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Bài 7.1:

Giải:

1)

Với F80 = 200 micro,

 S.G= 2,8 t/m3,

 W= 12,2 kW/t,

D=1m, ∅c=60

K= 30

!B1 = 13,11 mmVới F80 = "000 micro ,

!B2 = 8,#1 mm !B c$% !&%' = !B2 ( !B1" = , mm

2) *+%' k%- t- t- i %'-i%:

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 !c1 =

11,"mm ới F80 = 200 micro!c2 = 0,4 mm ới F80 = "000 micro

!c c$% !&%' = !c2 (  !c1 = 34, mm

Bài 8.#:

1. 5-6 ccit o t-6 mi99 %!6r !r %! ;6t 'ri%!i%' co!itio%<2. 5-6 o;6r co%<mtio%< t t-6 i%io% <-t %!6r !r %! ;6t co%!itio%<.3. 5-6 <6ciic 'ri%!i%' 6%6r'i6< !r %! ;6t co%!itio%< o 'ri%!i%'

Giải:

1. 5 c:> = k.?.D2,

Với ? = 3,# m@ D = 2,7" m@ k = π  /4

> = 3,1"2.

Với A  = 3#,1 to%6<@ D = 2,7" m@ ∅c = 0,7@ C  = 0,"

 A E!r) / A  = ",32 kW/t A E;6t) = A E!r) /1,3 = A E;6t) = 120 kW = A E;6t) / A  = 3,32 kW/t

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3. A E!r) = 1# kWA E;6t) = 120 kW

Bài 4.:

Giải:

1)

Với K = 10,#@ = 1,03@ CH = 0,"

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A = 1#8# kW

2)

?IFF = ",27 m

 J? = 173,84 kW

3)

Aà

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 JI5 = 103,38 kW A = 277,27 kW

Bài 10.:

Giải:

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11.3

A gold ore was crushed in a secondary crusher and screened dry on an 1180

micron square

aperture screen. The screen was constructed with 0.12 mm diameter uniform

stainless steel

wire. The size analysis of the feed, oersize and undersize streams are gien

in the following

ta!le. The gold content in the feed, undersize and oersize streams were" #ppm, 1.# ppm and

$ ppm respectiely. %alculate&

1. The mass ratios of the oersize and undersize to the feed,

2. 'erall e(ciency of the screen,

3. )istri!ution of gold in the oersize and undersize streams.