chapter 7
Direct Current (DC) Motor
&
Direct Current (DC) Generator
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DC Motor
There are four major types of DC motor in general use:
• Separately excited DC motor
• Shunt DC Motor
• Series DC Motor
• Compounded DC Motor
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Speed Regulations
• DC motors are often compared by their speed regulations.
• Speed Regulations (SR) of the a motor is defined by
100% xSRfl
flnl
100% xn
nnSR
fl
flnl
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The Equivalent Circuit of a DC Motor
Armature circuit represented by voltage source, EA and a resistor RA.
The brush voltage drop represented by battery, Vbrush opposing the direction of current flow in the machine.
The field coils, which produce the magnetic flux are represented by inductor LF and resistor RF.
The separate resistor, Radj represents an external variable resistor used to control the amount of current in the field circuit.
RA
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The Equivalent Circuit of a DC Motor
The brush voltage drop is often only a very tiny fraction of the generated voltage in a machine so the voltage drop may be left out or approximately included in the value of RA.
The internal resistor in the field coils is sometimes lump together with the variable resistor, and the total is called RF.
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The Equivalent Circuit of a DC Motor
The internal generated voltage in DC motor is
KEA
The induce torque developed by DC motor is
Aind IK
These two equations, the KVL equation of the armature circuit and the machine’s magnetization curve are all the tools necessary to
analyze the behavior and performance of the dc motor.
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Separately Excited and Shunt DC motors
Separately excited DC motor
Shunt DC motor
F
FF R
VI
AAAT RIEV
AL II
F
TF R
VI
AAAT RIEV
FAL III
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Example
1. the speed of this motor when its input current is 100A2. the speed of this motor when its input current is 200A3. the speed of this motor when its input current is 300A.4. the induced torque of this motor for above conditions.
A 50hp, 250V, 1200rpm DC shunt motor with compensating windings has an armature resistance of 0.06Ω. Its field circuit has a total resistance of 50Ω, which produces a no load speed of 1200rpm. There are 1200 turns per pole on the shunt field winding. Find:
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Solution
KEA
V250VT
rpm1200n
1rads67125x2
60
n2
.60
1200
The relationship between the speeds and internal generated voltages of the motor at two different load conditions is
11A KE (1)
22A KE (2)
The flux is constant and no armature reaction
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Solution
2
1
2A
1A
K
K
E
E
At no load, rpm1200n
IA = 0A
V250VE T1A
1)
A9550
250100
R
VIIII
F
TLFLA
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V3.244)06.0(95250RIVE AATA EA at this load will be
The resulting speed of this motor is
2
1
2A
1A
K
K
E
E
1
1A
12A2 rads8.122
250
67.125x3.244
E
E
rpm11732
8.122x60
2
60n2
Solution
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Answer
2)
IA = 195A,
EA = 238.3V,
n2 = 1144rpm
IA = 295A,
EA = 232.3V,
n2 = 1115rpm
3)
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Solution
4)
indAAconv IEP
AA
ind
IE
Nm1898.122
95x3.244ind
At IL = 100A
At IL = 200ANm388ind
At IL = 300ANm587ind
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Series DC Motor
)RR(IEV sAAAT
SAL III
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Compounded DC Motor
A compounded DC motor is a motor with both a shunt and a series field.
Current flowing into a dot produces a positive magnetomotive force.
If current flows into the dots on both field coils, the resulting magnetomotive forces add to produces a larger total magnetomotive force. It is called cumulative compounding.
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Equivalent circuit of compounded DC motor
)RR(IEV sAAAT
FLA III
F
FF R
VI
ARFnet F- F FF SE
F
ARA
F
SEF
*F N
IN
NII
F
Long shunt connection
Short shunt connection
The net magnetomotive force
Effective shunt field current
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Applications of DC motor types
Separately-excited dc motor applications:i) Golf cars (buggy)ii) Forkliftiii) Aerial lift equipment
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DC GeneratorThere are five major types of DC generators:
1. Separately excited generator. In a separately excited generator, the field flux is derived from a separately power source independent of the generator itself.
2. Shunt generator. In a shunt generator, the field flux is derived by connecting the field circuit directly across the terminals of the generator.
3. Series generator. In a series generator, the field flux is produced by connecting the field circuit in series with the armature of the generator.
4. Cumulatively compounded generator. In a cumulatively compounded generator, both a shunt and a series field are present, and their effects are additive.
5. Differentially compounded generator. In a differentially compounded generator, both a shunt and a series field are present, but their effects are subtractive.
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DC Generator
DC generators are compared by their voltages, power ratings, efficiencies, and voltage regulations.
Voltage regulation, VR is defined by
100%x V
VVVR
fl
flnl
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Separately Excited Generator
AL II
F
FF R
VI
AAAT RIEV
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Example
If no load voltage of a separately-excited dc generator is 135V at 850 r/min, what will be the voltage if the speed is increased to 1000 r/min? Assume constant field excitation
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Solution
V135V1 rpmn 8501 rpmn 10002
VV2 ?
2
1
2
1
2A
1A
n
n
nK
nK
E
E
Constant field excitation means; if1 = if2 or constant flux; 1 = 2
1A
1
22A E
n
nE V8158135
850
1000.)(
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Shunt DC Generator
AAAT RIEV
LFA III
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Series DC Generator
LSA III
)RR(IEV SAAAT
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The Cumulatively Compounded DC Generator
Cumulatively compounded dc generator with a long shunt connection
Cumulatively compounded dc generator with a short shunt connection
ARFnet F- F FF SE
Total Magnetomotive force
ARASEFF*FF INININ F
F
AR
F
ASEF
*F NN
INII
F
LFA III
)RR(IEV SAAAT
F
TF R
VI
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Differentially Compounded DC Generator
With a long shunt connection
ARFnet F- F FF SE
ARASEFF*FF INININ F
F
AR
F
ASEeq NN
INI
FEquivalent shunt field
current,
F
AR
F
ASEF
*F NN
INII
F
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Example
A short-shunt compound generator delivers 50A at 500V to a resistive load. The armature, series field and shunt field resistance are 0.16, 0.08 and 200, respectively. Calculate the armature current if the rotational losses are 520W, determine the efficiency of the generator
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Solution
W520Pu W25000A50Vx500Pout
A52200
500If . A552A50A52III Lfa ..
Armature Copper Loss: W441160552RIP 2a
2aca ).().()(
Series Field Copper Loss: W5220080552RIP 22f
2a2cf .).().()(
Shunt Field Copper Loss: W125020052RIP 21f
2f1cf )().()(
Friction + Stray + windage + etc: W520Pu
So,Total Losses = W5243152012505220441 .).(
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Continued…
Efficiency, η =sTotallossePout
Pout
Pin
Pout
%.@..
1391911305243125000
25000
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Assignment 6
The equivalent circuit of the separately-excited dc motor
Figure above shows fixed field voltage VF of 240V and armature voltage VA that can be varied from 120 V to 240 V. What is the no-load speed of this separately-excited dc motor when Radj =
175 and
a) VA = 120V, b) VA = 180V, c) VA = 240V ?
QUESTION 1
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Assignment 6
The equivalent circuit of the shunt dc motor
QUESTION 2
a) If the resistor Radj is adjusted to 175, what is the rotational speed of the motor at no-load conditions?
b) Assuming no armature reaction, what is the speed of the motor at full load? What is the speed regulation of the motor?
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The magnetization curve for the dc motor of Question 1 and Question 2. This curve was made at a constant speed of 1200 r/min.